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【题目】在不同高度同时释放两个铅球不计空气阻力,则在均未落地前,两者

在任一时刻具有相同的加速度、位移和速度

落地的时间间隔取决于两铅球释放时的高度

在第1 s内、第2 s内、第3 s内位移之比都为149

两铅球的距离和速度差都越来越大

A只有①②正确 B只有①②③正确

C只有①③④正确 D①②③④都正确

【答案】A

【解析】两个铅球都做自由落体运动,所以加速度都等于重力加速度,即加速度相等;由于同时释放,所以运动时间相同;根据公式h=gt2可得发生的位移相等,任意时刻的速度v=gt相等,正确;两铅球落地的时间间隔为Δt=,即取决于两铅球下落的高度,正确;在第1 s内、第2 s内、第3 s内位移之比都为135,错误;因为是同时释放的,所以两铅球下落过程中相同时间内的位移和速度都相等,故距离差是一个定值,即释放前的高度差,错误。显然只有选项A正确。

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