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A.2KClO3(s)= 2KCl(s)+ 3O2(g)   ¦¤H = £­78.03 kJ¡¤mol£­1£¬¦¤S = 494.4 J¡¤mol£­1¡¤K£­1

B.CO(g)= C(s,ʯī)+O2(g)  ¦¤H = 110.5 kJ¡¤mol£­1£¬¦¤S = £­89.4 J¡¤mol£­1¡¤K£­1

C.4Fe(OH)2(s)+2H2O(l)+O2(g)= 4Fe(OH)3(s) 

¦¤H = £­444.3 kJ¡¤mol£­1£¬¦¤S = £­280.1 J¡¤mol£­1¡¤K£­1

D.NH4HCO3(s) + CH3COOH(aq) = CH3COONH4 (aq) + CO2(g) +H2O(l) 

¦¤H = 37.30 kJ¡¤mol£­1£¬¦¤S = 184.0 J¡¤mol£­1¡¤K£­1

 

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A.2KClO3(s)2KCl(s)+3O2(g)?

¦¤H=-78.03 kJ¡¤mol-1¡¡¦¤S=1 110 J¡¤mol-1¡¤K-1?

B.CO(g)C(s,ʯī)+O2£¨g£©?

¦¤H=110.5 kJ¡¤mol-1¡¡¦¤S=-89.36 J¡¤mol-1¡¤K-1?

C.4Fe(OH)2(s)+2H2O(l)+O2(g)4Fe(OH)3(s)?

¦¤H=-444.3 kJ¡¤mol-1¡¡¦¤S=-280.1 J¡¤mol-1¡¤K-1?

D.NH4HCO3(s)+CH3COOH(aq)CO2(g)+CH3COONH4(aq)+H2O(l)?

¦¤H=37.301 kJ¡¤mol-1¡¡¦¤S=184.0 J¡¤mol-1¡¤K-1

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¡¡£Á£®£²KClO3(s)£½2KCl(s) £«£Ï2(g)   

                    ¦¤£È£½£­78.03 kJ¡¤mol£­1       ¦¤£Ó£½1110 J¡¤mol£­1¡¤K£­1

  £Â£®CO(g)£½C(sʯī) £«1/2£Ï2(g)¡¡ 

¦¤£È£½110.05 kJ¡¤mol£­1        ¦¤£Ó£½£­89.36 J¡¤mol£­1¡¤K £­1

  £Ã£®£´Fe(OH)2(s)£«2H2O(l)£«O2(g)£½£´Fe(OH)3(s)    

                    ¦¤£È£½£­444.3 kJ¡¤mol£­1       ¦¤£Ó£½£­280.3 J¡¤mol£­1 ¡¤K£­1

  £Ä£®NH4HCO3(s)£«CH3COOH(aq)£½CO2(g)£«CH3COO NH4(aq)£«H2O(l) 

¦¤£È£½37.30 kJ¡¤mol£­1      ¦¤£Ó£½184.05 J¡¤mol£­1 ¡¤K£­1

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A£®2KClO3(s)=2KCl(s)+3O2(g)¡¡ ¦¤H=-78.03kJ/mol¡¡¦¤S="1110" J/(mol¡¤K)

B£®CO(g)=C(s£¬Ê¯Ä«)+1/2O2(g)¡¡ ¦¤H=110.5kJ/mol¡¡¦¤S="-89.36" J/(mol¡¤K)

C£®4Fe(OH)2(s)+2H2O(l)+O2(g)=4Fe(OH)3(s)¡¡¦¤H=-444.3kJ/mol¦¤S="-280.1" J/(mol¡¤K)

D£®NH4HCO3(s)+CH3COOH(aq)=CO2(g)+CH3COONH4(aq)+H2O(l)

¦¤H=37.301kJ/mol¡¡    ¦¤S="184.05" J/(mol¡¤K)

 

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