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A.2KClO3(s)= 2KCl(s)+ 3O2(g) ¦¤H = £78.03 kJ¡¤mol£1£¬¦¤S = 494.4 J¡¤mol£1¡¤K£1
B.CO(g)= C(s,ʯī)+O2(g) ¦¤H = 110.5 kJ¡¤mol£1£¬¦¤S = £89.4 J¡¤mol£1¡¤K£1
C.4Fe(OH)2(s)+2H2O(l)+O2(g)= 4Fe(OH)3(s)
¦¤H = £444.3 kJ¡¤mol£1£¬¦¤S = £280.1 J¡¤mol£1¡¤K£1
D.NH4HCO3(s) + CH3COOH(aq) = CH3COONH4 (aq) + CO2(g) +H2O(l)
¦¤H = 37.30 kJ¡¤mol£1£¬¦¤S = 184.0 J¡¤mol£1¡¤K£1
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A.2KClO3(s)2KCl(s)+3O2(g)?
¦¤H=-78.03 kJ¡¤mol-1¡¡¦¤S=1 110 J¡¤mol-1¡¤K-1?
B.CO(g)C(s,ʯī)+O2£¨g£©?
¦¤H=110.5 kJ¡¤mol-1¡¡¦¤S=-89.36 J¡¤mol-1¡¤K-1?
C.4Fe(OH)2(s)+2H2O(l)+O2(g)4Fe(OH)3(s)?
¦¤H=-444.3 kJ¡¤mol-1¡¡¦¤S=-280.1 J¡¤mol-1¡¤K-1?
D.NH4HCO3(s)+CH3COOH(aq)CO2(g)+CH3COONH4(aq)+H2O(l)?
¦¤H=37.301 kJ¡¤mol-1¡¡¦¤S=184.0 J¡¤mol-1¡¤K-1
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¦¤£È£½110.05 kJ¡¤mol£1 ¦¤£Ó£½£89.36 J¡¤mol£1¡¤K £1
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£Ä£®NH4HCO3(s)£«CH3COOH(aq)£½CO2(g)£«CH3COO NH4(aq)£«H2O(l)
¦¤£È£½37.30 kJ¡¤mol£1 ¦¤£Ó£½184.05 J¡¤mol£1 ¡¤K£1
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A£®2KClO3(s)=2KCl(s)+3O2(g)¡¡ ¦¤H=-78.03kJ/mol¡¡¦¤S="1110" J/(mol¡¤K)
B£®CO(g)=C(s£¬Ê¯Ä«)+1/2O2(g)¡¡ ¦¤H=110.5kJ/mol¡¡¦¤S="-89.36" J/(mol¡¤K)
C£®4Fe(OH)2(s)+2H2O(l)+O2(g)=4Fe(OH)3(s)¡¡¦¤H=-444.3kJ/mol¦¤S="-280.1" J/(mol¡¤K)
D£®NH4HCO3(s)+CH3COOH(aq)=CO2(g)+CH3COONH4(aq)+H2O(l)
¦¤H=37.301kJ/mol¡¡ ¦¤S="184.05" J/(mol¡¤K)
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