Question

(14·Ö)ÒÑÖª´æÔÚÈçÏ·´Ó¦£º

ÆäÖÐAºÍCΪ³£¼û½ðÊôµ¥ÖÊ£»BºÍDΪÑõ»¯ÎïÇÒB¾ßÓдÅÐÔ£»EΪÎÞÉ«ÆøÌåµ¥ÖÊ¡£
¾Ý´Ë»Ø´ð£º
£¨1£©D¿ÉÈÜÓÚÇ¿ËáºÍÇ¿¼î£¬Ð´³öDÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ
                                                            ¡£
£¨2£©ÎïÖÊEÊÇ      £¨Ìѧʽ£©£»ÔÚ·´Ó¦¢ÙÖУ¬1mol B·¢Éú·´Ó¦Ê±×ªÒƵç×ÓµÄÎïÖʵÄÁ¿ÊÇ            ¡£
£¨3£©½«µ¥ÖÊAºÍCÓõ¼ÏßÁ¬½Ó£¬ÓëÏ¡ÁòËá¹¹³ÉÔ­µç³Ø£¬Ôò¸ÃÔ­µç³ØµÄ¸º¼«ÊÇ    £¨ÌîÔªËØ·ûºÅ£©£¬Õý¼«µÄµç¼«·´Ó¦Ê½ÊÇ                                         ¡£
£¨4£©BÓë¹ýÁ¿Ï¡ÏõËáÏàÓö£¬¿ÉÉú³ÉÒ»ÖÖÎÞÉ«ÆøÌ壬д³ö´Ë·´Ó¦µÄÀë×Ó·½³Ìʽ
                                                           £»
Èô½«BÈÜÓÚÑÎËáÖпÉÐγÉÈÜÒºF£¬FÖдæÔÚµÄÁ½ÖÖ½ðÊôÑôÀë×ÓÊÇ       £¨ÌîÀë×Ó·ûºÅ£©¡£
ÏÖÓÐÈçÏÂÈýÖÖ¼ìÑéFÖеĵͼ۽ðÊôÑôÀë×ÓµÄʵÑé·½°¸£¨°üÀ¨ÊµÑé²½Öè¼°Ô¤ÉèʵÑéÏÖÏ󣩣º
·Ö±ðÈ¡ÉÙÁ¿FÈÜÒºÓÚÈýÖ§½à¾»µÄÊÔ¹ÜÖУ¬
¢ÙÏòµÚÒ»Ö§ÊÔ¹ÜÖеμÓKSCNÈÜÒº£¬ÈÜÒº²»±äÉ«£¬ÔٵμÓÂÈË®£¬ÈÜÒº±äºìÉ«£»
¢ÚÏòµÚ¶þÖ§ÊÔ¹ÜÖÐÈÜÒºµÄµ×²¿ÓõιÜ×¢ÈëNaOHÈÜÒº£¬Éú³É°×É«³Áµí£¬È»ºóѸËÙ±äΪ»ÒÂÌÉ«£¬×îÖÕ±äΪºìºÖÉ«£»
¢ÛÏòµÚÈýÖ§ÊÔ¹ÜÖеμÓËáÐÔKMnO₄ÈÜÒº£¬Õñµ´£¬KMnO₄ÈÜÒº×ÏÉ«ÍÊÈ¥¡£
ÉÏÊöÈýÖÖ·½°¸ÖкÏÀíµÄÊÇ      £¨Ìî¢Ù¡¢¢Ú»ò¢Û£©£»
ÈôÏòÈÜÒºFÖмÓÈëÉÙÁ¿Í­·Û£¬Õñµ´ºó£¬Í­·ÛÖð½¥Èܽ⣬Çëд³ö´Ë¹ý³ÌÖз¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ                                                       ¡£

Answer 1

£¨14·Ö£©£¨1£©Al₂O₃ + 2OH^¡ª = 2AlO₂^¡ª + H₂O£¨2·Ö£©£¨2£©O₂£¨1·Ö£©  8mol£¨2·Ö£©
(3)Al£¨1·Ö£© 2H⁺ + 2e^¡ª = H₂¡ü£¨2·Ö£©  (4) 3Fe₃O₄ + 28H⁺ + NO₃^¡ª = 9Fe³⁺ + NO¡ü + 14H₂O£¨2·Ö£©
Fe²⁺¡¢Fe³⁺£¨1·Ö£©¢Û£¨1·Ö£©2Fe³⁺ + Cu = 2Fe²⁺ + Cu²⁺£¨2·Ö£©

ÂÔ