ÎïÖÊÔÚË®ÈÜÒºÖпÉÄÜ´æÔÚµçÀëƽºâ¡¢ÑεÄË®½âƽºâ»ò³ÁµíÈܽâƽºâ£¬ËüÃǶ¼¿É¿´×÷»¯Ñ§Æ½ºâµÄÒ»ÖÖ£®Çë¸ù¾ÝËùѧ»¯Ñ§ÖªÊ¶»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÓÐ0.1mol?L-1µÄ£¨NH4£©2SO4ÈÜÒº£¬ÔÚ¸ÃÈÜÒºÖÐÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ
 
£®
£¨2£©ÓÐ0.1mol?L-1µÄNaHCO3ÈÜÒº£¬ÔÚ¸ÃÈÜÒºÖдæÔÚµÄƽºâÓÐÈý¸ö£¬Çë·Ö±ðÓÃÀë×Ó·½³Ìʽ±íʾ£º
 
£®
£¨3£©ÒÑÖª£¨NH4£©2Fe£¨SO4£©2ÈÜÓÚˮȫ²¿µçÀë³ÉNH4+¡¢Fe2+¡¢SO42-£¬ÓÐÏàͬŨ¶ÈµÄ£¨NH4£©2Fe£¨SO4£©2ºÍ£¨NH4£©2SO4ÈÜÒº£¬ÔÚ
 
ÈÜÒºÖÐNH
 
+
4
Ũ¶È¸ü´ó£¨Ìѧʽ£©£¬ÆäÔ­ÒòÊÇ
 
£®
£¨4£©AgClÔÚÈÜÒºÖдæÔÚÈçÏÂƽºâ£ºAgCl£¨s£©?Ag+£¨aq£©+Cl-£¨aq£©£¬ÔÚ25¡æʱ£¬AgClµÄKsp=1.8¡Á10-10£®ÏÖ½«×ãÁ¿AgCl·Ö±ð·ÅÈëÏÂÁÐÒºÌåÖУº¢Ù100mLÕôÁóË®¡¡ ¢Ú100mL 0.3mol?L-1 AgNO3ÈÜÒº¡¡ ¢Û100mL 0.1mol?L-1MgCl2ÈÜÒº³ä·Ö½Á°èºóÀäÈ´µ½Ïàͬζȣ¬Ag+Ũ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ
 
£¨ÌîÐòºÅ£©£®
·ÖÎö£º£¨1£©ÒÀ¾ÝÁòËáï§ÈÜÒºÖÐ笠ùÀë×ÓË®½âÈÜÒº³ÊËáÐÔ·ÖÎöÀë×ÓŨ¶È´óС£»
£¨2£©Ì¼ËáÇâÄÆÈÜÒºÖдæÔÚµÄƽºâΪ̼ËáÇâ¸ùÀë×ÓË®½âƽºâ¡¢µçÀëƽºâºÍË®µÄµçÀëƽºâ£»
£¨3£©ÁòËáÑÇÌúï§ÈÜÒºÖÐÑÇÌúÀë×ÓË®½â³ÊËáÐÔÒÖÖÆ笠ùÀë×ÓË®½â£¬ï§¸ùÀë×ÓŨ¶È´óÓÚÁòËáï§ÈÜÒºÖÐ笠ùÀë×ÓŨ¶È£»
£¨4£©ÂÈ»¯Òø±¥ºÍÈÜÒºÖдæÔÚ³ÁµíÈܽâƽºâ£¬±¥ºÍÈÜÒºÖеÄÈܶȻýÊdz£Êý£¬¿ÉÓà KSP±íʾ£ºKSP=c£¨Ag+£©?c£¨Cl-£©£¬¸ù¾ÝƽºâÒƶ¯±È½ÏŨ¶È´óС£®
½â´ð£º£¨1£©ÓÐ0.1mol?L-1µÄ£¨NH4£©2SO4ÈÜÒº£¬ï§¸ùÀë×ÓË®½âÏÔËáÐÔ£¬Ë®½â³Ì¶È΢Èõ£¬ÔÚ¸ÃÈÜÒºÖÐÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳Ðòc£¨NH4+£©£¾c£¨SO42-£©£¾c£¨H+£©£¾c£¨OH-£©£»
¹Ê´ð°¸Îª£ºc£¨NH4+£©£¾c£¨SO42-£©£¾c£¨H+£©£¾c£¨OH-£©£»
£¨2£©Ì¼ËáÇâÄÆÈÜÒºÖдæÔÚµÄƽºâΪ̼ËáÇâ¸ùÀë×ÓË®½âƽºâHCO3-+H2O?H2CO3+OH-£»µçÀëƽºâHCO3-?H++CO32-£»Ë®µÄµçÀëƽºâH2O?H++OH-£»
¹Ê´ð°¸Îª£ºHCO3-?H++CO32-£»HCO3-+H2O?H2CO3+OH-£»H2O?H++OH-£»
£¨3£©ÁòËáÑÇÌúï§ÈÜÒºÖÐÑÇÌúÀë×ÓË®½â³ÊËáÐÔÒÖÖÆ笠ùÀë×ÓË®½â£¬ï§¸ùÀë×ÓŨ¶È´óÓÚÁòËáï§ÈÜÒºÖÐ笠ùÀë×ÓŨ¶È£»
¹Ê´ð°¸Îª£º£¨NH4£©2Fe£¨SO4£©2£¬Fe2+Ë®½âÏÔËáÐÔ£¬¶ÔNH4+µÄË®½âÓÐÒÖÖÆ×÷Óã»
£¨4£©¢Ù.100mLÕôÁóË®ÖÐÒøÀë×ÓŨ¶È²»±ä£»
¢Ú.100mL 0.3mol?L-1AgNO3ÈÜÒº£¬ÒøÀë×ÓŨ¶ÈÔö´ó£¬Æ½ºâÄæÏòÒƶ¯£¬×îÖÕc£¨Ag+£©Ôö´ó£»
¢Û.100mL0.1mol?L-1MgCl2ÈÜÒºÖУ¬ÂÈÀë×ÓŨ¶ÈÔö´ó£¬Æ½ºâÄæÏòÒƶ¯£¬c£¨Ag+£©¼õÉÙ£»
×ÛºÏÉÏÊö¼ÆËãµÃµ½£ºÒºÖÐc£¨Ag+£©ÓÉ´óµ½Ð¡µÄ˳ÐòΪ¢Ú¢Ù¢Û£¬
¹Ê´ð°¸Îª£º¢Ú¢Ù¢Û£®
µãÆÀ£º±¾Ì⿼²éÁ˵ç½âÖÊÈÜÒºÖÐÀë×ÓŨ¶ÈµÄ´óС±È½Ï£¬ÑÎÀàË®½âµÄ·ÖÎöÓ¦Ó㬳̶ÈÈܽâƽºâµÄÓ°ÏìÒòËØ·ÖÎöÅжϣ¬ÕÆÎÕ»ù´¡Êǹؼü£¬ÌâÄ¿ÄѶÈÖеȣ®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡°·ä»ÊËᡱQº¬Ì¼65.2%£¬Çâ8.75%£¬ÆäÓàΪÑõ¡£Q¾ßÓÐËáÐÔ£¬43.7mg QÐèÓÃ23.7rnL 0.0100mol?L£­1ÇâÑõ»¯ÄÆË®ÈÜÒºÀ´µÎ¶¨´ïµ½µÎ¶¨Öյ㡣¾­²â¶¨£¬QµÄ·Ö×ÓÁ¿²»´óÓÚ200¡£

£¨1£©Ð´³öQµÄ·Ö×Óʽ£»QÖпÉÄÜÓÐʲô¹ÙÄÜÍÅʹËü¾ßÓÐËáÐÔ£¿

ÔÚ²¬·Û´æÔÚÏÂQÓëÇâ·´Ó¦µÃµ½Ð»¯ºÏÎïA¡£AÔÚÒÒ´¼ÖÐÓëÅðÇ⻯ÄÆ·´Ó¦µÃµ½B¡£BÓëŨÁòËá¹²ÈÈʱÈÝÒ×ÍÑË®£¬µÃµ½Ï©ÌþC¡£CµÄ13CºË´Å¹²Õñ±íÃ÷ÔÚË«¼üÉÏÓÐÒ»¸ö¼×»ù¡£

£¨2£©ÉÏÊö·´Ó¦±íÃ÷´æÔÚÄÄЩ¹ÙÄÜÍÅ£¿

C³ôÑõÑõ»¯ºóÑõ»¯ÐÔË®½âÖ»µÃµ½Á½¸ö¶ÏƬ£¬ÒÒËáºÍÖ±Á´µÄ¶þôÈËáD¡£½«Q½øÐÐÀàËƵĶÏÁÑ£¬µÃµ½²ÝËáºÍº¬ÓÐÒ»¸öôÈ»ùµÄÎïÖÊE¡£

£¨3£©ÍÆÂÛDºÍEµÄ½á¹¹£¬Óɴ˸ø³öQµÄ¿ÉÄܽṹ¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸