£¨14·Ö£©
0.80g CuSO4¡¤5H2OÑùÆ·ÊÜÈÈÍÑË®¹ý³ÌµÄÈÈÖØÇúÏߣ¨ÑùÆ·ÖÊÁ¿Ëæζȱ仯µÄÇúÏߣ©ÈçÏÂͼËùʾ¡£
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÊÔÈ·¶¨200¡æʱ¹ÌÌåÎïÖʵĻ¯Ñ§Ê½______________£¨ÒªÇóд³öÍƶϹý³Ì£©£»
£¨2£©È¡270¡æËùµÃÑùÆ·£¬ÓÚ570¡æ×ÆÉյõ½µÄÖ÷Òª²úÎïÊǺÚÉ«·ÛÄ©ºÍÒ»ÖÖÑõ»¯ÐÔÆøÌ壬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______________¡£°Ñ¸ÃºÚÉ«·ÛÄ©ÈܽâÓÚÏ¡ÁòËáÖУ¬¾Å¨Ëõ¡¢ÀäÈ´£¬Óо§ÌåÎö³ö£¬¸Ã¾§ÌåµÄ»¯Ñ§Ê½Îª_________£¬Æä´æÔÚµÄ×î¸ßζÈÊÇ_____________£»
£¨3£©ÉÏÊöÑõ»¯ÐÔÆøÌåÓëË®·´Ó¦Éú³ÉÒ»ÖÖ»¯ºÏÎ¸Ã»¯ºÏÎïµÄŨÈÜÒºÓëCuÔÚ¼ÓÈÈʱ·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ________________£»
£¨4£©ÔÚ0.10mol¡¤L-1ÁòËáÍÈÜÒºÖмÓÈëÇâÑõ»¯ÄÆÏ¡ÈÜÒº³ä·Ö½Á°è£¬ÓÐdzÀ¶É«ÇâÑõ»¯Í³ÁµíÉú³É£¬µ±ÈÜÒºµÄpH=8ʱ£¬c£¨Cu2+£©=________________mol¡¤L-1£¨Ksp[Cu£¨OH£©2]=2.2¡Á10-20£©¡£
ÈôÔÚ0.1mol¡¤L-1ÁòËáÍÈÜÒºÖÐͨÈë¹ýÁ¿H2SÆøÌ壬ʹCu2+ÍêÈ«³ÁµíΪCuS£¬´ËʱÈÜÒºÖеÄH+Ũ¶ÈÊÇ_______________mol¡¤L-1¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011ÄêÆÕͨ¸ßµÈѧУÕÐÉúÈ«¹úͳһ¿¼ÊÔ»¯Ñ§¾í£¨Ð¿α꣩ ÌâÐÍ£ºÑ¡ÔñÌâ
0.80g¡¤5ÑùÆ·ÊÜÈÈÍÑË®¹ý³ÌµÄÈÈÖØÇúÏߣ¨ÑùÆ·ÖÊÁ¿Ëæζȱ仯µÄÇúÏߣ©ÈçÏÂͼËùʾ¡£
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÊÔÈ·¶¨200¡æʱ¹ÌÌåÎïÖʵĻ¯Ñ§Ê½______________£¨ÒªÇóд³öÍƶϹý³Ì£©£»
£¨2£©È¡270¡æËùµÃÑùÆ·£¬ÓÚ570¡æ×ÆÉյõ½µÄÖ÷Òª²úÎïÊǺÚÉ«·ÛÄ©ºÍÒ»ÖÖÑõ»¯ÐÔÆøÌ壬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______________¡£°Ñ¸ÃºÚÉ«·ÛÄ©ÈܽâÓÚÏ¡ÁòËáÖУ¬¾Å¨Ëõ¡¢ÀäÈ´£¬Óо§ÌåÎö³ö£¬¸Ã¾§ÌåµÄ»¯Ñ§Ê½Îª_________£¬Æä´æÔÚµÄ×î¸ßζÈÊÇ_____________£»
£¨3£©ÉÏÊöÑõ»¯ÐÔÆøÌåÓëË®·´Ó¦Éú³ÉÒ»ÖÖ»¯ºÏÎ¸Ã»¯ºÏÎïµÄŨÈÜÒºÓëCuÔÚ¼ÓÈÈʱ·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ________________£»
£¨4£©ÔÚ0.10mol¡¤L-1ÁòËáÍÈÜÒºÖмÓÈëÇâÑõ»¯ÄÆÏ¡ÈÜÒº³ä·Ö½Á°èÓÐdzÀ¶É«ÇâÑõ»¯Í³ÁµíÉú³É£¬µ±ÈÜÒºµÄpH=8ʱ£¬c£¨Cu2+£©=________________mol¡¤L-1£¨Kap[Cu£¨OH£©2]=2.2¡Á10-20£©¡£
ÈôÔÚ0.1mol¡¤L-1ÁòËáÍÈÜÒºÖÐͨÈë¹ýÁ¿H2SÆøÌ壬ʹCu2+ÍêÈ«³ÁµíΪCuS£¬´ËʱÈÜÒºÖеÄH+Ũ¶ÈÊÇ_______________mol¡¤L-1¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º¸ß¿¼ÕæÌâ ÌâÐÍ£ºÌî¿ÕÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
0.80g CuSO4¡¤5H2OÑùÆ·ÊÜÈÈÍÑË®¹ý³ÌµÄÈÈÖØÇúÏߣ¨ÑùÆ·ÖÊÁ¿Ëæζȱ仯µÄÇúÏߣ©ÈçÏÂͼËùʾ¡£
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÊÔÈ·¶¨200¡æʱ¹ÌÌåÎïÖʵĻ¯Ñ§Ê½______________£»
£¨2£©È¡270¡æËùµÃÑùÆ·£¬ÓÚ570¡æ×ÆÉյõ½µÄÖ÷Òª²úÎïÊǺÚÉ«·ÛÄ©ºÍÒ»ÖÖÑõ»¯ÐÔÆøÌ壬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______________¡£°Ñ¸ÃºÚÉ«·ÛÄ©ÈܽâÓÚÏ¡ÁòËáÖУ¬¾Å¨Ëõ¡¢ÀäÈ´£¬Óо§ÌåÎö³ö£¬¸Ã¾§ÌåµÄ»¯Ñ§Ê½Îª_________£¬Æä´æÔÚµÄ×î¸ßζÈÊÇ_____________£»
£¨3£©ÉÏÊöÑõ»¯ÐÔÆøÌåÓëË®·´Ó¦Éú³ÉÒ»ÖÖ»¯ºÏÎ¸Ã»¯ºÏÎïµÄŨÈÜÒºÓëCuÔÚ¼ÓÈÈʱ·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ________________£»
£¨4£©ÈôÔÚ0.1mol¡¤L-1ÁòËáÍÈÜÒºÖÐͨÈë¹ýÁ¿H2SÆøÌ壬ʹCu2+ÍêÈ«³ÁµíΪCuS£¬´ËʱÈÜÒºÖеÄH+Ũ¶ÈÊÇ_______________mol¡¤L-1¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
£¨14·Ö£©
0.80g CuSO4¡¤5H2OÑùÆ·ÊÜÈÈÍÑË®¹ý³ÌµÄÈÈÖØÇúÏߣ¨ÑùÆ·ÖÊÁ¿Ëæζȱ仯µÄÇúÏߣ©ÈçÏÂͼËùʾ¡£
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÊÔÈ·¶¨200¡æʱ¹ÌÌåÎïÖʵĻ¯Ñ§Ê½______________£¨ÒªÇóд³öÍƶϹý³Ì£©£»
£¨2£©È¡270¡æËùµÃÑùÆ·£¬ÓÚ570¡æ×ÆÉյõ½µÄÖ÷Òª²úÎïÊǺÚÉ«·ÛÄ©ºÍÒ»ÖÖÑõ»¯ÐÔÆøÌ壬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______________¡£°Ñ¸ÃºÚÉ«·ÛÄ©ÈܽâÓÚÏ¡ÁòËáÖУ¬¾Å¨Ëõ¡¢ÀäÈ´£¬Óо§ÌåÎö³ö£¬¸Ã¾§ÌåµÄ»¯Ñ§Ê½Îª_________£¬Æä´æÔÚµÄ×î¸ßζÈÊÇ_____________£»
£¨3£©ÉÏÊöÑõ»¯ÐÔÆøÌåÓëË®·´Ó¦Éú³ÉÒ»ÖÖ»¯ºÏÎ¸Ã»¯ºÏÎïµÄŨÈÜÒºÓëCuÔÚ¼ÓÈÈʱ·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ________________£»
£¨4£©ÔÚ0.10mol¡¤L-1ÁòËáÍÈÜÒºÖмÓÈëÇâÑõ»¯ÄÆÏ¡ÈÜÒº³ä·Ö½Á°è£¬ÓÐdzÀ¶É«ÇâÑõ»¯Í³ÁµíÉú³É£¬µ±ÈÜÒºµÄpH=8ʱ£¬c£¨Cu2+£©=________________mol¡¤L-1£¨Ksp[Cu£¨OH£©2]=2.2¡Á10-20£©¡£
ÈôÔÚ0.1mol¡¤L-1ÁòËáÍÈÜÒºÖÐͨÈë¹ýÁ¿H2SÆøÌ壬ʹCu2+ÍêÈ«³ÁµíΪCuS£¬´ËʱÈÜÒºÖеÄH+Ũ¶ÈÊÇ_______________mol¡¤L-1¡£
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com