´Ó¼×¡¢ÒÒÁ½ÌâÖÐÑ¡×öÒ»Ì⣬Èç¹ûÁ½Ìⶼ×ö£¬Ö»ÒÔ¼×Ìâ¼Æ·Ö¡£

Ìâ¼×£ºÈçͼ£¬ÌÝÐÎABCDÖУ¬AD¡ÎBC£¬µãEÊDZßADµÄÖе㣬Á¬½áBE½»ACÓÚµãF£¬BEµÄÑÓ³¤Ïß½»CDµÄÑÓ³¤ÏßÓÚµãG¡£

£¨1£©       ÇóÖ¤£º

£¨2£©       ÈôGE£½2£¬BF£½3£¬ÇóÏ߶ÎBFµÄ³¤

ÌâÒÒ£ºÏÂͼÊÇ·´±ÈÀýº¯ÊýµÄͼÏ󣬵±£­4¡Üx¡Ü£­1ʱ£¬£­4¡Üy¡Ü£­1

£¨1£©Çó¸Ã·´±ÈÀýº¯ÊýµÄ½âÎöʽ

£¨2£©ÈôM¡¢N·Ö±ðÔÚ·´±ÈÀýº¯ÊýͼÏóµÄÁ½Ö§ÉÏ£¬ÇëÖ¸³öʲôÇé¿öÏÂÏ߶ÎMN×î¶Ì£¨²»ÐèÖ¤Ã÷£©£¬²¢Çó³öÏ߶ÎMN³¤¶ÈµÄÈ¡Öµ·¶Î§¡£

ÎÒÑ¡×öµÄÊÇ         ¡£

¼×Ì⣺

£¨1£©Ö¤Ã÷£º£¬

£¬

ÓÖ£¬£®

£¨2£©½â£º

£¬

ÓÉ£¨1£©Öª£¬

£¬

É裬Ôò£¬

ÔòÓУ¬

¼´£¬

½âµÃ£º»ò£¬

¾­¼ìÑ飬»ò¶¼ÊÇÔ­·½³ÌµÄ¸ù£¬µ«²»ºÏÌâÒ⣬ÉáÈ¥£®

¹ÊµÄ³¤Îª1£®

ÒÒÌ⣺

½â£º£¨1£©ÒòΪ·´±ÈÀýº¯ÊýµÄͼÏó¾­¹ýµã

ÓУ¬

£®

ËùÒÔ·´±ÈÀýº¯ÊýµÄ½âÎöʽΪ£¬

£¨2£©µ±ÎªÒ»¡¢ÈýÏóÏÞ½Çƽ·ÖÏßÓë·´±ÈÀýº¯ÊýͼÏñµÄ½»µãʱ£¬

Ï߶Î×î¶Ì£®

½«´úÈ룬½âµÃ£¬¼´£¬£®

£¬

Ôò£¬

ÓÖΪ·´±ÈÀýº¯ÊýͼÏñÉϵÄÈÎÒâÁ½µã£¬

ÓÉͼÏóÌصãÖª£¬Ï߶ÎÎÞ×î´óÖµ£¬¼´£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£º

¾«Ó¢¼Ò½ÌÍø´Ó¼×¡¢ÒÒÁ½ÌâÖÐÑ¡×öÒ»Ìâ¼´¿É£®Èç¹ûÁ½Ìⶼ×ö£¬Ö»ÒÔ¼×Ìâ¼Æ·Ö£®
Ìâ¼×£ºÈçͼ£¬·´±ÈÀýº¯Êýy=
kx
µÄͼÏóÓëÒ»´Îº¯Êýy=mx+bµÄͼÏó½»ÓÚA£¨1£¬3£©£¬B£¨n£¬-1£©Á½µã£®
£¨1£©Çó·´±ÈÀýº¯ÊýÓëÒ»´Îº¯ÊýµÄ½âÎöʽ£»
£¨2£©¸ù¾ÝͼÏó»Ø´ð£ºµ±xÈ¡ºÎֵʱ£¬·´±ÈÀýº¯ÊýµÄÖµ´óÓÚÒ»´Îº¯ÊýµÄÖµ£®

ÌâÒÒ£ºÈçͼ£¬ÔÚ¾ØÐÎABCDÖУ¬AB=4£¬AD=10£®Ö±½Ç³ßµÄÖ±½Ç¶¥µãPÔÚADÉÏ»¬¶¯Ê±£¨µãPÓëA£¬D²»Öغϣ©£¬Ò»Ö±½Ç±ß¾­¹ýµãC£¬ÁíÒ»Ö±½Ç±ßAB½»ÓÚµãE£®ÎÒÃÇÖªµÀ£¬½áÂÛ¡°Rt¡÷AEP¡×Rt¡÷DPC¡±³ÉÁ¢£®
£¨1£©µ±¡ÏCPD=30¡ãʱ£¬ÇóAEµÄ³¤£»
£¨2£©ÊÇ·ñ´æÔÚÕâÑùµÄµãP£¬Ê¹¡÷DPCµÄÖܳ¤µÈÓÚ¡÷AEPÖܳ¤µÄ2±¶£¿Èô´æÔÚ£¬Çó³öDPµÄ³¤£»Èô²»´æÔÚ£¬Çë˵¾«Ó¢¼Ò½ÌÍøÃ÷ÀíÓÉ£®
ÎÒÑ¡×öµÄÊÇ
 
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£º

´Ó¼×¡¢ÒÒÁ½ÌâÖÐÑ¡×öÒ»Ì⣮Èç¹ûÁ½Ìⶼ×ö£¬Ö»ÒÔ¼×Ìâ¼Æ·Ö£®
Ìâ¼×£ºÈô¹ØÓÚxÒ»Ôª¶þ´Î·½³Ìx2-2£¨2-k£©x+k2+12=0ÓÐʵÊý¸ùa£¬¦Â£®
£¨1£©ÇóʵÊýkµÄÈ¡Öµ·¶Î§£»
£¨2£©Éèt=
a+¦Â
k
£¬ÇótµÄ×îСֵ£®
ÌâÒÒ£ºÈçͼËùʾ£¬ÔÚ¾ØÐÎABCDÖУ¬PÊÇBC±ßÉÏÒ»µã£¬Á¬½ÓDP²¢ÑÓ³¤£¬½»ABµÄÑÓ³¤Ïß¾«Ó¢¼Ò½ÌÍøÓÚµãQ£®
£¨1£©Èô
BP
PC
=
1
3
£¬Çó
AB
AQ
掙术
£¨2£©ÈôµãPΪBC±ßÉϵÄÈÎÒâÒ»µã£¬ÇóÖ¤£º
BC
BP
-
AB
BQ
=£®
ÎÒÑ¡×öµÄÊÇ
 
Ì⣮

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£º

´Ó¼×¡¢ÒÒÁ½ÌâÖÐÑ¡×öÒ»Ìâ¼´¿É£¬Èç¹ûÁ½Ìⶼ×ö£¬Ö»ÒÔ¼×Ìâ¼Æ·Ö£®
¼×£ºÐ¡¶«´ÓAµØ³ö·¢ÒÔijһËÙ¶ÈÏòBµØ×ßÈ¥£¬Í¬Ê±Ð¡Ã÷´ÓBµØ³ö·¢ÒÔÁí-ËÙ¶ÈÏòAµØ¶øÐУ®ÈçͼËùʾ£¬Í¼Öо«Ó¢¼Ò½ÌÍøµÄÏ߶Îy1¡¢y2·Ö±ð±íʾС¶«¡¢Ð¡Ã÷ÀëBµØµÄ¾àÀ루ǧÃ×£©ÓëËùÓÃʱ¼ä£¨Ð¡Ê±£©µÄ¹Øϵ£®
£¨1£©ÊÔÓÃÎÄ×Ö˵Ã÷£º½»µãPËù±íʾµÄʵ¼ÊÒâÒ壻
£¨2£©ÊÔÇóy1¡¢y2µÄ½âÎöʽ£»
£¨3£©ÊÔÇó³öA¡¢BÁ½µØÖ®¼äµÄ¾àÀ룮

ÒÒ£ºÈçͼ£¬?ABCDÖУ¬EÊÇBAµÄÑÓ³¤ÏßÉÏÒ»µã£¬CEÓëAD½»ÓÚµãF£®
£¨1£©ÇóÖ¤£º¡÷AEF¡×¡÷DCF£»¾«Ó¢¼Ò½ÌÍø
£¨2£©ÈôAB=2AE£¬¡÷AEFµÄÃæ»ýΪ2
2
£¬Çó?ABCDµÄÃæ»ý£®

ÎÒÑ¡×öµÄÊÇ
 
Ì⣮

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£º

¾«Ó¢¼Ò½ÌÍø±¾ÌâΪѡ×öÌ⣬´Ó¼×¡¢ÒÒÁ½ÌâÖÐÑ¡×öÒ»Ìâ¼´¿É£¬Èç¹ûÁ½Ìⶼ×ö£¬Ö»ÒÔ¼×Ìâ¼Æ·Ö£®
Ñ¡×öÌ⣺¼×£ºÒÑÖª¹ØÓÚxµÄÒ»Ôª¶þ´Î·½³Ìx2-£¨2m+1£©x+m2+m-2=0
£¨1£©ÇóÖ¤£º²»ÂÛmÈ¡ºÎÖµ£¬·½³Ì×ÜÓÐÁ½¸ö²»ÏàµÈµÄʵÊý¸ù£»
£¨2£©Èô·½³ÌµÄÁ½¸öʵÊý¸ùx1¡¢x2Âú×ã
1
x1
+
1
x2
=1+
1
m+2
£¬ÇómµÄÖµ£®
ÒÒ£ºÈçͼ£¬µãDÊÇ¡ÑOµÄÖ±¾¶CAÑÓ³¤ÏßÉÏÒ»µã£¬µãBÔÚ¡ÑOÉÏ£¬ÇÒAB=AD=AO£®
£¨1£©ÇóÖ¤£ºBDÊÇ¡ÑOµÄÇÐÏߣ®
£¨2£©ÈôµãEÊÇÁÓ»¡BCÉÏÒ»µã£¬AEÓëBCÏཻÓÚµãF£¬ÇÒ¡÷BEFµÄÃæ»ýΪ8£¬cos¡ÏBFA=
2
3
£¬Çó¡÷ACFµÄÃæ»ý£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£º

£¨2013•¶ëüɽÊжþÄ££©Ñ¡×öÌ⣺´Ó¼×¡¢ÒÒÁ½ÌâÖÐÑ¡×öÒ»Ì⣬Èç¹ûÁ½Ìⶼ×ö£¬Ö»ÒÔ¼×Ìâ¼Æ·Ö£®
Ìâ¼×£ºÈçͼ1£¬Õý±ÈÀýº¯Êýy=-
1
2
x
µÄͼÏóÓë·´±ÈÀýº¯Êýy=
k
x
(k¡Ù0)
ÔÚµÚ¶þÏóÏÞµÄͼÏó½»ÓÚAµã£¬¹ýAµã×÷xÖáµÄ´¹Ïߣ¬´¹×ãΪM£¬ÒÑÖª¡÷OAMµÄÃæ»ýΪ1£®
£¨1£©Çó·´±ÈÀýº¯ÊýµÄ½âÎöʽ£»
£¨2£©Èç¹ûBΪ·´±ÈÀýº¯ÊýͼÏóÉϵĵ㣬ÇÒBµãµÄºá×ø±êΪ-1£¬ÔÚxÖáÉÏÒ»µãP£¬Ê¹PA+PB×îС£¬ÇóPµãµÄ×ø±ê£®
ÌâÒÒ£ºÈçͼ2£¬ÒÑÖªAB¡¢AC·Ö±ðΪ¡ÑOµÄÖ±¾¶ºÍÏÒ£¬DΪBCµÄÖе㣬DE¡ÍACÓÚE£¬DE=6£¬AC=16£®
£¨1£©ÇóÖ¤£ºDEÓë¡ÑOÏàÇУ»
£¨2£©ÇóÖ±¾¶ABµÄ³¤£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸