Question

9£®²£Á§×°Ô˳µ¼ä³£Óá°µÍѹÎüÅ̵õ³µ¡±½øÐеõÔ˲£Á§£¨ÈçͼaËùʾ£©£¬ÏȽ«6¸öÎüÅÌѹÔÚ²£Á§ÉÏ£¬È»ºóÆô¶¯³éÆø»úʹÎüÅÌÄÚµÄÆøѹ¼õС£¬ÔÚ´óÆøѹ×÷ÓÃϽ«²£Á§¡°Îü¡±Æð£¬ÔÙÆô¶¯µç¶¯»úÇ£Òý»¬ÂÖ×éÉϵÄÉþ×ӾͿÉÒÔ½«²£Á§µõÆð£®ÏÂͼΪµÍѹÎüÅ̵õ³µ½á¹¹Ê¾Òâͼ£®¼ÙÉè6Ö»ÎüÅ̼°Ö§¼Ü¹²ÖØΪ500Å££¬Ã¿¸ö»¬ÂÖÖØ100Å££¬ÔÚij´Îµõ×°¹ý³ÌÖУ¬µõ³µ½«Ò»¿éÖØΪ1800Å£µÄ²£Á§ÒÔ0.2Ã×/ÃëµÄËٶȵõ¸ß2Ã×£¬²»¼Æ³éÆø¹ÜºÍÉþÖØ£¬²»¼Æ»¬ÂÖÓëÖá¼äµÄĦéߣ¬Çë¸ù¾ÝÐÅÏ¢»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÈôÔ²ÐÎÎüÅ̵ÄÖ±¾¶Îª20ÀåÃ×£¬µ±Ê±µÄÆøѹΪ1.0¡Á10⁵Pa£¬ÔòÎüÅÌÄÚµÄÆøѹÖÁÉÙÒª´ïµ½¶àÉÙÒÔϲÅÄܰѲ£Á§¡°Îü¡±Æ𣿣¨6Ö»ÎüÅÌÄÚµÄÆøѹÏàͬ£¬È¡¦Ð=3½øÐмÆË㣩
£¨2£©ÔÚÌáÉý¸Ã²£Á§µÄ¹ý³ÌÖУ¬¸ÃµõÉý»úеЧÂÊΪ¶à´ó£¿
£¨3£©Èç¹û´Ëʱµç¶¯»úµÄЧÂÊΪ80%£¬Ôòµç¶¯»úÏûºÄµÄµç¹¦ÂÊΪ¶à´ó£¿

Answer 1

·ÖÎö £¨1£©¸ù¾Ý¼ÆËã³öÒ»¸öÎüÅ̵ÄÃæ»ý£¬Çó³ö6¸öÎüÅ̵ÄÃæ»ý£®ÓÉ¡÷p=$\frac{F}{S}$¿ÉµÃÎüÅÌÊܵ½µÄѹǿ£®ÔòÎüÅÌÄÚµÄÆøѹÖÁÉÙÒª´ïµ½p_ÄÚ=p₀-¡÷p£®
£¨2£©ÀûÓù«Ê½¦Ç=$\frac{{G}_{Îï}}{{G}_{×Ü}}$¡Á100%Çó³öµõÉý»úеЧÂÊ£»
£¨3£©ÀûÓù«Ê½F=$\frac{{G}_{×Ü}}{n}$Çó³öµç¶¯»úµÄÀ­Á¦£¬È»ºóÓÉP¦Ç=FvµÃ£¬P=$\frac{Fv}{¦Ç}$Çó³öµç¶¯»úÏûºÄµÄµç¹¦ÂÊ£®

½â´ð ½â£º£¨1£©6¸öÎüÅ̵ÄÃæ»ý£ºS=6S₀=¦Ðr²=6¡Á3¡Á0.1²=0.18m²£»
ÎüÅÌÊܵ½µÄѹǿ£º¡÷p=$\frac{F}{S}$=$\frac{1800N}{0.18{m}^{2}}$=1¡Á10⁴Pa£¬
ÔòÎüÅÌÄÚµÄÆøѹÖÁÉÙÒª´ïµ½µÄÆøѹ£ºp_ÄÚ=p₀-¡÷p=1.0¡Á10⁵Pa-1¡Á10⁴Pa=9¡Á10⁴Pa£»
£¨2£©µõÉý»úеЧÂÊ£º¦Ç=$\frac{{G}_{Îï}}{{G}_{×Ü}}$¡Á100%=$\frac{1800N}{1800N+500N+100N}$¡Á100%=75%£»
£¨3£©µç¶¯»úµÄÀ­Á¦£ºF=$\frac{{G}_{×Ü}}{n}$=$\frac{1800N+500N+100N}{2}$=1200N£¬
ÓÉP¦Ç=FvµÃ£¬µç¶¯»úÏûºÄµÄµç¹¦ÂÊ£ºP=$\frac{Fv}{¦Ç}$=$\frac{1200N¡Á0.2m/s¡Á2}{80%}$=600W£®
´ð£º£¨1£©ÎüÅÌÄÚµÄÆøѹÖÁÉÙÒª´ïµ½9¡Á10⁴Pa²ÅÄܰѲ£Á§¡°Îü¡±Æð£»
£¨2£©ÔÚÌáÉý¸Ã²£Á§µÄ¹ý³ÌÖУ¬¸ÃµõÉý»úеЧÂÊΪ75%£»
£¨3£©Èç¹û´Ëʱµç¶¯»úµÄЧÂÊΪ80%£¬Ôòµç¶¯»úÏûºÄµÄµç¹¦ÂÊΪ600W£®

µãÆÀ ±¾Ì⿼²éÖØÁ¦µÄѹǿ£¬¹¦¡¢¹¦Âʺͻ¬ÂÖ×é»úеЧÂʵļÆË㣬×ÛºÏÐÔÇ¿£¬ÓÐÀûÓÚѧÉúÄÜÁ¦µÄÌá¸ß£®