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【题目】已知fx2x5+ax3+bx-3,若f4=10,则f4

A.16 B.10 C.10 D.-16

【答案】D

【解析】由fx2x5+ax3+bx-3

得fx32x5+ax3+bx,令gx=fx3

则gx是奇函数.∴g4=-g4

即f43=-f43.又f4=10,

f4=-f4-6=-10-6=-16.

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