9.观察下列一组等式的化简.然后解答后面的 问题:
$\frac{1}{\sqrt{2}+1}$=$\frac{1×(\sqrt{2}-1)}{(\sqrt{2}+1)(\sqrt{2}-1)}$=$\sqrt{2}-1$;$\frac{1}{\sqrt{3}+\sqrt{2}}$=$\frac{1×(\sqrt{3}-\sqrt{2})}{(\sqrt{3}+\sqrt{2})(\sqrt{3}-\sqrt{2})}$=$\sqrt{3}-\sqrt{2}$;
$\frac{1}{\sqrt{4}+\sqrt{3}}$=$\frac{1×(\sqrt{4}-\sqrt{3})}{(\sqrt{4}+\sqrt{3})(\sqrt{4}-\sqrt{3})}$=2-$\sqrt{3}$…
(1)在计算结果中找出规律$\frac{1}{\sqrt{n+1}+\sqrt{n}}$=$\sqrt{n+1}$-$\sqrt{n}$(n表示大于0的自然数)
(2)通过上述化简过程,可知$\sqrt{11}-\sqrt{10}$>$\sqrt{12}-\sqrt{11}$(天“>”、“<”或“=”);
(3)利用你发现的规律计算下列式子的值:
($\frac{1}{\sqrt{2}+1}+\frac{1}{\sqrt{3}+\sqrt{2}}+\frac{1}{\sqrt{4}+\sqrt{3}}+$…+$\frac{1}{\sqrt{2016}+\sqrt{2015}}$)($\sqrt{2016}+1$)