¹¤ÒµÉÏÖÆÁòËáµÄÉ豸·ÖΪÈý´ó²¿·Ö£¬Ò»ÊÇ·ÐÌÚ¯¡¢¶þÊǽӴ¥ÊÒ¡¢ÈýÊÇÎüÊÕËþ£»·ÂÕÕ¹¤ÒµÉÏÖƱ¸ÁòËáµÄÁ÷³ÌÉè¼Æ³öÏÂÃæµÄ×°Öã¬ÒÔ̽¾¿ÓйØÎÊÌâ¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Ð´³öFeS2ÓëÑõÆø·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º____________________________¡£

£¨2£©´ÓÒÒ×°ÖÃÖгöÀ´µÄÆøÌåÓÐ__________________________________________¡£

£¨3£©Ð´³öÉÏͼ±û×°ÖõÄ×÷ÓÃ__________________________________________¡£

£¨4£©ÔÚ×°ÖÃÒҵķ´Ó¦Æ÷ÄÚÒªÇóÑõÆøµÄÁ¿Òª±È¶þÑõ»¯ÁòµÄÁ¿¶àÒ»±¶×óÓÒ£¬ÊµÑéʱÄãÊÇÈçºÎ¿ØÖÆÓë¹À¼ÆµÄ£¿____________________________¡£

£¨5£©½Ó´¥·¨ÖÆÁòËá¹ý³ÌÖУ¬Èô·´Ó¦Èȶ¼Î´±»ÀûÓã¬ÔòÿÉú²ú1 000 g 98%ÁòËáÐèÒªÎüÊÕ3.6¡Á102 kJÄÜÁ¿¡£Èô·´Ó¦2SO2£¨g£©+O2£¨g£©2SO3£¨g£©£»¦¤H=-98.3 kJ¡¤mol-1µÄÈÈÁ¿ÄÜÔÚÉú²ú¹ý³ÌÖеõ½³ä·ÖÀûÓã¨ÆäËû·´Ó¦ÈȲ»¼Æ£©£¬ÔòÿÉú²ú1 000 g 98%ÁòËáÖ»ÐèÍâ½çÌṩ£¨»ò¿ÉÏòÍâ½çÊä³ö£©__________________kJÄÜÁ¿¡£

£¨6£©±¾ÊµÑéÔö¼Ó¶¡×°ÖõÄÄ¿µÄÊÇΪÁË̽¾¿____________________________¡£

£¨7£©±¾ÊµÑéÉè¼Æ»¹´æÔڵĽÏÃ÷ÏÔȱÏÝÊÇ_______________________________¡£

½âÎö£º·ÐÌÚ¯ÄÚ·´Ó¦Îª4FeS2+11O22Fe2O3+8SO2£»

ÓÉÓÚSO2ºÍO2ת»¯ÎªSO3µÄ·´Ó¦ÊÇ¿ÉÄæ·´Ó¦£¬ËùÒÔÆøÌå·Ö×Ó¹²´æ£»×¢Ò⹤ҵÎüÊÕSO3µÄÔ­ÀíÊDzÉÓÃŨÁòËᣬ˵Ã÷SO3ÈÜÓÚŨÁòË᣻ÀûÓü××°ÖÿØÖÆÆøÌåÁ÷ËÙÀ´¿ØÖÆÆøÌå·´Ó¦Îï±ÈÀýµÄ·½·¨Êdz£¼ûµÄ·½·¨£¬¿Éͨ¹ýµ÷½ÚÆø·§A¡¢B£¬¹Û²ì×°ÖÃÄÚðÆøÅÝËÙÂÊ¿ØÖÆÆøÌåÁ÷Á¿£»·´Ó¦ÈȺͷ´Ó¦ÎïÖʵÄÁ¿³ÉÕý±È£¬98.3 kJ¡¤mol-1¡Á5 mol-360 kJ=131.5 kJ¡£

×¢Òâ¶Ô±È¡°±û¡¢¶¡¡±×°ÖõÄÇø±ð£¨ÊÔ¼Á²»Í¬ºÍµ¼¹Ü³¤¶Ì²»Í¬£©¿ÉÖª±ûΪÎüÊÕSO3×°Ö㬶¡Îª¶Ô±È×°Öã»»·±£ÒâʶºÍ½ÚÔ¼Òâʶ£¨¿ØÖÆÁ¿£©ÊÇ»¯Ñ§ÊµÑé±ØÐ뿼ÂǵÄÎÊÌ⣬ȱÉÙβÆøÎüÊÕ×°Öá£

´ð°¸£º

£¨1£©4FeS2+11O22Fe2O3+8SO2

£¨2£©SO2¡¢O2¡¢SO3

£¨3£©ÎüÊÕSO3ÆøÌ壨ģÄâÎüÊÕËþ£©

£¨4£©¿ÉÒÔͨ¹ýµ÷½ÚÆø·§£¬¿ØÖÆÆøÌåÁ÷Á¿£»¹Û²ì¼××°ÖõÄðÅÝËÙÂʹÀ¼Æ

£¨5£©131.5

£¨6£©Ì½¾¿¹¤ÒµÉÏΪºÎ²ÉÓÃ98.3%µÄŨÁòËáÎüÊÕÈýÑõ»¯Áò¶ø²»ÓÃË®£¨ÎüÊÕ²úÉúËáÎí£©

£¨7£©È±ÉÙβÆøÎüÊÕ×°ÖÃ

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

ÔÚÖÐѧ»¯Ñ§ÊµÑéÖУ¬Í¨³£ÓÃÎÞË®ÁòËáÍ­¼ìÑéÉÙÁ¿Ë®µÄ´æÔÚ£®ÓÉÓÚÎÞË®ÁòËáÍ­ÎüʪÐÔºÜÇ¿£¬ÐèÒªÏÖÖÆÏÖÓã®
·½·¨¼×£ºÈ¡2Ò©³×ϸСµÄÁòËáÍ­¾§ÌåÖÃÓÚ
Ñв§
Ñв§
ÖÐÑÐËéºó·ÅÈëÛáÛö£¬½«ÛáÛö·ÅÔÚ
ÄàÈý½Ç
ÄàÈý½Ç
ÉÏÓÃС»ðÂýÂý¼ÓÈȲ¢Óò£Á§°ô²»Í£½Á°è£¬×îºó½«ÛáÛöÒÆÈë
¸ÉÔïÆ÷
¸ÉÔïÆ÷
ÖнøÐÐÀäÈ´£¨ÇëÑ¡ÓúÏÊÊÒÇÆ÷»òÉ豸Ìî¿Õ£º±íÃæÃó¡¢Ñв§¡¢ÉÕ±­¡¢Í¨·ç³÷¡¢ÊԹܼС¢¸ÉÔïÆ÷¡¢ÄàÈý½Ç£©£®
·½·¨ÒÒ£ºÈ¡2Ò©³×ÑÐËéµÄÁòËáÍ­¾§ÌåÓÚСÉÕ±­ÖУ¬¼ÓÈë20mlŨÁòËᣨÖÊÁ¿·ÖÊý²»µÍÓÚ98%£©£¬²¢Óò£Á§°ô½Á°è£¬¾²ÖÃ5minºóÇãȥŨÁòËᣬÓÃÎÞË®ÒÒ´¼Ï´µÓÊý´Î£¬µ¹ÔÚÂËÖ½ÉÏÁÀ¸É£®
½»Á÷ÓëÌÖÂÛ£º
£¨1£©·½·¨¼×ÖУ¬¼ÓÈÈζÈÉÔ¸ßʱ»á³öÏÖ±äºÚÏÖÏó£¬Ô­ÒòÊÇ
CuSO4?5H2O
  ¡÷  
.
 
CuO+SO3+5H2O»òCuSO4?5H2O
  ¡÷  
.
 
CuO+H2SO4+4H2O
CuSO4?5H2O
  ¡÷  
.
 
CuO+SO3+5H2O»òCuSO4?5H2O
  ¡÷  
.
 
CuO+H2SO4+4H2O
£¨Óû¯Ñ§·½³Ìʽ±íʾ£©£»
£¨2£©·½·¨ÒÒÖУ¬Å¨ÁòËáµÄ×÷ÓÃÊÇ
ÎüË®¼Á
ÎüË®¼Á
£¬ÎªÁ˲»ÀË·ÑÒ©Æ·£¬¶ÔÎÞË®ÒÒ´¼Ï´µÓÒº½øÐÐÔÙÉúµÄ·½·¨ÊÇ
¼ÓCaOºóÕôÁó
¼ÓCaOºóÕôÁó
£¬ËùÓõÄÖ÷Òª²£Á§ÒÇÆ÷ÓÐÕôÁóÉÕÆ¿¡¢Î¶ȼơ¢³Ð½Ó¹Ü£¨Å£½Ç¹Ü£©¡¢×¶ÐÎÆ¿
¾Æ¾«µÆ¡¢ÀäÄý¹Ü
¾Æ¾«µÆ¡¢ÀäÄý¹Ü
µÈ£»
£¨3£©ÓÃÖƵõÄÎÞË®ÁòËáÍ­¼ìÑéij˫ÑõË®ÖÐÊÇ·ñº¬Ë®Ê±£¬³ýÁË·¢ÏÖ¹ÌÌå±äÀ¶Í⣬»¹·¢ÏÖ¸ÃË«ÑõË®ÖÐÓÐÆøÅݲúÉú£¬¶Ô´ËÄãÓкβÂÏë
Í­Àë×Ó£¨»òÁòËáÍ­£©¶ÔË«ÑõË®·Ö½âÓд߻¯×÷ÓÃ
Í­Àë×Ó£¨»òÁòËáÍ­£©¶ÔË«ÑõË®·Ö½âÓд߻¯×÷ÓÃ
£»
£¨4£©Ä¿Ç°¹¤ÒµÉÏÕý»ý¼«Ì½Ë÷ÓÃŨHNO3×÷Ñõ»¯¼Á£¬ÓÃCuÓëŨH2SO4¡¢Å¨HNO3·´Ó¦£¬²ÉÈ¡¼äЪ¼ÓÈÈ¡¢Öð½¥¼ÓÈëŨHNO3µÄ·½·¨À´ÖƱ¸CuSO4?5H2O µÄй¤ÒÕ£®Ä£ÄâÖƱ¸×°ÖÃÈçͼËùʾ£®
ÎÊÌâÒ»ÈçͼװÖÃÖУ¬·ÖҺ©¶·ÄÚ×°µÄÒºÌåÊÇ
ŨÏõËá
ŨÏõËá
£»·´Ó¦½áÊøʱ£¬»ñÈ¡CuSO4?5H2OµÄ²Ù×÷¹ý³ÌÊÇÏÈ
Ïȳ·È¥µ¼¹Ü
Ïȳ·È¥µ¼¹Ü
£¬ºó
Í£Ö¹¼ÓÈÈ
Í£Ö¹¼ÓÈÈ
£»³ÃÈȽ«Èý¾±Æ¿ÖеÄÒºÌåµ¹ÈëÉÕ±­ÖÐÀäÈ´£¬Îö³ö¾§ÌåCuSO4?5H2O£¬¹ýÂË¡¢ÁÀ¸É£»
ÎÊÌâ¶þ¹¤ÒµÉÏÓÃʯ»ÒÈéÎüÊÕβÆø£¬³ýÁË·ÀÖ¹»·¾³ÎÛȾÍ⣬»¹Äܵõ½ÁËÓо­¼ÃʵÓüÛÖµµÄ¸±²úÆ·----ÑÇÏõËá¸Æ£®Î²ÆøÎüÊÕÉú³ÉÑÇÏõËá¸ÆµÄ»¯Ñ§·½³ÌʽÊÇ£º
NO2+NO+Ca£¨OH£©2=Ca£¨NO2£©2+H2O »ò4NO2+2Ca£¨OH£©2=Ca£¨NO3£©2+Ca£¨NO2£©2+2H2O
NO2+NO+Ca£¨OH£©2=Ca£¨NO2£©2+H2O »ò4NO2+2Ca£¨OH£©2=Ca£¨NO3£©2+Ca£¨NO2£©2+2H2O
£»
ÎÊÌâÈý½«Ê¯»ÒÈéÏ¡ÊÍ£¬¿ÉµÃµ½³ÎÇåʯ»ÒË®£® ³ÎÇåʯ»ÒË®ÓëCO2ÏàÓöÄܹ»²úÉú°×É«³Áµí£®Ä³Í¬Ñ§ÏëÓÃÈçͼËùʾװÖÃÒÔ´óÀíʯºÍÏ¡ÑÎËá·´Ó¦ÖÆÈ¡CO2£®½Ìʦָ³öÖÆÈ¡µÈÁ¿µÄÆøÌ壬¸Ã×°ÖÃÐèҪ̫¶àµÄÑÎËᣬÔì³ÉÀË·Ñ£®¸Ãͬѧ¶Ô¸Ã×°ÖÃij²¿Î»¼ÓÁËÒ»¸öСÊԹܣ¬½â¾öÁËÕâ¸öÎÊÌ⣮ÇëÄã°Ñ¸Ä½ø»­ÔÚͼÖкÏÊʵÄλÖã®
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

ÔÚÖÐѧ»¯Ñ§ÊµÑéÖУ¬Í¨³£ÓÃÎÞË®ÁòËáÍ­¼ìÑéÉÙÁ¿Ë®µÄ´æÔÚ£®ÓÉÓÚÎÞË®ÁòËáÍ­ÎüʪÐÔºÜÇ¿£¬ÐèÒªÏÖÖÆÏÖÓã®
·½·¨¼×£ºÈ¡2Ò©³×ϸСµÄÁòËáÍ­¾§ÌåÖÃÓÚ______ÖÐÑÐËéºó·ÅÈëÛáÛö£¬½«ÛáÛö·ÅÔÚ______ÉÏÓÃС»ðÂýÂý¼ÓÈȲ¢Óò£Á§°ô²»Í£½Á°è£¬×îºó½«ÛáÛöÒÆÈë______ÖнøÐÐÀäÈ´£¨ÇëÑ¡ÓúÏÊÊÒÇÆ÷»òÉ豸Ìî¿Õ£º±íÃæÃó¡¢Ñв§¡¢ÉÕ±­¡¢Í¨·ç³÷¡¢ÊԹܼС¢¸ÉÔïÆ÷¡¢ÄàÈý½Ç£©£®
·½·¨ÒÒ£ºÈ¡2Ò©³×ÑÐËéµÄÁòËáÍ­¾§ÌåÓÚСÉÕ±­ÖУ¬¼ÓÈë20mlŨÁòËᣨÖÊÁ¿·ÖÊý²»µÍÓÚ98%£©£¬²¢Óò£Á§°ô½Á°è£¬¾²ÖÃ5minºóÇãȥŨÁòËᣬÓÃÎÞË®ÒÒ´¼Ï´µÓÊý´Î£¬µ¹ÔÚÂËÖ½ÉÏÁÀ¸É£®
½»Á÷ÓëÌÖÂÛ£º
£¨1£©·½·¨¼×ÖУ¬¼ÓÈÈζÈÉÔ¸ßʱ»á³öÏÖ±äºÚÏÖÏó£¬Ô­ÒòÊÇ______£¨Óû¯Ñ§·½³Ìʽ±íʾ£©£»
£¨2£©·½·¨ÒÒÖУ¬Å¨ÁòËáµÄ×÷ÓÃÊÇ______£¬ÎªÁ˲»ÀË·ÑÒ©Æ·£¬¶ÔÎÞË®ÒÒ´¼Ï´µÓÒº½øÐÐÔÙÉúµÄ·½·¨ÊÇ______£¬ËùÓõÄÖ÷Òª²£Á§ÒÇÆ÷ÓÐÕôÁóÉÕÆ¿¡¢Î¶ȼơ¢³Ð½Ó¹Ü£¨Å£½Ç¹Ü£©¡¢×¶ÐÎÆ¿______µÈ£»
£¨3£©ÓÃÖƵõÄÎÞË®ÁòËáÍ­¼ìÑéij˫ÑõË®ÖÐÊÇ·ñº¬Ë®Ê±£¬³ýÁË·¢ÏÖ¹ÌÌå±äÀ¶Í⣬»¹·¢ÏÖ¸ÃË«ÑõË®ÖÐÓÐÆøÅݲúÉú£¬¶Ô´ËÄãÓкβÂÏë______£»
£¨4£©Ä¿Ç°¹¤ÒµÉÏÕý»ý¼«Ì½Ë÷ÓÃŨHNO3×÷Ñõ»¯¼Á£¬ÓÃCuÓëŨH2SO4¡¢Å¨HNO3·´Ó¦£¬²ÉÈ¡¼äЪ¼ÓÈÈ¡¢Öð½¥¼ÓÈëŨHNO3µÄ·½·¨À´ÖƱ¸CuSO4?5H2O µÄй¤ÒÕ£®Ä£ÄâÖƱ¸×°ÖÃÈçͼËùʾ£®
ÎÊÌâÒ»ÈçͼװÖÃÖУ¬·ÖҺ©¶·ÄÚ×°µÄÒºÌåÊÇ______£»·´Ó¦½áÊøʱ£¬»ñÈ¡CuSO4?5H2OµÄ²Ù×÷¹ý³ÌÊÇÏÈ______£¬ºó______£»³ÃÈȽ«Èý¾±Æ¿ÖеÄÒºÌåµ¹ÈëÉÕ±­ÖÐÀäÈ´£¬Îö³ö¾§ÌåCuSO4?5H2O£¬¹ýÂË¡¢ÁÀ¸É£»
ÎÊÌâ¶þ¹¤ÒµÉÏÓÃʯ»ÒÈéÎüÊÕβÆø£¬³ýÁË·ÀÖ¹»·¾³ÎÛȾÍ⣬»¹Äܵõ½ÁËÓо­¼ÃʵÓüÛÖµµÄ¸±²úÆ·----ÑÇÏõËá¸Æ£®Î²ÆøÎüÊÕÉú³ÉÑÇÏõËá¸ÆµÄ»¯Ñ§·½³ÌʽÊÇ£º______£»
ÎÊÌâÈý½«Ê¯»ÒÈéÏ¡ÊÍ£¬¿ÉµÃµ½³ÎÇåʯ»ÒË®£® ³ÎÇåʯ»ÒË®ÓëCO2ÏàÓöÄܹ»²úÉú°×É«³Áµí£®Ä³Í¬Ñ§ÏëÓÃÈçͼËùʾװÖÃÒÔ´óÀíʯºÍÏ¡ÑÎËá·´Ó¦ÖÆÈ¡CO2£®½Ìʦָ³öÖÆÈ¡µÈÁ¿µÄÆøÌ壬¸Ã×°ÖÃÐèҪ̫¶àµÄÑÎËᣬÔì³ÉÀË·Ñ£®¸Ãͬѧ¶Ô¸Ã×°ÖÃij²¿Î»¼ÓÁËÒ»¸öСÊԹܣ¬½â¾öÁËÕâ¸öÎÊÌ⣮ÇëÄã°Ñ¸Ä½ø»­ÔÚͼÖкÏÊʵÄλÖã®______£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÎÊ´ðÌâ

ÔÚÖÐѧ»¯Ñ§ÊµÑéÖУ¬Í¨³£ÓÃÎÞË®ÁòËáÍ­¼ìÑéÉÙÁ¿Ë®µÄ´æÔÚ£®ÓÉÓÚÎÞË®ÁòËáÍ­ÎüʪÐÔºÜÇ¿£¬ÐèÒªÏÖÖÆÏÖÓã®
·½·¨¼×£ºÈ¡2Ò©³×ϸСµÄÁòËáÍ­¾§ÌåÖÃÓÚ______ÖÐÑÐËéºó·ÅÈëÛáÛö£¬½«ÛáÛö·ÅÔÚ______ÉÏÓÃС»ðÂýÂý¼ÓÈȲ¢Óò£Á§°ô²»Í£½Á°è£¬×îºó½«ÛáÛöÒÆÈë______ÖнøÐÐÀäÈ´£¨ÇëÑ¡ÓúÏÊÊÒÇÆ÷»òÉ豸Ìî¿Õ£º±íÃæÃó¡¢Ñв§¡¢ÉÕ±­¡¢Í¨·ç³÷¡¢ÊԹܼС¢¸ÉÔïÆ÷¡¢ÄàÈý½Ç£©£®
·½·¨ÒÒ£ºÈ¡2Ò©³×ÑÐËéµÄÁòËáÍ­¾§ÌåÓÚСÉÕ±­ÖУ¬¼ÓÈë20mlŨÁòËᣨÖÊÁ¿·ÖÊý²»µÍÓÚ98%£©£¬²¢Óò£Á§°ô½Á°è£¬¾²ÖÃ5minºóÇãȥŨÁòËᣬÓÃÎÞË®ÒÒ´¼Ï´µÓÊý´Î£¬µ¹ÔÚÂËÖ½ÉÏÁÀ¸É£®
½»Á÷ÓëÌÖÂÛ£º
£¨1£©·½·¨¼×ÖУ¬¼ÓÈÈζÈÉÔ¸ßʱ»á³öÏÖ±äºÚÏÖÏó£¬Ô­ÒòÊÇ______£¨Óû¯Ñ§·½³Ìʽ±íʾ£©£»
£¨2£©·½·¨ÒÒÖУ¬Å¨ÁòËáµÄ×÷ÓÃÊÇ______£¬ÎªÁ˲»ÀË·ÑÒ©Æ·£¬¶ÔÎÞË®ÒÒ´¼Ï´µÓÒº½øÐÐÔÙÉúµÄ·½·¨ÊÇ______£¬ËùÓõÄÖ÷Òª²£Á§ÒÇÆ÷ÓÐÕôÁóÉÕÆ¿¡¢Î¶ȼơ¢³Ð½Ó¹Ü£¨Å£½Ç¹Ü£©¡¢×¶ÐÎÆ¿______µÈ£»
£¨3£©ÓÃÖƵõÄÎÞË®ÁòËáÍ­¼ìÑéij˫ÑõË®ÖÐÊÇ·ñº¬Ë®Ê±£¬³ýÁË·¢ÏÖ¹ÌÌå±äÀ¶Í⣬»¹·¢ÏÖ¸ÃË«ÑõË®ÖÐÓÐÆøÅݲúÉú£¬¶Ô´ËÄãÓкβÂÏë______£»
£¨4£©Ä¿Ç°¹¤ÒµÉÏÕý»ý¼«Ì½Ë÷ÓÃŨHNO3×÷Ñõ»¯¼Á£¬ÓÃCuÓëŨH2SO4¡¢Å¨HNO3·´Ó¦£¬²ÉÈ¡¼äЪ¼ÓÈÈ¡¢Öð½¥¼ÓÈëŨHNO3µÄ·½·¨À´ÖƱ¸CuSO4?5H2O µÄй¤ÒÕ£®Ä£ÄâÖƱ¸×°ÖÃÈçͼËùʾ£®
ÎÊÌâÒ»ÈçͼװÖÃÖУ¬·ÖҺ©¶·ÄÚ×°µÄÒºÌåÊÇ______£»·´Ó¦½áÊøʱ£¬»ñÈ¡CuSO4?5H2OµÄ²Ù×÷¹ý³ÌÊÇÏÈ______£¬ºó______£»³ÃÈȽ«Èý¾±Æ¿ÖеÄÒºÌåµ¹ÈëÉÕ±­ÖÐÀäÈ´£¬Îö³ö¾§ÌåCuSO4?5H2O£¬¹ýÂË¡¢ÁÀ¸É£»
ÎÊÌâ¶þ¹¤ÒµÉÏÓÃʯ»ÒÈéÎüÊÕβÆø£¬³ýÁË·ÀÖ¹»·¾³ÎÛȾÍ⣬»¹Äܵõ½ÁËÓо­¼ÃʵÓüÛÖµµÄ¸±²úÆ·----ÑÇÏõËá¸Æ£®Î²ÆøÎüÊÕÉú³ÉÑÇÏõËá¸ÆµÄ»¯Ñ§·½³ÌʽÊÇ£º______£»
ÎÊÌâÈý½«Ê¯»ÒÈéÏ¡ÊÍ£¬¿ÉµÃµ½³ÎÇåʯ»ÒË®£® ³ÎÇåʯ»ÒË®ÓëCO2ÏàÓöÄܹ»²úÉú°×É«³Áµí£®Ä³Í¬Ñ§ÏëÓÃÈçͼËùʾװÖÃÒÔ´óÀíʯºÍÏ¡ÑÎËá·´Ó¦ÖÆÈ¡CO2£®½Ìʦָ³öÖÆÈ¡µÈÁ¿µÄÆøÌ壬¸Ã×°ÖÃÐèҪ̫¶àµÄÑÎËᣬÔì³ÉÀË·Ñ£®¸Ãͬѧ¶Ô¸Ã×°ÖÃij²¿Î»¼ÓÁËÒ»¸öСÊԹܣ¬½â¾öÁËÕâ¸öÎÊÌ⣮ÇëÄã°Ñ¸Ä½ø»­ÔÚͼÖкÏÊʵÄλÖã®______£®
¾«Ó¢¼Ò½ÌÍø

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸