Question

1£®µ±½ñÊг¡´ó²¿·Ö¼ÓÈȲúÆ·Ìú¡¢ÂÁ¡¢²»Ðâ¸ÖµÈ£¬Ê¹Óùý³ÌÖлá²úÉú¶àÖÖ¶þ´Î»¯Ñ§·´Ó¦£¬Éú½ðÊôÀë×Ó¼°Óк¦ÎïÖÊ£¬¶ÔÈËÌ彡¿µÓÐÒ»¶¨Ó°Ï죬ËùÒÔ½¥½¥Á÷ÐÐÆð²£Á§µçÈÈË®ºø£®²£Á§µçÈÈË®ºøÊÇÖ¸Ò»ÖÖÓÃÓÚÑøÉú±£½¡µÄ¿ÉÒÔÅëÒûµÄÈÝÆ÷£¬ÀàËÆÓÚµçË®ºø£¬Æä×î´óµÄÌصãÊDzÉÓÃÒ»ÖÖÐÂÐ͵ĵç¼ÓÈȲÄÁÏ£¬Í¨¹ý¸ßΰѵçÈÈĤµç×Ó½¬ÁÏ£¨½ðÊô»¯ºÏÎÅçÍ¿ÔÚ²£Á§±íÃæÐγÉÃæ×´µç×裬ÔÚÁ½¶ËÖÆ×÷Òøµç¼«£¬Í¨µçºó²úÉúÈÈÁ¿°ÑºøÄÚµÄË®¼ÓÈÈ£®Ð¡Ã÷¼ÒÂòÁËÒ»°ÑÑøÉúºø£¨Í¼¼×£©£¬ÆäÃúÅÆÈçϱíËùʾ£®
220V 10A 50Hz 3000c£¨kW•h£©

ÐͺÅ	HX-201504
¶î¶¨µçѹ	220V
ƵÂÊ	50Hz
¶î¶¨¹¦ÂÊ	1210W

СÃ÷¹Ø±ÕÁ˼ÒÖеÄÆäËûËùÓÐÓõçÆ÷£¬²¢ÔÚºøÖмÓÈë³õÎÂΪ25¡æµÄË®£¬6min½«Ë®ÉÕ¿ª£¨±ê×¼´óÆøѹÏ£©£¬Çó£º
£¨1£©ÔÚ¼ÓÈȹý³ÌÖмÒÓõçÄÜ±í£¨Í¼ÒÒ£©µÄתÅÌתÁË300ת£¬´Ë¹ý³ÌÖÐÑøÉúºøÏûºÄµÄµçÄÜÊǶàÉÙ£¿
£¨2£©Èç¹ûÑøÉúºøµÄÈÈЧÂÊÊÇ87.5%£¬´Ë¹ý³ÌÖкøÖÐË®µÄÖÊÁ¿ÊǶàÉÙ£¿
£¨3£©²»¿¼ÂÇζȶԵç×èµÄÓ°Ï죬Ôڴ˹ý³ÌÖУ¬ÑøÉúºøÁ½¶ËµÄʵ¼ÊµçѹÊǶàÉÙ£¿

Answer 1

·ÖÎö £¨1£©ÀûÓõçÄܱí²ÎÊýºÍ±íÅ̵ÄתÊýÇó³öÏûºÄµÄµçÄÜ£»
£¨2£©ÀûÓÃЧÂʹ«Ê½Çó½âË®ÎüÊÕµÄÈÈÁ¿£»È»ºó¸ù¾ÝQ=cm¡÷t¿ÉÇóµÃË®µÄÖÊÁ¿£»
£¨3£©Ïȸù¾Ý¶î¶¨¹¦ÂʺͶµçѹ½áºÏR=$\frac{{U}^{2}}{P}$Çó³öÑøÉúºøµÄµç×裬ÔËÓÃʵ¼Ê¹¦Âʺ͵ç×èÇó½âʵ¼Êµçѹ£®

½â´ð ½â£º
£¨1£©ÑøÉúºøÏûºÄµÄµçÄÜΪ£ºW=$\frac{300}{3000}$kW•h=0.1kW•h=3.6¡Á10⁵J£»
£¨2£©ÓɦÇ=$\frac{{Q}_{Îü}}{W}$¿ÉµÃË®ÎüÊÕµÄÈÈÁ¿Îª£º
Q_Îü=W¦Ç=3.6¡Á10⁵J¡Á87.5%=3.15¡Á10⁵J£»
ÓÉQ_Îü=cm¡÷t¿ÉµÃ£º
m=$\frac{{Q}_{Îü}}{c¡÷t}$=$\frac{3.15¡Á1{0}^{5}J}{4.2¡Á1{0}^{3}J/£¨kg•¡æ£©¡Á£¨100¡æ-25¡æ£©}$=1kg£»
£¨3£©¸ù¾ÝP=$\frac{{U}^{2}}{R}$¿ÉµÃ£º
R=$\frac{{U}_{¶î}^{2}}{{P}_{¶î}}$=$\frac{{£¨220V£©}^{2}}{1210W}$=40¦¸£¬
ʵ¼Êµç¹¦ÂÊΪ£ºP_ʵ=$\frac{W}{t}$=$\frac{3.6¡Á1{0}^{5}J}{360s}$=1000W£¬
Ôòʵ¼ÊµçѹΪ£ºU_ʵ=$\sqrt{{P}_{ʵ}R}$=$\sqrt{1000W¡Á40¦¸}$=200V£®
´ð£º£¨1£©ÏûºÄµÄµçÄÜÊÇ3.6¡Á10⁵J£»
£¨2£©ºøÖÐË®µÄÖÊÁ¿ÊÇ1kg£»
£¨3£©ÑøÉúºøÁ½¶ËµÄʵ¼ÊµçѹÊÇ200V£®

µãÆÀ ÒÔÑøÉúºøΪÔØÌ壬¿¼²éÁ˵çÄܱí²ÎÊýµÄÀí½â¡¢µçÄÜ¡¢µç¹¦ÂÊ£¬Êµ¼ÊµçѹµÄÇó½â£¬ÕâÊÇÖп¼µÄѹÖá´óÌ⣬×öÌâʱҪϸÐÄ·ÖÎö½â´ð£®