K2Cr2O7ºÍH2O2ÔÚH2SO4ÈÜÒºÖлìºÏʱ£¬¿É¹Û²ìµ½ÏÂÃæÁ½¸öÏÖÏó£º

¢Ù»ìºÏºó5¡«10ÃëÄÚ£¬ÈÜÒºÓɳÈÉ«±äΪ°µÀ¶É«£»

¢ÚÔÚ80¡«150ÃëÄÚÓÉ°µÀ¶É«±äΪÂÌÉ«£¬Óë´Ëͬʱ·Å³öÆøÅÝ¡£ÓëÖ®ÏàÓ¦µÄÁ½¸ö·´Ó¦Îª£º

A£®Cr2O£«H2O2£«H£«¨D¡úCrO5£«H2O

B£®CrO5£«H£«¨D¡úCr3£«£«O2¡ü£«H2O

(1)ÒÑÖª·´Ó¦A²»ÊÇÑõ»¯»¹Ô­·´Ó¦£¬ÔòCrO5ÖÐCrÔªËصļÛ̬Ϊ____________¡£

(2)·´Ó¦BÊÇ·ñÊôÓÚÑõ»¯»¹Ô­·´Ó¦£¿

´ð£º____________£¬ÆäÀíÓÉÊÇ____________________________________________¡£

(3)½«·´Ó¦AºÍ·´Ó¦BÏà¼Ó£¬¿ÉÒԵõ½Ò»¸ö×Ü»¯Ñ§·½³Ìʽ£¬¸Ã×Ü·´Ó¦ÖÐÑõ»¯¼ÁÊÇ________¡£


(1)£«6¡¡(2)ÊÇ¡¡CrÔªËصļÛ̬´Ó£«6¼Û±äΪ£«3¼Û¡¡(3)Cr2O


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


25¡æʱ£¬ÑÎËáÈÜÒºµÄpHÊÇ4£¬ÂÈ»¯ï§ÈÜÒºµÄpHÊÇ5£¬ÑÎËáÓëÂÈ»¯ï§ÈÜÒºÖÐË®µçÀëµÄc£¨H+£©Ö®±ÈΪ£¨  £©

A£®10£º1      B£®1£º10       C£®1£º105       D£® 105£º1

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÈçͼËùʾ£¬ÔÚÊ¢ÓÐË®µÄÉÕ±­ÖУ¬ÌúȦºÍÒøȦµÄÁ¬½Ó´¦µõÓÐÒ»¸ù¾øÔµµÄϸ˿£¬Ê¹Ö®Æ½ºâ¡£

(1)ÏòÉÕ±­ÖмÓÈëCuSO4ÈÜÒº£¬Æ¬¿Ìºó¿É¹Û²ìµ½µÄÏÖÏó(Ö¸ÐüµõµÄ½ðÊôȦ)ÊÇ(¡¡¡¡)

A£®ÌúȦºÍÒøȦ×óÓÒÒ¡°Ú²»¶¨

B£®±£³Öƽºâ״̬²»±ä

C£®ÌúȦÏòÏÂÇãб

D£®ÒøȦÏòÏÂÇãб

(2)²úÉúÉÏÊöÏÖÏóµÄÔ­ÒòÊÇ¡¢________________________________________________

________________________________________________________________________

________________________________________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÑÇÏõËá(HNO2)ÔÚ·´Ó¦ÖмȿÉ×öÑõ»¯¼Á£¬ÓÖ¿É×ö»¹Ô­¼Á¡£µ±Ëü×ö»¹Ô­¼Áʱ£¬ÆäÑõ»¯²úÎï¿ÉÄÜÊÇ(¡¡¡¡)

A£®NH3       B£®N2       C£®NO2       D£®NO

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÔÚH£«¡¢Mg2£«¡¢Fe2£«¡¢S2£­¡¢I£­¡¢SÖУ¬Ö»¾ßÓÐÑõ»¯ÐÔµÄÊÇ______________________£¬Ö»¾ßÓл¹Ô­ÐÔµÄÊÇ________________£¬¼ÈÓÐÑõ»¯ÐÔÓÖÓл¹Ô­ÐÔµÄÊÇ______________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


×ãÁ¿µÄŨH2SO4ºÍm gÍ­ÍêÈ«·´Ó¦£¬µÃµ½±ê×¼×´¿öÏÂn L SO2£¬Ôò±»»¹Ô­µÄÁòËáÊÇ(¡¡¡¡)

A. mol                  B. mol

C. g                  D. g

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ËáÓêÊÇÖ¸Ìì¿Õ½µË®³ÊËáÐÔ(pHСÓÚ5.6)£¬¸ö±ðµØ·½ËáÓêµÄpH¾¹µÍÓÚ2.1(ʳ´×µÄpH£½3)¡£ÐγÉËáÓêµÄÖ÷ÒªÊÇ´óÆøÖеÄSO2ºÍµªÑõ»¯Îï¡£ËüÃǵÄÖ÷ÒªÀ´Ô´ÊÇúºÍʯÓ͵ÄȼÉÕ£¬È«ÊÀ½çÿÄêÓÐ1.5ÒÚ¶ÖSO2µÄÅÅ·ÅÁ¿¡£

(1)SO2¿ÉÔÚ¿ÕÆøÖÐÊܹâÕÕ±»Ñõ»¯£¬×îÖÕÓëÓêË®ÐγÉËáÓê¡£ÊÔд³öÕâÁ½¸ö»¯Ñ§·´Ó¦·½³Ìʽ£º

________________________________________________________________________

________________________________________________________________________¡£

(2)Æû³µÅŷŵÄβÆø¡¢ÏõË᳧ºÍ»¯·Ê³§µÄ·ÏÆø¶¼º¬µªÑõ»¯ÎȫÊÀ½çÿÄêÅÅ·ÅÁ¿Ô¼5¡Á107 kg¡£NO2ÈÜÓÚË®Éú³É________Ëá¡£

(3)ËáÓê¿Éµ¼ÖµÄΣº¦ÓÐ(¡¡¡¡)

A£®¸¯Ê´½¨ÖþÎï                 B£®µ¼ÖÂÊ÷ľ¿Ýή

C£®Ôì³ÉºéÀÔÔÖº¦               D£®¶ñ»¯ÈËÀà»·¾³

(4)ΪÁ˼õÉÙËáÓêµÄÐγɣ¬±ØÐë¼õÉÙSO2µÄÅÅ·ÅÁ¿£¬¶ÔȼÁÏÖеÄÁò»¯Îï½øÐÐ________£¬¶Ô·ÏÆøÖеĵªÑõ»¯Îï½øÐÐ________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


³ýÈ¥ÏÂÁÐÎïÖÊÖÐËùº¬µÄÔÓÖÊ(À¨ºÅÄÚΪÔÓÖÊ)£¬½«Ñ¡ÓõÄÊÔ¼ÁºÍ·ÖÀë·½·¨ÌîÔÚÌâºóµÄºáÏßÉÏ£¬²¢Ð´³öÓйط´Ó¦µÄÀë×Ó·½³Ìʽ¡£

(1)Fe2O3[Fe(OH)3]______________________________£»

(2)Fe2O3(Al2O3)_________________________________________________________£»

(3)FeCl3(FeCl2)__________________________________________________________£»

(4)FeCl2(FeCl3)___________________________________________________________£»

(5)FeCl2(CuCl2)___________________________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÂÁÐÒÇÆ÷ÄÜÓþƾ«µÆÖ±½Ó¼ÓÈȵÄÊÇ

A.ÉÕÆ¿                B.ÈÝÁ¿Æ¿             C.ÊԹܠ                   D.ÉÕÆ¿

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸