Question

13£®±ûÏ©´¼£¨CH₂=CH-CH₂OH£©ÊÇÒ»ÖÖÎÞÉ«Óд̼¤ÐÔÆøζµÄÒºÌ壬ÊÇÖØÒªµÄÓлúºÏ³ÉÔ­ÁÏ£®Çë»Ø´ð£º
£¨1£©±ûÏ©´¼µÄ·Ö×ÓʽΪC₃H₆O£»±ûÏ©´¼Öк¬ÓеĹÙÄÜÍŵÄÃû³ÆÊÇ̼̼˫¼üºÍ´¼ôÇ»ù£®
£¨2£©Ð´³ö±ûÏ©´¼ÔÚÍ­×÷´ß»¯¼Á´æÔÚÏ·´Ó¦µÄ»¯Ñ§·½³Ìʽ2CH₂=CH-CH₂OH+O₂$¡ú_{¡÷}^{Cu}$2CH₂=CHCHO+2H₂O£¨²»¿¼ÂÇË«¼üµÄÑõ»¯£©
£¨3£©Ð´³ö±ûÏ©´¼ÓëäåË®·´Ó¦µÄ»¯Ñ§·½³ÌʽCH₂=CH-CH₂OH+Br₂¡úCH₂BrCHBrCH₂OH£¬·´Ó¦ÀàÐÍΪ¼Ó³É·´Ó¦
£¨4£©±ûÏ©´¼ÓëCH₃CO¹⁸OH·¢Éúõ¥»¯·´Ó¦µÄ»¯·½³ÌʽΪ£ºCH₃CO¹⁸OH+CH₂=CH-CH₂OHCH₃COOCH₂CH=CH₂+H₂¹⁸O£¬õ¥»¯·´Ó¦Éú³ÉµÄ²úÎïÔÚÒ»¶¨Ìõ¼þÏ¿ÉÒÔ·¢Éú¼Ó¾Û·´Ó¦µÃµ½¸ß·Ö×Ó»¯ºÏÎÆä½á¹¹¼òʽ£®

Answer 1

·ÖÎö £¨1£©¸ù¾Ý½á¹¹¼òʽȷ¶¨·Ö×Óʽ£»±ûÏ©´¼ÖйÙÄÜÍÅÊÇ̼̼˫¼üºÍ´¼ôÇ»ù£»
£¨2£©ÔÚCu×÷´ß»¯¼Á¡¢¼ÓÈÈÌõ¼þÏ£¬±ûÏ©´¼·¢ÉúÑõ»¯·´Ó¦Éú³É±ûÏ©È©£»
£¨3£©±ûÏ©´¼ºÍäå·¢Éú¼Ó³É·´Ó¦Éú³É1£¬2-¶þäå±û´¼£»
£¨4£©±ûÏ©´¼ºÍÒÒËá·¢Éúõ¥»¯·´Ó¦Éú³ÉÒÒËá±ûÏ©õ¥£¬ÒÒËá±ûÏ©õ¥ÔÚÒ»¶¨Ìõ¼þÏ·¢Éú¼Ó¾Û·´Ó¦Éú³É¸ß·Ö×Ó»¯ºÏÎ

½â´ð ½â£º£¨1£©¸ù¾Ý½á¹¹¼òʽ֪£¬±ûÏ©´¼·Ö×ÓʽΪC₃H₆O£¬±ûÏ©´¼ÖйÙÄÜÍÅΪ̼̼˫¼üºÍ´¼ôÇ»ù£»
¹Ê´ð°¸Îª£ºC₃H₆O£»Ì¼Ì¼Ë«¼ü¡¢´¼ôÇ»ù£»
£¨2£©ÔÚCu×÷´ß»¯¼Á¡¢¼ÓÈÈÌõ¼þÏ£¬±ûÏ©´¼·¢ÉúÑõ»¯·´Ó¦Éú³É±ûÏ©È©£¬·´Ó¦·½³ÌʽΪ2CH₂=CH-CH₂OH+O₂$¡ú_{¡÷}^{Cu}$2CH₂=CHCHO+2H₂O£¬
¹Ê´ð°¸Îª£º2CH₂=CH-CH₂OH+O₂$¡ú_{¡÷}^{Cu}$2CH₂=CHCHO+2H₂O£»
£¨3£©±ûÏ©´¼º¬ÓÐ̼̼˫¼ü£¬¿ÉÓëäåË®·¢Éú¼Ó³É·´Ó¦£¬·´Ó¦µÄ·½³ÌʽΪCH₂=CH-CH₂OH+Br₂¡úCH₂BrCHBrCH₂OH£¬
¹Ê´ð°¸Îª£ºCH₂=CH-CH₂OH+Br₂¡úCH₂BrCHBrCH₂OH£»¼Ó³É·´Ó¦£»
£¨4£©Ï©±û´¼ÓëCH₃CO¹⁸OH·¢Éúõ¥»¯·´Ó¦µÄ»¯·½³ÌʽΪCH₃CO¹⁸OH+CH₂=CH-CH₂OHCH₃COOCH₂CH=CH₂+H₂¹⁸O£¬õ¥»¯·´Ó¦Éú³ÉµÄ²úÎïÔÚÒ»¶¨Ìõ¼þÏ¿ÉÒÔ·¢Éú¼Ó¾Û·´Ó¦µÃµ½¾Û±ûÏ©ËáÒÒõ¥£¬½á¹¹¼òʽΪ£¬
¹Ê´ð°¸Îª£ºCH₃CO¹⁸OH+CH₂=CH-CH₂OHCH₃COOCH₂CH=CH₂+H₂¹⁸O£»£®

µãÆÀ ±¾Ì⿼²éÓлúÎï½á¹¹ºÍÐÔÖÊ£¬Îª¸ßƵ¿¼µã£¬Ã÷È·¹ÙÄÜÍż°ÆäÐÔÖʹØϵ¼´¿É½â´ð£¬×¢Òâõ¥»¯·´Ó¦¶Ï¼üºÍ³É¼ü·½Ê½£¬ÎªÒ×´íµã£®