·ÖÎö £¨1£©Ê¹ÓÃÌìƽ²âÁ¿ÎïÌåÖÊÁ¿Ö®Ç°£¬ÐèÒª½øÐе÷ƽ£¬Æ½ºâÂÝĸµ÷½ÚµÄ¹æÂÉÊǸù¾ÝÖ¸Õë¡°×óÆ«ÓÒµ÷£¬ÓÒÆ«×óµ÷¡±£»ÔÚ²âÁ¿¹ý³ÌÖУ¬ÐèҪͨ¹ýÔö¼õíÀÂë»ò¸Ä±äÓÎÂëλÖÃʹºáÁºÆ½ºâ£»
£¨2£©¸ù¾Ýͼ¼×¶Á³öÉÕ±ºÍËáÄ̵Ä×ÜÖÊÁ¿µÈÓÚíÀÂë×ÜÖÊÁ¿¼ÓÉÏÓÎÂëÔÚ±ê³ßÉ϶ÔÓ¦µÄ¿Ì¶ÈÖµ£»
ÔÚÓÃÁ¿Í²²âÁ¿ÒºÌåÌå»ýʱ£¬Òª×¢Òâ¶ÁÊýÎÊÌ⣬ÊÓÏßÒªÓëÒºÃæµÄ°¼µ×Ïàƽ£¬Í¬Ê±Òª×¢ÒâÁ¿Í²µÄµ¥Î»ºÍ·Ö¶ÈÖµ£»ÓÃÔÀ´µÄ×ÜÖÊÁ¿¼õÈ¥³éÈ¡ºóÉÕ±ºÍÊ£ÓàËáÄ̵Ä×ÜÖÊÁ¿´Ó¶øµÃµ½³éÈ¡ËáÄ̵ÄÖÊÁ¿£¬¸ù¾Ý¦Ñ=$\frac{m}{V}$Çó³öËáÄ̵ÄÃܶȣ»
£¨3£©¸ù¾Ý²Ù×÷¹ý³Ì·ÖÎö²âÁ¿µÄÎïÀíÁ¿£¬ÓÉÓÚÕëͲµÄ¿Ì¶ÈÏßÇ°µÄ¼â¶Ë»¹ÊÇÓÐÒ»µãС¡°¿Õ϶¡±£¬Ôì³ÉËù²âÌå»ýƫС£¬´Ó¶ø¼ÆËã³öµÄÃܶÈÆ«´ó£»
ºÏÀíµÄʵÑé²Ù×÷¿ÉÒÔ¼õС²âÁ¿Ê±µÄÎó²î£¬²¢Ê¹²Ù×÷¼ò±ã£¬´ÓÕâÒ»½Ç¶È·ÖÎö²½Ö裻
ÖªµÀÕëͲÖеÄÒ»²¿·ÖËáÄÌ·µ»ØÉÕ±ÖÐʱÉÕ±ºÍÊ£ÓàËáÄ̵Ä×ÜÖÊÁ¿m3ºÍÓÃÕëͲ³éÈ¡5mLËáÄÌʱÉÕ±ºÍÊ£ÓàËáÄ̵Ä×ÜÖÊÁ¿m2£¬½ø¶ø¿ÉÒԵóö·µ»ØÉÕ±ÄÚËáÄ̵ÄÖÊÁ¿£¬
ÔÙ¼ÇÏ´ËʱÕëͲÄÚËáÄ̵ÄÌå»ýV¿ÉµÃ³ö·µ»ØÉÕ±ÄÚËáÄ̵ÄÌå»ý£¬È»ºó¸ù¾ÝÃܶȹ«Ê½µÃËáÄÌÃܶȱí´ïʽ£®
½â´ð ½â£º£¨1£©ÓÉͼ֪£¬ÔÚ²âÁ¿ÖÊÁ¿Ç°£¬Ö¸ÕëÖ¸ÔÚ·Ö¶ÈÅÌÆ«ÓҲ࣬ËùÒÔƽºâÂÝĸҪÏò×ó²àÒƶ¯£¬Ö±µ½Ö¸ÕëÖ¸ÔÚ·Ö¶ÈÅÌÖÐÑ룻
²âÁ¿ÖÊÁ¿¹ý³ÌÖУ¬Ö¸ÕëÖ¸ÔÚ·Ö¶ÈÅÌÆ«×ó²à£¬ËµÃ÷ÓÒÅÌíÀÂëµÄ×ÜÖÊÁ¿±ÈÎïÌåÖÊÁ¿ÂÔС£¬ËùÒÔÐèÒª½«ÓÎÂëÏòÓÒµ÷½Ú£¬Ö±µ½Ö¸ÕëÖ¸ÔÚ·Ö¶ÈÅÌÖÐÑ룻
£¨2£©ÓÉͼÒÒ¿ÉÖª£¬±ê³ßµÄ·Ö¶ÈֵΪ0.2g£¬
ÉÕ±ºÍËáÄ̵Ä×ÜÖÊÁ¿£ºm1=50g+10g+3g=63g£¬
ÓÃÕëͲ³éÈ¡µÄËáÄÌÖÊÁ¿£ºm=m1-m2=63g-57.6g=5.4g£¬
ÓÃÕëͲ³éÈ¡µÄËáÄÌV=5mL=5cm3£¬
ÔòËáÄ̵ÄÃܶȣº¦Ñ=$\frac{m}{V}$=$\frac{5.4g}{5c{m}^{3}}$=1.08g/cm3=1.08¡Á103kg/m3£®
ÕëͲµÄ·Ö¶ÈÖµ±ÈÁ¿Í²Ð¡£¨»òÕëͲ±ÈÁ¿Í²²âÁ¿Ìå»ý¾«È·¡¢»òÕëͲ²âÁ¿Ìå»ý¾«¶È¸ü¸ß£©£¬ËùÒÔ²âÁ¿µÄÌå»ý¸ü¾«È·£®
£¨3£©ÓÉÓÚÕëͲµÄ¿Ì¶ÈÏßÇ°µÄ¼â¶Ë»¹ÊÇÓÐÒ»µãС¡°¿Õ϶¡±£¬Ê¹µÃÕëͲÄÚ²âÁ¿µÄËáÄÌÌå»ýƫС£¬
ÓɦÑ=$\frac{m}{V}$¿ÉÖª£¬ÖÊÁ¿²»±ä£¬Ìå»ýƫС£¬ÃܶȻáÆ«´ó£®
ΪÁ˼õСʵÑéÎó²î£¬¿É²ÉÈ¡Ê£Óà·¨²âÁ¿ËáÄ̵ÄÃܶȣº½«´Ëʱ³éÂúËáÄ̵ÄÕëͲÖеÄÒ»²¿·ÖËáÄÌ·µ»ØÉÕ±£¬²âÁ¿ÉÕ±ºÍÊ£ÓàËáÄ̵Ä×ÜÖÊÁ¿m3£¬
ÕëͲÄÚ·µ»ØÉÕ±ËáÄ̵ÄÖÊÁ¿£ºm¡ä=m3-m2=m3-57.6g£¬
ÕëͲÄÚ·µ»ØÉÕ±ËáÄ̵ÄÌå»ý£ºV¡ä=5mL-V£¬
ÔòËáÄÌÃܶȱí´ïʽ£º¦ÑËáÄÌ=$\frac{{m}_{3}-{m}_{2}}{5-V}$»ò¦ÑËáÄÌ=$\frac{{m}_{3}-57.6}{5-V}$£®
¹Ê´ð°¸Îª£º
£¨1£©×ó£»½«ÓÎÂëÏòÓÒµ÷½Ú£¬Ö±µ½Ö¸ÕëÖ¸ÔÚ·Ö¶ÈÅÌÖÐÑ룻
£¨2£©63£»1.08¡Á103£»ÕëͲµÄ·Ö¶ÈÖµ±ÈÁ¿Í²Ð¡£¨»òÕëͲ±ÈÁ¿Í²²âÁ¿Ìå»ý¾«È·¡¢»òÕëͲ²âÁ¿Ìå»ý¾«¶È¸ü¸ß£©£»
£¨3£©Æ«´ó£»ÕëͲÄÚËáÄÌÌå»ýV£»¦ÑËáÄÌ=$\frac{{m}_{3}-{m}_{2}}{5-V}$»ò¦ÑËáÄÌ=$\frac{{m}_{3}-57.6}{5-V}$£®
µãÆÀ ±¾Ì⿼²éÁËÒºÌåÃܶȵIJâÁ¿£¬ÓÃÌìƽºÍÁ¿Í²À´²âÒºÌåµÄÃܶȣ¬ÊÇʵÑéÊÒÖÐ×î³£Óõķ½·¨£¬ÖصãÓ¦ÕÆÎÕÌìƽµÄµ÷½ÚÓëʹÓ÷½·¨¡¢Á¿Í²µÄ¶ÁÊý¡¢Ãܶȹ«Ê½µÄÔËÓá¢ÊµÑé²½ÖèµÄºÏÀí°²ÅÅÒÔ¼°ÊµÑéÎó²îµÄ·ÖÎöµÈ£®
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º³õÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
A£® | ½ÚÈÕÀïÒ»´®Ð¡²ÊµÆ | B£® | ¼ÒÍ¥ÖеıùÏäºÍµçÊÓ | ||
C£® | ¼ÒÍ¥ÖеĵçµÆ | D£® | Âí·ÉϵÄ·µÆ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
A£® | ÎïÌå²»ÊÜÁ¦£¬Ò»¶¨¾²Ö¹ | |
B£® | ÎïÌåÔ˶¯·½Ïò·¢Éú¸Ä±ä£¬ÔòÒ»¶¨Êܵ½Á¦µÄ×÷Óà | |
C£® | ×÷ÓÃÔÚÔ˶¯ÎïÌåÉϵÄÁ¦Ò»¶¨²»Æ½ºâ | |
D£® | ÎïÌåÊܵ½Á¦µÄ×÷Óã¬ËٶȴóСһ¶¨¸Ä±ä |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¼ÆËãÌâ
Ì«ÑôÄܵç³Ø°å | ×ÜÃæ»ýΪ15m2£¬Ã¿Æ½·½Ã×ÿСʱÎüÊÕÄÜÁ¿Îª1.2¡Á107J£¬ ÆäÖÐ10%ת»¯ÎªµçÄÜ |
ÿÌìÕý³£¹¤×÷ʱ¼ä | 6h |
ÓõçÆ÷Õý³£ ¹¤×÷µçѹ | 220V |
µçÄܱí | 3000r/kW•h |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
A£® | ×ÀÃæ¶ÔÎľߺеÄÖ§³ÖÁ¦ÓëÎľߺжÔ×ÀÃæµÄѹÁ¦ | |
B£® | ×À×ÓÊܵ½ÎľߺеÄѹÁ¦ÓëÎľߺÐÊܵ½µÄÖØÁ¦ | |
C£® | ÎľߺÐÊܵ½µÄÖØÁ¦Óë×ÀÃæ¶ÔÎľߺеÄÖ§³ÖÁ¦ | |
D£® | ÎľߺжÔ×ÀÃæµÄѹÁ¦ÓëµØÃæ¶Ô×À×ÓµÄÖ§³ÖÁ¦ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¼ÆËãÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÊµÑé̽¾¿Ìâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com