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【题目】有两只电压表V1和V2,量程已知,电阻未知。另有一干电池,它的内阻不能忽略,但不知等于多少,其电动势数值不超出电压表的量程,干电池不许拆开。现给你上述两只电压表、一个开关S和若干导线,请设计一个测量上述干电池电动势E的实验方案。

1画出测量电路图。

2实验中应测定的物理量是:________。

3以测得的物理量为已知量,导出计算干电池电动势的公式E=________。

【答案】1如图

2S闭合时电压表V1的示数U1

S断开时电压表V1、V2的示数U1′、U2

3

【解析】1电路图如下

2S闭合时,V1示数为U1;S断开时,V1、V2的示数分别为U1′和U2′。

3设V1表的内电阻为RV,由闭合电路欧姆定律

E=U1r,E=U1′+U2′+r

解得:E=

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