ÏÂÁÐÓйØʵÑé²Ù×÷¡¢ÏÖÏóºÍ½âÊÍ»ò½áÂÛ¶¼ÕýÈ·µÄ£¨    £©

Ñ¡Ïî

ʵÑé²Ù×÷

ÏÖÏó

½âÊÍ»ò½áÂÛ

¢Ù

¹ýÁ¿µÄ·ÛÖмÓÈëÏ¡£¬³ä·Ö·´Ó¦ºó£¬µÎÈëÈÜÒº

ÈÜÒº³ÊºìÉ«

Ï¡½«Ñõ»¯Îª

¢Ú

AgI³ÁµíÖеÎÈëÏ¡ÈÜÒº

Óа×É«³Áµí³öÏÖ

±È¸üÄÑÈÜ

¢Û

Al²­²åÈëÏ¡ÖÐ

ÎÞÏÖÏó

²­±íÃæ±»Ñõ»¯£¬ÐγÉÖÂÃܵÄÑõ»¯Ä¤

¢Ü

Óò£Á§°ôպȡŨ°±Ë®µãµ½ºìɫʯÈïÊÔÖ½ÉÏ

ÊÔÖ½±äÀ¶É«

Ũ°±Ë®³Ê¼îÐÔ

¢Ý

½«Å¨ÁòËáµÎµ½ÕáÌDZíÃæ

¹ÌÌå±äºÚÅòÕÍ

ŨÁòËáÓÐÍÑË®ÐÔºÍÇ¿Ñõ»¯ÐÔ

¢Þ

½«×ãÁ¿µÄÈÜÒºµÎÈëÈÜÒºÖÐ

ÈÜÒºÍÊÉ«

2MnO4£­+7H2O2+6H+=2Mn2++6O2¡ü+10H2O

¢ß

½«Ò»Ð¡¿é·ÅÈëÎÞË®ÒÒ´¼ÖÐ

²úÉúÆøÅÝ

ÄÜÖû»³ö´¼ôÇ»ùÖеÄÇâ

¢à

½«Ë®ÕôÆøͨ¹ý×ÆÈȵÄÌú·Û

·ÛÄ©±äºì

ÌúÓëË®ÔÚ¸ßÎÂÏ·´Ó¦

       A£®¢Ù¢Ü¢Ý¢Þ¢ß            B£®¢Ü¢Ý                      C£®¢Ü¢Ý¢ß                   D£®¢Ù¢Ý

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


NA±íʾ°¢·ü¼ÓµÂÂÞ³£Êý£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©

A¡¢30 g SiO2º¬ÓÐNA¸öSi£­O¹²¼Û¼ü

B¡¢1 L 0.2mol·L£­1 Al2(SO4)3ÈÜÒºÖеÄÀë×Ó×ÜÊýΪNA

C¡¢±ê×¼×´¿öÏ£¬22.4 L H2OËùº¬Ô­×Ó¸öÊý´óÓÚ3NA

D¡¢º¬4 mol HClµÄŨÑÎËá¸ú×ãÁ¿MnO2¼ÓÈÈ·´Ó¦¿ÉÖƵÃCl2µÄ·Ö×ÓÊýΪNA

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


¿ÉÓëBa£¨OH£©2£¨ÒºÌ¬£©¡¢CuSO4£¨¹Ì̬£©¡¢´¿CH3COOHÈýÖÖÎïÖʹéÓÚÒ»ÀàµÄÎïÖÊÊÇ                                 

A£®C2H5OH£¨ÈÜÒº£©      B£®HCl£¨Æø̬£©         C£®Ë®ÃºÆø        D£®¶¹½¬

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏàͬÎïÖʵÄÁ¿µÄCO2ºÍO2£¬ÆäËùº¬Ô­×ÓÊýÄ¿Ö®±ÈΪ______________£¬Ëùº¬ÑõÔ­×ÓÊýÄ¿Ö®±ÈΪ________________£¬ÖÊÁ¿ÏàͬµÄCO2ºÍO2£¬ÆäÎïÖʵÄÁ¿Ö®±ÈΪ________________£»ÏàͬÌõ¼þÏ£¬Í¬Ìå»ýµÄCO2ºÍO2 Æä·Ö×ÓÊýÖ®±ÈΪ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÎÀÉú²¿·¢³ö¹«¸æ£¬×Ô2011Äê5ÔÂ1ÈÕÆ𣬽ûÖ¹ÔÚÃæ·ÛÉú²úÖÐÌí¼Ó¹ýÑõ»¯¸Æ£¨CaO2£©µÈʳƷÌí¼Ó¼Á¡£ÏÂÁжԹýÑõ»¯¸ÆµÄÐðÊö´íÎóµÄÊÇ

       A£®CaO2¾ßÓÐÑõ»¯ÐÔ£¬¶ÔÃæ·Û¿ÉÄܾßÓÐÔö°××÷ÓÃ

       B£®CaO2ºÍË®·´Ó¦Ê±£¬Ã¿²úÉú1 mol O2תÒƵç×Ó2 mol

       C£®CaO2ÖÐÒõÑôÀë×ӵĸöÊý±ÈΪ2¡Ã1

       D£®CaO2ºÍCO2·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º2CaO2+2CO2 £½2Ca CO3+O2

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÎÞÉ«ÈÜÒº¿ÉÄÜÓÉK2CO3¡¢MgCl2¡¢NaHCO3¡¢BaCl2ÈÜÒºÖеÄÒ»ÖÖ»ò¼¸ÖÖ×é³É¡£ÏòÈÜÒºÖмÓÈëÉÕ¼îÈÜÒº³öÏÖ°×É«³Áµí£¬¼ÓÈëÏ¡ÁòËáÒ²³öÏÖ°×É«³Áµí²¢·Å³öÆøÌå¡£¾Ý´Ë·ÖÎö£¬ÏÂÁÐÅжÏÖÐÕýÈ·µÄÊÇ£¨¡¡¡¡£©

    ¢Ù¿Ï¶¨ÓÐBaCl2¡¡         ¢Ú¿Ï¶¨ÓÐMgCl2¡¡        ¢Û¿Ï¶¨ÓÐNaHCO3¡¡

    ¢Ü¿Ï¶¨ÓÐNa2CO3»òNaHCO3¡¡¢Ý¿Ï¶¨Ã»ÓÐMgCl2

       A£®¢Ù¢Ú¢Û              B£®¢Ú¢Ü              C£®¢Ù¢Û                    D£®¢Ù¢Û¢Ý

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÁòÌú¿óÓֳƻÆÌú¿ó£¬ÊÇÉú²úÁòËáµÄÔ­ÁÏ£¬ÆäÖ÷Òª³É·ÖΪFeS2¡£850¡æ~950¡æʱ£¬ÁòÌú¿óÔÚ¿ÕÆøÖÐìÑÉÕ£¬¿ÉÄÜ·¢ÉúÏÂÁз´Ó¦£¨Éè¿ÕÆøÖÐN2ÓëO2Ìå»ý±ÈΪ4¡Ã1£©£º

        3FeS2 + 8O2 = Fe3O4 + 6SO2              ¢Ù

        4FeS2 + 11O2 = 2Fe2O3 + 8SO2           ¢Ú

       £¨1£©º¬Áò35%µÄÁòÌú¿óÑùÆ·£¨ÔÓÖʲ»º¬Áò£©£¬ÆäFeS2µÄº¬Á¿Îª_________________¡£

       £¨2£©Éè1 t´¿¾»µÄFeS2°´¢ÚʽÍêÈ«·´Ó¦£¬²úÉú±ê×¼×´¿öÏÂSO2__________ m3¡£

       £¨3£©ÎªÊ¹FeS2ìÑÉÕÍêÈ«Éú³ÉFe2O3£¬¹¤ÒµÉÏʹÓùýÁ¿¿ÕÆø£¬µ±¿ÕÆø¹ýÁ¿20%ʱ£¬ËùµÃ¯ÆøÖÐSO2µÄÌå»ý·ÖÊýΪ¶àÉÙ£¿     ¡£

       £¨4£©480 g´¿¾»µÄFeS2ÔÚ¿ÕÆøÖÐÍêÈ«·´Ó¦£¬ÈôËùµÃ¹ÌÌåÖУ¬FeºÍOµÄÎïÖʵÄÁ¿Ö®±Èn£¨Fe£©¡Ãn£¨O£© =4¡Ãa£¬´ËʱÏûºÄ¿ÕÆøΪbmol¡£

    ¢ÙÊÔд³öbÓëaµÄ¹Øϵʽ£º___________________¡£

    ¢Ú²¢×÷³öbÓëaµÄ¹ØϵÇúÏß¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


 NA±íʾ°¢·ü¼ÓµÂÂÞ³£Êý£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ

A£®32 gÑõÆøÓë×ãÁ¿ï®ÍêÈ«·´Ó¦µÃµ½µÄµç×ÓÊýΪ2NA

B£®1 L 2 mol¡¤L-1 MgCl2ÈÜÒºÖк¬ÓеÄClÊýΪ2NA

C. ±ê×¼×´¿öÏ£¬11.2 LÂÈÆøÓë×ãÁ¿NaOHÈÜÒº·´Ó¦×ªÒƵĵç×ÓÊýΪ0.5NA

D. ±ê×¼×´¿öÏ£¬2.24 L CO2Óë2.24 L H2OÖÐËùº¬Ô­×ÓÊý¾ùΪ0.3NA

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ijÎÞÉ«ÈÜÒºÖк¬ÓÐK£«¡¢Cl£­¡¢OH£­¡¢SO¡¢SO£¬Îª¼ìÑéÈÜÒºÖÐËùº¬µÄijЩÒõÀë×Ó£¬ÏÞÓõÄÊÔ¼ÁÓУºÑÎËá¡¢ÏõËá¡¢ÏõËáÒøÈÜÒº¡¢ÏõËá±µÈÜÒº¡¢äåË®ºÍ·Ó̪ÊÔÒº¡£¼ìÑéÆäÖÐOH£­µÄʵÑé·½·¨Ê¡ÂÔ£¬¼ìÑéÆäËûÒõÀë×ӵĹý³ÌÈçÏÂͼËùʾ¡£

(1)ͼÖÐÊÔ¼Á¢Ù¡«¢ÝÈÜÖʵĻ¯Ñ§Ê½·Ö±ðÊÇ

¢Ù________£¬¢Ú________£¬¢Û________£¬¢Ü__________£¬

¢Ý__________¡£

(2)ͼÖÐÏÖÏóa¡¢b¡¢c±íÃ÷¼ìÑé³öµÄÀë×Ó·Ö±ðÊÇ

a________¡¢b________¡¢c________¡£

(3)°×É«³ÁµíA¼ÓÊÔ¼Á¢Ú·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ_________________________________

________________________________________________________________________¡£

(4)ÎÞÉ«ÈÜÒºC¼ÓÊÔ¼Á¢ÛµÄÖ÷ҪĿµÄÊÇ_____________________________________¡£

(5)°×É«³ÁµíAÈô¼ÓÊÔ¼Á¢Û¶ø²»¼ÓÊÔ¼Á¢Ú£¬¶ÔʵÑéµÄÓ°ÏìÊÇ____________________¡£

(6)ÆøÌåEͨÈëÊÔ¼Á¢Ü·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ_______________________________

________________________________________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸