ËÕµ¤ºìÒ»ºÅ(sudan 1)ÊÇÒ»ÖÖżµªÈ¾ÁÏ£¬²»ÄÜ×÷ΪʳƷÌí¼Ó¼ÁʹÓá£ËüÊÇÓɱ½°·ºÍ2-ÝÁ·ÓΪÖ÷ÒªÔ­ÁÏÖƱ¸µÄ£¬ËüÃǵĽṹ¼òʽÈçÏÂËùʾ£º

(1)ËÕµ¤ºìÒ»ºÅµÄ»¯Ñ§Ê½(·Ö×Óʽ)Ϊ______________________¡£

(2)ÔÚÊʵ±µÄÌõ¼þÏ£¬2-ÝÁ·Ó¾­·´Ó¦¿ÉµÃµ½·¼Ï㻯ºÏÎïE(C8H6O4)£¬1 mol EÓëÊÊÁ¿µÄ̼ËáÇâÄÆÈÜÒº·´Ó¦¿É·Å³ö¶þÑõ»¯Ì¼44.8 L(±ê×¼×´¿ö)£¬EÓëäåÔÚÓд߻¯¼Á´æÔÚʱ·´Ó¦Ö»ÄÜÉú³ÉÁ½ÖÖÒ»äå´úÎÁ½ÖÖÒ»äå´úÎïµÄ½á¹¹¼òʽ·Ö±ðÊÇ_____________________£¬________________________£»EÓë̼ËáÇâÄÆ·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ____________________________________¡£

(3)Èô½«EÓë×ãÁ¿ÒÒ´¼ÔÚŨÁòËá×÷ÓÃϼÓÈÈ£¬¿ÉÒÔÉú³ÉÒ»¸ö»¯Ñ§Ê½(·Ö×Óʽ)ΪC12H14O4µÄл¯ºÏÎ¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ_______________________________£»·´Ó¦ÀàÐÍΪ___________¡£

(1)C16H12N2O

  õ¥»¯·´Ó¦

½âÎö£º(1)Ö÷Òª¿¼²é¸÷ÔªËØÔ­×ӵijɼü¹æÂÉ£¬ËÕµ¤ºìÒ»ºÅµÄ»¯Ñ§Ê½Ö±½ÓÓɽṹ¼òʽ²é³öC¡¢H¡¢N¡¢OµÄÔ­×Ó¸öÊý¡£(2)Ö÷Òª¿¼ÓÉÐÔÖÊÍƶÏÓлúÎïµÄ½á¹¹£¬1 molµÄEÓëÊÊÁ¿µÄ̼ËáÇâÄÆÈÜÒº·´Ó¦¿É·Å³ö2 mol¶þÑõ»¯Ì¼£¬¿ÉÖªEÖк¬ÓÐÁ½¸ö¡ªCOOH£¬ÓÖÒò2¡ªÝÁ·Ó¾­·´Ó¦¿ÉµÃµ½·¼Ï㻯ºÏÎïE(C8H6O4)£¬¼´EµÄ½á¹¹¼òʽΪ£¬1 molµÄEÖк¬ÓÐ2 mol ¡ªCOOH£¬Óë2 molµÄÒÒ´¼·¢Éúõ¥»¯·´Ó¦£¬Éú³ÉÎïµÄ»¯Ñ§Ê½ÕýºÃΪC12H14O4¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ËÕµ¤ºìÒ»ºÅ(sudan 1)ÊÇÒ»ÖÖżµªÈ¾ÁÏ£¬²»ÄÜ×÷ΪʳƷÌí¼Ó¼ÁʹÓá£ËüÊÇÓɱ½°·ºÍ2-ÝÁ·ÓΪÖ÷ÒªÔ­ÁÏÖƱ¸µÄ£¬ËüÃǵĽṹ¼òʽÈçÏÂËùʾ£º

(1)ËÕµ¤ºìÒ»ºÅµÄ»¯Ñ§Ê½(·Ö×Óʽ)Ϊ______________________________¡£

(2)ÔÚÊʵ±µÄÌõ¼þÏ£¬2-ÝÁ·Ó¾­·´Ó¦¿ÉµÃµ½·¼Ï㻯ºÏÎïE(C8H6O4)£¬1 mol EÓëÊÊÁ¿µÄ̼ËáÇâÄÆÈÜÒº·´Ó¦¿É·Å³ö¶þÑõ»¯Ì¼44.8 L(±ê×¼×´¿ö)£¬EÓëäåÔÚÓд߻¯¼Á´æÔÚʱ·´Ó¦Ö»ÄÜÉú³ÉÁ½ÖÖÒ»äå´úÎÁ½ÖÖÒ»äå´úÎïµÄ½á¹¹¼òʽ·Ö±ðÊÇ___________£¬___________£»EÓë̼ËáÇâÄÆ·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ______________________________¡£

(3)Èô½«EÓë×ãÁ¿ÒÒ´¼ÔÚŨÁòËá×÷ÓÃϼÓÈÈ£¬¿ÉÒÔÉú³ÉÒ»¸ö»¯Ñ§Ê½(·Ö×Óʽ)ΪC12H14O4µÄл¯ºÏÎ¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ________________________________________  £¬·´Ó¦ÀàÐÍÊÇ____________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ËÕµ¤ºìÒ»ºÅ(sudan ¢ñ)ÊÇÒ»ÖÖżµªÈ¾ÁÏ£¬²»ÄÜ×÷ΪʳƷÌí¼Ó¼ÁʹÓá£ËüÊÇÓɱ½°·ºÍ2-ÝÁ·ÓΪÖ÷ÒªÔ­ÁÏÖƱ¸µÄ£¬ËüÃǵĽṹ¼òʽÈçÏÂËùʾ£º

(1)ËÕµ¤ºìÒ»ºÅµÄ»¯Ñ§Ê½(·Ö×Óʽ)Ϊ____________¡£

(2)ÔÚÏÂÃ滯ºÏÎïA¡ªDÖУ¬Óë2-ÝÁ·Ó»¥ÎªÍ¬·ÖÒì¹¹ÌåµÄÓÐ(Ìî×Öĸ´úºÅ) ____________ (Ìáʾ£º¿É±íʾΪ)

(3)ÉÏÊö»¯ºÏÎï(C)º¬ÓеĹÙÄÜÍÅÊÇ____________________¡£

(4)ÔÚÊʵ±µÄÌõ¼þÏ£¬2-ÝÁ·Ó¾­·´Ó¦¿ÉµÃµ½·¼Ï㻯ºÏÎïE(C8H6O4)£¬1 mol EÓëÊÊÁ¿µÄ̼ËáÇâÄÆÈÜÒº·´Ó¦¿É·Å³ö¶þÑõ»¯Ì¼44.8 L(±ê×¼×´¿ö)£¬EÓëäåÔÚÓд߻¯¼Á´æÔÚʱ·´Ó¦Ö»ÄÜÉú³ÉÁ½ÖÖÒ»äåÈ¡´úÎÁ½ÖÖÒ»äåÈ¡´úÎïµÄ½á¹¹¼òʽ·Ö±ðÊÇ__________£¬EÓë̼ËáÇâÄÆ·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ____________________¡£

(5)Èô½«EÓë×ãÁ¿ÒÒ´¼ÔÚŨÁòËá×÷ÓÃϼÓÈÈ£¬¿ÉÒÔÉú³ÉÒ»¸ö»¯Ñ§Ê½(·Ö×Óʽ)ΪC12H14O4µÄл¯ºÏÎ¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ__________£¬·´Ó¦ÀàÐÍÊÇ____________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ËÕµ¤ºìÒ»ºÅ(sudan ¢ñ)ÊÇÒ»ÖÖżµªÈ¾ÁÏ£¬²»ÄÜ×÷ΪʳƷÌí¼Ó¼ÁʹÓá£ËüÊÇÓɱ½°·ºÍ2-ÝÁ·ÓΪÖ÷ÒªÔ­ÁÏÖƱ¸µÄ£¬ËüÃǵĽṹ¼òʽÈçÏÂËùʾ£º

(1)ËÕµ¤ºìÒ»ºÅµÄ»¯Ñ§Ê½(·Ö×Óʽ)Ϊ___________¡£

(2)ÔÚÏÂÃ滯ºÏÎï(A)¡ª(D)ÖУ¬Óë2-ÝÁ·Ó»¥ÎªÍ¬·ÖÒì¹¹ÌåµÄÓÐ(Ìî×Öĸ´úºÅ)___________¡£

(3)ÉÏÊö»¯ºÏÎï(C)º¬ÓеĹÙÄÜÍÅÊÇ___________¡£

(4)ÔÚÊʵ±µÄÌõ¼þÏ£¬2-ÝÁ·Ó¾­·´Ó¦¿ÉµÃµ½·¼Ï㻯ºÏÎïE(C8H6O4)£¬1mol EÓëÊÊÁ¿µÄ̼ËáÇâÄÆÈÜÒº·´Ó¦¿É·Å³ö¶þÑõ»¯Ì¼44.8 L(±ê×¼×´¿ö)£¬EÓëäåÔÚÓд߻¯¼Á´æÔÚʱ·´Ó¦Ö»ÄÜÉú³ÉÁ½ÖÖÒ»äå´úÎÁ½ÖÖÒ»äå´úÎïµÄ½á¹¹¼òʽ·Ö±ðÊÇ______________________£¬EÓë̼ËáÇâÄÆ·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ__________________________________________________________________¡£

(5)Èô½«EÓë×ãÁ¿ÒÒ´¼ÔÚŨÁòËá×÷ÓÃϼÓÈÈ£¬¿ÉÒÔÉú³ÉÒ»¸ö»¯Ñ§Ê½(·Ö×Óʽ)ΪC12H14O4µÄл¯ºÏÎ¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ______________________£¬·´Ó¦ÀàÐÍÊÇ___________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ËÕµ¤ºìÒ»ºÅ(sudan ¢ñ)ÊÇÒ»ÖÖżµªÈ¾ÁÏ£¬²»ÄÜ×÷ΪʳƷÌí¼Ó¼ÁʹÓá£ËüÊÇÓɱ½°·ºÍ2ÝÁ·ÓΪÖ÷ÒªÔ­ÁÏÖƱ¸µÄ£¬ËüÃǵĽṹ¼òʽÈçÏÂËùʾ£º

(1)ËÕµ¤ºìÒ»ºÅµÄ»¯Ñ§Ê½(·Ö×Óʽ)Ϊ_________¡£

(2)ÔÚÏÂÃ滯ºÏÎï(A)¡«(D)ÖУ¬Óë2-ÝÁ·Ó»¥ÎªÍ¬·ÖÒì¹¹ÌåµÄÓÐ(Ìî×Öĸ´úºÅ)______¡£(Ìáʾ£º¿É±íʾΪ)

(3)ÉÏÊö»¯ºÏÎï(C)º¬ÓеĹÙÄÜÍÅÊÇ______________¡£

(4)ÔÚÊʵ±µÄÌõ¼þÏ£¬2-ÝÁ·Ó¾­·´Ó¦¿ÉµÃµ½·¼Ï㻯ºÏÎïE(C8H6O4)£¬1 mol EÓëÊÊÁ¿µÄ̼ËáÇâÄÆÈÜÒº·´Ó¦¿É·Å³ö¶þÑõ»¯Ì¼44.8 L(±ê×¼×´¿ö)£¬EÓëäåÔÚÓд߻¯¼Á´æÔÚʱ·´Ó¦Ö»ÄÜÉú³ÉÁ½ÖÖÒ»äåÈ¡´úÎÁ½ÖÖÒ»äåÈ¡´úÎïµÄ½á¹¹¼òʽ·Ö±ðÊÇ__________________£¬EÓë̼ËáÇâÄÆ·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ___________________________¡£

(5)Èô½«EÓë×ãÁ¿ÒÒ´¼ÔÚŨÁòËá×÷ÓÃϼÓÈÈ£¬¿ÉÒÔÉú³ÉÒ»¸ö»¯Ñ§Ê½(·Ö×Óʽ)ΪC12H14O4µÄл¯ºÏÎ¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ_______________________£¬·´Ó¦ÀàÐÍÊÇ________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ËÕµ¤ºìÒ»ºÅ(sudan ¢ñ)ÊÇÒ»ÖÖżµªÈ¾ÁÏ£¬²»ÄÜ×÷ΪʳƷÌí¼Ó¼ÁʹÓá£ËüÊÇÓɱ½°·ºÍ2-ÝÁ·ÓΪÖ÷ÒªÔ­ÁÏÖƱ¸µÄ£¬ËüÃǵĽṹ¼òʽÈçÏÂËùʾ£º

 

(1)ËÕµ¤ºìÒ»ºÅµÄ»¯Ñ§Ê½(·Ö×Óʽ)Ϊ______________¡£

(2)ÔÚÏÂÃ滯ºÏÎïA¡ªDÖУ¬Óë2-ÝÁ·Ó»¥ÎªÍ¬·ÖÒì¹¹ÌåµÄÓÐ(Ìî×Öĸ´úºÅ) _______¡£

(Ìáʾ£º¿É±íʾΪ)

   

(3)ÉÏÊö»¯ºÏÎïCº¬ÓеĹÙÄÜÍÅÊÇ___________¡£

(4)ÔÚÊʵ±µÄÌõ¼þÏ£¬2-ÝÁ·Ó¾­·´Ó¦¿ÉµÃµ½·¼Ï㻯ºÏÎïE(C8H6O4)£¬1 mol EÓëÊÊÁ¿µÄ̼ËáÇâÄÆÈÜÒº·´Ó¦¿É·Å³ö¶þÑõ»¯Ì¼44.8 L(±ê×¼×´¿ö)£¬EÓëäåÔÚÓд߻¯¼Á´æÔÚʱ·´Ó¦Ö»ÄÜÉú³ÉÁ½ÖÖÒ»äåÈ¡´úÎÁ½ÖÖÒ»äåÈ¡´úÎïµÄ½á¹¹¼òʽ·Ö±ðÊÇ___________£»EÓë̼ËáÇâÄÆ·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ ___________ ¡£

(5)Èô½«EÓë×ãÁ¿ÒÒ´¼ÔÚŨÁòËá×÷ÓÃϼÓÈÈ£¬¿ÉÒÔÉú³ÉÒ»¸ö»¯Ñ§Ê½(·Ö×Óʽ)ΪC12H14O4µÄл¯ºÏÎ¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ_________________£¬·´Ó¦ÀàÐÍÊÇ_________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸