µª¼°Æ仯ºÏÎïÔÚÉú»î¡¢Éú²úºÍ¿Æ¼¼µÈ·½ÃæÓÐÖØÒªÓ¦Óã®Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©µªÔªËØ»ù̬ԭ×ӵļ۵ç×ÓÅŲ¼Ê½Îª______£»
£¨2£©ÔÚµªÆø·Ö×ÓÖУ¬µªÔ­×ÓÖ®¼ä´æÔÚ×Å______¸ö¦Ò¼üºÍ______¸ö¦Ð¼ü£»
£¨3£©µª¡¢Ñõ¡¢·úÊÇͬÖÜÆÚÏàÁÚµÄÈýÖÖÔªËØ£¬±È½Ï£º
¢ÙµªÔ­×ӵĵÚÒ»µçÀëÄÜ______£¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©ÑõÔ­×ӵĵÚÒ»µçÀëÄÜ£»
¢ÚN2·Ö×ÓÖеªµª¼üµÄ¼ü³¤______£¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©F2·Ö×ÓÖзú·ú¼üµÄ¼ü³¤£»
£¨4£©µªÔªËصÄÇ⻯Îï--NH3ÊÇÒ»ÖÖÒ×Òº»¯µÄÆøÌ壬¸ÃÆøÌåÒ×Òº»¯µÄÔ­ÒòÊÇ______£»
£¨5£©ÅäºÏÎï[Cu£¨NH3£©4]Cl2Öк¬ÓÐ4¸öÅäλ¼ü£¬ÈôÓÃ2¸öN2H4´úÌæÆäÖеÄ2¸öNH3£¬µÃµ½µÄÅäºÏÎï[Cu£¨NH3£©2£¨N2H4£©2]Cl2Öк¬ÓÐÅäλ¼üµÄ¸öÊýΪ______£®

½â£º£¨1£©µªÔ­×ӵĵç×ÓÅŲ¼Ê½Îª1s22s22p3£¬ËùÒÔµªÔªËØ»ù̬ԭ×ӵļ۵ç×ÓÅŲ¼Ê½Îª2s22p3£®
¹Ê´ð°¸Îª£º2s22p3£®
£¨2£©µªÆø·Ö×ÓÖдæÔÚN¡ÔN£¬Èý¼üÖÐ1¸ö¦Ò¼ü¡¢2 ¸ö¦Ð¼ü£®
¹Ê´ð°¸Îª£º1¡¢2£®
£¨3£©¢ÙNÔ­×ÓµÄ2pÄܼ¶´¦ÓÚ°ëÂú״̬£¬½ÏÎȶ¨£¬¹ÊNÔªËصĵÚÒ»µçÀëÄܸßÓÚÑõÔªËصĵÚÒ»µçÀëÄÜ£®
¹Ê´ð°¸Îª£º´óÓÚ£®
¢Ú¼üÄÜÔ½´ó£¬¼ü³¤Ô½¶Ì£¬N¡ÔN¼üµÄ¼üÄÜÔ­´óÓÚF-F¼üµÄ¼üÄÜ£¬ËùÒÔN2·Ö×ÓÖеªµª¼üµÄ¼ü³¤Ð¡ÓÚF2·Ö×ÓÖзú·ú¼üµÄ¼ü³¤£®
¹Ê´ð°¸Îª£ºÐ¡ÓÚ£®
£¨4£©°±·Ö×ÓÖ®¼äÈÝÒ×ÐγÉÇâ¼ü£¬Ê¹Æä·ÐµãÉý¸ß¶øÈÝÒ×Òº»¯£®
¹Ê´ð°¸Îª£º°±·Ö×ÓÖ®¼äÈÝÒ×ÐγÉÇâ¼ü£¬Ê¹Æä·ÐµãÉý¸ß¶øÈÝÒ×Òº»¯£®
£¨5£©ÅäºÏÎïÖÐÐÄÀë×Óδ±ä»¯£¬Åäλ¼üÊýÄ¿²»±ä£¬º¬ÓÐÅäλ¼üµÄ¸öÊýΪ4£®
¹Ê´ð°¸Îª£º4£®
·ÖÎö£º£¨1£©¸ù¾ÝºËÍâµç×ÓÅŲ¼¹æÂÉÊéдµªÔªËØ»ù̬ԭ×ӵļ۵ç×ÓÅŲ¼Ê½£®
£¨2£©µªÆø·Ö×ÓÖдæÔÚN¡ÔN£¬Èý¼üÖÐ1¸ö¦Ò¼ü¡¢2 ¸ö¦Ð¼ü£®
£¨3£©¢ÙNÔ­×ÓµÄ2pÄܼ¶´¦ÓÚ°ëÂú״̬£¬½ÏÎȶ¨£®
¢Ú¼üÄÜÔ½´ó£¬¼ü³¤Ô½¶Ì£®
£¨4£©°±·Ö×ÓÖ®¼äÈÝÒ×ÐγÉÇâ¼ü£¬Ê¹Æä·ÐµãÉý¸ß¶øÈÝÒ×Òº»¯£®
£¨5£©ÅäºÏÎïÖÐÐÄÀë×Óδ±ä»¯£¬Åäλ¼üÊýÄ¿²»±ä£®
µãÆÀ£º¿¼²éºËÍâµç×ÓÅŲ¼¹æÂÉ¡¢µçÀëÄÜ¡¢¼üÄÜÓë¼ü³¤¹Øϵ¡¢»¯Ñ§¼üÓëÇâ¼ü¡¢ÅäºÏÎïµÈ£¬ÄѶȲ»´ó£¬×¢Òâ»ù´¡ÖªÊ¶µÄÈ«ÃæÕÆÎÕ£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

µª¼°Æ仯ºÏÎïÔÚÉú»î¡¢Éú²úºÍ¿Æ¼¼µÈ·½ÃæÓÐÖØÒªÓ¦Óã®Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©µªÔªËØ»ù̬ԭ×ӵļ۵ç×ÓÅŲ¼Ê½Îª
2s22p3
2s22p3
£»
£¨2£©ÔÚµªÆø·Ö×ÓÖУ¬µªÔ­×ÓÖ®¼ä´æÔÚ×Å
1
1
¸ö¦Ò¼üºÍ
2
2
¸ö¦Ð¼ü£»
£¨3£©µª¡¢Ñõ¡¢·úÊÇͬÖÜÆÚÏàÁÚµÄÈýÖÖÔªËØ£¬±È½Ï£º
¢ÙµªÔ­×ӵĵÚÒ»µçÀëÄÜ
´óÓÚ
´óÓÚ
£¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©ÑõÔ­×ӵĵÚÒ»µçÀëÄÜ£»
¢ÚN2·Ö×ÓÖеªµª¼üµÄ¼ü³¤
СÓÚ
СÓÚ
£¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©F2·Ö×ÓÖзú·ú¼üµÄ¼ü³¤£»
£¨4£©µªÔªËصÄÇ⻯Îï--NH3ÊÇÒ»ÖÖÒ×Òº»¯µÄÆøÌ壬¸ÃÆøÌåÒ×Òº»¯µÄÔ­ÒòÊÇ
°±·Ö×ÓÖ®¼äÈÝÒ×ÐγÉÇâ¼ü£¬Ê¹Æä·ÐµãÉý¸ß¶øÈÝÒ×Òº»¯
°±·Ö×ÓÖ®¼äÈÝÒ×ÐγÉÇâ¼ü£¬Ê¹Æä·ÐµãÉý¸ß¶øÈÝÒ×Òº»¯
£»
£¨5£©ÅäºÏÎï[Cu£¨NH3£©4]Cl2Öк¬ÓÐ4¸öÅäλ¼ü£¬ÈôÓÃ2¸öN2H4´úÌæÆäÖеÄ2¸öNH3£¬µÃµ½µÄÅäºÏÎï[Cu£¨NH3£©2£¨N2H4£©2]Cl2Öк¬ÓÐÅäλ¼üµÄ¸öÊýΪ
4
4
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾»¯Ñ§¡ª¡ªÎïÖʽṹÓëÐÔÖÊ¡¿

µª¼°Æ仯ºÏÎïÔÚÉú»îÉú²úºÍ¿Æ¼¼µÈ·½ÃæÓÐÖØÒªµÄÓ¦Óá£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)µªÔªËØ»ù̬ԭ×ӵļ۵ç×ÓÅŲ¼Ê½Îª                      £»

(2)ÔÚµªÆø·Ö×ÓÖУ¬µªÔ­×ÓÖ®¼ä´æÔÚ×Å       ¸ö¦Ò¼üºÍ       ¸ö¦Ð¼ü£»

(3)Áס¢°±¡¢ÑõÊÇÖÜÆÚ±íÖÐÏàÁÚµÄÈýÖÖÔªËØ£¬±È½Ï£º

¢ÙµªÔ­×ӵĵÚÒ»µçÀëÄÜ         (Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±)ÑõÔ­×ӵĵÚÒ»µçÀëÄÜ£»

¢ÚN2·Ö×ÓÖеªµª¼üµÄ¼ü³¤       (Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±)°×Á×·Ö×ÓÖÐÁ×Á×¼üµÄ¼ü³¤£»

(4)µªÔªËصÄÇ⻯Î¡ªNH3ÊÇÒ»ÖÖÒ×Òº»¯µÄÆøÌ壬°±·Ö×ÓÖеªÔ­×ÓÔÓ»¯ÀàÐÍΪ    ÔÓ»¯£¬¸ÃÆøÌåÒ×Òº»¯µÄÔ­ÒòÊÇ                                     ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010Ä긣½¨Ê¡»ª°²Ò»Öи߶þÏÂѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔÌâ ÌâÐÍ£ºÌî¿ÕÌâ

£¨9·Ö£©µª¼°Æ仯ºÏÎïÔÚÉú»î¡¢Éú²úºÍ¿Æ¼¼µÈ·½ÃæÓÐÖØÒªµÄÓ¦Óá£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©µªÔªËØ»ù̬ԭ×ӵļ۵ç×ÓÅŲ¼Ê½Îª  ¡¡¡¡¡¡          £»
£¨2£©ÔÚµªÆø·Ö×ÓÖУ¬µªÔ­×ÓÖ®¼ä´æ·Å×Å          ¸ö¦Ò¼üºÍ         ¸ö¦Ð¼ü£»
£¨3£©N2·Ö×ÓÖеªµª¼üµÄ¼ü³¤             £¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©
F2·Ö×ÓÖзú·ú¼üµÄ¼ü³¤£»
£¨4£©µªÔªËصÄÇ⻯Î¡ªNH3ÊÇÒ»ÖÖÒ×Òº»¯µÄÆøÌ壬¸ÃÆøÌåÒ×Òº»¯µÄÔ­Òò
ÊÇ        ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡                  ¡£
£¨5£©ÅäºÏÎï[Cu(NH3)4]C12Öк¬ÓÐ4¸öÅäλ¼ü£¬ÈôÓÃ2¸öN2H4´úÌæÆäÖÐ2¸öNH3£¬µÃµ½µÄÅäºÏÎï[Cu(NH3)2(N2H4)2]C12Öк¬ÓÐÅäλ¼üµÄ¸öÊýΪ             ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄêºÓÄÏÊ¡Ö£ÖÝÊеÚËÄÖÐѧ¸ß¶þÏÂѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ

µª¼°Æ仯ºÏÎïÔÚÉú»î¡¢Éú²úºÍ¿Æ¼¼µÈ·½ÃæÓÐÖØÒªµÄÓ¦Óá£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1) Li3N¾§ÌåÖеªÒÔN3£­´æÔÚ£¬»ù̬N3£­µÄµç×ÓÅŲ¼Ê½Îª_____         ___¡£
(2)µªÔªËØ¿ÉÒÔÐγɱ»¯Îï¡¢µª»¯Îï¡¢µþµª»¯Îï¼°ÅäºÏÎïµÈ¶àÖÖ»¯ºÏÎï¡£
¢ÙNF3¡¢NBr3¡¢NCl3µÄ·ÐµãÓɸߵ½µÍµÄ˳ÐòÊÇ                 £¬ÆäÖÐNF3ÖÐNÔ­×ÓµÄÔÓ»¯ÀàÐÍÊÇ        £¬·Ö×ӵĿռ乹ÐÍÊÇ        ¡£
¢ÚµþµªËᣨHN3£©ÊÇÒ»ÖÖÈõËᣬ¿ÉµçÀë³öN3-£¬ÆäµçÀë·½³Ìʽ                 ¡£Áíд³öÁ½ÖÖÓëN3-»¥ÎªµÈµç×ÓÌåµÄ·Ö×Ó         ¡¢          ¡£
¢ÛµªÔªËصÄÇ⻯ÎNH3ÊÇÒ»ÖÖÒ×Òº»¯µÄÆøÌ壬ÆäÒ×Òº»¯µÄÔ­ÒòÊÇ      £»
(3)ÅäºÏÎï[Cu(NH3)4]Cl2ÖÐCu2+µÄÅäλÊýÊÇ       ¡£
(4) (CH3)3NH£«ºÍAlCl4¡ª¿ÉÐγÉÀë×ÓÒºÌå¡£Àë×ÓÒºÌåÓÉÒõ¡¢ÑôÀë×Ó×é³É£¬ÈÛµãµÍÓÚ100¡æ£¬Æä»Ó·¢ÐÔÒ»°ã±ÈÓлúÈܼÁ________(Ìî¡°´ó¡±»ò¡°Ð¡¡±)£¬¿ÉÓÃ×÷________(Ìî´úºÅ)¡£
a£®Öúȼ¼Á      b£®¡°ÂÌÉ«¡±ÈܼÁ   c£®¸´ºÏ²ÄÁÏ    d£®¾øÈȲÄÁÏ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010Ä긣½¨Ê¡¸ß¶þÏÂѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔÌâ ÌâÐÍ£ºÌî¿ÕÌâ

£¨9·Ö£©µª¼°Æ仯ºÏÎïÔÚÉú»î¡¢Éú²úºÍ¿Æ¼¼µÈ·½ÃæÓÐÖØÒªµÄÓ¦Óá£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©µªÔªËØ»ù̬ԭ×ӵļ۵ç×ÓÅŲ¼Ê½Îª   ¡¡¡¡¡¡           £»

£¨2£©ÔÚµªÆø·Ö×ÓÖУ¬µªÔ­×ÓÖ®¼ä´æ·Å×Å           ¸ö¦Ò¼üºÍ          ¸ö¦Ð¼ü£»

£¨3£©N2·Ö×ÓÖеªµª¼üµÄ¼ü³¤              £¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©

F2·Ö×ÓÖзú·ú¼üµÄ¼ü³¤£»

£¨4£©µªÔªËصÄÇ⻯Î¡ªNH3ÊÇÒ»ÖÖÒ×Òº»¯µÄÆøÌ壬¸ÃÆøÌåÒ×Òº»¯µÄÔ­Òò

ÊÇ         ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡                    ¡£

£¨5£©ÅäºÏÎï[Cu(NH3)4]C12Öк¬ÓÐ4¸öÅäλ¼ü£¬ÈôÓÃ2¸öN2H4´úÌæÆäÖÐ2¸öNH3£¬µÃµ½µÄÅäºÏÎï[Cu(NH3)2(N2H4)2]C12Öк¬ÓÐÅäλ¼üµÄ¸öÊýΪ              ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸