Question

17£®»¯Ñ§ÓÃÓïÊÇѧϰ»¯Ñ§µÄ¹¤¾ßºÍ»ù´¡£®ÏÂÁÐÓйػ¯Ñ§ÓÃÓïµÄʹÓÃÕýÈ·µÄÊÇ£¨¡¡¡¡£©

• A£® ±½·ÓÄÆÈÜÒºÓëÉÙÁ¿µÄCO₂·´Ó¦µÄÀë×Ó·½³Ìʽ£ºC₆H₅O^-+CO₂+H₂O¡úC₆H₅OH+HCO₃^-
• B£® ´¿¼îÈÜÒº³Ê¼îÐÔµÄÔ­ÒòÊÇ£ºCO₃^2-+2H₂O?H₂CO₃+2OH^-
• C£® ÓÃʳ´×³ýȥˮºøÄÚµÄË®¹¸£ºCaCO₃+2H⁺¨TCa²⁺+CO₂¡ü+H₂O
• D£® ±íʾÇâÆøȼÉÕÈȵÄÈÈ»¯Ñ§·½³ÌʽΪ£º2H₂£¨g£©+O₂£¨g£©¨T2H₂O£¨g£©£»¡÷H=-571.6  KJ•mol^-1

Answer 1

·ÖÎö A£®±½·ÓµÄËáÐÔ´óÓÚ̼ËáÇâ¸ùÀë×Ó£¬¶þÕß·´Ó¦Éú³É±½·ÓºÍ̼ËáÇâ¸ùÀë×Ó£»
B£®Ì¼Ëá¸ùÀë×ÓµÄË®½â·Ö²½½øÐУ¬Ö÷ÒªÒÔµÚÒ»²½ÎªÖ÷£»
C£®´×ËáΪÈõËᣬÀë×Ó·½³ÌʽÖд×Ëá²»Äܲ𿪣»
D£®ÇâÆøȼÉÕÈȵÄÈÈ»¯Ñ§·½³ÌʽÖУ¬Ë®Ó¦¸ÃΪҺ̬£®

½â´ð ½â£ºA£®±½·ÓÄÆÈÜÒºÓëÉÙÁ¿µÄCO₂·´Ó¦Éú³É±½·ÓºÍ̼ËáÇâÄÆ£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ£ºC₆H₅O^-+CO₂+H₂O¡úC₆H₅OH+HCO₃^-£¬¹ÊAÕýÈ·£»
B£®´¿¼îÈÜÒºÖУ¬Ì¼Ëá¸ùÀë×Ó²¿·ÖË®½âÉú³É̼ËáÇâ¸ùÀë×ÓºÍÇâÑõ¸ùÀë×Ó£¬ÈÜÒº³Ê¼îÐÔ£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ£ºCO₃^2-+H₂O?HCO₃^-+OH^-£¬¹ÊB´íÎó£»
C£®ÓÃʳ´×³ýȥˮºøÄÚµÄË®¹¸£¬´×ËáºÍ̼Ëá¸Æ¶¼²»Äܲ𿪣¬ÕýÈ·µÄÀë×Ó·½³ÌʽΪ£ºCaCO₃+2CH₃COOH=Ca²⁺+H₂O+CO₂¡ü+2CH₃COO^-£¬¹ÊC´íÎó£»
D£®ÇâÆøȼÉÕÈȵÄÈÈ»¯Ñ§·½³ÌʽÖУ¬Ë®Ó¦¸ÃΪҺ̬£¬ÕýÈ·µÄÈÈ»¯Ñ§·½³ÌʽΪ£º2H₂£¨g£©+O₂£¨g£©¨T2H₂O£¨g£©£»¡÷H=-571.6 KJ•mol^-1£¬¹ÊD´íÎó£»
¹ÊÑ¡A£®

µãÆÀ ±¾Ì⿼²éÁËÀë×Ó·½³ÌʽµÄÅжϣ¬ÎªÖеÈÄѶȵÄÊÔÌ⣬עÒâÃ÷È·Àë×Ó·½³ÌʽÕýÎóÅжϳ£Ó÷½·¨£º¼ì²é·´Ó¦Îï¡¢Éú³ÉÎïÊÇ·ñÕýÈ·£¬¼ì²é¸÷ÎïÖʲð·ÖÊÇ·ñÕýÈ·£¬ÈçÄÑÈÜÎï¡¢Èõµç½âÖʵÈÐèÒª±£Áô»¯Ñ§Ê½£¬¼ì²éÊÇ·ñ·ûºÏÔ­»¯Ñ§·½³ÌʽµÈ£®