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【题目】根据元素周期表1~20号元素的性质和递变规律,回答下列问题:

1属于金属元素的有 种,其中金属性最强的元素的单质与氧气反应生成的化合物的化学式为 填两种

2最高正化合价最高的元素是 填元素符号,其最高正化合价为

3单质既能与HCl反应,又能与NaOH反应的是 ,其最高价氧化物对应的水化物具有 填“酸性”“碱性”或“两性”

4第三周期中,原子半径最大的元素是稀有气体元素除外

5比较Si、N最简单氢化物的稳定性: 用化学式表示

【答案】17;K2O、K2O2KO2也可以

2Cl;+7价

3Al;两性

4Na

5NH3>SiH4

【解析】前20号元素中,1属于金属元素的共有7种,其中金属性最强的元素是钾,钾单质与氧气反应生成的化合物有K2O、K2O2、KO2;2最高正化合价最高的元素是Cl,其最高正化合价为+7价;3既能与HCl反应又能与NaOH反应的单质是铝,其最高价氧化物对应的水化物是AlOH3,具有两性;4同一周期从左往右,原子半径逐渐减小,故第三周期中,原子半径最大的是Na;5非金属性:N>P>Si,故NH3的稳定性大于SiH4的稳定性。

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