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If the linear function y=ax+b passes through the point (-2,0),but not the first Quadrant,then the solution set for ax>b is(  )
分析:将(-2,0)代入y=ax+b求得b=2a;再根据该直线不经过第一象限知a<0;然后再根据以上两个条件解不等式ax>b即可.
解答:解:∵y=ax+b 经过点(-2,0),
∴0=-2a+b,
∴b=2a,
∵该直线不经过第一象限,
∴a<0,
ax>b,即ax>2a,
∴x<2.
故选D.
点评:本题考查了一次函数与一元一次不等式.解答此题的关键是熟知一次函数y=ax+b 图象的特点:①当a>0时,函数图象经过第一、二、三象限;②当a<0时,函数图象经过第二、三、四象限.
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