Question

3．甲、乙两班共植树50株，乙班植树的株数是甲班的$\frac{1}{4}$．设甲班植树x株，乙班植树y株，根据题意，可列方程组$\left\{\begin{array}{l}{x+y=50}\\{y=\frac{1}{4}x}\end{array}\right.$．

Answer 1

分析 设甲班植树x株，乙班植树y株，根据题意甲、乙两班共植树50株，乙班植树的株数是甲班的$\frac{1}{4}$，列方程组即可．

解答 解：设甲班植树x株，乙班植树y株，根据题意可得：$\left\{\begin{array}{l}{x+y=50}\\{y=\frac{1}{4}x}\end{array}\right.$，
故答案为：$\left\{\begin{array}{l}{x+y=50}\\{y=\frac{1}{4}x}\end{array}\right.$

点评 本题考查了有实际问题抽象出二元一次方程组，解答本题的关键是读懂题意，找出合适的等量关系，列方程组．