¡¾ÌâÄ¿¡¿COºÍH2¿É×÷ΪÄÜÔ´ºÍ»¯¹¤ÔÁÏ£¬Ó¦ÓÃÊ®·Ö¹ã·º¡£¹¤ÒµÉÏ¿ÉÀûÓÃCO»òCO2ÓëH2·´Ó¦À´ÖƱ¸¼×´¼¡£
·´Ó¦¢Ù£º2H2(g)+CO(g)CH3OH(g)¡÷H£½£90.8kJ¡¤mol-1
·´Ó¦¢Ú£ºH2(g)+CO2(g)H2O(g)+CO(g)¡÷H£½+41.2kJ¡¤mol-1
£¨1£©Ð´³öÓÃCO2ÓëH2·´Ó¦ÖƱ¸¼×´¼µÄÈÈ»¯Ñ§·½³Ìʽ______________¡£
£¨2£©ÒÑÖªµÈÌå»ýµÄÒ»Ñõ»¯Ì¼ºÍË®ÕôÆø½øÈë·´Ó¦Æ÷ʱ£¬»á·¢ÉúÈçÏ·´Ó¦£ºCO(g)+H2O(g)H2(g)+CO2(g)£¬¸Ã·´Ó¦Æ½ºâ³£ÊýËæζȵı仯Èç±íËùʾ£º
ζÈ/¡æ | 400 | 500 | 800 |
ƽºâ³£ÊýK | 9.94 | 9 | 1 |
Éý¸ßζȣ¬¸ÃƽºâµÄÒƶ¯·½ÏòÊÇ______________£¨Ìî¡°ÕýÏò¡±»ò¡°ÄæÏò¡±£©¡£500¡æʱ£¬COºÍH2OµÄÆðʼŨ¶È¾ùΪ0.020mol¡¤L-1£¬¸ÃÌõ¼þÏÂCOµÄƽºâŨ¶ÈΪ£º______________mol¡¤L-1¡£
£¨3£©Ò»¶¨Ìõ¼þÏ£¬¿ÉÒÔÓÉCO2(g)ºÍH2(g)ºÏ³ÉCH4(g)£¬Í¬Ê±»¹Éú³ÉH2O(g)¡£ÏòºãÈÝÃܱÕÈÝÆ÷ÖгäÈëÒ»¶¨Á¿µÄCO2ºÍH2£¬ÔÚ300¡æʱ·¢ÉúÉÏÊö·´Ó¦£¬10min´ïµ½Æ½ºâʱ²¿·ÖÎïÖʵÄÁ¿Å¨¶ÈÈçͼËùʾ,¸ÃζÈϵĵÄƽºâ³£ÊýµÈÓÚ_______________¡£
£¨4£©ÈôÔÚ20minʱ¼õСѹǿ£¬²¢ÔÚ30minʱ´ïµ½Æ½ºâ״̬£¬ÇëÔÚͼ2Öл³öH2µÄÎïÖʵÄÁ¿Å¨¶ÈËæʱ¼ä±ä»¯µÄͼÏñ__________________¡£
£¨5£©¹¤ÒµÉϵç½âNa2CO3ÈÜÒº¿ÉÒÔÉú³ÉNaHCO3ºÍNaOHÁ½ÖÖ¹¤ÒµÖØÒªÔÁÏ£¬×°ÖÃÈçͼËùʾ¡£Çëд³öÑô¼«µÄµç¼«·´Ó¦Ê½______________________¡£
¡¾´ð°¸¡¿CO2(g)+3H2(g)£½CH3OH(g)+H2O(g)¡÷H=-49.6kJ¡¤mol-1 ÄæÏò 0.005 25 4CO32-+2H2O-4e-£½4HCO3-+O2¡ü
¡¾½âÎö¡¿
£¨1£©ÒÑÖª£º·´Ó¦¢Ù£º2H2(g)+CO(g)CH3OH(g)¡÷H£½£90.8kJ¡¤mol-1
·´Ó¦¢Ú£ºH2(g)+CO2(g)H2O(g)+CO(g)¡÷H£½+41.2kJ¡¤mol-1
ÓɸÇ˹¶¨ÂÉ¿ÉÖª¢Ù+¢Ú¿ÉµÃCO2(g)+3H2(g)£½CH3OH(g)+H2O(g)¡÷H=-49.6kJ¡¤mol-1£¬¹Ê´ð°¸Îª£ºCO2(g)+3H2(g)£½CH3OH(g)+H2O(g)¡÷H=-49.6kJ¡¤mol-1£»
£¨2£©Î¶ÈÉý¸ßKÖµ¼õС£¬ÔòƽºâÏòÄæ·½ÏòÒƶ¯£»ÉèCOµÄŨ¶È±ä»¯Îªxmol/LÔò
Ôòx=0.015mol/L£¬ÔòCOµÄƽºâŨ¶ÈΪ0.02 mol/L -0.015 mol/L=0.005 mol/L£¬¹Ê´ð°¸Îª£ºÄæÏò£»0.005£»
£¨3£©Ò»¶¨Ìõ¼þÏ£¬¿ÉÒÔÓÉCO2(g)ºÍH2(g)ºÏ³ÉCH4(g)£¬Í¬Ê±»¹Éú³ÉH2O(g)·´Ó¦Îª£º£¬¸ù¾ÝͼÏñ¿ÉÖªc(CH4)=0.8mol/L£¬Ôòc(H2O)= 2c(CH4)=1.6mol/L£¬ £¬¹Ê´ð°¸Îª£º25£»
£¨4£©¼õСѹǿ£¬ÈÝÆ÷Ìå»ýÔö´ó£¬Å¨¶È¼õС£¬Æ½ºâÄæÒÆ£¬¸ù¾ÝÀÕÏÄÌØÁÐÔÀí¿ÉÖª×îÖÕŨ¶ÈСÓÚƽºâ10minÖÐʱŨ¶È£¬Í¼ÏñΪ£¬¹Ê´ð°¸Îª£º£»
£¨5£©Óɵç½â×°ÖÃʾÒâͼ¿ÉÖª£¬ºÍµçÔ´Õý¼«ÏàÁ¬µÄΪÑô¼«£¬µç½âÖÊΪNa2CO3ÈÜÒºÉú³ÉO2ºÍNaHCO3£¬Ñô¼«µç¼«·´Ó¦Îª£º4CO32-+2H2O-4e-£½4HCO3-+O2¡ü£¬¹Ê´ð°¸Îª£º4CO32-+2H2O-4e-£½4HCO3-+
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿Ä³·´Ó¦Öз´Ó¦ÎïÓëÉú³ÉÎïÓУºAsH3¡¢H2SO4¡¢KBrO3¡¢K2SO4¡¢H3AsO4¡¢H2OºÍÒ»ÖÖδ֪ÎïÖÊX¡£
£¨1£©ÒÑÖªKBrO3ÔÚ·´Ó¦Öеõ½µç×Ó£¬·¢Éú_____£¨Ìî¡°Ñõ»¯¡±»ò¡°»¹Ô¡±£©·´Ó¦£¬Ôò¸Ã·´Ó¦µÄ»¹Ô¼ÁÊÇ________¡£
£¨2£©ÒÑÖª0.2molKBrO3ÔÚ·´Ó¦Öеõ½1molµç×ÓÉú³ÉX£¬ÔòXµÄ»¯Ñ§Ê½Îª____¡£
£¨3£©¸ù¾ÝÉÏÊö·´Ó¦¿ÉÍÆÖª________(ÌîÐòºÅ)¡£
a£®Ñõ»¯ÐÔ£ºKBrO3>H3AsO4
b£®Ñõ»¯ÐÔ£ºH3AsO4>HBrO3
c£®»¹ÔÐÔ£ºAsH3>X
d£®»¹ÔÐÔ£ºX>AsH3
£¨4£©½«Ñõ»¯¼ÁºÍ»¹Ô¼ÁµÄ»¯Ñ§Ê½¼°ÆäÅäƽºóµÄϵÊýÌîÈëÏÂÁз½¿òÖУ¬²¢±ê³öµç×ÓתÒƵķ½ÏòºÍÊýÄ¿¡£_____________
£«
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿¡°ÂÌË®Çàɽ¾ÍÊǽðɽÒøɽ¡±£¬½üÄêÀ´£¬ÂÌÉ«·¢Õ¹¡¢Éú̬±£»¤³ÉΪÖйúչʾ¸øÊÀ½çµÄÒ»ÕÅС°ÃûƬ¡±¡£
(I)Æû³µÎ²ÆøÊÇÔì³É´óÆøÎÛȾµÄÖØÒªÔÒòÖ®Ò»£¬¼õÉÙµªµÄÑõ»¯ÎïÔÚ´óÆøÖеÄÅÅ·ÅÊÇ»·¾³±£»¤µÄÖØÒªÄÚÈÝÖ®Ò»¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)ÒÑÖª£º
Èôij·´Ó¦µÄƽºâ³£Êý±í´ïʽΪ£¬Ôò´Ë·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ_______¡£
(2)ÔÚÒ»¶¨Ìõ¼þÏ¿ɷ¢Éú·Ö½â£º£¬Ò»¶¨Î¶ÈÏ£¬ÔÚºãÈÝÃܱÕÈÝÆ÷ÖгäÈëÒ»¶¨Á¿½øÐи÷´Ó¦£¬ÄÜÅжϷ´Ó¦ÒÑ´ïµ½»¯Ñ§Æ½ºâ״̬µÄÊÇ_____(Ìî×Öĸ)¡£
a. ºÍµÄŨ¶È±È±£³Ö²»±ä b.ÈÝÆ÷ÖÐѹǿ²»Ôٱ仯
c. d. ÆøÌåµÄÃܶȱ£³Ö²»±ä
(¢ò)¼×´¼¡¢ÒÒ´¼À´Ô´·á¸»¡¢¼Û¸ñµÍÁ®¡¢ÔËÊäÖü´æ·½±ã£¬¶¼ÊÇÖØÒªµÄ»¯¹¤ÔÁÏ£¬ÓÐ×ÅÖØÒªµÄÓÃ;ºÍÓ¦ÓÃÇ°¾°£¬¿ÉÒÔÓöàÖÖ·½·¨ºÏ³É¡£ CO2(g) + 3H2(g)CH3OH(g) + H2O(g)
(3)½«ºÍ°´ÎïÖʵÄÁ¿Ö®±È1£º3³äÈëÌå»ýΪ2.0LµÄºãÈÝÃܱÕÈÝÆ÷Öз´Ó¦Éú³É£¬Èçͼ1±íʾѹǿΪ0.1 MPaºÍ5.0 MPaÏÂת»¯ÂÊËæζȵı仯¹Øϵ¡£
¢Ùa¡¢bÁ½µã»¯Ñ§·´Ó¦ËÙÂÊ·Ö±ðÓ㬱íʾ£¬Ôò_____(Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±)
¢ÚÁгöaµã¶ÔÓ¦µÄƽºâ³£Êý±í´ïʽK= ____________________¡£
(4)ÔÚ1.0 LºãÈÝÃܱÕÈÝÆ÷ÖÐͶÈë1 mol ºÍ2.75 mol ·¢Éú·´Ó¦£º
A.¸Ã·´Ó¦µÄÕý·´Ó¦Îª·ÅÈÈ·´Ó¦
B.ѹǿ´óС¹ØϵΪP1£¼P2£¼P3
C.Mµã¶ÔÓ¦µÄƽºâ³£ÊýKµÄֵԼΪ
D.ÔÚ¼°512 Kʱ£¬Í¼ÖÐNµã
(5)´ß»¯¼ÓÇâºÏ³ÉÒÒ´¼µÄ·´Ó¦Îª£º2CO2(g) + 6H2(g) C2H5OH(g) + 3H2O(g) £»m´ú±íÆðʼʱµÄͶÁϱȣ¬¼´¡£
¢Ù ͼ3ÖÐͶÁϱÈÏàͬ£¬Î¶ȣ¬Ôò¸Ã·´Ó¦µÄìʱä_______0(Ìî)¡£
¢Ú m=3ʱ£¬ºãѹÌõ¼þϸ÷ÎïÖʵÄÎïÖʵÄÁ¿·ÖÊýÓëζȵĹØϵÈçͼ4Ëùʾ£¬ÔòÇúÏßb´ú±íµÄÎïÖÊΪ_________(Ìѧʽ)¡£
(6)ÒÔ¼×´¼ÎªÖ÷ÒªÔÁÏ£¬µç»¯Ñ§ºÏ³É̼Ëá¶þ¼×õ¥µÄ¹¤×÷ÔÀíÈçͼ5Ëùʾ¡£Àë×Ó½»»»Ä¤aΪ ______(Ìî¡°ÑôĤ¡±¡¢¡°ÒõĤ¡±)£¬Ñô¼«µÄµç¼«·´Ó¦Ê½Îª_______________________________________
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿½«ÎïÖÊXÖð½¥¼ÓÈë(»òͨÈë)YÈÜÒºÖУ¬ÆäÉú³É³ÁµíµÄÎïÖʵÄÁ¿Óë¼ÓÈëXµÄÎïÖʵÄÁ¿µÄ¹ØϵÈçÏÂͼËùʾ£¬·ûºÏͼʾÇé¿öµÄÊÇ
A.AB.BC.CD.D
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿ÊµÑéÊÒÖƱ¸´¿¼îµÄÖ÷Òª²½ÖèÈçÁ÷³ÌËùʾ£º
ËÄÖÖÑÎÔÚ²»Í¬Î¶ÈϵÄÈܽâ¶È£¨g/100gH2O£©±í
ÎÂ¶È ÎïÖÊ | 0¡æ | 10¡æ | 20¡æ | 30¡æ | 40¡æ | 50¡æ | 60¡æ | 100¡æ |
NaCl | 35.7 | 35.8 | 36.0 | 36.3 | 36.6 | 37.0 | 37.3 | 39.8 |
NH4HCO3 | 11.9 | 15.8 | 21.0 | 27.0 | - | - | - | - |
NaHCO3 | 6.9 | 8.1 | 9.6 | 11.1 | 12.7 | 14.5 | 16.4 | - |
NH4Cl | 29.4 | 33.3 | 37.2 | 41.4 | 45.8 | 50.4 | 55.3 | 77.3 |
Ìáʾ£ºÎ¶ȸßÓÚ35¡æʱNH4HCO3»á·Ö½â£¬Çë»Ø´ð£º
£¨1£©ÏÂÁвÙ×÷»òÃèÊöÕýÈ·µÄÊÇ________¡£
A£®Î¶ȿØÖÆÔÚ30-35¡æÊÇÒòΪζÈÌ«¸ßNH4HCO3»á·Ö½â£¬Î¶ÈÌ«µÍ·´Ó¦ËÙÂÊÌ«Âý
B£®±£ÎÂ30minµÄÄ¿µÄÊÇʹ·´Ó¦³ä·Ö½øÐÐ
C£®¹ýÂ˺óµÄÂËÒºÖ»ÓÐNH4ClºÍNH4HCO3ÈÜÖÊ
D£®Ï´È¥¾§Ìå±íÃæµÄÔÓÖÊ¿ÉÒÔÑ¡ÓÃÕôÁóË®
£¨2£©·´Ó¦Î¶ȿØÖÆÔÚ30¡«35¡æ£¬Îª¿ØÖÆ´Ëζȷ¶Î§£¬²ÉÈ¡µÄ¼ÓÈÈ·½·¨Îª______________¡£
£¨3£©³£ÎÂʱ£¬¹ýÂ˺óÖ÷ÒªµÃµ½NaHCO3¾§ÌåµÄÔÒòÊÇ______________¡£
£¨4£©×ÆÉÕNaHCO3¾§ÌåµÄ×°ÖÃΪ________¡£
A.B.C.
£¨5£©Ï´µÓNaHCO3¾§ÌåµÄ²Ù×÷______________¡£
£¨6£©²â¶¨´¿¼î²úÆ·ÖÐNaHCO3º¬Á¿µÄ·½·¨£º×¼È·³ÆÈ¡´¿¼îÑùÆ·Wg·ÅÈë׶ÐÎÆ¿ÖмÓÕôÁóË®Èܽ⣬¼Ó1¡«2µÎ·Óָ̪ʾ¼Á£¬ÓÃÎïÖʵÄÁ¿Å¨¶ÈΪc£¨mol¡¤L-1£©µÄHClÈÜÒºµÎ¶¨ÖÁÈÜÒºÓɺìÉ«µ½ÎÞÉ«(ָʾCO32-+H+=HCO3£·´Ó¦µÄÖÕµã)ËùÓÃHClÈÜÒºÌå»ýΪV1mL¡£ÔÙ¼Ó1¡«2µÎ¼×»ù³Èָʾ¼Á£¬¼ÌÐøÓÃHClÈÜÒºµÎ¶¨ÖÁÈÜÒºÓɻƱä³È£¬ËùÓÃHClÈÜÒºÌå»ýΪV2mL£¬Ð´³ö´¿¼îÑùÆ·ÖÐNaHCO3ÖÊÁ¿·ÖÊýµÄ¼ÆËãʽ£º______________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿Ïò20mL¡¢0.2mol/LNaOHÈÜÒºÖУ¬»º»ºÍ¨ÈëÒ»¶¨Á¿CO2ÆøÌ壬½«ÈÜÒºÔÚÒ»¶¨Ìõ¼þÏÂÕô¸É¡£
£¨1£©ÈôµÃµ½°×É«¹ÌÌåÊÇ´¿¾»ÎÔòͨÈëµÄCO2µÄÌå»ýΪ__mL»ò__mL£¨±ê¿ö£©¡£Ð´³öÓйصÄÀë×Ó·½³Ìʽ£º__¡¢__¡£
£¨2£©½«ÉÏÊö°×É«¹ÌÌå¼ÓË®Èܽ⣬¼ÓÑÎËáÖÁpH£½7ÔÙÕô¸ÉµÃ°×É«¹ÌÌåÖÊÁ¿Îª__g¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿ÏòÊ¢ÓÐKLÈÜÒºµÄÊÔ¹ÜÖмÓÈëÉÙÐíºóµÎ¼ÓÂÈË®£¬²ã±ä³É×ÏÉ«¡£Èç¹û¼ÌÐøÏòÊÔ¹ÜÖеμÓÂÈË®£¬Õñµ´£¬²ã»áÖð½¥±ädz£¬×îºó±ä³ÉÎÞÉ«¡£
Íê³ÉÏÂÁÐÌî¿Õ£º
1) д³ö²¢Åäƽ²ãÓÉ×ÏÉ«±ä³ÉÎÞÉ«µÄ»¯Ñ§·´Ó¦·½³Ìʽ(Èç¹ûϵÊýÊÇ1£¬²»ÓÃÌîд)£º
_____
2)Õû¸ö¹ý³ÌÖеĻ¹Ô¼ÁÊÇ___¡£
3)°ÑKL»»³ÉKBr£¬Ôò²ã±äΪ__É«£º¼ÌÐøµÎ¼ÓÂÈË®£¬²ãµÄÑÕɫûÓб仯¡£¡¢¡¢Ñõ»¯ÐÔÓÉÇ¿µ½ÈõµÄ˳ÐòÊÇ______¡£
4)¼ÓµâÑÎÖꬵâÁ¿Îª20mg¡«50mg£¯kg¡£ÖÆÈ¡¼ÓµâÑÎ(º¬µÄʳÑÎ)1000kg£¬ÈôׯKlÓë·´Ó¦ÖÆ£¬ÖÁÉÙÐèÒªÏûºÄ________L(±ê×¼×´¿ö£¬±£Áô2λСÊý)¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿ÏÂÁÐÀë×Ó·½³ÌʽÕýÈ·µÄÊÇ £¨¡¡¡¡£©
A. ÏòBa(OH)2ÈÜÒºÖеμÓNaHSO4ÈÜÒºÖÁ³Áµí¸ÕºÃÍêÈ«£ºBa2+ + 2OH£ + 2H+ + SO42£ = BaSO4¡ý+ 2 H2O
B. AlCl3ÈÜÒºÖмÓÈë¹ýÁ¿°±Ë®£ºAl3+£«4OH£=== £«2H2O
C. Ïò̼ËáÇâ¸ÆÈÜÒºÖмÓÈë¹ýÁ¿ÇâÑõ»¯ÄÆ£ºCa2£«£«2HCO3££«2OH££½CaCO3¡ý£«2H2O£«CO32£
D. ³ÎÇåʯ»ÒË®ºÍ̼ËáÄÆÈÜÒº·´Ó¦£ºCa(OH)2+CO32-=CaCO3¡ý+OH-
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿NH3ÊÇÖØÒªµÄ»¯¹¤ÔÁÏ£¬¾Ò»ÏµÁз´Ó¦¿ÉµÃµ½HNO3¡¢CO(NH2)2¡¢HCNµÈ²úÆ·¡£
(1)ÒÔ°±ÆøΪÔÁϺϳÉHNO3¹¤ÒÕÈçÏ£¬Ð´³öN2O4ת»¯ÎªHNO3µÄ·´Ó¦·½³Ìʽ_____¡£
(2)ÒÔNH3ºÍCO2ΪÔÁÏÉú²úÄòËصķ´Ó¦ÈçÏ£º
·´Ó¦¢ñ£º2NH3(l) £« CO2(g) NH2COONH4(l) ¦¤ H1 £½ a kJ¡¤mol-1
·´Ó¦¢ò£ºNH2COONH4(l) NH2CONH2(l) £« H2O(l) ¦¤ H2 £½ b kJ¡¤mol-1
¢Ù ÒÑÖªNH3(l) NH3(g) ¦¤ H3 £½ c kJ¡¤mol-1 ·´Ó¦2NH3(g) £« CO2(g) NH2CONH2(l) £« H2O(l) ¦¤ H4£½_____kJ¡¤mol-1(Óú¬a¡¢b¡¢cµÄʽ×Ó±íʾ)£¬¸Ã·´Ó¦ÄÜ×Ô·¢½øÐеÄÖ÷ÒªÔÒòÊÇ_____¡£
¢Ú Ò»¶¨Ìõ¼þÏ£¬ÍùºãÈÝÃܱÕÈÝÆ÷ÖÐͶÈë4 mol NH3ºÍ 1 mol CO2£¬²âµÃ¸÷×é·ÖÎïÖʵÄÁ¿Ëæʱ¼ä±ä»¯Èçͼ1¡£ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ_____¡£
A£®Ñ¡ÔñºÏÊʵÄ̼µª±ÈÓÐÀûÓÚÌá¸ß²úÂÊ
B£®·´Ó¦¢ñµÄ»î»¯Äܱȷ´Ó¦¢òС
C£®¹ýÁ¿°±Æø¿ÉÒÔÓë·´Ó¦Éú³ÉµÄË®½áºÏ£¬ÓÐÀûÓÚÄòËغϳÉ
D£®ÆøÌåÎïÖʵÄÁ¿²»Ôٱ仯ʱ£¬·´Ó¦´ïµ½Æ½ºâ״̬
(3)¹¤ÒµÉÏÀûÓð±ÆøÉú²úÇâÇèËáµÄ·´Ó¦ÎªCH4(g) + NH3(g) HCN(g) + 3H2(g) ¦¤ H>0
¢Ù ÆäËûÌõ¼þÒ»¶¨£¬´ïµ½Æ½ºâʱNH3ת»¯ÂÊËæÍâ½çÌõ¼þX±ä»¯µÄ¹ØϵÈçͼËùʾ¡£X´ú±íµÄÊÇ_____(Ìζȡ±»ò¡°Ñ¹Ç¿¡±)¡£
¢Ú ÆäËüÌõ¼þÒ»¶¨Ê±£¬Ïò2 LÃܱÕÈÝÆ÷ÖмÓÈën mol CH4ºÍ2 mol NH3£¬Æ½ºâʱNH3Ìå»ý·ÖÊýËæn±ä»¯µÄ¹ØϵÈçͼËùʾ¡£Æ½ºâ³£ÊýK=_____£¨Çëд³ö¼ÆËã¹ý³Ì£©
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com