ÈçͼÊÇ´«Í³µÄ¹¤ÒµÉú²ú½ðÊôÂÁµÄ»ù±¾Á÷³Ìͼ¡£

Çë»Ø´ð£º
£¨1£©½ðÊôÂÁ³£ÓÃÀ´ÖÆÔìÈÝÆ÷£¬µ«ÂÁÖƲ;߲»ÒËÓÃÀ´ÕôÖó»ò³¤Ê±¼ä´æ·ÅËáÐÔ¡¢¼îÐÔµÈʳÎд³öÂÁÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ£º_____________________________________¡£
ʯÓÍÁ¶ÖƺÍúµÄ¸ÉÁó²úÆ·________(ÌîÎïÖÊÃû³Æ)×÷µç½âÂÁµÄÒõ¼«ºÍÑô¼«²ÄÁÏ¡£
£¨2£©ÔÚÒ±Á¶¹ý³ÌÖУ¬Ñô¼«²ÄÁÏÐèÒª¶¨ÆÚ½øÐиü»»£¬Ô­ÒòÊǸü«²ÄÁϲ»¶Ï±»ÏûºÄ£¬²úÉúÕâÖÖÏÖÏóµÄÔ­ÒòÊÇ____________________________________(Óû¯Ñ§·½³Ìʽ±íʾ)¡£
£¨3£©¹¤ÒµÉÏͨ¹ýµç½âÈÛÈÚµÄMgCl2ÖÆÈ¡½ðÊôþ£¬µç½â·´Ó¦·½³ÌʽΪ________________¡£Ã¾ºÍÂÁ¶¼ÊÇ»îÆýðÊô£¬ÎªÊ²Ã´ÔÚµç½âÒ±Á¶¹ý³ÌÖУ¬Ò»¸öÓÃÂÈ»¯Îһ¸öÓÃÑõ»¯ÎÇë˵Ã÷ÀíÓÉ¡£________________________________________________¡£
£¨1£©2Al£«2OH£­£«2H2O=2AlO2-£«3H2¡ü¡¡Ê¯Ä«(»ò̼)
£¨2£©2C£«O22CO
£¨3£©MgCl2(ÈÛÈÚ)Mg£«Cl2¡ü¡¡MgOµÄÈܵãÌ«¸ß£¬¶øMgCl2µÄÈÛµã½ÏµÍ£¬ÈÛ»¯Ê±MgCl2ÄÜ·¢ÉúµçÀë¶øµ¼µç£»AlCl3Êǹ²¼Û»¯ºÏÎÈÛ»¯Ê±²»ÄÜ·¢ÉúµçÀë
£¨1£©AlÓëÇ¿¼îÈÜÒº×÷Óõõ½Æ«ÂÁËáÑÎÓëÇâÆø£¬¹Ê·´Ó¦µÄÀë×Ó·½³ÌʽΪ2Al£«2OH£­£«2H2O=2AlO2-£«3H2¡ü¡£
£¨2£©µç½â¹ý³ÌÖÐÑô¼«²úÉúÑõÆø£¬ÔÚ¸ßÎÂÏÂÑõÆøÓëµç¼«²ÄÁÏ(ʯī)·´Ó¦Éú³ÉCO¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

3 gþÂÁºÏ½ðÓë100 mLÏ¡ÁòËáÇ¡ºÃÍêÈ«·´Ó¦£¬½«·´Ó¦ºóµÄÈÜÒº¼ÓÈÈÕô¸É£¬µÃµ½ÎÞË®ÁòËáÑÎ17.4 g£¬ÔòÔ­ÁòËáµÄÎïÖʵÄÁ¿Å¨¶ÈΪ  (¡¡¡¡)¡£
A£®1 mol¡¤L£­1B£®1.5 mol¡¤L£­1
C£®2 mol¡¤L£­1D£®2.5 mol¡¤L£­1

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

½«Ò»¿éÂÁ¹èºÏ½ðÇ¡ºÃÓëNaOHÈÜÒºÍêÈ«·´Ó¦¶øÈܽ⡣
(1)д³öºÏ½ðÈܽâµÄÀë×Ó·½³Ìʽ______________________________________________¡£
(2)ÏòËùµÃµÄÈÜÒºÖмÓÈë×ãÁ¿µÄÑÎËᣬ³ä·Ö·´Ó¦ºó£¬ÈÜÒºÖдóÁ¿´æÔÚµÄÀë×ÓΪ_______¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

Ã÷·¯Ê¯¾­´¦ÀíºóµÃµ½Ã÷·¯[KAl£¨SO4£©2¡¤12H2O]¡£´ÓÃ÷·¯ÖƱ¸Al¡¢K2SO4ºÍH2SO4µÄ¹¤ÒÕ¹ý³ÌÈçÏÂËùʾ£º
±ºÉÕÃ÷·¯µÄ»¯Ñ§·½³ÌʽΪ£º4KAl£¨SO4£©2¡¤12H2O£«3S=2K2SO4£«2Al2O3£«9SO2¡ü£«48H2O
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÔÚ±ºÉÕÃ÷·¯µÄ·´Ó¦ÖУ¬»¹Ô­¼ÁÊÇ________¡£
£¨2£©´ÓË®½þºóµÄÂËÒºÖеõ½K2SO4¾§ÌåµÄ·½·¨ÊÇ________¡£

£¨3£©Al2O3ÔÚÒ»¶¨Ìõ¼þÏ¿ÉÖƵÃAlN£¬Æ侧Ìå½á¹¹ÈçÓÒͼËùʾ£¬¸Ã¾§ÌåÖÐAlµÄÅäλÊýÊÇ________¡£
£¨4£©ÒÔAlºÍNiO£¨OH£©Îªµç¼«£¬NaOHÈÜҺΪµç½âÒº×é³ÉÒ»ÖÖÐÂÐ͵ç³Ø£¬·ÅµçʱNiO£¨OH£©×ª»¯ÎªNi£¨OH£©2£¬¸Ãµç³Ø·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ________¡£
£¨5£©±ºÉÕ²úÉúµÄSO2¿ÉÓÃÓÚÖÆÁòËá¡£ÒÑÖª25¡æ¡¢101 kPaʱ£º
2SO2£¨g£©£«O2£¨g£©2SO3£¨g£©¡¡¦¤H1£½£­197 kJ/mol£»
H2O£¨g£©=H2O£¨l£©¡¡¦¤H2£½£­44 kJ/mol£»
2SO2£¨g£©£«O2£¨g£©£«2H2O£¨g£©=2H2SO4£¨l£©¡¡¦¤H3£½£­545 kJ/mol¡£
ÔòSO3£¨g£©ÓëH2O£¨l£©·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÊÇ________¡£±ºÉÕ948 tÃ÷·¯£¨M£½474 g/mol£©£¬ÈôSO2µÄÀûÓÃÂÊΪ96%£¬¿ÉÉú²úÖÊÁ¿·ÖÊýΪ98%µÄÁòËá________t¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

A¡¢B¡¢C¡¢D¡¢EÊÇÖÐѧ½×¶Î³£¼ûµÄ5ÖÖ»¯ºÏÎA¡¢BÊÇÑõ»¯ÎԪËØX¡¢YµÄµ¥ÖÊÊÇÉú»îÖг£¼ûµÄ½ðÊô£¬Ïà¹ØÎïÖʼäµÄת»¯¹ØϵÈçͼËùʾ£º

(1)XµÄµ¥ÖÊÓëA·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ_______________________________¡£
(2)ÈôÊÔ¼Á1ÊÇNaOHÈÜÒº£¬ÔòXµÄµ¥ÖÊÓëÊÔ¼Á1·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ
___________________________________
(3)ÈôÊÔ¼Á1ºÍÊÔ¼Á2¾ùÊÇÏ¡ÁòËá¡£
¢Ù¼ìÑéÎïÖÊDµÄÈÜÒºÖнðÊôÀë×ӵķ½·¨ÊÇ___________________________________¡£
¢Ú½«ÎïÖÊCÈÜÓÚË®£¬ÆäÈÜÒº³ÊËáÐÔ£¬Ô­ÒòÊÇ(ÓÃÀë×Ó·½³Ìʽ±íʾ)
________________________________________________¡£
¢Ûij¸ßЧ¾»Ë®¼ÁÊÇÓÉY(OH)SO4¾ÛºÏµÃµ½µÄ£¬¹¤ÒµÉÏÒÔE¡¢Ï¡ÁòËáºÍÑÇÏõËáÄÆΪԭÁÏÖƱ¸Y(OH)SO4£¬·´Ó¦ÖÐÓÐNOÉú³É£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ_____________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

¶þ¼×ÃÑ(CH3OCH3)ÊÇÎÞÉ«ÆøÌ壬¿É×÷ΪһÖÖÐÂÐÍÄÜÔ´¡£ÓɺϳÉÆø(×é³ÉΪH2¡¢COºÍÉÙÁ¿µÄCO2)Ö±½ÓÖƱ¸¶þ¼×ÃÑ£¬ÆäÖеÄÖ÷Òª¹ý³Ì°üÀ¨ÒÔÏÂËĸö·´Ó¦£º
¼×´¼ºÏ³É·´Ó¦£º
(¢¡)CO(g)£«2H2(g)=CH3OH(g)    ¦¤H1£½£­90.1 kJ¡¤mol£­1
(¢¢)CO2(g)£«3H2(g)=CH3OH(g)£«H2O(g)    ¦¤H2£½£­49.0 kJ¡¤mol£­1
ˮúÆø±ä»»·´Ó¦£º
(¢£)CO(g)£«H2O(g)=CO2(g)£«H2(g)   ¦¤H3£½£­41.1 kJ¡¤mol£­1
¶þ¼×ÃѺϳɷ´Ó¦£º
(¢¤)2CH3OH(g)=CH3OCH3(g)£«H2O(g)    ¦¤H4£½£­24.5 kJ¡¤mol£­1
»Ø´ðÏÂÁÐÎÊÌ⣺
(1)Al2O3ÊǺϳÉÆøÖ±½ÓÖƱ¸¶þ¼×ÃÑ·´Ó¦´ß»¯¼ÁµÄÖ÷Òª³É·ÖÖ®Ò»¡£¹¤ÒµÉÏ´ÓÂÁÍÁ¿óÖƱ¸½Ï¸ß´¿¶ÈAl2O3µÄÖ÷Òª¹¤ÒÕÁ÷³ÌÊÇ____________________________________________(ÒÔ»¯Ñ§·½³Ìʽ±íʾ)¡£
(2)·ÖÎö¶þ¼×ÃѺϳɷ´Ó¦(¢¤)¶ÔÓÚCOת»¯ÂʵÄÓ°Ïì
________________________________________________________________________¡£
(3)ÓÐÑо¿ÕßÔÚ´ß»¯¼Á(º¬Cu­Zn­Al­OºÍAl2O3)¡¢Ñ¹Ç¿Îª5.0 MPaµÄÌõ¼þÏ£¬ÓÉH2ºÍCOÖ±½ÓÖƱ¸¶þ¼×ÃÑ£¬½á¹ûÈçͼËùʾ¡£ÆäÖÐCOת»¯ÂÊËæζÈÉý¸ß¶ø½µµÍµÄÔ­ÒòÊÇ_________________________________________________¡£

(4)¶þ¼×ÃÑÖ±½ÓȼÁϵç³Ø¾ßÓÐÆô¶¯¿ì¡¢Ð§ÂʸߵÈÓŵ㣬ÆäÄÜÁ¿ÃܶȸßÓÚ¼×´¼Ö±½ÓȼÁϵç³Ø(5.93 kW¡¤h¡¤kg£­1)¡£Èôµç½âÖÊΪËáÐÔ£¬¶þ¼×ÃÑÖ±½ÓȼÁϵç³ØµÄ¸º¼«·´Ó¦Îª__________
_____________________£¬Ò»¸ö¶þ¼×ÃÑ·Ö×Ó¾­¹ýµç»¯Ñ§Ñõ»¯£¬¿ÉÒÔ²úÉú________________¸öµç×ӵĵçÁ¿£»¸Ãµç³ØµÄÀíÂÛÊä³öµçѹΪ1.20 V£¬ÄÜÁ¿ÃܶÈE£½_______________(ÁÐʽ¼ÆËã¡£ÄÜÁ¿Ãܶȣ½µç³ØÊä³öµçÄÜ/ȼÁÏÖÊÁ¿£¬1 kW¡¤h£½3.6¡Á106 J)¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

ÓÉÂÁÍÁ¿ó£¨Ö÷Òª³É·ÖÊÇAl2O3£©Á¶ÖÆÂÁµÄ¹¤ÒÕÁ÷³ÌʾÒâͼÈçÏ£º

£¨1£©µç½âÉú³ÉµÄÂÁÔÚÈÛÈÚÒºµÄ       £¨Ìî¡°Éϲ㡱»ò¡°Ï²㡱£©£¬µç½âʱ²»¶ÏÏûºÄµÄµç¼«ÊÇ       £¨Ìî¡°Òõ¼«¡±»ò¡°Ñô¼«¡±£©¡£
£¨2£©Ð´³öͨÈë¹ýÁ¿¶þÑõ»¯Ì¼Ëữʱ·´Ó¦µÄÀë×Ó·½³Ìʽ                                                                       
                                                                       ¡£
£¨3£©µç½âÖƱ¸ÂÁʱ£¬Ðè¼ÓÈë±ù¾§Ê¯£¨Na3AlF6£©£¬Æä×÷ÓÃÊÇ           £¬¹¤ÒµÉÏ¿ÉÒÔÓ÷ú»¯ÇâÆøÌå¡¢ÇâÑõ»¯ÂÁºÍ´¿¼îÔÚ¸ßÎÂÌõ¼þÏ·¢Éú·´Ó¦À´ÖÆÈ¡±ù¾§Ê¯£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ                                                                       ¡£
£¨4£©ÉÏÊö¹¤ÒÕËùµÃÂÁÖÐÍùÍùº¬ÓÐÉÙÁ¿FeºÍSiµÈÔÓÖÊ£¬¿ÉÓõç½â·½·¨½øÒ»²½Ìá´¿£¬¸Ãµç½â³ØµÄÒõ¼«²ÄÁÏÊÇ       £¨Ìѧʽ£©£¬Ñô¼«µÄµç¼«·´Ó¦Ê½Îª                                                                       ¡£
£¨5£©¶Ô½ðÊôÖÆÆ·½øÐп¹¸¯Ê´´¦Àí£¬¿ÉÑÓ³¤ÆäʹÓÃÊÙÃü¡£
¢Ù¿ØÖÆÒ»¶¨Ìõ¼þ½øÐеç½â£¨¼ûͼ£©£¬´ËʱÂÁ±íÃæ¿ÉÐγÉÄÍËáµÄÖÂÃÜÑõ»¯Ä¤£¬Æäµç¼«·´Ó¦Ê½Îª                                 £»

¢Ú¸Ö²Ä¶ÆÂÁºó£¬ÄÜ·ÀÖ¹¸Ö²Ä¸¯Ê´£¬ÆäÔ­ÒòÊÇ                                                                                                                                               ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÎïÖʵÄÁ¿Îª0£®10 molµÄþÌõÔÚÖ»º¬ÓÐCO2ºÍO2»ìºÏÆøÌåµÄÈÝÆ÷ÖÐȼÉÕ£¨²úÎï²»º¬Ì¼Ëáþ£©£¬·´Ó¦ºóÈÝÆ÷ÄÚ¹ÌÌåÎïÖʵÄÖÊÁ¿¿ÉÄÜΪ£¨  £©
A£®3£®2 gB£®4£®0 gC£®4£®2 gD£®4£®6 g

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

ij»¯Ñ§ÐËȤС×éÀûÓ÷ÏÆúÂÁ¿ó£¨º¬CuO¡¢Al2O3¼°SiO2£©£¬Ä£Ä⹤ҵÉÏÌáÈ¡ÂÁµÄ¹¤ÒÕ£¬Éè¼ÆÈçÏÂͼËùʾµÄ¼òµ¥²Ù×÷Á÷³Ì£º

ÒÑÖª£º²¿·ÖÑôÀë×ÓÒÔÇâÑõ»¯ÎïÐÎʽ³ÁµíʱÈÜÒºµÄpH¼ûÏÂ±í£º
³ÁµíÎï



¿ªÊ¼³Áµí
2.3
7.5
3.4
ÍêÈ«³Áµí
3.2
9.7
4.4
 
»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÂËÔüÖ÷Òª³É·ÖµÄ»¯Ñ§Ê½Îª______________________¡£
£¨2£©×ÆÉÕʱ£¬Óõ½¶àÖÖ¹èËáÑÎÖʵÄÒÇÆ÷£¬³ý²£Á§°ô¡¢¾Æ¾«µÆ¡¢ÄàÈý½ÇÍ⣬»¹ÓÐ___________£¨ÌîÒÇÆ÷Ãû³Æ£©¡£
£¨3£©ÈÜÒºYÖÐÒª¼ÓÈëÉÔ¹ýÁ¿Ô­ÁÏA£¬Ô­ÁÏAµÄ»¯Ñ§Ê½ÊÇ_________£¬²½Öè¢Ý·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ_______________________¡£
£¨4£©²Ù×÷Á÷³ÌÖТ۵ÄÀë×Ó·½³ÌʽΪ_______________________¡£
£¨5£©ÂÁµç³ØÐÔÄÜÓÅÔ½£¬Al¡ªAg2Oµç³Ø¿ÉÓÃ×÷ˮ϶¯Á¦µçÔ´£¬ÆäÔ­ÀíÈçͼËùʾ£º

Çëд³ö¸Ãµç³ØÕý¼«·´Ó¦Ê½_________________£»³£ÎÂÏ£¬Óøû¯Ñ§µçÔ´ºÍ¶èÐԵ缫µç½â300mLÂÈ»¯ÄÆÈÜÒº£¨¹ýÁ¿£©£¬ÏûºÄ27mg Al£¬Ôòµç½âºóÈÜÒºµÄpH£½_________£¨²»¿¼ÂÇÈÜÒºÌå»ýµÄ±ä»¯£©¡£
£¨6£©ÒÔÈÛÈÚÑÎΪµç¶ÆÒº¿ÉÒÔÔڸֲıíÃæ¶ÆÂÁ£¬¶ÆÂÁµç½â³ØÖУ¬¸Ö²ÄΪ________¼«£»¶ÆÂÁºóÄÜ·ÀÖ¹¸Ö²Ä¸¯Ê´£¬ÆäÔ­ÒòÊÇ____________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸