ijУ̽¾¿Ñ§Ï°Ð¡×éͬѧÓú¬ÓÐÉÙÁ¿ÔÓÖÊ(Ö÷ҪΪÉÙÁ¿Äàɳ¡¢CaCl2¡¢MgCl2¡¢Na2SO4µÈ)µÄ´ÖÑÎÖÆÈ¡¡°»¯Ñ§´¿¡±¼¶µÄNaCl£¬ÊµÑéÇ°ËûÃÇÉè¼ÆÁËÈçÏ·½°¸(¿òͼ)¡£

(1)Çëд³ö²Ù×÷µÚ¢Ü¡¢¢Ý²½Ëù¼ÓÊÔ¼ÁÃû³Æ¼°µÚ¢Þ²½²Ù×÷Ãû³Æ£º¢Ü       £¬¢Ý         £¬¢Þ      £»
(2) ³Áµí»ìºÏÎïCµÄ»¯Ñ§³É·ÖÓÐ(ÓÃÎÄ×ֺͻ¯Ñ§Ê½±íʾ)£º                              £»
(3)д³öµÚ¢Ý²½²Ù×÷ÖпÉÄÜ·¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ£º
                                                                            £»
(4)ÈçºÎÓÃ×î¼òµ¥·½·¨¼ìÑéµÚ¢Ý²½ÊµÑéÊÇ·ñ´ïµ½ÁËÄ¿µÄ£º                               
                                                                              £»
(5)ÄãÈÏΪ¸ÃÉè¼ÆÀïÄÄЩ²½Öèµ÷»»ºó²»Ó°ÏìʵÑé½á¹û£º                                 £»
(6)ÓÐͬѧÈÏΪÉÏÊöʵÑéÉè¼Æ²½Öè¿ÉÒÔ¼ò»¯£¬ÇëÄãÌá³ö¼ò»¯µÄÒ»ÖÖÉèÏ룺                
                                                                ¡£

¢Å¢Ü̼ËáÄÆÈÜÒº  ¢ÝÑÎËá  ¢ÞÕô·¢£¨Õô·¢½á¾§Ò²¿É£©£¨¸÷1·Ö£©
¢Æ Äàɳ¡¢BaSO4¡¢BaCO3¡¢CaCO3¡¢Mg(OH)2£¨2·Ö£©
¢ÇµÚ¢Ý²½£ºH+ OH- = H2O  £¨1·Ö£©   CO32- + 2H+ = H2O + CO2¡ü£¨1·Ö£©
¢È Óò£Á§°ôպȡÈÜÒºµãÔÚpHÊÔÖ½Öв¿£¬Èô±äºì£¬ËµÃ÷ÈÜÒº³ÊËáÐÔ£¬ÎÞOH-¡¢CO32-´æÔÚ£»Èô±äÀ¶£¬ËµÃ÷ÈÜÒºÈԳʼîÐÔ£¬ÓÐOH-¡¢CO32-´æÔÚ£¬Ðè¼ÌÐøµÎ¼ÓÑÎËáÖÁ³ÊËáÐÔ¡££¨2·Ö£©
¢É¢ÚºÍ¢Û»ò¢ÛºÍ¢Ü£¨2·Ö£©
¢Ê ÓÃBa (OH)2´úÌæBaCl2ºÍNaOH£¬Ê¹¢Ú¢Û²½ºÏ²¢ÎªÒ»²½£¨1·Ö£©

ÊÔÌâ·ÖÎö£º£¨1£©·ÖÎöÁ÷³ÌͼÒѸø³öµÄÊÔ¼ÁµÄ×÷Óã¬BaCl2ÈÜÒº³ýÈ¥Na2SO4£¬NaOHÈÜÒº³ýÈ¥MgCl2£¬ËùÒԢܵÄ×÷ÓÃΪ³ýÈ¥CaCl2£¬ËùÑ¡ÊÔ¼ÁΪNa2CO3ÈÜÒº£¬¢ÝµÄ×÷ÓÃÊdzýÈ¥¹ýÁ¿µÄNaOH¡¢Na2CO3£¬Ó¦Ñ¡ÓÃÑÎËᣬ¢ÞµÄ×÷ÓÃÊÇ´ÓNaClÈÜÒºÖеõ½»¯Ñ§´¿NaCl£¬ÎªÕô·¢²Ù×÷¡£
£¨2£©BaCl2¡¢NaOH¡¢Na2CO3·´Ó¦ºóµÃµ½µÄ³Áµí¹²ÓУºÄàɳ¡¢BaSO4¡¢BaCO3¡¢CaCO3¡¢Mg(OH)2¡£
£¨3£©µÚ¢Ý²½¼ÓÈëHCl£¬ÓëNaOHºÍNa2CO3·´Ó¦£¬ËùÒÔÀë×Ó·½³ÌʽΪ£ºH+ OH- = H2O£»  CO32- + 2H+ = H2O + CO2¡ü¡£
£¨4£©HCl×ãÁ¿Ê±µÚ¢Ý²½´ïµ½ÁËÄ¿µÄ£¬¿ÉÓÃpHÊÔÖ½¼ìÑ飬ÈôÊÔÖ½±ä»¯£¬Ö¤Ã÷HCl¹ýÁ¿£¬OH?¡¢CO32?²»´æÔÚ£¬Èô±äÀ¶£¬ËµÃ÷»¹ÓÐOH?¡¢CO32?£¬Ðè¼ÌÐøµÎ¼ÓÑÎËáÖÁ³ÊËáÐÔ¡£
£¨5£©NaOH²»Ó°ÏìÆäËûÎïÖʵijýÈ¥£¬ËùÒÔNaOHµÄ¼ÓÈë˳Ðò¿ÉÒÔÌáÇ°£¬Ò²¿ÉÒÔÏòºóµ÷Õû£¬¼´¢ÚºÍ¢Û»ò¢ÛºÍ¢Ü¿Éµ÷»»¡£
£¨6£©ÓÃBa (OH)2´úÌæBaCl2ºÍNaOH£¬¿Éͬʱ³ýÈ¥Na2SO4ºÍMgCl2£¬Ê¹¢Ú¢Û²½ºÏ²¢ÎªÒ»²½¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÊµÑéÌâ

ÂÈ»¯¼ØÑùÆ·Öк¬ÓÐÉÙÁ¿Ì¼Ëá¼Ø¡¢ÁòËá¼ØºÍ²»ÈÜÓÚË®µÄÔÓÖÊ¡£ÎªÁËÌá´¿ÂÈ»¯¼Ø£¬ÏȽ«ÑùÆ·ÈÜÓÚÊÊÁ¿Ë®ÖУ¬³ä·Ö½Á°èºó¹ýÂË£¬ÔÙ½«ÂËÒº°´ÏÂͼËùʾ²½Öè½øÐвÙ×÷¡£

(1)Ϊ¼ìÑéÆðʼÂËÒºÖеÄCl£­£¬ËùÓÃÊÔ¼Á³ýÏ¡HNO3£¬»¹Ó¦ÓР                  
(Ìѧʽ)
(2)ÊÔ¼Á¢ñ¡¢¢ò¡¢¢óµÄ»¯Ñ§Ê½·Ö±ðΪ          ¡¢         ¡¢              
(3)²½Öè¢ÙºÍ¢ÚÖУ¬ËùÓõIJ£Á§ÒÇÆ÷³ý½ºÍ·µÎ¹Ü£¬»¹Ó¦ÓР                   
(4)²½Öè¢ÙÖУ¬ÅжÏÊÔ¼Á¢ñÒѼÓÈë¹ýÁ¿µÄ·½·¨ÊÇ£º                                         
(5)ijͬѧ¸ù¾Ý×îÖÕËùµÃKCl¾§ÌåºÍÔ­ÑùÆ·µÄÖÊÁ¿ÇóËã³öÂÈ»¯¼ØÑùÆ·µÄ´¿¶È£¬ÄãÈÏΪÆä½á¹ûÊÇ·ñ¿É¿¿£¿²¢ËµÃ÷Àí (²»¿¼ÂÇʵÑéÎó²î)£º                                                           

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÊµÑéÌâ

Ϊ̽¾¿Cl2¡¢Æ¯°×·ÛµÄÖƱ¸¼°ÓйØÐÔÖÊ£¬Ä³ÐËȤС×éÉè¼Æ²¢½øÐÐÁËÒÔÏÂʵÑé̽¾¿¡£Çë»Ø´ðÒÔÏÂÎÊÌ⣺
£¨1£©ÊµÑéÊÒÄâÓÃÏÂÁÐ×°ÖÃÖƱ¸¸ÉÔï´¿¾»µÄÂÈÆø£¬Çë°´ÕÕÆøÌå´Ó×óÏòÓÒÁ÷¶¯µÄ·½Ïò½«ÒÇÆ÷½øÐÐÁ¬½Ó£ºH¡ú_______¡¢_______¡ú_______¡¢_______¡ú_______£»ÆäÖйã¿ÚÆ¿¢òÖеÄÊÔ¼ÁΪ_______¡£
    
£¨2£©Ð´³ö¹¤ÒµÉÏÓÃÂÈÆøºÍʯ»ÒÈéÖÆȡƯ°×·ÛµÄ»¯Ñ§·´Ó¦·½³Ìʽ_______£»
£¨3£©ÊµÑéÊÒÓÐһƿÃÜ·â²»ÑϵÄƯ°×·ÛÑùÆ·£¬ÆäÖп϶¨´æÔÚCaCl2¡£ÇëÉè¼ÆʵÑ飬̽¾¿¸ÃÑùÆ·ÖгýCaCl2Í⻹º¬ÓеÄÆäËû¹ÌÌåÎïÖÊ¡£
¢ÙÌá³öºÏÀí¼ÙÉè¡£
¼ÙÉè1£º¸ÃƯ°×·Ûδ±äÖÊ£¬»¹º¬ÓÐCa(ClO)2
¼ÙÉè2£º¸ÃƯ°×·ÛÈ«²¿±äÖÊ£¬»¹º¬ÓÐ______£»
¼ÙÉè3£º¸ÃƯ°×·Û²¿·Ö±äÖÊ£¬»¹º¬ÓÐCa(ClO)2ºÍCaCO3¡£
¢ÚÉè¼ÆʵÑé·½°¸£¬½øÐÐʵÑé¡£ÇëÔÚϱíÖÐд³öʵÑé²½Öè¡¢Ô¤ÆÚÏÖÏóºÍ½áÂÛ¡£
ÏÞÑ¡ÓõÄÒÇÆ÷ºÍÒ©Æ·£ºÊԹܡ¢µÎ¹Ü¡¢´øµ¼¹ÜµÄµ¥¿×Èû¡¢ÕôÁóË®¡¢×ÔÀ´Ë®¡¢Æ·ºìÈÜÒº¡¢1 mol¡¤L-1 HClÈÜÒº¡¢ÐÂÖƳÎÇåʯ»ÒË®¡££¨Ìáʾ£º²»±Ø¼ìÑéCa2+ºÍCl-¡££©
 
ʵÑé²½Öè
Ô¤ÆÚÏÖÏóÓë½áÂÛ
²½Öè1
È¡ÉÙÁ¿ÉÏÊöƯ°×·ÛÓÚÊÔ¹ÜÖУ¬ÏȼÓÈë     Èܽâºó£¬ÔÙ°ÑÉú³ÉµÄÆøÌåͨÈë     ¡£
Èô       £¬Ôò¼ÙÉè1³ÉÁ¢£»
Èô       £¬Ôò¼ÙÉè2»ò¼ÙÉè3³ÉÁ¢¡£
²½Öè2
ÒÑÈ·¶¨Æ¯°×·Û±äÖÊ£¬ÔòÁíÈ¡ÉÙÁ¿ÉÏÊöƯ°×·ÛÓÚÊÔ¹ÜÖУ¬ÏȼÓÈëÊÊÁ¿1 mol¡¤L-1 HClÈÜÒº£¬ÔÙ¼ÓÈë    ¡£
Èô       £¬Ôò¼ÙÉè2³ÉÁ¢£»
Èô       £¬Ôò¼ÙÉè3³ÉÁ¢¡£
 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

¿ÉÒÔÒ»´Î¼ø±ð³öÒÒËá¡¢ÒÒ´¼¡¢ÒÒËáÒÒõ¥¡¢ÆÏÌÑÌÇËÄÖÖÎïÖʵÄÊÔ¼ÁÊÇ
A£®äåË®B£®Na2CO3ÈÜÒºC£®Ê¯ÈïÊÔÒºD£®¼îÐÔCu(OH) 2Ðü×ÇÒº

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÖÓÐMgCl2¡¢AlCl3¡¢CuCl2¡¢FeCl3¡¢NH4ClÎåÖÖÈÜÒº£¬Èç¹ûÖ»ÓÃÒ»ÖÖÊÔ¼Á°ÑËüÃǼø±ð¿ªÀ´£¬Ó¦Ñ¡ÓõÄÊÔ¼ÁÊÇ£¨ £©
A£®Å¨NaOHÈÜÒºB£®AgNO3ÈÜÒºC£®°±Ë®D£®NaClÈÜÒº

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁÐʵÑé·½°¸Éè¼ÆÕýÈ·µÄÊÇ
A£®·Ö½â¸ßÃÌËá¼ØÖÆÑõÆøºó£¬²ÐÁôÔÚÊÔ¹ÜÄÚ±ÚÉϵĺÚÉ«ÎïÖÊ¿ÉÓÃÏ¡ÑÎËáÏ´µÓ
B£®Ê§È¥±êÇ©µÄÏõËáÒøÈÜÒº¡¢Ï¡ÑÎËá¡¢ÇâÑõ»¯ÄÆÈÜÒº¡¢ÂÈ»¯ÂÁÈÜÒº£¬¿ÉÒÔÓÃ̼Ëáï§ÈÜÒº¼ø±ð
C£®½«CuCl2ÈÜÒºÔÚÕô·¢ÃóÖмÓÈÈÕô¸É£¬µÃµ½ÎÞË®CuCl2¹ÌÌå
D£®¼ìÑé´Ó»ðÐÇÉÏ´ø»ØÀ´µÄºìÉ«ÎïÌåÊÇ·ñÊÇFe2O3 µÄ²Ù×÷²½ÖèΪ£ºÑùÆ·¡ú·ÛËé¡ú¼ÓË®Èܽâ¡ú¹ýÂË¡úÏòÂËÒºÖеμÓKSCNÈÜÒº

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÊµÑéÌâ

I£®ÏÂͼ±íʾ´Ó¹ÌÌå»ìºÏÎïÖзÖÀëQµÄ2ÖÖ·½°¸£¬Çë»Ø´ðÓйØÎÊÌâ¡£

£¨1£©Ñ¡Ó÷½°¸(i)ʱ£¬QÓ¦¸Ã¾ßÓеÄÐÔÖÊÊÇ_____________£¬²ÐÁôÎïÓ¦¸Ã¾ß
ÓеÄÐÔÖÊÊÇ__________________________________¡£
£¨2£©Ñ¡Ó÷½°¸(ii)´Óij½ðÊô·ÛÄ©£¨º¬ÓÐAu¡¢AgºÍCu£©ÖзÖÀëAu£¬¼ÓÈëµÄÊÔ¼ÁΪ____________¡£
£¨3£©ÎªÌᴿijFe2O3ÑùÆ·£¨Ö÷ÒªÔÓÖÊÓÐSiO2.Al2O3£©£¬²ÎÕÕ·½°¸(i)ºÍ(ii)£¬ÇëÉè¼ÆÒ»ÖÖÒÔ¿òͼÐÎʽ±íʾµÄʵÑé·½°¸£¨×¢Ã÷ÎïÖʺͲÙ×÷£©£º
______________________________________________________________________________¡£
¢ò£®Ä³ÖÖº¬ÓÐÉÙÁ¿Ñõ»¯ÄƵĹýÑõ»¯ÄÆÑùÆ·£¨¼ºÖªÑùÆ·ÖÊÁ¿Îª1.560g¡¢×¶ÐÎÆ¿ºÍË®µÄÖÊÁ¿Îª
190.720g)£¬ÀûÓÃÓÒÏÂͼËùʾװÖòⶨ»ìºÏÎïÖÐNa2O2µÄÖÊÁ¿·ÖÊý£¬Ã¿¸ôÏàͬʱ¼ä¶ÁµÃµç
×ÓÌìƽµÄÊý¾ÝÈçÏÂ±í£º

£¨4£©Ð´³öNa2O2ÓëH2O·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º________________________________________£®
£¨5£©¼ÆËãNa2O2ÖÊÁ¿·ÖÊýʱ£¬±ØÐèµÄÊý¾ÝÊÇ_________________________________________.
²»±Ø×÷µÚ6´Î¶ÁÊýµÄÔ­ÒòÊÇ_____________________________________________________£®
£¨6£©²â¶¨ÉÏÊöÑùÆ·(1.560g)ÖÐNa2O2ÖÊÁ¿·ÖÊýµÄÁíÒ»ÖÖ·½°¸£¬Æä²Ù×÷Á÷³ÌÈçÏ£º

²Ù×÷¢ÚµÄÃû³ÆÊÇ____________£¬¸Ã·½°¸ÐèÖ±½Ó²â¶¨µÄÎïÀíÁ¿ÊÇ_____________ £¬²â¶¨¹ý³ÌÖÐ
ÐèÒªµÄÒÇÆ÷Óеç×ÓÌìƽ¡¢Õô·¢Ã󡢾ƾ«µÆ£¬»¹ÐèÒª___________¡¢__________£¨¹Ì¶¨¡¢¼Ð
³ÖÒÇÆ÷³ýÍ⣩,ÔÚתÒÆÈÜҺʱ£¬ÈçÈÜҺתÒƲ»ÍêÈ«£¬ÔòNa2O2ÖÊÁ¿·ÖÊýµÄ²â¶¨½á¹û_______£¨Ìî
¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±»ò¡°²»±ä¡±£©¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

º£Ë®ÊǾ޴óµÄ×ÊÔ´±¦¿â¡£ÏÂͼÊÇÈËÀà´Óº£Ë®×ÊÔ´»ñȡijЩÖØÒª»¯¹¤Ô­ÁϵÄÁ÷³ÌʾÒâͼ¡£

»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©²Ù×÷AÊÇ_________________(ÌîʵÑé»ù±¾²Ù×÷Ãû³Æ)¡£ÓúÎÖÖ·½·¨ÖªµÀº£Ë®É¹ÑεĹý³ÌÖÐÈÜÒºÀïʳÑκ¬Á¿ÔÚÖð½¥Ìá¸ß£¿________
a£®·ÖÎöÂÈ»¯Äƺ¬Á¿      b£®²â¶¨ÈÜÒºÃܶȠ       c£®¹Û²ìÊÇ·ñÓгÁµíÎö³ö
£¨2£©²Ù×÷BÐè¼ÓÈëÏÂÁÐÊÔ¼ÁÖеÄÒ»ÖÖ£¬×îºÏÊʵÄÊÇ______£¨Ñ¡Ìî±àºÅ£©¡£
a£®ÇâÑõ»¯ÄÆÈÜÒº      b£®³ÎÇåʯ»ÒË®      c£®Ê¯»ÒÈé      d£®Ì¼ËáÄÆÈÜÒº
£¨3£©Ïò¿à±ÖÐͨÈëCl2£¬·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ____________________________£¬²Ù×÷CÊÇ_______________________________¡£
£¨4£©ÉÏͼÖÐÐéÏß¿òÄÚÁ÷³ÌµÄÖ÷Òª×÷ÓÃÊÇ_______________________£»Óë֮ĿµÄÏàͬµÄÁ÷³ÌÔÚÉÏͼÖл¹Óм¸´¦£¬ÊÔÖ¸³öÆäÖÐÒ»´¦________________________¡£
£¨5£©½«MgCl2ת»¯ÎªMgʱ»ñµÃµÄ¸±²úÆ·ÊÇ_____________£¬Óû¯Ñ§·½³Ìʽ±íʾ¸ÃÎïÖʵÄijÖÖÓÃ;______________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁÐÒÇÆ÷³£ÓÃÓÚÎïÖÊ·ÖÀëµÄÊÇ
A£®¢Ù¢Û¢ÝB£®¢Ú¢Û¢ÝC£®¢Ú¢Ü¢ÝD£®¢Ù¢Ü¢Þ

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸