º£Ë®ÊǷḻµÄ×ÊÔ´±¦¿â£¬´Óº£Ë®ÖÐÌáÈ¡ÔªËØÊÇ»¯Ñ§¹¤ÒµµÄÖØÒª×é³É²¿·Ö¡£
£¨1£©´ÖÑξ«ÖƾÍÊdzýÈ¥ÆäÖеÄCa2+¡¢Fe3+¡¢SO42-¼°ÄàɳµÈÔÓÖÊ£¬Ðè¼ÓÈëµÄÊÔ¼ÁÓУº¢ÙNa2CO3ÈÜÒº ¢ÚHCl£¨ÑÎËᣩ ¢ÛBa£¨OH£©2ÈÜÒº£¬ÕâÈýÖÖÊÔ¼ÁµÄÌí¼Ó˳ÐòÊÇ_________£¨ÌîÐòºÅ£©¡£
£¨2£©ÓÃÂÈÆø½øÐС°º£Ë®Ìáä塱ÖÐÖÆÈ¡äåµ¥ÖÊ·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º__________¡£
£¨3£©Ä³Í¬Ñ§Éè¼ÆÁËÈçͼװÖýøÐÐÒÔϵ绯ѧʵÑé¡£

¢Ùµ±¿ª¹ØKÓëaÁ¬½Óʱ£¬Á½¼«¾ùÓÐÆøÅݲúÉú£¬ÔòÒõ¼«Îª_______¼«¡£
¢ÚÒ»¶Îʱ¼äºó£¬Ê¹¿ª¹ØKÓëa¶Ï¿ª¡¢ÓëbÁ¬½Óʱ£¬ÐéÏß¿òÄÚµÄ×°ÖÿɳÆΪ__________¡£Çëд³ö´ËʱFeµç¼«Éϵĵ缫·´Ó¦Ê½_________________¡£
£¨4£©Ä³¹«³§ÏòÊ¢ÓÐCaSO4Ðü×ÇÒºµÄ·´Ó¦³ØÖÐͨÈë°±ÆøÓûÖÆÈ¡µª·Ê£¨NH4£©2SO4£¬Ð§¹û²»ºÃ¡£ÔÙͨÈëCO2£¬ÔòÖð½¥²úÉú´óÁ¿£¨NH4£©2SO4¡£Çë·ÖÎöÆäÔ­Òò¡£

£¨1£©¢Û¢Ù¢Ú£¨2·Ö£©  
£¨2£©Cl2£«2Br£­=2Cl£­£«Br2£¨2·Ö£©
£¨3£©¢ÙFe£¨»òÌú£©£¨2·Ö£© 
¢ÚÔ­µç³Ø£¨2·Ö£©£¬Fe£­2e£­£«2OH£­= Fe(OH)2¡ý£¨3·Ö£©
£¨4£©CO2ÈÜÓÚ°±Ë®²úÉú´óÁ¿CO32-£ºCO2+2NH3¡¤H2O =£¨NH4£©2CO3+ H2O£¨1·Ö£© £¬CO32-ÓëÁòËá¸Æ·´Ó¦²úÉúÈܶȻý³£Êý¸üСµÄ̼Ëá¸Æ³Áµí£ºCaSO4£¨s£©£«CO32-£¨aq£©= CaCO3£¨s£©£«SO42-£¨aq£©£¨2·Ö£©£¬Ê¹ÁòËá¸ÆµÄ³ÁµíÈܽâƽºâÏòÈܽâµÄ·½ÏòÒƶ¯£¨3·Ö£©£¬´Ó¶ø²úÉú´óÁ¿£¨NH4£© 2SO4¡££¨¹²3·Ö£©

½âÎöÊÔÌâ·ÖÎö£º£¨1£©Na2CO3¼È³ýÈ¥Ca2+£¬»¹³ýÈ¥¹ýÁ¿µÄBa£¨OH£©2£¬¹ýÁ¿µÄNa2CO3ÓÉÑÎËá³ýµô£¬ËùÒÔ˳ÐòΪ£º¢Û¢Ù¢Ú¡£
£¨3£©¢ÙÒòΪÁ½µç¼«¾ùÓÐÆøÅݲúÉú£¬Feµç¼«Ö»ÄÜ×÷Òõ¼«£»
¢Ú¿ª¹ØKÓëa¶Ï¿ª¡¢ÓëbÁ¬½Óʱ£¬ÐγÉÔ­µç³Ø¡£
£¨4£©·ÖÎö¡¢¶Ô±ÈKsp¿ÉÒÔ¿´³öCaCO3¸üÄÑÈÜ£¬ËùÒÔͨÈëCO2Ó백ˮÉú³É£¨NH4£©2CO3£¬CO32?ʹCaSO4ת»¯Îª£¨NH4£© 2SO4¡£
¿¼µã£º ±¾Ì⿼²ìÁ˳ýÔÓÊÔ¼ÁµÄÑ¡Ôñ¡¢Àë×Ó·½³ÌʽµÄÊéд¡¢µç»¯Ñ§ºÍ³ÁµíÈܽâƽºâ¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

£©ÈçͼװÖÃËùʾ£¬C¡¢D¡¢E¡¢F¶¼ÊǶèÐԵ缫£¬¼×¡¢ÒÒÖÐÈÜÒºµÄÌå»ýºÍŨ¶È¶¼Ïàͬ(¼ÙÉèͨµçÇ°ºóÈÜÒºÌå»ý²»±ä)£¬A¡¢BΪÍâ½ÓÖ±Á÷µçÔ´µÄÁ½¼«¡£½«Ö±Á÷µçÔ´½Óͨºó£¬F¼«¸½½ü³ÊºìÉ«¡£Çë»Ø´ð£º

£¨1£© Ò»¶Îʱ¼äºó£¬¼×ÖÐÈÜÒºÑÕÉ«              £¬
д³ö¼×ÖÐCµÄµç¼«·´Ó¦Ê½                        ¡£
£¨2£© Èô¼×¡¢ÒÒ×°ÖÃÖеÄC¡¢D¡¢E¡¢Fµç¼«¾ùÖ»ÓÐÒ»ÖÖµ¥ÖÊÉú³Éʱ£¬¶ÔÓ¦µ¥ÖʵÄÎïÖʵÄÁ¿Ö®±ÈΪ        ¡£
£¨3£© ÏÖÓñû×°ÖøøÍ­¼þ¶ÆÒø£¬µç¶ÆÒºÊÇ        ÈÜÒº¡£µ±ÒÒÖÐÈÜÒºµÄpHÊÇ13ʱ(´ËʱÒÒÈÜÒºÌå»ýΪ500 mL)£¬±ûÖжƼþÉÏÎö³öÒøµÄÖÊÁ¿Îª                ¡£
£¨4£© Èô½«Fµç¼«¸ü»»ÎªÌú£¬ÆäËû×°Öö¼²»±ä£¬ÔòÒÒÖз¢Éú×Ü·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ                   ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

ÈçÏÂͼËùʾµÄ×°ÖÃÖУ¬ÈôͨÈëÖ±Á÷µç5 minʱ£¬Í­µç¼«ÖÊÁ¿Ôö¼Ó2.16 g£¬ÊԻشð£º

£¨1£©µçÔ´µç¼«XµÄÃû³ÆΪ________¡£
£¨2£©pH±ä»¯£ºA________£¬B________£¬C________¡£(Ìî¡°Ôö´ó¡±¡°¼õС¡±»ò¡°²»±ä¡±)
£¨3£©Í¨µç5 minºó£¬BÖй²ÊÕ¼¯224 mLÆøÌå(±ê×¼×´¿ö)£¬ÈÜÒºÌå»ýΪ200 mL£¬ÔòͨµçÇ°CuSO4ÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ________(Éèµç½âÇ°ºóÈÜÒºÌå»ýÎޱ仯)¡£
£¨4£©ÈôAÖÐKClÈÜÒºµÄÌå»ýÒ²ÊÇ200 mL£¬µç½âºó£¬ÈÜÒºÖÐOH£­µÄÎïÖʵÄÁ¿Å¨¶ÈΪ________(Éèµç½âÇ°ºóÈÜÒºÌå»ýÎޱ仯)¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

ÏÂͼËùʾװÖÃÖУ¬¼×¡¢ÒÒ¡¢±ûÈý¸öÉÕ±­ÒÀ´Î·Ö±ðÊ¢·Å109g5.51£¥µÄNaOHÈÜÒº¡¢×ãÁ¿µÄCuSO4ÈÜÒººÍ200g10.00£¥µÄK2SO4ÈÜÒº£®µç¼«¾ùΪʯīµç¼«¡£

½ÓͨµçÔ´£¬¾­¹ýÒ»¶Îʱ¼äºó£¬²âµÃ±ûÖÐK2SO4Ũ¶ÈΪ10.47£¥£¬ÒÒÖÐcµç¼«ÖÊÁ¿Ôö¼Ó¡£¾Ý´Ë»Ø´ðÎÊÌ⣺
£¨1£©µç¼«bÉÏ·¢ÉúµÄµç¼«·´Ó¦Îª___________________________________¡£
£¨2£©µç¼«bÉÏÉú³ÉµÄÆøÌåÔÚ±ê×´¿öϵÄÌå»ýΪ__________________£¬´Ëʱ¼×ÉÕ±­ÖÐNaOHÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ£¨ÉèÈÜÒºµÄÃܶÈΪ1g/cm3£©_______________¡£
£¨3£©µç¼«cµÄÖÊÁ¿±ä»¯ÊÇ___________g£¬Óûʹµç½âºóÒÒÖеĵç½âÒº»Ö¸´µ½Æðʼ״̬£¬Ó¦¸ÃÏòÈÜÒºÖмÓÈëÊÊÁ¿µÄ___________£¨Ìî×Öĸ±àºÅ£©¡£

A£®Cu(OH)2B£®Cu2OC£®CuCO3D£®Cu2(OH)2CO3
£¨4£©ÆäËûÌõ¼þ²»±ä£¬Èç¹û°ÑÒÒ×°ÖøÄΪµç½â¾«Á¶Í­£¬Ôòcµç¼«µÄ²ÄÁÏΪ___________£¬dµç¼«µÄ²ÄÁÏΪ______¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

ÈçºÎ·ÀÖ¹ÌúµÄÐâÊ´Êǹ¤ÒµÉÏÑо¿µÄÖصãÄÚÈÝ¡£ÎªÑо¿ÌúµÄÐâÊ´£¬ÈçÏÂͼËùʾ£¬Ìú´¦ÓÚ¢Ù¡¢¢Ú¡¢¢ÛÈýÖÖ²»Í¬µÄ»·¾³ÖС£Çë»Ø´ð£º

£¨1£©½ðÊô¸¯Ê´Ö÷Òª·ÖΪ              ¸¯Ê´ºÍ               ¸¯Ê´Á½ÖÖ¡£
£¨2£©Ìú±»¸¯Ê´µÄËÙÂÊÓÉ¿ìµ½ÂýµÄ˳ÐòÊÇ                 £¨ÌîÐòºÅ£©¡£
£¨3£©¢ÚÖÐÕý¼«µÄµç¼«·´Ó¦Ê½Îª                           £¬
¸º¼«µÄµç¼«·´Ó¦Ê½Îª                           £¬
¢ÛÖиº¼«µÄµç¼«·´Ó¦Ê½Îª                           ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

ÐÂÐ͸ßЧµÄ¼×ÍéȼÁϵç³Ø²ÉÓò¬Îªµç¼«²ÄÁÏ£¬Á½µç¼«ÉÏ·Ö±ðͨÈëCH4ºÍO2£¬µç½âÖÊΪKOHÈÜÒº¡£Ä³Ñо¿Ð¡×齫¼×ÍéȼÁϵç³Ø×÷ΪµçÔ´½øÐÐÂÈ»¯Ã¾ÈÜÒº¹ê½âʵÑ飬µç½â×°ÖÃÈçͼËùʾ¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©¼×ÍéȼÁϵç³Ø¸º¼«µÄµç¼«·´Ó¦Ê½Îª£º                                  ¡£
£¨2£©±ÕºÏ¿ª¹ØKºó£¬a¡¢bµç¼«ÉϾùÓÐÆøÌå²úÉú£¬ÆäÖÐaµç¼«ÉϵÄÆøÌå¿ÉÓà         ¼ìÑ飬bµç¼«Éϵõ½µÄÆøÌåÊÇ         £¬µç½âÂÈ»¯Ã¾ÈÜÒºµÄÀë×Ó·½³ÌʽΪ            ¡£
£¨3£©Èô¼×ÍéͨÈëÁ¿Îª1.12 L£¨±ê×¼×´¿ö£©£¬ÇÒ·´Ó¦ÍêÈ«£¬ÔòÀíÂÛÉÏͨ¹ýµç½â³ØµÄµç×ÓµÄÎïÖʵÄÁ¿Îª           £¬²úÉúµÄÂÈÆøÌå»ýΪ           L£¨±ê×¼×´¿ö£©¡£
£¨4£©ÒÑÖª³£Î³£Ñ¹Ï£¬0.25molCH4ÍêȫȼÉÕÉú³ÉCO2ºÍH2Oʱ£¬·Å³ö222.5kJÈÈÁ¿£¬Çëд³öCH4ȼÉÕÈȵÄÈÈ»¯Ñ§·½³Ìʽ                                          ¡£
ÒÑÖª£»¢ÙC£¨Ê¯Ä«£©+O2£¨g£©=CO2£¨g£©¡÷H1=-393£®5kJ/mol
¢Ú2H2£¨g£©+O2£¨g£©=2H2O£¨l£©¡÷H2=-571£®6kJ/mol
¼ÆË㣺C£¨Ê¯Ä«£©ÓëH2£¨g£©·´Ó¦Éú³É1molCH4£¨g£©µÄ¡÷H=             ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

ÈçÏÂͼËùʾ£¬Ä³Í¬Ñ§Éè¼ÆÁËÒ»¸öȼÁϵç³Ø²¢Ì½¾¿ÂȼҵԭÀíºÍ´ÖÍ­µÄ¾«Á¶Ô­Àí£¬ÆäÖÐÒÒ×°ÖÃÖÐXΪÑôÀë×Ó½»»»Ä¤¡£Çë°´ÒªÇó»Ø´ðÏà¹ØÎÊÌâ:

£¨1£©¼×ÍéȼÁϵç³Ø¸º¼«µç¼«·´Ó¦Ê½ÊÇ:                                        
£¨2£©Ê¯Ä«µç¼«(C)µÄµç¼«·´Ó¦Ê½Îª                                       
£¨3£©ÈôÔÚ±ê×¼×´¿öÏ£¬ÓÐ2£® 24 LÑõÆø²Î¼Ó·´Ó¦£¬ÔòÒÒ×°ÖÃÖÐÌúµç¼«ÉÏÉú³ÉµÄÆøÌåÌå»ýΪ_  L;±û×°ÖÃÖÐÒõ¼«Îö³öÍ­µÄÖÊÁ¿Îª      g
£¨4£©Ä³Í¬Ñ§Àû¼×ÍéȼÁϵç³ØÉè¼Æµç½â·¨ÖÆȡƯ°×Òº»òFe(OH)2µÄʵÑé×°ÖÃ(ÈçͼËùʾ)¡£ÈôÓÃÓÚÖÆƯ°×ҺʱaΪµç³Ø_  ¼«£¬µç½âÖÊÈÜÒº×îºÃÓÃ_        ¡£ÈôÓÃÓÚÖÆ   Fe(OH)2£¬Ê¹ÓÃÁòËáÄÆ×öµç½âÖÊÈÜÒº£¬Ñô¼«Ñ¡Óà     ×÷µç¼«¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

µç½âÔ­ÀíÔÚ»¯Ñ§¹¤ÒµÖÐÓй㷺ӦÓá£ÏÂͼ±íʾһ¸öµç½â³Ø£¬×°Óеç½âÒºa£»X¡¢YÊÇÁ½¿éµç¼«°å£¬Í¨¹ýµ¼ÏßÓëÖ±Á÷µçÔ´ÏàÁ¬¡£

Çë»Ø´ðÒÔÏÂÎÊÌ⣺
£¨1£©ÈôX¡¢Y¶¼ÊǶèÐԵ缫£¬aÊDZ¥ºÍNaClÈÜÒº£¬ÊµÑ鿪ʼʱ£¬Í¬Ê±ÔÚÁ½±ß¸÷µÎÈ뼸µÎ·Ó̪ÊÔÒº£¬Ôò
¢Ùµç½â³ØÖÐX¼«Éϵĵ缫·´Ó¦Ê½Îª                                  ¡£
ÔÚX¼«¸½½ü¹Û²ìµ½µÄÏÖÏóÊÇ                                        ¡£¡¡
¢ÚYµç¼«Éϵĵ缫·´Ó¦Ê½Îª                                         £¬
¼ìÑé¸Ãµç¼«·´Ó¦²úÎïµÄ·½·¨ÊÇ                                       ¡£
£¨2£©ÈçÒªÓõç½â·½·¨¾«Á¶´ÖÍ­£¬µç½âÒºaÑ¡ÓÃCuSO4ÈÜÒº£¬Ôò
¢ÙXµç¼«µÄ²ÄÁÏÊÇ          £¬µç¼«·´Ó¦Ê½ÊÇ                         ¡£
¢ÚYµç¼«µÄ²ÄÁÏÊÇ          £¬µç¼«·´Ó¦Ê½ÊÇ                        ¡£
£¨ËµÃ÷£ºÔÓÖÊ·¢ÉúµÄµç¼«·´Ó¦²»±Øд³ö£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÊµÑéÌâ

(16·Ö)ijÑо¿Ð¡×éÄâÓôÖʳÑÎ(º¬Ca2+¡¢Mg2+¡¢SOµÈ)¡¢´Ö¹è(º¬C¼°²»ÓëCl2·´Ó¦µÄ¹ÌÌåÔÓÖÊ)ÖÆÈ¡´¿¹è£¬Éè¼ÆÈçÏµĹ¤ÒÕÁ÷³Ì£º

ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©¹¤ÒµÉÏÒ»°ãÊÇÀûÓùýÁ¿½¹Ì¿ÔÚ¸ßÎÂÏ»¹Ô­Ê¯Ó¢É°À´ÖÆÈ¡´Ö¹è£¬Ð´³ö¸Ã¹ý³ÌµÄ»¯Ñ§·½³Ìʽ£º_______________________________________________________________________¡£
£¨2£©¾«ÖÆ´ÖÑÎË®ËùÐèÊÔ¼ÁΪ¢ÙBaC12£»¢ÚNa2CO3£»¢ÛHC1£»¢ÜNaOH£¬ÆäµÎ¼ÓµÄÏȺó˳ÐòÊÇÏÂÁеÄ________(ÌîÏÂÁи÷ÏîµÄÐòºÅ)¡£
a£®¢Ù¢Ú¢Ü¢Û    b£®¢Ü¢Ú¢Ù¢Û    c£®¢Ü¢Ù¢Û¢Ú    d£®¢Ú¢Ü¢Ù¢Û
ÒÑÖª£¬£¬¼ÙÉè¸Ã´ÖÑÎË®ÖеÄŨ¶È¾ùΪ0.01 mol¡¤L-1£¬ÈôÏò1 L¸Ã´ÖÑÎË®ÖÐÖð½¥µÎÈëÒ»¶¨Á¿Na2CO3ÈÜÒº£¬Ê×ÏȳöÏֵijÁµíÊÇ__________¡£
£¨3£©ÒÑÖªSiCl4µÄ·ÐµãÊÇ57.6¡æ£¬CC14µÄ·ÐµãÊÇ76.8¡æ¡£ÔÚ·´Ó¦Æ÷IÖеõ½µÄSiCl4´ÖÆ·Öк¬ÓÐCCl4£¬´ÓÖеõ½´¿¾»SiCl4¿É²ÉÓõķ½·¨ÊÇÏÂÁи÷ÏîÖеÄ________(ÌîÐòºÅ)¡£
a£®ÕôÁó    b£®¸ÉÁó    c£®·ÖÒº    d£®¹ýÂË
·´Ó¦Æ÷¢òÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ__________________________________________¡£
£¨4£©ÏÂͼÊÇÓÃÀë×Ó½»»»Ä¤·¨µç½â±¥ºÍʳÑÎË®µÄʾÒâͼ£¬µç½â²ÛÖÐÒõ¼«²úÉúµÄÆøÌåÊÇ_____¡£²úÆ·AµÄ»¯Ñ§Ê½Îª____________¡£

Èô²ÉÓÃÎÞĤµç½â²Ûµç½â±¥ºÍʳÑÎË®¿ÉÖÆÈ¡´ÎÂÈËáÄÆ£¬ÊÔд³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ__              ___¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸