¸ù¾ÝµâÓëÇâÆø·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£º

(¢¡)I2(g)+H2(g)2HI(g)       ¦¤H=-9.48 kJ¡¤mol-1

(¢¢)I2(s)+H2(g)2HI(g)      ¦¤H=+26.48 kJ¡¤mol-1

ÏÂÁÐÅжÏÕýÈ·µÄÊÇ£¨   £©

A.254 g I2(g)ÖÐͨÈë2 g H2(g)£¬·´Ó¦·ÅÈÈ9.48 kJ

B.1 mol¹Ì̬µâÓë1 molÆø̬µâËùº¬µÄÄÜÁ¿Ïà²î17.00 kJ

C.·´Ó¦(¢¡)µÄ²úÎï±È·´Ó¦(¢¢)µÄ²úÎïÎȶ¨

D.·´Ó¦(¢¢)µÄ·´Ó¦Îï×ÜÄÜÁ¿±È·´Ó¦(¢¡)µÄ·´Ó¦Îï×ÜÄÜÁ¿µÍ


Ñ¡D¡£·´Ó¦ÊÇ¿ÉÄæ·´Ó¦£¬·´Ó¦Îï²»ÄÜÍêȫת»¯£»ÀûÓøÇ˹¶¨Âɿɵóö1 mol¹Ì̬µâÓë1 molÆø̬µâËùº¬µÄÄÜÁ¿Ïà²î35.96 kJ£»Í¬Ò»ÖÖÎïÖʵÄÄÜÁ¿ÔÚÏàͬÌõ¼þÏ£¬ÄÜÁ¿Ò»Ñù¶à¡£Í¬ÑùÀûÓøÇ˹¶¨ÂɿɵóöÑ¡ÏîDÕýÈ·¡£


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÎïÖÊA¡¢B¡¢C¡¢D¡¢E¡¢F¡¢G¡¢H¡¢I¡¢J¡¢K´æÔÚÏÂͼת»¯¹Øϵ£¬ÆäÖÐÆøÌåD¡¢EΪµ¥ÖÊ£¬ÊԻشð£º

(1)д³öÏÂÁÐÎïÖʵĻ¯Ñ§Ê½£ºA________£¬B________£¬D________£¬K________¡£

(2)д³ö·´Ó¦¡°C¡úF¡±µÄÀë×Ó·½³Ìʽ£º____________________________________________________________________________¡£

(3)д³ö·´Ó¦¡°F¡úG¡±µÄ»¯Ñ§·½³Ìʽ£º__________________________________________________________________________________¡£

(4)д³ö·´Ó¦¡°J¡úK¡±µÄÀë×Ó·½³Ìʽ£º__________________________________________________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÂÁÐʵÑéÏÖÏó»òÃèÊöÕýÈ·µÄÊÇ£¨  £©

A. ÏòÐÂÖÆÂÈË®ÖеμÓÉÙÁ¿×ÏɫʯÈïÊÔÒº£¬³ä·ÖÕñµ´ºóÈÜÒº³ÊºìÉ«

B. Í­ÔÚÂÈÆøÖÐȼÉÕÉú³ÉÀ¶É«ÑÌ

C. ¶þÑõ»¯¹è²»ÓëÈκÎËá·´Ó¦£¬¿ÉÓÃʯӢÖÆÔìÄÍËáÈÝÆ÷

D. Ã÷·¯[KAl(SO4)2¡¤12H2O]ÔÚË®ÖÐÄÜÐγÉAl(OH)3½ºÌ壬¿ÉÓÃ×÷¾»Ë®¼Á

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


 ÓÃÏÂÁÐÓйØʵÑé×°ÖýøÐÐÏàӦʵÑ飬´íÎóµÄÊÇ£¨    £©

A£®ÓÃͼ1ËùʾװÖÃʵÑéÊÒÖÆÈ¡ÉÙÁ¿Cl2

B£®ÓÃͼ2ËùʾװÖÃÖÆÈ¡¼°¹Û²ìFe(OH)2

C£®ÓÃͼ3ËùʾװÖÃÓÃH2O2ÈÜÒºÖƱ¸O2 

D£®ÓÃͼ4ËùʾװÖñȽÏS¡¢C¡¢SiµÄ·Ç½ðÊôÐÔÇ¿Èõ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


NÔªËØÓжàÖÖ»¯ºÏÎËüÃÇÖ®¼ä¿ÉÒÔ·¢Éúת»¯£¬È磺N2H4£«HNO2£½2H2O+HN3¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©NÓëOµç¸ºÐԽϴóµÄÊÇ        ¡£

£¨2£©NaN3µÄ¾§ÌåÀàÐÍÊÇ            ¡£

£¨3£©´¿µþµªËáHN3ÔÚ³£ÎÂÏÂÊÇÒ»ÖÖÒºÌ壬·Ðµã½Ï¸ß£¬Îª308.8K£¬Ö÷ÒªÔ­ÒòÊÇ                   ¡£

£¨4£©N2H4ÖеÄNÔ­×ÓµÄÔÓ»¯ÀàÐÍÊÇ              ¡£

£¨5£©NO2£­Àë×ÓÊÇÒ»ÖֺܺõÄÅäλÌ壬ÄÜÌṩ¹Âµç×Ó¶ÔÊÇ£¨    £©

A£®ÑõÔ­×Ó       B£®µªÔ­×Ó      C£®Á½Õ߶¼¿ÉÒÔ

NO2£­ÓëîÜÑÎͨ¹ýÅäλ¼üÐγɵÄ[Co(NO2)6]3£­ÄÜÓëK£«Àë×Ó½áºÏÉú³É»ÆÉ«K3[Co(NO2)6]³Áµí£¬´Ë·½·¨¿ÉÓÃÓÚ¼ìÑéÈÜÒºÖеÄK£«Àë×Ó£¬Ð´³ö¸ÃÅäºÏÎïÖÐîÜÀë×ӵĵç×ÓÅŲ¼Ê½:                        ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


Ñо¿NOx¡¢SO2¡¢COµÈ´óÆøÎÛȾÆøÌåµÄ´¦Àí·½·¨¾ßÓÐÖØÒªÒâÒå¡£

£¨1£©´¦Àíº¬CO¡¢SO2Ñ̵ÀÆøÎÛȾµÄÒ»ÖÖ·½·¨Êǽ«ÆäÔÚ´ß»¯¼Á×÷ÓÃÏÂת»¯Îªµ¥ÖÊS¡£ÒÑÖª£º

¢ÙCO(g)+O2(g)====CO2(g)      ¦¤H=-283.0 kJ¡¤mol-1

¢ÚS(s)+ O2(g)==== SO2(g)     ¦¤H=-296.0 kJ¡¤mol-1

´Ë·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÊÇ_________________________¡£

£¨2£©µªÑõ»¯ÎïÊÇÔì³É¹â»¯Ñ§ÑÌÎíºÍ³ôÑõ²ãËðºÄµÄÖ÷ÒªÆøÌå¡£

ÒÑÖª£º¢ÙCO(g)+NO2(g)====NO(g)+CO2(g)   ¦¤H=-akJ¡¤mol-1(a>0)

¢Ú2CO(g)+2NO(g)====N2(g)+2CO2(g)     ¦¤H=-bkJ¡¤mol-1(b>0)

ÈôÓñê×¼×´¿öÏÂ3.36 L CO»¹Ô­NO2ÖÁN2(COÍêÈ«·´Ó¦)µÄÕû¸ö¹ý³ÌÖÐתÒƵç×ÓµÄÎïÖʵÄÁ¿Îª________mol£¬·Å³öµÄÈÈÁ¿Îª________kJ(Óú¬ÓÐaºÍbµÄ´úÊýʽ±íʾ)¡£

£¨3£©ÓÃCH4´ß»¯»¹Ô­NOxÒ²¿ÉÒÔÏû³ýµªÑõ»¯ÎïµÄÎÛȾ¡£ÀýÈ磺

¢ÙCH4(g)+4NO2(g)====4NO(g)+CO2(g)+2H2O(g)   ¦¤H1=-574 kJ¡¤mol-1¢Ù

¢ÚCH4(g)+4NO(g)====2N2(g)+CO2(g)+2H2O(g)¡¡¦¤H2=£¿¢Ú

Èô1 mol CH4»¹Ô­NO2ÖÁN2Õû¸ö¹ý³ÌÖзųöµÄÈÈÁ¿Îª867 kJ£¬Ôò¦¤H2=________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÂÁÐÓйØÎïÖÊÐÔÖʵÄ˵·¨´íÎóµÄÊÇ(¡¡¡¡)

A£®ÈÈÎȶ¨ÐÔ£ºHCl>HI  B£®Ô­×Ӱ뾶£ºNa>Mg

C£®ËáÐÔ£º  H2SO3>H2SO4  D£®½áºÏÖÊ×ÓÄÜÁ¦£ºS2£­>Cl£­

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÎåÖÖ¶ÌÖÜÆÚÔªËØA¡¢B¡¢C¡¢D¡¢EµÄÔ­×ÓÐòÊýÒÀ´ÎÔö´ó£¬AºÍCͬ×壬BºÍD ͬ×壬CÀë×ÓºÍBÀë×Ó¾ßÓÐÏàͬµÄµç×Ó²ã½á¹¹¡£AºÍB¡¢D¡¢E¾ùÄÜÐγɹ²¼ÛÐÍ»¯ºÏÎï¡£AºÍBÐγɵĻ¯ºÏÎïÔÚË®ÖгʼîÐÔ£¬CºÍEÐγɵĻ¯ºÏÎïÔÚË®ÖгÊÖÐÐÔ¡£»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÎåÖÖÔªËØÖУ¬Ô­×Ӱ뾶×î´óµÄÊÇ          £¬·Ç½ðÊôÐÔ×îÇ¿µÄÊÇ         £¨ÌîÔªËØ·ûºÅ£©£»

£¨2£©ÓÉAºÍB¡¢D¡¢EËùÐγɵĹ²¼ÛÐÍ»¯ºÏÎïÖУ¬ÈÈÎȶ¨ÐÔ×î²îµÄÊÇ           £¨Óû¯Ñ§Ê½±íʾ£©£»

£¨3£©AºÍEÐγɵĻ¯ºÏÎïÓëAºÍBÐγɵĻ¯ºÏÎï·´Ó¦£¬²úÎïµÄ»¯Ñ§Ê½Îª                       £¬ÆäÖдæÔڵĻ¯Ñ§¼üÀàÐÍΪ                          £»

£¨4£©D×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïµÄ»¯Ñ§Ê½Îª                £»

£¨5£©µ¥ÖÊDÔÚ³ä×ãµÄµ¥ÖÊEÖÐȼÉÕ£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                                    £»DÔÚ²»³ä×ãµÄEÖÐȼÉÕ£¬Éú³ÉµÄÖ÷Òª²úÎïµÄ»¯Ñ§Ê½Îª             £»

£¨6£©µ¥ÖÊEÓëË®·´Ó¦µÄÀë×Ó·½³ÌʽΪ                                        ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÔÚÒ»¶¨Ìõ¼þÏÂAÓëB·´Ó¦¿ÉÉú³ÉCºÍD£¬ÆäÄÜÁ¿±ä»¯Èçͼ£º

ÏÂÁÐÓйط´Ó¦A£«B===C£«DµÄ˵·¨ÕýÈ·µÄÊÇ           (¡¡¡¡)¡£

A£®·´Ó¦Ç°ºóÔ­×ÓµÄÖÖÀàºÍÊýÄ¿Ò»¶¨²»±ä

B£®·´Ó¦Ç°ºó·Ö×ÓµÄÖÖÀàºÍÊýÄ¿Ò»¶¨¸Ä±ä

C£®·´Ó¦ÎïµÄ×ÜÄÜÁ¿E1ÓëÉú³ÉÎïµÄ×ÜÄÜÁ¿E2Ò»¶¨ÏàµÈ

D£®´Ë·´Ó¦Ò»¶¨ÓÐÈÈÁ¿µÄ±ä»¯

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸