¹è¿×ȸʯÊÇÒ»ÖÖº¬Í­µÄ¿óʯ£¬º¬Í­ÐÎ̬Ϊ£¬Í¬Ê±º¬ÓеÈÔÓÖÊ¡£ÒÔ¹è¿×ȸʯΪԭÁÏÖÆÈ¡ÁòËáÍ­µÄ¹¤ÒÕÁ÷³ÌÈçÏÂͼ£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

¢ÅÍê³É²½Öè¢ÙÖÐÏ¡ÁòËáÓë·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ

£»

ÓÃÀë×Ó·½³Ìʽ±íʾ˫ÑõË®µÄ×÷ÓÃ_____________________________¡£

¢Æ²½Öè¢Úµ÷½ÚÈÜÒºpHÑ¡ÓõÄ×î¼ÑÊÔ¼ÁÊÇ__________________

A.                B.CuO                  C.A12O3                      D.

¢ÇÓйØÇâÑõ»¯Î↑ʼ³ÁµíºÍÍêÈ«³ÁµíµÄpHÈçÏÂ±í£º

ÓÉÉϱí¿ÉÖª£ºµ±ÈÜÒºpH=4ʱ£¬¿ÉÒÔÍêÈ«³ýÈ¥µÄÀë×ÓÊÇ______£¬²»ÄÜÍêÈ«³ýÈ¥µÄÀë×ÓÊÇ________¡£

¢ÈÂËÒºBͨ¹ýÕô·¢Å¨Ëõ£¨ÉèÌå»ýŨËõΪԭÀ´µÄÒ»°ë£©¡¢ÀäÈ´½á¾§¿ÉÒԵõ½¾§Ì塣ijͬѧÈÏΪÉÏÊö²Ù×÷»á°èÓÐÁòËáÂÁ¾§ÌåµÄÎö³ö¡£ÇëÄã½áºÏÏà¹ØÊý¾Ý¶Ô¸ÃͬѧµÄ¹ÛµãÓèÒÔÆÀ¼Û£¨ÒÑÖª³£ÎÂÏ£¬±¥ºÍÈÜÒºÖÐ

mol______________¡£

¢ÉÈôÒª²â¶¨ÁòËáÍ­¾§ÌåÖнᾧˮµÄº¬Á¿£¬ÐèÒªµÄÒÇÆ÷ÊǾƾ«µÆ¡¢ÍÐÅÌÌìƽ¡¢Èý½Ç¼Ü¡¢ÄàÈý½Ç¡¢²£Á§°ô¡¢¸ÉÔïÆ÷¡¢ÛáÛöǯ¡¢Ñв§¡¢Ò©³×¡¢_________________¡£ÊµÑé¹ý³ÌÖÐÁòËáÍ­¾§Ìå¼ÓÈÈʧˮºóÔÚ¿ÕÖÐÀäÈ´ºó³ÆÁ¿£¬Ôò²â¶¨½á¹û______________(Ìî¡°Æ«¸ß¡±¡¢  ¡°Æ«µÍ¡±»ò¡°²»±ä¡±)¡£   

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÂÁÐÓйØÎïÖÊÐÔÖʵÄÓ¦ÓÃÕýÈ·µÄÊÇ                  

A£®ÓлúÁ×Å©Ò©¶àΪÁ×Ëáõ¥»òÁò´úÁ×Ëáõ¥ÀàÎïÖÊ£¬·ÊÔíË®µÈ¼îÐÔÎïÖÊÓÐÀûÆäË®½â¶ø½â¶¾

    B£®¶þÑõ»¯¹èÊÇÖÆÔìÌ«ÑôÄܵç³Ø°åµÄÖ÷Òª²ÄÁÏ

    C£®¶þÑõ»¯ÁòͨÈëËáÐÔKMnO4ÈÜÒº£¬ÈÜÒº×ϺìÉ«ÍÊÈ¥£¬ÌåÏÖÁËSO2µÄƯ°×ÐÔ

    D£®³£ÎÂÏÂŨH2SO4ºÍŨHNO3¶¼ÄÜʹCu·¢Éú¶Û»¯

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


º£ÑóÊǸö¾Þ´óµÄ×ÊÔ´±¦¿â£¬ÀûÓú£Ë®¿ÉÖÆÈ¡Ðí¶à»¯¹¤²úÆ·¡£

£¨1£©ÂȼҵÊÇÒÔµç½âʳÑÎˮΪ»ù´¡»¯Ñ§¹¤Òµ£¬Ð´³öµç½âʳÑÎË®µÄ»¯Ñ§·½³Ìʽ_________

__________________________________________________________.

£¨2£©´Óº£Ë®ÖÐÌáÈ¡äå³£Óôµ³ö·¨£¬¼´ÓÃÂÈÆø(Cl2)½«º£Ë®Àïä廯ÄÆ£¨NaBr£©ÖеÄäåÖû»³öÀ´£¬ÔÙÓÿÕÆø´µ³öäå(Br2)¡£Á÷³ÌʾÒâͼÈçÏ£º

¢Ùд³öÂÈÆø´ÓNaBrÖÐÖû»³öäåµ¥ÖʵĻ¯Ñ§·½³Ìʽ£º____________________;¸Ã·´Ó¦ÔÚpH=3µÄËáÐÔÌõ¼þϽøÐУ¬¿ÉÓÃ________²â¶¨·´Ó¦ÒºµÄËá¼î¶È¡£

¢Ú´µ³öµÄäåºÍ´óÁ¿¿ÕÆø»ìºÏÔÚ—Æð½øÈëÎüÊÕËþ£¬¸ù¾ÝÁ÷³Ìͼ·ÖÎö£¬Í¨ÈëSO2ºÍË®µÄÄ¿µÄÊÇ¡£_____________________________________________________.£¨Óû¯Ñ§·½³Ìʽ±íʾ£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


12

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


X¡¢Y¡¢Z¡¢WΪËÄÖÖ¶ÌÖÜÆÚÖ÷×åÔªËØ£¬ÆäÖÐX¡¢Zͬ×壬Y¡¢ZͬÖÜÆÚ£¬WÊǶÌÖÜÆÚÖ÷×åÔªËØÖÐÔ­×Ӱ뾶×î´óµÄ£¬XÔ­×Ó×îÍâ²ãµç×ÓÊýÊǺËÍâµç×Ó²ãÊýµÄ3±¶£¬YµÄ×î¸ßÕý¼ÛÓë×îµÍ¸º¼Û´úÊýºÍΪ6¡£ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ

A£®YÔªËØ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎﻯѧʽH2YO4

B£®Ô­×Ӱ뾶ÓÉ´óµ½Ð¡µÄ˳ÐòΪ£ºZ>Y> W

C£®X¡¢ZÁ½ÖÖÔªËصÄÆø̬Ç⻯ÎïÖУ¬ZµÄÆø̬Ç⻯Îï½ÏÎȶ¨

D£®XÓëWÐγɵÄÁ½ÖÖ»¯ºÏÎïÖУ¬Òõ¡¢ÑôÀë×ÓÎïÖʵÄÁ¿Ö®±È¾ùΪ1︰2

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


14

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÓÐ50ml0.1mol/LµâË®£¬µ±Í¨Èë×ãÁ¿Cl2ÍêÈ«·´Ó¦ºó£¬¹²×ªÒÆÁË0.05molµç×Ó,ÔòÏÂÁÐÐðÊö´íÎóµÄÊÇ

A£®¸Ã·´Ó¦ÖÐH2OÊÇ·´Ó¦ÎïÖ®Ò»   B£®Ñõ»¯¼ÁÓ뻹ԭ¼ÁµÄÎïÖʵÄÁ¿Ö®±ÈΪ1¡Ã5

C£®Ñõ»¯²úÎïΪHIO3                   D£®ÈôÓÐ1 mol I2²Î¼ÓÑõ»¯·´Ó¦,תÒÆ10 mol e-

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÓÃNA±íʾ°¢·ü¼ÓµÂÂÞ³£ÊýµÄÊýÖµ£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ £¨ £©

A¡¢±ê×¼×´¿öÏ£¬11.2 L SO3Ëùº¬µÄÔ­×ÓÊýΪ2NA

B¡¢±ê×¼×´¿öÏ£¬22.4LÑõÆøºÍÒÒȲ»ìºÏÎïËùº¬µÄ·Ö×ÓÊýΪNA

C¡¢23 gÄÆÔÚÑõÆøÖÐÍêȫȼÉÕʧµç×ÓÊýΪ0.5 NA

D¡¢100 mL 2.0 mol/LµÄNa2SÈÜÒºÖÐS2-Àë×Ó¸öÊýµÈÓÚ0.2 NA

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ij¿ÆÑлú¹¹Óú¬ÂȵÄÓлúÎïAºÏ³ÉÃÞÖ¯ÎïÃâÌÌ¿¹ÖåÕûÀí¼ÁM£¬Éè¼ÆºÏ³É·ÏßÈçͼ(²¿·Ö·´Ó¦ÊÔ¼ÁºÍÌõ¼þδעÃ÷)£º

ÒÑÖª£º¢ÙÓÃÖÊÆ×·¨²âµÃDµÄÏà¶Ô·Ö×ÓÖÊÁ¿ÔÚ90ÖÁ110Ö®¼ä£¬ÇÒÑõÔªËصÄÖÊÁ¿·ÖÊýΪ0.615£¬

E±ÈDµÄÏà¶Ô·Ö×ÓÖÊÁ¿´ó28£¬ºË´Å¹²ÕñÇâÆ×ÏÔʾE·Ö×ÓÄÚÓÐ2ÖÖ²»Í¬»·¾³µÄÇâÔ­×Ó£¬Æä

¸öÊý±ÈΪ3¡Ã1¡£

Ìþ»ù£©

 

»Ø´ðÏÂÁÐÎÊÌ⣺

(1)A·Ö×ÓÖк¬Ñõ¹ÙÄÜÍŵÄÃû³ÆÊÇ________£¬G¡úHµÄ·´Ó¦ÀàÐÍÊÇ_______________________¡£

(2)DµÄ·Ö×ÓʽΪ_________£»EµÄ½á¹¹¼òʽΪ__________________________________¡£

(3)H¡úJ·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ________________________________________¡£

(4)JÔÚÒ»¶¨Ìõ¼þÏ¿ÉÒԺϳɸ߷Ö×Ó»¯ºÏÎ¸Ã¸ß·Ö×Ó»¯ºÏÎïµÄ½á¹¹¼òʽÊÇ______________¡£

(5)ÒÑÖª1 mol EÓë2 mol J·´Ó¦Éú³É1 mol M£¬ÔòMµÄ½á¹¹¼òʽÊÇ___________________¡£

(6)д³öÓëA¾ßÓÐÏàͬ¹ÙÄÜÍŵÄAµÄËùÓÐͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£º_______________________________________________________________________________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸