¡¾ÌâÄ¿¡¿ÁòËáÑÇÌúÊÇÒ»ÖÖÖØÒªµÄ»¯¹¤ÔÁÏ£¬¿ÉÒÔÖƱ¸Ò»ÏµÁÐÎïÖÊ(ÈçÏÂͼ)£¬ÏÂÁÐ˵·¨´íÎóµÄÊÇ( )
A. ¼îʽÁòËáÌúË®½âÄܲúÉúFe(OH)3½ºÌ壬¿ÉÓÃ×ö¾»Ë®¼Á
B. Ϊ·ÀÖ¹NH4HCO3·Ö½â£¬Éú²úFeCO3ÐèÔڽϵÍζÈϽøÐУ¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ£ºFe2++2HCO3£= FeCO3+ CO2¡ü+H2O
C. ¿ÉÓÃKSCNÈÜÒº¼ìÑé(NH4)2Fe(SO4)2ÊÇ·ñ±»Ñõ»¯
D. ¸ÃζÈÏ£¬(NH4)2Fe(SO4)2ÔÚË®ÖеÄÈܽâ¶È±ÈFeSO4µÄ´ó
¡¾´ð°¸¡¿D
¡¾½âÎö¡¿
A.¼îʽÁòËáÌúÖÐË®½â²úÉú½ºÌ壬½ºÌå¿ÉÒÔÎü¸½Ë®ÖÐÔÓÖÊ£¬¹ÊAÕýÈ·£»
B.¼ÓÈÈÒ׷ֽ⣬Ϊ·ÀÖ¹Æä·Ö½â£¬Éú²úÐèÔڽϵÍζÈϽøÐУ¬¹ÊBÕýÈ·£»
C.Öк¬ÓУ¬Èô±»Ñõ»¯ÔòÉú³É£¬ÓëÈÜÒº²úÉúѪºìÉ«ÎïÖÊ£¬¹ÊCÕýÈ·£»
D.ÀäÈ´½á¾§Ê±£¬Èܽâ¶ÈСµÄÎïÖÊÏÈÎö³ö£¬³£ÎÂÏ£¬ÔÚË®ÖеÄÈܽâ¶È±ÈµÄС£¬¹ÊD´íÎó£»
±¾Ìâ´ð°¸ÎªD¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿ÒÑÖª£º¢ÙAµÄ²úÁ¿Í¨³£ÓÃÀ´ºâÁ¿Ò»¸ö¹ú¼ÒµÄʯÓÍ»¯¹¤Ë®Æ½£»¢Ú2CH3CHO£«O22CH3COOH¡£ÏÖÒÔAΪÖ÷ÒªÔÁϺϳɻ¯ºÏÎïE£¬ÆäºÏ³É·ÏßÈçͼ1Ëùʾ¡£»Ø´ðÏÂÁÐÎÊÌ⣺
ͼ1
(1)д³öÏÂÁÐÎïÖʵĹÙÄÜÍÅÃû³Æ£º
B£º____________________£»D£º____________________¡£
(2)·´Ó¦¢ÜµÄ»¯Ñ§·½³ÌʽΪ________________________________________________£¬·´Ó¦ÀàÐÍ£º________¡£
(3)ijѧϰС×éÉè¼ÆÎïÖÊB´ß»¯Ñõ»¯µÄʵÑé×°ÖÃÈçÏ£¬¸ù¾Ýͼ2×°ÖûشðÎÊÌâ¡£
¼× ÒÒ ±û ¶¡
ͼ2
¢Ù×°Öü×׶ÐÎÆ¿ÖÐÊ¢·ÅµÄ¹ÌÌåÒ©Æ·¿ÉÄÜΪ________(Ìî×Öĸ)¡£
A Na2O2 B KCl C Na2CO3 D MnO2
¢ÚʵÑé¹ý³ÌÖУ¬±û×°ÖÃÓ²Öʲ£Á§¹ÜÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_________________________¡£
¢ÛÎïÖÊBµÄ´ß»¯Ñõ»¯²úÎïÓëÆÏÌÑÌǾßÓÐÏàͬµÄÌØÕ÷·´Ó¦£¬½«ËùµÃµÄÑõ»¯²úÎïµÎ¼Óµ½ÐÂÖÆÇâÑõ»¯ÍÐü×ÇÒºÖмÓÈÈ£¬ÏÖÏóΪ______________________________________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿A¡¢B¡¢C¡¢D¡¢EÊǺ˵çºÉÊýÒÀ´ÎÔö´óµÄÎåÖÖ¶ÌÖÜÆÚÖ÷×åÔªËØ£¬AÔ×ÓºËÄÚÖ»ÓÐ1¸öÖÊ×Ó£»BÔ×Ӱ뾶ÊÇÆäËùÔÚÖ÷×åÖÐ×îСµÄ£¬BµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïµÄ»¯Ñ§Ê½ÎªHBO3£»CÔ×Ó×îÍâ²ãµÄµç×ÓÊý±È´ÎÍâ²ãµÄ¶à4£»CµÄ¼òµ¥ÒõÀë×ÓÓëDµÄÑôÀë×Ó¾ßÓÐÏàͬµÄµç×Ó²ã½á¹¹£¬Á½ÔªËØ¿ÉÐγɻ¯ºÏÎïD2C£»C¡¢EͬÖ÷×å¡£»Ø´ðÏÂÁÐÎÊÌ⣺
(1)BÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃΪ______________________¡£
(2)EµÄÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïÓÐ______________________ (д»¯Ñ§Ê½)¡£
(3)B¡¢C¡¢D¡¢EÐγɵļòµ¥Àë×Ӱ뾶ÓÉ´óµ½Ð¡µÄ¹ØϵÊÇ______________________(ÓÃÀë×Ó·ûºÅ±íʾ)¡£
(4)»¯ºÏÎïD2CµÄÐγɹý³ÌΪ______________________(Óõç×Óʽ±íʾ)¡£
(5)ÓÉA¡¢B¡¢CÈýÖÖÔªËØÐγɵij£¼ûµÄÀë×Ó»¯ºÏÎïµÄ»¯Ñ§Ê½Îª___________£¬¸Ã»¯ºÏÎïµÄË®ÈÜÒºÓëÇ¿¼îÈÜÒº¹²ÈÈ·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ______________________¡£
(6)»¯ºÏÎïD2EC3ÔÚÒ»¶¨Ìõ¼þÏ¿ÉÒÔ·¢Éú·Ö½â·´Ó¦Éú³ÉÁ½ÖÖÑΣ¬ÆäÖÐÒ»ÖÖ²úÎïΪÎÞÑõËáÑΣ¬Ôò´Ë·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿POCl3³£ÓÃ×÷°ëµ¼Ìå²ôÔÓ¼Á¼°¹âµ¼ÏËάÔÁÏ£¬ÊµÑéÊÒ²ÉÓÃÑõÆøÑõ»¯ÒºÌ¬PCl3·¨ÖÆÈ¡POCl3£¬ÓйØÎïÖʵIJ¿·ÖÐÔÖÊÈçϱí
ÎïÖÊ | ÈÛµã/¡æ | ·Ðµã/¡æ | Ïà¶Ô·Ö×ÓÖÊÁ¿ | ÆäËû |
PCl3 | -112.0 | 76.0£¨Ò×»Ó·¢£© | 137.5 | Á½Õß»¥ÈÜ£¬¾ùΪÎÞÉ«ÒºÌ壬ÓöË®¾ù¾çÁÒ·´Ó¦Éú³Éº¬ÑõËáºÍÂÈ»¯Çâ |
POC13 | 2.0 | 106.0 | 153.5 |
ʵÑé×°Ö㨼ÓÈȼ°¼Ð³ÖÒÇÆ÷ÂÔ£©ÈçÏ£º
£¨1£©¼××°ÖõÄÃû³ÆÊÇ____________£¬¸ÉÔï¹ÜµÄ×÷ÓÃÊÇ____________
£¨2£©×°ÖÃCÖÐÉú³ÉPOCl3µÄ»¯Ñ§·½³ÌʽΪ______________
£¨3£©×°ÖÃBµÄ×÷Óóý¹Û²ìÆøÌåµÄÁ÷ËÙÍ⣬»¹ÓÐ________ ¡¢________
£¨4£©·´Ó¦Î¶Ȳ»Äܹý¸ß£¬ÔÒòÊÇ______________¡£
£¨5£©·´Ó¦Ò»¶Îʱ¼äºó£¬´ýÈý¾±Æ¿ÖеÄÒºÌåÀäÈ´ÖÁÊÒΣ¬×¼È·³ÆÈ¡29.1g²úÆ·£¨½öº¬PCl3ÔÓÖÊ£©£¬ÖÃÓÚÊ¢ÓÐ60.00 mLÕôÁóË®µÄÃܱÕË®½âÆ¿ÖÐÒ¡¶¯ÖÁÍêÈ«ÓëË®·´Ó¦£¬½«Ë®½âÒºÅä³É100.00 mLÈÜÒº£¬¼ÓÈëAgNO3ÈÜÒºÖÁÇ¡ºÃÍêÈ«·´Ó¦£¬²âµÃÉú³ÉµÄAgClµÄÖÊÁ¿Îª86.1g£¬Ôò²úÆ·ÖÐPOC13µÄÖÊÁ¿·ÖÊýΪ___£¨±£ÁôÈýλÓÐЧÊý×Ö£©
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿¢Ù¡«¢ßÔÚÔªËØÖÜÆÚ±íµÄ¶ÔӦλÖÃÈçͼËùʾ£¬»Ø´ðÏÂÁÐÎÊÌâ¡£
ÖÜÆÚ | ¢ñA | ¢òA | ¢óA | ¢ôA | ¢õA | ¢öA | ¢÷A | 0 |
2 | ¢ß | ¢Ù | ¢Ú | |||||
3 | ¢Û | ¢Ü | ¢Ý | ¢Þ |
£¨1£©ÔªËØ¢ÞµÄÔ×ӽṹʾÒâͼ___________£»ÔªËصÄ×î¸ßÕý¼Û¢Ù___________¢Ú(Ìî>¡¢<¡¢=)
£¨2£©ÏòÔªËآݺ͢ÞÐγɵĻ¯ºÏÎïµÄË®ÈÜÒºÖмÓÈë¹ýÁ¿µÄ¢ÙµÄÇ⻯ÎïµÄË®ÈÜÒº£¬·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ______________
£¨3£©ÔªËØ¢ÛµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïΪ_______£¨ÌîÀë×Ó»¯ºÏÎï»ò¹²¼Û»¯ºÏÎ
£¨4£©ÔªËآں͢ÛÐγɵÄÒ»ÖÖ»¯ºÏÎïΪµ»ÆÉ«¹ÌÌ壬¸Ã»¯ºÏÎïµÄµç×ÓʽΪ______£¬¸Ã»¯ºÏÎïÖл¯¼üÓÐ_______£¨ÌîÀë×Ó¼ü¡¢¼«ÐÔ¼ü»ò·Ç¼«ÐÔ¼ü£©£¬¸Ã»¯ºÏÎïÓë¢ßµÄ×î¸ß¼ÛÑõ»¯Îï·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_____¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿ÏÂÁÐ˵·¨»ò±íʾ·¨²»ÕýÈ·µÄÊÇ£¨ £©
A£®µÈÁ¿µÄÁòÕôÆøºÍÁò¹ÌÌå·Ö±ðÍêȫȼÉÕ£¬ºóÕ߷ųöÈÈÁ¿¶à
B£®ÓÉC(ʯī)¡úC(½ð¸Õʯ) ¦¤H = +1.9 kJ¡¤mol¡ª1¿É֪ʯī±È½ð¸ÕʯÎȶ¨
C£®ÔÚÏ¡ÈÜÒºÖУºH++OH£ H2O ¦¤H =£57.3 kJ¡¤mol¡ª1£¬Èô½«º¬1mol CH3COOHµÄ´×ËáÈÜÒºÓ뺬1 mol NaOHµÄÈÜÒº»ìºÏ£¬·Å³öµÄÈÈÁ¿Ð¡ÓÚ57.3 kJ
D£®ÔÚÈÈ»¯Ñ§·½³ÌʽÖÐÎÞÂÛÊÇ·´Ó¦ÎﻹÊÇÉú³ÉÎï±ØÐë±íÃ÷¾Û¼¯×´Ì¬
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿ÎªÁËÇåÀí·Ãæ»ýÑ©£¬ÈËÃdz£Ê¹ÓÃÒ»ÖÖÈÚÑ©¼Á£¬ÆäÖ÷Òª³É·ÖµÄ»¯Ñ§Ê½ÎªXY2£¬X¡¢Y¾ùΪÖÜÆÚ±íÇ°20ºÅÔªËØ£¬ÆäÑôÀë×ÓºÍÒõÀë×ӵĵç×Ó²ã½á¹¹Ïàͬ£¬ÇÒ1 mol XY2º¬ÓÐ54molµç×Ó¡£
£¨1£©¸ÃÈÚÑ©¼ÁµÄ»¯Ñ§Ê½ÊÇ____£¬¸ÃÎïÖÊÖл¯Ñ§¼üÀàÐÍÊÇ______£¬µç×ÓʽÊÇ______¡£
£¨2£©ÔªËØD¡¢EÔ×ÓµÄ×îÍâ²ãµç×ÓÊýÊÇÆäµç×Ó²ãÊýµÄ2±¶£¬DÓëYÏàÁÚ£¬ÔòDµÄÀë×ӽṹʾÒâͼÊÇ__________£»DÓëEÄÜÐγÉÒ»ÖֽṹÀàËÆÓÚCO2µÄÈýÔ×Ó·Ö×Ó£¬ÇÒÿ¸öÔ×Ó¾ù´ïµ½ÁË8e£Îȶ¨½á¹¹£¬¸Ã·Ö×ӵĽṹʽΪ_________£¬µç×ÓʽΪ_______£¬»¯Ñ§¼üÀàÐÍΪ_________(Ìî¡°Àë×Ó¼ü¡±¡°·Ç¼«ÐÔ¹²¼Û¼ü¡±»ò¡°¼«ÐÔ¹²¼Û¼ü¡±)¡£
£¨3£©WÊÇÓëDͬÖ÷×åµÄ¶ÌÖÜÆÚÔªËØ£¬ZÊǵÚÈýÖÜÆÚ½ðÊôÐÔ×îÇ¿µÄÔªËØ£¬ZµÄµ¥ÖÊÔÚWµÄ³£¼ûµ¥ÖÊÖз´Ó¦Ê±ÓÐÁ½ÖÖ²úÎ²»¼ÓÈÈʱÉú³É____£¬Æ仯ѧ¼üÀàÐÍΪ___£»¼ÓÈÈʱÉú³É_____£¬Æ仯ѧ¼üÀàÐÍΪ_______¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿ÏÂÁÐA¡¢B¡¢C¡¢DÊÇÖÐѧ³£¼ûµÄ»ìºÏÎï·ÖÀë»òÌá´¿µÄ»ù±¾×°Öã®
Çë¸ù¾Ý»ìºÏÎï·ÖÀë»òÌá´¿µÄÔÀí£¬½«A¡¢B¡¢C¡¢D ÌîÈëÊʵ±µÄ¿Õ¸ñÖУ®
(1)ÓÃËÄÂÈ»¯Ì¼µâË®ÖÐÌáÈ¡µâ_____£»
(2)³ýÈ¥´ÖÑÎÖеÄÄàɳ_____£»
(3)Ó뺣ˮɹÑÎÔÀíÏàËƵÄÊÇ_____£»
(4)·ÖÀëCCl4(·Ðµã£º76.75¡æ)ºÍ¼×±½(·Ðµã£º110.6¡æ)µÄ»ìºÏÎï_____£®
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿ÏÂÁл¯Ñ§ÊµÑé»ù±¾²Ù×÷ÖÐÕýÈ·µÄÊÇ£¨ £©
A.´ÓµâË®ÖÐÌáÈ¡I2ʱ£¬ÏòµâË®ÈÜÒº¼ÓÈë¾Æ¾«½øÐÐÝÍÈ¡·ÖÒº
B.Õô·¢½á¾§Ê±£¬Õô·¢ÃóÓ¦·ÅÔÚʯÃÞÍøÉϼÓÈÈ
C.ÓÃ10 mLÁ¿Í²Á¿È¡7.50 mLŨÑÎËá
D.ÕôÁóʱ£¬ÀäÄýË®´ÓÀäÄý¹ÜϹܿڽø£¬ÓÉÉϹܿڳö
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com