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【题目】果蝇红眼对白眼为显性,控制该性状的基因位于X染色体上。果蝇缺失1条号染色体仍能正常生存和繁殖,缺失2条则胚胎致死。一对都缺失1条号染色体的红眼果蝇杂交亲本雌果蝇为杂合子,则F1

A缺失1条号染色体的红眼果蝇占3/8

B染色体数正常的白眼果蝇占1/4

C缺失1条号染色体的白眼果蝇占1/4

D染色体数正常的红眼果蝇占1/4

【答案】D

【解析】亲本缺失染色体组成及基因型表示为OXBXbOXBY,由于缺失2条染色体致死,则F1中缺失1条号染色体的概率为2/3,红眼果蝇概率为3/4,则A选项为1/2;B选项为1/3×1/4=1/12;C选项2/3×1/4=1/6;D选项1/3×3/4=1/4。

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