¡¾ÌâÄ¿¡¿ÄøÓëVA×åÔªËØÐγɵĻ¯ºÏÎïÊÇÖØÒªµÄ°ëµ¼Ìå²ÄÁÏ£¬Ó¦ÓÃ×î¹ã·ºµÄÊÇÉ黯ïØ(GaAs)£¬»Ø´ðÏÂÁÐÎÊÌ⣺

(1)»ù̬GaÔ­×ӵĺËÍâµç×ÓÅŲ¼Ê½Îª_____£¬»ù̬AsÔ­×ÓºËÍâÓÐ_________¸öδ³É¶Ôµç×Ó¡£

(2)ïØʧȥµç×ÓµÄÖ𼶵çÀëÄÜ(µ¥Î»£ºkJ¡¤mol-1)µÄÊýÖµÒÀ´ÎΪ577¡¢1984.5¡¢2961.8¡¢6192ÓÉ´Ë¿ÉÍÆÖªïصÄÖ÷Òª»¯ºÏ¼ÛΪ____ºÍ+3¡£ÉéµÄµç¸ºÐÔ±ÈÄø____(Ìî¡°´ó¡±»ò¡°Ð¡¡±)¡£

(3)±È½ÏÏÂÁÐïصı»¯ÎïµÄÈÛµãºÍ·Ðµã£¬·ÖÎöÆä±ä»¯¹æÂɼ°Ô­Òò£º________________________¡£

ïصı»¯Îï

GaCl3

GaBr3

GaI3

ÈÛµã/¡æ

77.75

122.3

211.5

·Ðµã/¡æ

201.2

279

346

GaF3µÄÈ۵㳬¹ý1000 ¡æ£¬¿ÉÄܵÄÔ­Òò___________________________________________¡£

(4)¶þË®ºÏ²ÝËáïصĽṹÈçͼËùʾ£¬ÆäÖÐïØÔ­×ÓµÄÅäλÊýΪ______£¬²ÝËá¸ùÖÐ̼ԭ×ÓµÄÔÓ»¯·½Ê½Îª______________¡£

(5)É黯ïØÈÛµãΪ1238¡æ£¬Á¢·½¾§°û½á¹¹ÈçͼËùʾ£¬¾§°û²ÎÊýΪa=565 pm¡£¸Ã¾§ÌåµÄÀàÐÍΪ_________£¬¾§ÌåµÄÃܶÈΪ___________(ÉèNAΪ°¢·ü¼ÓµÂÂÞ³£ÊýµÄÊýÖµ,ÁгöËãʽ¼´¿É)g¡¤cm-3¡£

¡¾´ð°¸¡¿[Ar]3d104s24p1»ò1s22s22p63s23p63d104s24p1 3 +1 ´ó GaCl3¡¢GaBr3¡¢GaI3µÄÈ۷еãÒÀ´ÎÉí¸ß£¬ËüÃǾùΪ·Ö×Ó¾§Ì壬½á¹¹ÏàËÆ£¬Ïà¶Ô·Ö×ÓÖÊÁ¿ÒÀ´ÎÔö´ó£¬·Ö×Ó¼ä×÷ÓÃÁ¦ÒÀ´ÎÔöÇ¿ GaF3ΪÀë×Ó¾§Ìå 4 sp2 Ô­×Ó¾§Ìå g/cm3

¡¾½âÎö¡¿

(1)GaµÄÔ­×ÓÐòÊýΪ31£¬Æä»ù̬ԭ×ӵĵç×ÓʽÅŲ¼Ê½Îª£º[Ar]3d104s24p1»ò1s22s22p63s23p63d104s24p1£¬AsµÄÔ­×ÓÐòÊýΪ33£¬ÔòAsµÄ»ù̬ԭ×ӵĵç×ÓÅŲ¼Ê½Îª£º[Ar]3d104s24p3£¬ËùÒÔ»ù̬AsÔ­×ÓºËÍâÓÐ3¸öδ³É¶Ôµç×Ó£¬

¹Ê´ð°¸Îª£º[Ar]3d104s24p1»ò1s22s22p63s23p63d104s24p1£¬3£»

(2)µçÀëÄÜÊÇÆø̬ԭ×Óʧȥµç×ÓËùÐèÒªµÄÄÜÁ¿£¬ÓÉïصÄÇ°Ëļ¶µçÀëÄÜ¿ÉÖª£¬ÆäÖ÷Òª»¯ºÏ¼ÛΪ+1£¬+3£¬ÓÉÓÚAsµÄ×îÍâ²ãµç×ÓÅŲ¼Îª4s24p3£¬ÊÇ°ëÂúÎȶ¨×´Ì¬£¬¶øGaµÄ×îÍâ²ãµç×ÓÅŲ¼Îª4s24p1ÌرðÊÇ4p1Ò×ʧµç×Ó£¬ËùÒÔAsµÄµç¸ºÐÔ±ÈGa´ó£¬

¹Ê´ð°¸Îª£º+1£¬´ó£»

(3)±íÖÐÊý¾Ý¿ÉÖª£¬ïصı»¯ÎïµÄÈÛµãºÍ·Ðµã¶¼²»¸ß£¬ÇÒ°´ÕÕÂÈ¡¢äå¡¢µâÒÀ´ÎÉý¸ß£¬ÓÉÓÚËüÃÇ×é³ÉÏàͬ£¬½á¹¹ÏàËÆ£¬¶¼ÊÇ·Ö×Ó¾§Ì壬ËùÒÔËæ×ÅÏà¶Ô·Ö×ÓÖÊÁ¿µÄÔö´ó£¬·Ö×Ó¼ä×÷ÓÃÁ¦Ôö´ó£¬¹ÊÈ۷еãÉý¸ß£¬GaF3µÄÈ۵㳬¹ý1000¡æ£¬ÊÇÓÉÓÚFµÄµç¸ºÐԺܴó£¬ÐγɵÄGaF3ÊÇÀë×Ó¾§Ì壬

¹Ê´ð°¸Îª£ºGaCl3¡¢GaBr3¡¢GaI3µÄÈ۷еãÒÀ´ÎÉí¸ß£¬ËüÃǾùΪ·Ö×Ó¾§Ì壬½á¹¹ÏàËÆ£¬Ïà¶Ô·Ö×ÓÖÊÁ¿ÒÀ´ÎÔö´ó£¬·Ö×Ó¼ä×÷ÓÃÁ¦ÒÀ´ÎÔöÇ¿£»GaF3ΪÀë×Ó¾§Ì壻

(4)ÓɶþË®ºÏ²ÝËáïصĽṹͼ¿ÉÖª£¬ïØÔ­×ÓµÄÅäλÊýΪ4£¬²ÝËá¸ùÖÐ̼ԭ×ÓÓëôÈ»ùÖеÄ̼ԭ×ÓµÄÔÓ»¯·½Ê½Ïàͬ£¬ÐγɵĶ¼ÊÇƽÃæ½á¹¹£¬ËùÒÔÓ¦¸ÃÊÇsp2ÔÓ»¯£»

¹Ê´ð°¸Îª£º4£¬sp2£»

(5)ÓÉÓڸþ§ÌåµÄÈÛµã¸ß£¬ÇÒÉéºÍïض¼²»ÊÇ»îÆÃÔªËØ£¬ËùÒԸþ§ÌåÊÇÔ­×Ó¾§Ì壬Æ仯ѧʽΪGa4As4£¬¸Ã¾§ÌåµÄÖÊÁ¿m=g£¬Ìå»ýΪV=£¨565¡Á10-10£©3cm3£¬ÔòÆäÃܶÈΪ£ºg/cm3£¬

¹Ê´ð°¸Îª£ºÔ­×Ó¾§Ì壬g/cm3¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÓлúÎïHÊÇÒ»ÖÖÖØÒªµÄ¸ß·Ö×Ó»¯ºÏÎÆäºÏ³É·ÏßÈçÏ£º

ÒÑÖª£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©AµÄÃû³ÆÊÇ_______________£¬CÖк¬Ñõ¹ÙÄÜÍÅÃû³ÆÊÇ______________¡£

£¨2£©Ð´³ö·´Ó¦ÀàÐÍ£ºA¡úB______________£¬C¡úD__________________¡£

£¨3£©B¡úCµÄ·´Ó¦ÊÔ¼ÁºÍ·´Ó¦Ìõ¼þÊÇ______________________¡£

£¨4£©D+E¡úFµÄ·´Ó¦·½³ÌʽÊÇ_________________¡£

£¨5£©GµÄ·Ö×ÓʽÊÇ____________________¡£

£¨6£©Âú×ãÏÂÁÐÌõ¼þµÄFµÄͬ·ÖÒì¹¹Ìå¹²ÓÐ__________ÖÖ(²»¿¼ÂÇÁ¢ÌåÒì¹¹)¡£

a.±½»·ÉÏÓÐÁ½¸öÈ¡´ú»ù£¬ÎÞÆäËû»·×´½á¹¹£»b.º¬Ì¼Ì¼Èý¼ü£¬ÎÞ-C¡ÔCOH½á¹¹¡£

£¨7£©¶à»·»¯ºÏÎïÊÇÓлúÑо¿µÄÖØÒª·½Ïò£¬ÇëÉè¼ÆÓÉ¡¢.CH3CHO¡¢-CHOºÏ³É¶à»·»¯ºÏÎïµÄ·Ïß(ÎÞ»úÊÔ¼ÁÈÎÑ¡)______________

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿·ÏÄø´ß»¯¼ÁÖÐÖ÷ÒªÓÐNi£¬»¹ÓÐAl¡¢Fe¡¢SiO2¼°ÆäËü²»ÈÜÓÚËá¡¢¼îµÄÔÓÖÊ¡£ÏÖÓ÷ÏÄø´ß»¯¼ÁÖƱ¸NiSO4¡¤7H2O¾§Ì壬ÆäÁ÷³ÌÈçÏÂͼ£º

ÒÑÖª£ºKsp[Fe(OH)3]=8.0¡Á10£­38£¬Ka sp[Fe(OH)2]=8.0¡Á10£­16£¬K[Al(OH)3]=3.2¡Á10£­34£¬Ksp[Ni(OH)2]=2.0¡Á10£­15£¬1g2=0.3£¬

»Ø´ðÏÂÁÐÎÊÌâ

£¨1£©¡°¼î½þ¡±µÄÄ¿µÄÊÇ______¡£

£¨2£©¡°Ëá½þʱ·¢ÉúµÄÀë×Ó·½³ÌʽΪFe+2H+=Fe2++H2¡ü¡¢_______¡£

£¨3£©¡°¾»»¯³ýÔÓÐèÒªÏȼÓÈëH2O2ÈÜÒº£¬·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ______£¬È»ºóµ÷½ÚPH=_______ʱ£¬Ê¹ÔÓÖÊÀë×ÓÇ¡ºÃÍêÈ«³Áµí(×¢£ºÀë×ÓŨ¶ÈСÓÚ»òµÈÓÚ1¡Á10£­5mol/Lʱ³ÁµíÍêÈ«)

£¨4£©¡°²Ù×÷AΪ¡±______¡£

£¨5£©Ni2+ÔÚÇ¿¼îÐÔÈÜÒºÖл¹¿É±»NaClOÑõ»¯ÎªNiOOH£¬¸Ã·´Ó¦Àë×Ó·½³ÌʽΪ______¡£

£¨6£© NiOOHÒ²¿É×÷Ϊԭµç³ØµÄµç¼«²ÄÁÏ£¬ÈôÔÚ¼îÐÔÌõ¼þÏÂÐγÉȼÁϵç³Ø£¬¸º¼«Í¨ÈëN2H4ÆøÌ壬Ôò¸º¼«µÄµç¼«·´Ó¦Ê½Îª______¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿´Ó¹ÅÖÁ½ñ£¬Ìú¼°Æ仯ºÏÎïÔÚÈËÀàÉú²úÉú»îÖеÄ×÷Ó÷¢ÉúÁ˾޴ó¸Ä±ä¡£

(1)¹Å´úÖйúËÄ´ó·¢Ã÷Ö®Ò»µÄÖ¸ÄÏÕëÊÇÓÉÌìÈ»´ÅʯÖƳɵÄ,ÆäÖ÷Òª³É·ÖÊÇ____(Ìî×ÖĸÐòºÅ)¡£

a£®Fe b£®FeO c£®Fe3O4 d£®Fe2O3

(2)ÁòËáÔüµÄÖ÷Òª»¯Ñ§³É·ÖΪ£ºSiO2Ô¼45%£¬Fe2O3Ô¼40%£¬Al2O3Ô¼10%£¬MgOÔ¼5%¡£Óø÷ÏÔüÖÆÈ¡Ò©Óø¨ÁϺìÑõ»¯ÌúµÄ¹¤ÒÕÁ÷³ÌÈçÏÂ(²¿·Ö²Ù×÷ºÍÌõ¼þÂÔ)£º

¢ÙÔÚ²½Öè¢ñÖвúÉúµÄÓж¾ÆøÌå¿ÉÄÜÓÐ_____________________¡£

¢ÚÔÚ²½Öè¢ó²Ù×÷ÖУ¬Òª³ýÈ¥µÄÀë×Ó֮һΪAl3+¡£Èô³£ÎÂʱKsp[Al(OH)3]=1.0¡Á10-32£¬´ËʱÀíÂÛÉϽ«Al3+ ³ÁµíÍêÈ«£¬ÔòÈÜÒºµÄpHΪ_________¡£(c(Al3+)¡Ü1.0¡Á10-5mol/L ÊÓΪAl3+³ÁµíÍêÈ«)

¢Û²½Öè¢ôÖУ¬Éú³ÉFeCO3µÄÀë×Ó·½³ÌʽÊÇ____________________________¡£

(3)ÂÈ»¯ÌúÈÜÒº³ÆΪ»¯Ñ§ÊÔ¼ÁÖеġ°¶àÃæÊÖ¡±¡£ÏòÂÈ»¯Í­ºÍÂÈ»¯ÌúµÄ»ìºÏÈÜÒºÖмÓÈëÑõ»¯Í­·ÛÄ©»á²úÉú³Áµí£¬Ð´³ö¸Ã³ÁµíµÄ»¯Ñ§Ê½______________¡£ÇëÓÃƽºâÒƶ¯µÄÔ­Àí£¬½áºÏ±ØÒªµÄÀë×Ó·½³Ìʽ£¬¶Ô´ËÏÖÏó×÷³ö½âÊÍ£º__________________________________________________________¡£

(4)¢Ù¹ÅÀ϶øÉñÆæµÄÀ¶É«È¾ÁÏÆÕ³ʿÀ¶µÄºÏ³É·½·¨ÈçÏ£º

¸´·Ö½â·´Ó¦¢òµÄÀë×Ó·½³ÌʽÊÇ____________________________________________¡£

¢ÚÈç½ñ»ùÓÚÆÕ³ʿÀ¶ºÏ³ÉÔ­Àí¿É¼ì²âʳƷÖÐÊÇ·ñº¬CN-£¬·½°¸ÈçÏ£º

ÈôÊÔÖ½½»À¶ÔòÖ¤Ã÷ʳƷÖк¬ÓÐCN-£¬Çë½âÊͼì²âʱÊÔÖ½ÖÐFeSO4µÄ×÷Óãº____________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿µâ»¯¼Ø¿ÉÓÃÓÚÓлúºÏ³É¡¢ÖÆÒ©µÈ£¬ËüÊÇÒ»ÖÖ°×É«Á¢·½½á¾§»ò·ÛÄ©£¬Ò×ÈÜÓÚË®¡£ÊµÑéÊÒÖƱ¸KI µÄʵÑé×°ÖÃÈçÏÂ

ʵÑé²½ÖèÈçÏ£º

¢ÙÔÚÉÏͼËùʾµÄCÖмÓÈë 127g ÑÐϸµÄµ¥ÖÊI2 ºÍ 195g 30%µÄ KOH ÈÜÒº£¬¾çÁÒ½Á°è¡£

¢ÚI2ÍêÈ«·´Ó¦ºó£¬´ò¿ªµ¯»É¼ÐÏòÆäÖÐͨÈë×ãÁ¿µÄ H2S¡£

¢Û½«×°Öà C ÖÐËùµÃÈÜÒºÓÃÏ¡ H2SO4Ëữºó£¬ÖÃÓÚˮԡÉϼÓÈÈ 10min¡£

¢ÜÔÚ×°Öà C µÄÈÜÒºÖмÓÈë BaCO3 £¬³ä·Ö½Á°èºó£¬¹ýÂË¡¢Ï´µÓ¡£

¢Ý½«ÂËÒºÓÃÇâµâËáËữ£¬Õô·¢Å¨ËõÖÁ±íÃæ³öÏֽᾧĤ£¬ ¡¢ ¡¢Ï´µÓ¡¢¸ÉÔï¡£

¢ÞµÃ²úÆ· 145g¡£

»Ø´ðÏÂÁÐÎÊÌ⣻

(1)²½Öè¢Ù½«µâÑÐϸµÄÄ¿µÄÊÇ_____________________________________¡£

(2)×°ÖÃA Öз¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ_______________________________ £»×°Öà B ÖеÄÊÔ¼ÁÊÇ____________________£¬C×°ÖõÄÃû³ÆÊÇ_____________¡£

(3)×°Öà C ÖÐI2Óë KOH ·´Ó¦²úÎïÖ®Ò»ÊÇ KIO3 £¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_______________¡£

(4)²½Öè¢ÜµÄÄ¿µÄÊÇ___________________________________ ¡£

(5)²¹³äÍêÕû²½Öè¢Ý __________________¡¢_______________¡£

(6)±¾´ÎʵÑé²úÂÊΪ__________________ (±£ÁôËÄλÓÐЧÊý×Ö)¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÀûÓÃĤ¼¼ÊõÔ­ÀíºÍµç»¯Ñ§Ô­ÀíÖƱ¸ÉÙÁ¿ÁòËáºÍÂÌÉ«Ïõ»¯¼ÁN2O5£¬×°ÖÃÈçͼËùʾ£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨ £©

A. µç¼«b·´Ó¦Ê½ÊÇO2+4e-+2H2O=4OH-

B. µç½âºóÒÒ×°ÖÃdµç¼«¸½½üÈÜÒºµÄpH²»±ä

C. cµç¼«Éϵĵ缫·´Ó¦Ê½ÎªN2O4-2e-+H2O=N2O5+2H+

D. ¼×ÖÐÿÏûºÄ1mol SO2£¬ÒÒ×°ÖÃÖÐÓÐ1mol H+ͨ¹ý¸ôĤ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿£¨11·Ö£©ÒÑÖªX¡¢YºÍZÈýÖÖÔªËصÄÔ­×ÓÐòÊýÖ®ºÍµÈÓÚ42¡£XÔªËØÔ­×ÓµÄ4p¹ìµÀÉÏÓÐ3¸öδ³É¶Ôµç×Ó£¬YÔªËØÔ­×ÓµÄ×îÍâ²ã2p¹ìµÀÉÏÓÐ2¸öδ³É¶Ôµç×Ó¡£X¸úY¿ÉÐγɻ¯ºÏÎïX2Y3£¬ZÔªËØ¿ÉÒÔÐγɸºÒ»¼ÛÀë×Ó¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)XÔªËØÔ­×Ó»ù̬ʱµÄµç×ÓÅŲ¼Ê½Îª________£¬¸ÃÔªËصķûºÅÊÇ________¡£

(2)YÔªËØÔ­×ӵļ۲ãµç×ӵĵç×ÓÅŲ¼Í¼Îª________£¬¸ÃÔªËصÄÃû³ÆÊÇ________¡£

(3)XÓëZ¿ÉÐγɻ¯ºÏÎïXZ3£¬¸Ã»¯ºÏÎïµÄ¿Õ¼ä¹¹ÐÍΪ________¡£

(4)ÒÑÖª»¯ºÏÎïX2Y3ÔÚÏ¡ÁòËáÈÜÒºÖпɱ»½ðÊôп»¹Ô­ÎªXZ3£¬²úÎﻹÓÐZnSO4ºÍH2O£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ___________________________________________________________¡£

(5)±È½ÏXµÄÇ⻯ÎïÓëͬ×åµÚ¶þ¡¢ÈýÖÜÆÚÔªËØËùÐγɵÄÇ⻯ÎïÎȶ¨ÐÔ¡¢·Ðµã¸ßµÍ²¢ËµÃ÷ÀíÓÉ

_________________________________________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿¼ÓÈÈN2O5£¬ÒÀ´Î·¢Éú·Ö½â·´Ó¦£º¢ÙN2O5(g)N2O3(g)£«O2(g)¡¢¢ÚN2O3(g)N2O(g)£«O2(g)¡£ÔÚÌå»ýΪ2 LµÄºãÈÝÃܱÕÈÝÆ÷ÖгäÈë8 mol N2O5£¬¼ÓÈȵ½T ¡æʱ·´Ó¦´ïµ½Æ½ºâ״̬£¬´ËʱO2ºÍN2O3µÄÎïÖʵÄÁ¿·Ö±ðΪ9 mol¡¢3.4 mol£¬ÔòT ¡æʱ·´Ó¦¢ÙµÄƽºâ³£ÊýΪ

A. 10.7 B. 8.5 C. 9.6 D. 10.2

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÏÂÁÐÓйشӺ£´øÖÐÌáÈ¡µâµÄʵÑéÔ­ÀíºÍ×°ÖÃÄܴﵽʵÑéÄ¿µÄµÄÊÇ

A. ÓÃ×°Öü××ÆÉÕË麣´ø

B. ÓÃ×°ÖÃÒÒ¹ýÂ˺£´ø»ÒµÄ½þÅÝÒº

C. ÓÃ×°ÖñûÖƱ¸ÓÃÓÚÑõ»¯½þÅÝÒºÖÐIµÄCl2

D. ÓÃ×°Öö¡ÎüÊÕÑõ»¯½þÅÝÒºÖÐIºóµÄCl2βÆø

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸