£¨14·Ö£©³£¼û»¯Ñ§·´Ó¦·½³ÌʽA+BX+Y+H2O¡£Çë»Ø´ð£º

       (1) ÈôAΪÒ×ÈÜÓÚË®µÄÑΣ¬BÊÇÇ¿¼î£¬ÊµÑéÊÒ³£Óô˷´Ó¦ÖƱ¸ÆøÌåX£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ                £¬¼ì²éÆäÖÐÆøÌåXµÄ·½·¨ÊÇ                                   ¡£

       (2) ÈôAΪºÚÉ«¹ÌÌ壬YÊÇ»ÆÂÌÉ«ÆøÌ壬д³öY µÄµç×Óʽ               £¬¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ ÊÇ                    ¡£½«ÆøÌåYͨÈëNaOHÈÜÒºÖмÓÈÈ·¢Éú·´Ó¦£¬µ±ÏûºÄ6.72L(±ê×¼×´¿ö)YÆøÌåʱ£¬×ªÒÆ0.5molµç×Ó£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ                 ¡£

       (3) ÈôAΪ½ðÊôµ¥ÖÊ£¬BÊÇÏ¡ÏõËᣬµ±AÓëBÒÔÎïÖʵÄÁ¿Ö®±ÈΪ1:4½øÐз´Ó¦£¬Éú³ÉÎÞÉ«ÆøÌåX£¬Óö¿ÕÆøÁ¢¼´±äΪºì×ØÉ«¡£ÇÒA¿ÉÈÜÓÚYÈÜÒºÖС£

       ¢Ùд³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ                                   ¡£

       ¢Úº¬0.5molYµÄÈÜÒºÈܽâÁËÒ»¶¨Á¿Aºó£¬ÈôÈÜÒºÖÐÁ½ÖÖ½ðÊôÑôÀë×ÓµÄÎïÖʵÄÁ¿Ç¡ºÃÏàµÈ£¬Ôò±»»¹Ô­µÄYÊÇ       mol¡£

 

¡¾´ð°¸¡¿

£¨Ã¿¿Õ¸÷2·Ö£©(1) 2NH4Cl+Ca£¨OH£©2 CaCl2+2H2O +2NH3¡ü£»ÓÃʪÈóµÄºìɫʯÈïÊÔÖ½¼ìÑ飬Èô±äÀ¶£¬ÔòÊÇNH3¡£»òÓÃպŨÑÎËáµÄ²£Á§°ô¼ìÑ飬Èôð°×ÑÌ£¬ÔòÊÇNH3¡£

(2) £»MnO2+4H++2Cl£­Mn2++Cl2¡ü+2H2O£»

6NaOH +3Cl2 NaClO3+5NaCl+ 3H2O

(3) ¢Ù Fe+4HNO3   NO¡ü+Fe(NO3)3+2H2O  ¢Ú 0.2

¡¾½âÎö¡¿ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

³£¼û»¯Ñ§·´Ó¦·½³ÌʽA+B¡úX+Y+H2O£®Çë»Ø´ð£º
£¨1£©ÈôAΪºìÉ«½ðÊôµ¥ÖÊ£¬BÊÇŨÁòËᣬд³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ
2H2SO4£¨Å¨£©+Cu
  ¡÷  
.
 
CuSO4+2H2O+SO2¡ü
2H2SO4£¨Å¨£©+Cu
  ¡÷  
.
 
CuSO4+2H2O+SO2¡ü
£¬¼ì²éÆäÖÐÆøÌå²úÎïXµÄ·½·¨ÊÇ
½«ÎÞÉ«SO2ͨÈëÆ·ºìÈÜÒº£¬ÈôÍÊÉ«£¬ÔòÖ¤Ã÷ÊÇSO2
½«ÎÞÉ«SO2ͨÈëÆ·ºìÈÜÒº£¬ÈôÍÊÉ«£¬ÔòÖ¤Ã÷ÊÇSO2
£®
£¨2£©ÈôAΪºÚÉ«¹ÌÌ壬YÊÇ»ÆÂÌÉ«ÆøÌ壬д³öY µÄµç×Óʽ
£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ
MnO2+4H++2Cl-
  ¡÷  
.
 
Mn2++Cl2¡ü+2H2O
MnO2+4H++2Cl-
  ¡÷  
.
 
Mn2++Cl2¡ü+2H2O
£®½«ÆøÌåYͨÈëNaOHÈÜÒºÖмÓÈÈ·¢Éú·´Ó¦£¬µ±ÏûºÄ6.72L£¨±ê×¼×´¿ö£©µÄÆøÌåʱ£¬×ªÒÆ0.5molµç×Ó£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ
6NaOH+3Cl2
  ¡÷  
.
 
NaClO3+5NaCl+3H2O
6NaOH+3Cl2
  ¡÷  
.
 
NaClO3+5NaCl+3H2O
£®
£¨3£©ÈôAΪ½ðÊôµ¥ÖÊ£¬BÊÇÏ¡ÏõËᣬµ±AÓëBÒÔÎïÖʵÄÁ¿Ö®±ÈΪ1£º4½øÐз´Ó¦£¬Éú³ÉÎÞÉ«ÆøÌåX£¬Óö¿ÕÆøÁ¢¼´±äΪºì×ØÉ«£®ÇÒA¿ÉÈÜÓÚYÈÜÒºÖУ®
¢Ùд³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ
Fe+4HNO3=NO¡ü+Fe£¨NO3£©3+2H2O
Fe+4HNO3=NO¡ü+Fe£¨NO3£©3+2H2O
£®
¢Úº¬amolYµÄÈÜÒºÈܽâÁËÒ»¶¨Á¿Aºó£¬ÈôÈÜÒºÖÐÁ½ÖÖ½ðÊôÑôÀë×ÓµÄÎïÖʵÄÁ¿Ç¡ºÃÏàµÈ£¬Ôò±»»¹Ô­µÄYÊÇ
0.2a
0.2a
mol£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨14·Ö£©³£¼û»¯Ñ§·´Ó¦·½³ÌʽA+BX+Y+H2O¡£Çë»Ø´ð£º

       (1) ÈôAΪÒ×ÈÜÓÚË®µÄÑΣ¬BÊÇÇ¿¼î£¬ÊµÑéÊÒ³£Óô˷´Ó¦ÖƱ¸ÆøÌåX£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ               £¬¼ì²éÆäÖÐÆøÌåXµÄ·½·¨ÊÇ                                  ¡£

       (2) ÈôAΪºÚÉ«¹ÌÌ壬YÊÇ»ÆÂÌÉ«ÆøÌ壬д³öY µÄµç×Óʽ              £¬¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ ÊÇ                   ¡£½«ÆøÌåYͨÈëNaOHÈÜÒºÖмÓÈÈ·¢Éú·´Ó¦£¬µ±ÏûºÄ6.72L(±ê×¼×´¿ö)YÆøÌåʱ£¬×ªÒÆ0.5molµç×Ó£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ                ¡£

       (3) ÈôAΪ½ðÊôµ¥ÖÊ£¬BÊÇÏ¡ÏõËᣬµ±AÓëBÒÔÎïÖʵÄÁ¿Ö®±ÈΪ1:4½øÐз´Ó¦£¬Éú³ÉÎÞÉ«ÆøÌåX£¬Óö¿ÕÆøÁ¢¼´±äΪºì×ØÉ«¡£ÇÒA¿ÉÈÜÓÚYÈÜÒºÖС£

       ¢Ùд³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ                                  ¡£

       ¢Úº¬0.5molYµÄÈÜÒºÈܽâÁËÒ»¶¨Á¿Aºó£¬ÈôÈÜÒºÖÐÁ½ÖÖ½ðÊôÑôÀë×ÓµÄÎïÖʵÄÁ¿Ç¡ºÃÏàµÈ£¬Ôò±»»¹Ô­µÄYÊÇ       mol¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012½ì½­Î÷Ê¡ÁùУ¸ßÈýÁª¿¼Àí¿Æ×ÛºÏÊÔ¾í£¨»¯Ñ§²¿·Ö£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨14·Ö£©³£¼û»¯Ñ§·´Ó¦·½³ÌʽA+BX+Y+H2O¡£Çë»Ø´ð£º
(1) ÈôAΪÒ×ÈÜÓÚË®µÄÑΣ¬BÊÇÇ¿¼î£¬ÊµÑéÊÒ³£Óô˷´Ó¦ÖƱ¸ÆøÌåX£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ               £¬¼ì²éÆäÖÐÆøÌåXµÄ·½·¨ÊÇ                                  ¡£
(2) ÈôAΪºÚÉ«¹ÌÌ壬YÊÇ»ÆÂÌÉ«ÆøÌ壬д³öY µÄµç×Óʽ              £¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ                   ¡£½«ÆøÌåYͨÈëNaOHÈÜÒºÖмÓÈÈ·¢Éú·´Ó¦£¬µ±ÏûºÄ6.72L(±ê×¼×´¿ö)YÆøÌåʱ£¬×ªÒÆ0.5molµç×Ó£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ                ¡£
(3) ÈôAΪ½ðÊôµ¥ÖÊ£¬BÊÇÏ¡ÏõËᣬµ±AÓëBÒÔÎïÖʵÄÁ¿Ö®±ÈΪ1:4½øÐз´Ó¦£¬Éú³ÉÎÞÉ«ÆøÌåX£¬Óö¿ÕÆøÁ¢¼´±äΪºì×ØÉ«¡£ÇÒA¿ÉÈÜÓÚYÈÜÒºÖС£
¢Ùд³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ                                  ¡£
¢Úº¬0.5molYµÄÈÜÒºÈܽâÁËÒ»¶¨Á¿Aºó£¬ÈôÈÜÒºÖÐÁ½ÖÖ½ðÊôÑôÀë×ÓµÄÎïÖʵÄÁ¿Ç¡ºÃÏàµÈ£¬Ôò±»»¹Ô­µÄYÊÇ      mol¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄê±±¾©ÊвýƽÇø¸ßÈý£¨ÉÏ£©ÆÚÄ©»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£º½â´ðÌâ

³£¼û»¯Ñ§·´Ó¦·½³ÌʽA+B¡úX+Y+H2O£®Çë»Ø´ð£º
£¨1£©ÈôAΪºìÉ«½ðÊôµ¥ÖÊ£¬BÊÇŨÁòËᣬд³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ______ CuSO4+2H2O+SO2¡ü

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸