»·¾³±£»¤ÊÇÄ¿Ç°ÈËÀàÃæÁÙµÄÒ»ÏîÖØ´ó¿ÎÌ⣮ΪӦ¶ÔȼÁÏʹÓÃÔì³ÉµÄ»·¾³ÎÛȾ£¬¿Æѧ¼Ò¹¹ÏëÁËÀûÓÃÌ«ÑôÄÜ´Ù½øȼÁϵÄÑ»·Ê¹Óã¬Æä¹¹Ïë¿ÉÓÃÈçͼ±íʾ£º
ÆäÖÐÖ÷ÒªµÄ·´Ó¦Îª£º
¢Ù2CO
22CO+O
2¢Ú2H
2O
2H
2+O
2¢Û2N
2+6H
2O
4NH
3+3O
2¢Ü2CO
2+4H
2O
2CH
3OH+3O
2¢Ý
+H
2O
CH
4+
£®
ÇëÄãÌî¿Õ£º
£¨1£©ÇëÄ㽫·´Ó¦¢Ý²¹³äÍêÕû£º
+H
2O
CH
4+
£¨2£©¹ý³Ì¢òÖеġ÷H
0£¨Ìî¡°£¼¡±¡¢¡°£¾¡±»ò¡°=¡±£©£®
£¨3£©ÏÂÁжԹý³Ì¢ñºÍ¢òµÄÃèÊöÖÐÕýÈ·µÄÊÇ
£®
a£®Ì«ÑôÄÜ×îÖÕת»¯Îª»¯Ñ§ÄÜÖü´æÓÚ»¯Ñ§ÎïÖÊÖÐ
b£®Ì«ÑôÄÜ×îÖÕÖ÷Ҫת»¯ÎªÈÈÄÜ
c£®¾¹ýÉÏÊöÒ»¸öÑ»·ºó·Å³öO
2d£®¾¹ýÉÏÊöÒ»¸öÑ»·ºó²»»á²úÉúÐÂÎïÖÊ
£¨4£©ÒªÊµÏÖÉÏÊöÑ»·£¬µ±Ç°ÐèÒª½â¾öµÄ¹Ø¼üÎÊÌâÊǹý³Ì
£¨Ìî¡°¢ñ¡±»ò¡°¢ò¡±£©£¬´Ë¹ý³ÌµÄÉè¼Æ¿É²Î¿¼×ÔÈ»½çÖÐ
×÷Óã®
£¨5£©ÓÃCH
4´ß»¯»¹ÔNOx¿ÉÒÔÏû³ýµªÑõ»¯ÎïµÄÎÛȾ£®ÀýÈ磺
CH
4£¨g£©+4NO
2£¨g£©¨T4NO£¨g£©+CO
2£¨g£©+2H
2O£¨g£©¡÷H=-574kJ?mol
-1CH
4£¨g£©+4NO£¨g£©¨T2N
2£¨g£©+CO
2£¨g£©+2H
2O£¨g£©¡÷H=-1160kJ?mol
-1ÈôÓñê×¼×´¿öÏÂ4.48L CH
4»¹ÔNO
2ÖÁN
2£¬Õû¸ö¹ý³ÌÖÐתÒƵç×ÓµÄÎïÖʵÄÁ¿Îª
£¬ÊÔд³öÉÏÊöNO
2ת»¯ÎªN
2µÄÈÈ»¯Ñ§·½³Ìʽ£º
£®