ÏÂÁÐÍÆÂÛÕýÈ·µÄÊÇ(¡¡¡¡)
A£®S(g)£«O2(g)===SO2(g)¡¡¦¤H1£»S(s)£«O2===SO2(g)¡¡¦¤H2£¬Ôò¦¤H1£¾¦¤H2
B£®C(ʯī£¬s)===C(½ð¸Õʯ£¬s)¡¡¦¤H£½£«1.9 kJ·mol£1£¬ÔòÓÉʯīÖÆÈ¡½ð¸ÕʯµÄ·´Ó¦ÊÇÎüÈÈ·´Ó¦£¬½ð¸Õʯ±ÈʯīÎȶ¨
C£®NaOH(aq)£«HCl(aq)===NaCl(aq)£«H2O(l)¡¡¦¤H£½£57.4 kJ·mol£1£¬Ôò£ºº¬20 g NaOHµÄÏ¡ÈÜÒºÓëÏ¡ÑÎËáÍêÈ«·´Ó¦£¬·Å³öµÄÈÈÁ¿Îª28.7 kJ
D£®2C(s)£«O2(g)===2CO(g)¡¡¦¤H£½£221 kJ·mol£1£¬Ôò̼µÄȼÉÕÈȵÈÓÚ110.5 kJ·mol£1
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÈçͼËùʾµÄ¸ÖÌú¸¯Ê´ÖУ¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ(¡¡¡¡)
¡¡
A£®Ì¼±íÃæ·¢ÉúÑõ»¯·´Ó¦
B£®¸ÖÌú±»¸¯Ê´µÄ×îÖÕ²úÎïΪFeO
C£®Éú»îÖиÖÌúÖÆÆ·µÄ¸¯Ê´ÒÔͼ¢ÚËùʾΪÖ÷
D£®Í¼¢ÚÖУ¬Õý¼«·´Ó¦Ê½ÎªO2£«4e££«2H2O===4OH£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÔõÑùÓû·Ðβ£Á§½Á°è°ô½Á°èÈÜÒº£¬²»ÄÜÓÃÍË¿½Á°è°ô´úÌæµÄÀíÓÉÊÇʲô£¿
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÇâÆøÊÇÒ»ÖÖÇå½àÄÜÔ´£¬ÇâÆøµÄÖÆÈ¡Óë´¢´æÊÇÇâÄÜÔ´ÀûÓÃÁìÓòµÄÑо¿Èȵ㡣
ÒÑÖª£ºCH4(g)£«H2O(g)===CO(g)£«3H2(g)
¦¤H£½206.2 kJ·mol£1
CH4(g)£«CO2(g)===2CO(g)£«2H2(g)
¦¤H£½247.4 kJ·mol£1
2H2S(g)===2H2(g)£«S2(g)
¦¤H£½169.8 kJ·mol£1
(1)ÒÔ¼×ÍéΪÔÁÏÖÆÈ¡ÇâÆøÊǹ¤ÒµÉϳ£ÓõÄÖÆÇâ·½·¨¡£
CH4(g)ÓëH2O(g)·´Ó¦Éú³ÉCO2(g)ºÍH2(g)µÄÈÈ»¯Ñ§·½³ÌʽΪ________________________________________________________________________¡£
(2)H2SÈÈ·Ö½âÖÆÇâʱ£¬³£Ïò·´Ó¦Æ÷ÖÐͨÈëÒ»¶¨±ÈÀý¿ÕÆø£¬Ê¹²¿·ÖH2SȼÉÕ£¬ÆäÄ¿µÄÊÇ____________________________£»È¼ÉÕÉú³ÉµÄSO2ÓëH2S½øÒ»²½·´Ó¦£¬Éú³ÉÎïÔÚ³£ÎÂϾù·ÇÆøÌ壬д³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º_____________________________________________¡£
(3)H2OµÄÈÈ·Ö½âÒ²¿ÉµÃµ½H2£¬¸ßÎÂÏÂË®·Ö½âÌåϵÖÐÖ÷ÒªÆøÌåµÄÌå»ý·ÖÊýÓëζȵĹØϵÈçÏÂͼËùʾ¡£Í¼ÖÐA¡¢B±íʾµÄÎïÖÊÒÀ´ÎÊÇ________________________¡£
(5)Mg2CuÊÇÒ»ÖÖ´¢ÇâºÏ½ð¡£350 ¡æʱ£¬Mg2CuÓëH2·´Ó¦£¬Éú³ÉMgCu2ºÍ½öº¬Ò»ÖÖ½ðÊôÔªËصÄÇ⻯Îï(ÆäÖÐÇâµÄÖÊÁ¿·ÖÊýΪ0.077)¡£Mg2CuÓëH2·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ________________________________________________________________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÒÒ´¼ÊÇÖØÒªµÄÓлú»¯¹¤ÔÁÏ£¬¿ÉÓÉÒÒÏ©ÆøÏàÖ±½ÓË®ºÏ·¨»ò¼ä½ÓË®ºÏ·¨Éú²ú¡£»Ø´ðÏÂÁÐÎÊÌ⣺
(1)¼ä½ÓË®ºÏ·¨ÊÇÖ¸ÏȽ«ÒÒÏ©ÓëŨÁòËá·´Ó¦Éú³ÉÁòËáÇâÒÒõ¥(C2H5OSO3H)£¬ÔÙË®½âÉú³ÉÒÒ´¼¡£Ð´³öÏàÓ¦·´Ó¦µÄ»¯Ñ§·½³Ìʽ_____________________________________________
________________________________________________________________________¡£
(2)ÒÑÖª£º
¼×´¼ÍÑË®·´Ó¦2CH3OH(g)===CH3OCH3(g)£«H2O(g)
¦¤H1£½£23.9 kJ·mol£1
¼×´¼ÖÆÏ©Ìþ·´Ó¦2CH3OH(g)===C2H4(g)£«2H2O(g)
¦¤H2£½£29.1 kJ·mol£1
ÒÒ´¼Òì¹¹»¯·´Ó¦C2H5OH(g)===CH3OCH3(g)
¦¤H3£½£«50.7 kJ·mol£1
ÔòÒÒÏ©ÆøÏàÖ±½ÓË®ºÏ·´Ó¦C2H4(g)£«H2O(g)===C2H5OH(g)µÄ¦¤H£½______________ kJ·mol£1¡£
Óë¼ä½ÓË®ºÏ·¨Ïà±È£¬ÆøÏàÖ±½ÓË®ºÏ·¨µÄÓŵãÊÇ_____________________________________
________________________________________________________________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ(¡¡¡¡)
A£®ÈκÎËáÓë¼î·¢ÉúÖкͷ´Ó¦Éú³É1 mol H2OµÄ¹ý³ÌÖУ¬ÄÜÁ¿±ä»¯¾ùÏàͬ
B£®Í¬ÎÂͬѹÏ£¬H2(g)£«Cl2(g)===2HCl(g)ÔÚ¹âÕպ͵ãȼÌõ¼þϵĦ¤HÏàͬ
C£®ÒÑÖª£º¢Ù2H2(g)£«O2(g)===2H2O(g)¡¡¦¤H1£½£a kJ·mol£1£¬¢Ú2H2(g)£«O2(g)===2H2O(l)
¦¤H2£½£b kJ·mol£1£¬Ôòa>b
D£®ÒÑÖª£º¢ÙC(ʯī£¬s)£«O2(g)===CO2(g)¡¡¦¤H1£½£393.5 kJ·mol£1£¬¢ÚC(½ð¸Õʯ£¬s)£«O2(g)===
CO2(g)¡¡¦¤H2£½£395.0 kJ·mol£1£¬Ôò½ð¸Õʯ±ÈʯīÎȶ¨
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
25 ¡æʱ£¬ÏàͬÎïÖʵÄÁ¿Å¨¶ÈµÄÏÂÁÐÈÜÒº£º¢ÙNaCl¡¡¢ÚNaOH¡¡¢ÛH2SO4¡¡¢Ü(NH4)2SO4£¬ÆäÖÐË®µÄµçÀë³Ì¶È°´ÓÉ´óµ½Ð¡Ë³ÐòÅÅÁеÄÒ»×éÊÇ(¡¡¡¡)
A£®¢Ü>¢Û>¢Ú>¢Ù B£®¢Ú>¢Û>¢Ù>¢Ü
C£®¢Ü>¢Ù>¢Ú>¢Û D£®¢Û>¢Ú>¢Ù>¢Ü
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ijѧÉúÓÃÒÑÖªÎïÖʵÄÁ¿Å¨¶ÈµÄÑÎËáÀ´²â¶¨Î´ÖªÎïÖʵÄÁ¿Å¨¶ÈµÄNaOHÈÜҺʱ£¬Ñ¡Ôñ¼×»ù³È×÷ָʾ¼Á¡£ÇëÌîдÏÂÁпհףº
(1)Óñê×¼µÄÑÎËáµÎ¶¨´ý²âµÄNaOHÈÜҺʱ£¬×óÊÖÎÕËáʽµÎ¶¨¹ÜµÄ»îÈû£¬ÓÒÊÖÒ¡¶¯×¶ÐÎÆ¿£¬ÑÛ¾¦×¢ÊÓ________£¬Ö±µ½Òò¼ÓÈëÒ»µÎÑÎËáºó£¬ÈÜÒºÓÉ»ÆÉ«±äΪ³ÈÉ«£¬²¢______Ϊֹ¡£
(2)ÏÂÁвÙ×÷ÖпÉÄÜʹËù²âNaOHÈÜÒºµÄŨ¶ÈÊýֵƫµÍµÄÊÇ________(Ìî×ÖĸÐòºÅ)¡£
A£®ËáʽµÎ¶¨¹ÜδÓñê×¼ÑÎËáÈóÏ´¾ÍÖ±½Ó×¢Èë±ê×¼ÑÎËá
B£®µÎ¶¨Ç°Ê¢·ÅNaOHÈÜÒºµÄ׶ÐÎÆ¿ÓÃÕôÁóˮϴ¾»ºóûÓиÉÔï
C£®ËáʽµÎ¶¨¹ÜÔڵζ¨Ç°ÓÐÆøÅÝ£¬µÎ¶¨ºóÆøÅÝÏûʧ
D£®¶ÁÈ¡ÑÎËáÌå»ýʱ£¬¿ªÊ¼ÑöÊÓ¶ÁÊý£¬µÎ¶¨½áÊøʱ¸©ÊÓ¶ÁÊý
(3)ÈôµÎ¶¨¿ªÊ¼ºÍ½áÊøʱ£¬ËáʽµÎ¶¨¹ÜÖеÄÒºÃæÈçͼËùʾ£¬ÔòÆðʼ¶ÁÊýΪ________mL£¬ÖÕµã¶ÁÊýΪ________mL£¬
ËùÓÃÑÎËáÈÜÒºµÄÌå»ýΪ________mL¡£
(4)ijѧÉú¸ù¾Ý3´ÎʵÑé·Ö±ð¼Ç¼ÓйØÊý¾ÝÈçÏÂ±í£º
µÎ¶¨´ÎÊý | ´ý²âNaOHÈÜÒºµÄÌå»ý/mL | 0.100 0 mol·L£1ÑÎËáµÄÌå»ý/mL | ||
µÎ¶¨Ç°¿Ì¶È | µÎ¶¨ºó¿Ì¶È | ÈÜÒºÌå»ý/mL | ||
µÚÒ»´Î | 25.00 | 0.00 | 26.11 | 26.11 |
µÚ¶þ´Î | 25.00 | 1.56 | 30.30 | 28.74 |
µÚÈý´Î | 25.00 | 0.22 | 26.31 | 26.09 |
ÒÀ¾ÝÉϱíÊý¾ÝÁÐʽ¼ÆËã¸ÃNaOHÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶È¡£
´ð°¸¡¡(1)׶ÐÎÆ¿ÖÐÈÜÒºÑÕÉ«±ä»¯¡¡ÔÚ°ë·ÖÖÓÄÚ²»±äÉ«
(2)D¡¡(3)0.00¡¡26.10¡¡26.10
(4)£½£½26.10 mL£¬c(NaOH)£½£½0.104 4 mol·L£1
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
Cu£«»ù̬ºËÍâµç×ÓÅŲ¼Ê½Îª
________________________________________________________________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com