ϱíÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö£¬±íÖÐËùÁеÄ×Öĸ·Ö±ð´ú±íÒ»ÖÖ»¯Ñ§ÔªËØ¡£
(1)д³öÓÉÉÏÊöÁ½ÖÖÔªËØ×é³ÉX2Y2ÐÍ»¯ºÏÎïµÄ»¯Ñ§Ê½·Ö±ðΪ____________£¬Æ侧ÌåÀàÐÍ·Ö±ðΪ__________________¡£
(2)B¡¢C¡¢DµÄÇ⻯ÎïÖУ¬·Ðµã×î¸ßµÄÇ⻯ÎïµÄ½á¹¹Ê½ÊÇ____________£¬¸»º¬·Ðµã×îµÍµÄÇ⻯ÎïµÄ¿óÎïµÄÃû³ÆÊÇ____________¡£
(3)ÉÏÊöÔªËØÐγɵĵ¥ÖÊÖУ¬ÊôÓÚÔ×Ó¾§ÌåµÄÊÇ________(ÌîÃû³Æ)£¬Æä¿Õ¼ä¹¹ÐÍΪ________________¡£
(4)д³öÓÉÉÏÊöÔªËØÖÐÏàͬµÄËÄÖÖÔªËØ×é³ÉµÄÁ½ÖÖ»¯ºÏÎïµÄË®ÈÜÒº·¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ£º_____________________¡£
(5)д³öÓÉÉÏÊöÔªËØÖеÄÈýÖÖÐγɵļȺ¬ÓÐÀë×Ó¼üÓÖº¬Óм«ÐÔ¹²¼Û¼üµÄ»¯ºÏÎïµÄµç×Óʽ£º____________________(ÈÎдÁ½¸ö)¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ºÏ³É°±µÄÁ÷³ÌʾÒâͼÈçÏ£º
»Ø´ðÏÂÁÐÎÊÌ⣺
(1)¹¤ÒµºÏ³É°±µÄÔÁÏÊǵªÆøºÍÇâÆø¡£µªÆøÊÇ´Ó¿ÕÆøÖзÖÀë³öÀ´µÄ£¬Í¨³£Ê¹ÓõÄÁ½ÖÖ·ÖÀë·½·¨ÊÇ________¡¢________£»ÇâÆøµÄÀ´Ô´ÊÇË®ºÍ̼Ç⻯ºÏÎд³ö·Ö±ð²ÉÓÃúºÍÌìÈ»ÆøΪÔÁÏÖÆÈ¡ÇâÆøµÄ»¯Ñ§·½³Ìʽ_______________________¡£
(2)É豸AÖк¬Óеç¼ÓÈÈÆ÷£¬´¥Ã½ºÍÈȽ»»»Æ÷£¬É豸AµÄÃû³ÆÊÇ________£¬ÆäÖз¢ÉúµÄ»¯Ñ§·´Ó¦·½³ÌʽΪ____________¡£
(3)É豸BµÄÃû³ÆΪ________£¬ÆäÖÐmºÍnÊÇÁ½¸öͨˮ¿Ú£¬ÈëË®¿ÚÊÇ________(Ìî¡°m¡±»ò¡°n¡±)¡£²»ÒË´ÓÏà·´·½ÏòͨˮµÄÔÒòÊÇ______________¡£
(4)É豸CµÄ×÷ÓÃÊÇ______________________¡£
(5)ÔÚÔÁÏÆøÖƱ¸¹ý³ÌÖлìÓеÄCO¶Ô´ß»¯¼ÁÓж¾º¦×÷Óã¬Óû³ýÈ¥ÔÁÏÆøÖеÄCO£¬¿Éͨ¹ýÈçÏ·´Ó¦À´ÊµÏÖ£º
CO(g)£«H2O(g) CO2(g)£«H2(g)
ÒÑÖª1 000 Kʱ¸Ã·´Ó¦µÄƽºâ³£ÊýK£½0.627£¬ÈôҪʹCOµÄת»¯Âʳ¬¹ý90%£¬ÔòÆðʼÎïÖÐc(H2O)¡Ãc(CO)²»µÍÓÚ________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÃÀ¹ú¿Æѧ¼ÒÀí²éµÂ·º£¿ËºÍÈÕ±¾¿Æѧ¼Ò¸ù°¶Ó¢Ò»¡¢ÁåľÕÃÒòÔÚÑз¢¡°ÓлúºÏ³ÉÖеÄîÙ´ß»¯µÄ½»²æżÁª¡±¶ø»ñµÃ2010Äê¶Èŵ±´¶û»¯Ñ§½±¡£ÓлúºÏ³É³£ÓõÄîÙ/»îÐÔÌ¿´ß»¯¼Á£¬³¤ÆÚʹÓô߻¯¼Á»á±»ÔÓÖÊ(È磺Ìú¡¢ÓлúÎïµÈ)ÎÛȾ¶øʧȥ»îÐÔ£¬³ÉΪ·Ï´ß»¯¼Á£¬Ðè¶ÔÆäÔÙÉú»ØÊÕ¡£Ò»ÖÖÓÉ·Ï´ß»¯¼ÁÖÆÈ¡ÂÈ»¯îٵŤÒÕÁ÷³ÌÈçÏ£º
(1)·ÏîÙ´ß»¯¼Á¾ºæ¸Éºó£¬ÔÙÔÚ700 ¡æµÄ¸ßÎÂϱºÉÕ£¬±ºÉÕ¹ý³ÌÖÐÐèͨÈë×ãÁ¿¿ÕÆøµÄÔÒòÊÇ________________________________________________________________________£»
¼×ËỹÔÑõ»¯îٵĻ¯Ñ§·½³ÌʽΪ__________________________________________¡£
(2)îÙÔÚÍõË®(ŨÏõËáÓëŨÑÎËá°´Ìå»ý±È1¡Ã3)ÖÐת»¯ÎªH2PdCl4£¬ÏõËỹÔΪNO£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______________________¡£
(3)îÙ¾«ÔüÖÐîٵĻØÊÕÂʸߵÍÖ÷Ҫȡ¾öÓÚÍõË®ÈܽâµÄ²Ù×÷Ìõ¼þ£¬ÒÑÖª·´Ó¦Î¶ȡ¢·´Ó¦Ê±¼äºÍÍõË®ÓÃÁ¿¶ÔîÙ»ØÊÕÂʵÄÓ°ÏìÈçÏÂͼ1¡«Í¼3Ëùʾ£¬ÔòÍõË®ÈܽâîÙ¾«ÔüµÄÊÊÒËÌõ¼þ(ζȡ¢Ê±¼äºÍÍõË®ÓÃÁ¿)Ϊ__________¡¢__________¡¢__________¡£
(4)¼ÓŨ°±Ë®Ê±£¬îÙת±äΪ¿ÉÈÜÐÔ[Pd(NH3)2]2£«£¬´ËʱÌúµÄ´æÔÚÐÎʽÊÇ________________________________________________________________________(д»¯Ñ§Ê½)¡£
(5)700 ¡æ±ºÉÕ1µÄÄ¿µÄÊÇ________________£»550 ¡æ±ºÉÕ2µÄÄ¿µÄÊÇ________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÔçÆÚ·¢ÏÖµÄÒ»ÖÖÌìÈ»×¼¾§¿ÅÁ£ÓÉÈýÖÖAl¡¢Cu¡¢FeÔªËØ×é³É¡£»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©×¼¾§ÊÇÒ»ÖÖÎÞƽÒÆÖÜÆÚÐò£¬µ«ÓÐÑϸñ×¼ÖÜÆÚλÖÃÐòµÄ¶ÀÌؾ§Ì壬¿Éͨ¹ý ·½·¨Çø·Ö¾§Ìå¡¢×¼¾§ÌåºÍ·Ç¾§Ìå¡£
£¨2£©»ù̬ÌúÔ×ÓÓÐ ¸öδ³É¶Ôµç×Ó£¬Èý¼ÛÌúÀë×ӵĵç×ÓÅŲ¼Ê½Îª£º ¿ÉÓÃÁòÇ軯¼Ø¼ìÑéÈý¼ÛÌúÀë×Ó£¬ÐγÉÅäºÏÎïµÄÑÕɫΪ
£¨3£©ÐÂÖƱ¸µÄÇâÑõ»¯Í¿É½«ÒÒÈ©Ñõ»¯ÎªÒÒËᣬ¶ø×ÔÉí»¹Ô³ÉÑõ»¯ÑÇÍ£¬ÒÒÈ©ÖÐ̼Ô×ÓµÄÔÓ»¯¹ìµÀÀàÐÍΪ ______£»Ò»Ä¦¶ûÒÒÈ©·Ö×ÓÖк¬ÓеĦҼüµÄÊýĿΪ£º ¡£ÒÒËáµÄ·ÐµãÃ÷ÏÔ¸ßÓÚÒÒÈ©£¬ÆäÖ÷ÒªÔÒòÊÇ£º ¡£Ñõ»¯ÑÇÍΪ°ëµ¼Ìå²ÄÁÏ£¬ÔÚÆäÁ¢·½¾§°ûÄÚ²¿ÓÐËĸöÑõÔ×Ó£¬ÆäÓàÑõÔ×ÓλÓÚÃæÐĺͶ¥µã£¬Ôò¸Ã¾§°ûÖÐÓÐ ¸öÍÔ×Ó¡£
£¨4£©ÂÁµ¥ÖÊΪÃæÐÄÁ¢·½¾§Ì壬Æ侧°û²ÎÊýa£½0£®405nm£¬¾§°ûÖÐÂÁÔ×ÓµÄÅäλÊýΪ ¡£ÁÐʽ±íʾÂÁµ¥ÖʵÄÃÜ¶È g·cm£3(²»±Ø¼ÆËã³ö½á¹û)
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
A¡¢B¡¢C¡¢DÊÇÔªËØÖÜÆÚ±íÖÐÇ°36ºÅÔªËØ,ËüÃǵĺ˵çºÉÊýÒÀ´ÎÔö´ó¡£AÔ×ÓL²ãµÄ³É¶Ôµç×ÓÊýºÍδ³É¶Ôµç×ÓÊýÏàµÈ,BÔ×ÓµÄ×îÍâ²ãp¹ìµÀµÄµç×ÓΪ°ë³äÂú½á¹¹,CÊǵؿÇÖк¬Á¿×î¶àµÄÔªËØ¡£DÊǵÚËÄÖÜÆÚÔªËØ,ÆäÔ×ÓºËÍâ×îÍâ²ãµç×ÓÊýÓëÇâÔ×ÓÏàͬ,ÆäÓà¸÷²ãµç×Ó¾ù³äÂú¡£Çë»Ø´ðÏÂÁÐÎÊÌâ:
(1)A¡¢B¡¢CµÄµÚÒ»µçÀëÄÜÓÉСµ½´óµÄ˳ÐòÊÇ¡¡¡¡¡¡¡¡(ÓöÔÓ¦µÄÔªËØ·ûºÅ±íʾ);»ù̬DÔ×ӵĵç×ÓÅŲ¼Ê½Îª¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£
(2)AµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯Îï·Ö×ÓÖÐ,ÆäÖÐÐÄÔ×Ó²ÉÈ¡¡¡¡¡¡¡¡¡ÔÓ»¯;BµÄ¿Õ¼ä¹¹ÐÍΪ¡¡¡¡¡¡¡¡(ÓÃÎÄ×ÖÃèÊö)¡£
(3)1 mol AB-Öк¬ÓеĦмü¸öÊýΪ¡¡¡¡¡¡¡¡¡£
(4)ÈçͼÊǽðÊôCaºÍDËùÐγɵÄijÖֺϽðµÄ¾§°û½á¹¹Ê¾Òâͼ,Ôò¸ÃºÏ½ðÖÐCaºÍDµÄÔ×Ó¸öÊý±ÈÊÇ¡¡¡¡¡¡¡¡¡£
(5)ïçÄøºÏ½ðÓëÉÏÊöºÏ½ð¶¼¾ßÓÐÏàͬÀàÐ͵ľ§°û½á¹¹XYn,ËüÃÇÓкÜÇ¿µÄ´¢ÇâÄÜÁ¦¡£ÒÑÖªïçÄøºÏ½ðLaNin¾§°ûÌå»ýΪ9.0¡Á10-23 cm3,´¢ÇâºóÐγÉLaNinH4.5ºÏ½ð(Çâ½øÈ뾧°û¿Õ϶,Ìå»ý²»±ä),ÔòLaNinÖÐn=¡¡¡¡¡¡¡¡(ÌîÊýÖµ);ÇâÔںϽðÖеÄÃܶÈΪ¡¡¡¡¡¡¡¡¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
Ò»Ïî¿ÆѧÑо¿³É¹û±íÃ÷£¬ÍÃÌÑõ»¯Îï(CuMn2O4)ÄÜÔÚ³£ÎÂÏ´߻¯Ñõ»¯¿ÕÆøÖеÄÒ»Ñõ»¯Ì¼ºÍ¼×È©(HCHO)¡£
(1)ÏòÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄCu(NO3)2ºÍMn(NO3)2ÈÜÒºÖмÓÈëNa2CO3ÈÜÒº£¬ËùµÃ³Áµí¾¸ßÎÂ×ÆÉÕ£¬¿ÉÖƵÃCuMn2O4¡£
¢ÙMn2£«»ù̬µÄµç×ÓÅŲ¼Ê½¿É±íʾΪ________¡£
¢ÚNOµÄ¿Õ¼ä¹¹ÐÍÊÇ________(ÓÃÎÄ×ÖÃèÊö)¡£
(2)ÔÚÍÃÌÑõ»¯ÎïµÄ´ß»¯Ï£¬CO±»Ñõ»¯ÎªCO2£¬HCHO±»Ñõ»¯ÎªCO2ºÍH2O¡£
¢Ù¸ù¾ÝµÈµç×ÓÌåÔÀí£¬CO·Ö×ӵĽṹʽΪ________¡£
¢ÚH2O·Ö×ÓÖÐOÔ×Ó¹ìµÀµÄÔÓ»¯ÀàÐÍΪ________¡£
¢Û1 mol CO2Öк¬ÓеĦҼüÊýĿΪ________¡£
(3)ÏòCuSO4ÈÜÒºÖмÓÈë¹ýÁ¿NaOHÈÜÒº¿ÉÉú³É[Cu(OH)4]2£¡£²»¿¼Âǿռ乹ÐÍ£¬[Cu(OH)4]2£µÄ½á¹¹¿ÉÓÃʾÒâͼ±íʾΪ________________________________________________________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¢Ú»¯Ñ§¶ÆÄøµÄÈÜÒºÖк¬ÓÐNi2+ºÍH2PO2££¬ÔÚËáÐÔµÈÌõ¼þÏ·¢ÉúÏÂÊö·´Ó¦£º£¨a£© Ni2+ + H2PO2£+ ¡ú Ni++ H2PO3£+
ÇëÔÚ´ðÌ⿨ÉÏд³ö²¢Åäƽ·´Ó¦Ê½£¨a£©¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÏÂÁжԡ°Ä¦¶û mol¡±µÄÐðÊö²»ÕýÈ·µÄÊÇ¡¡¡¡
A£®Ä¦¶ûÊÇÒ»¸öµ¥Î»£¬ÓÃÓÚ¼ÆÁ¿ÎïÖÊËùº¬Î¢¹ÛÁ£×ӵĶàÉÙ
B£®Ä¦¶û¼ÈÄÜÓÃÀ´¼ÆÁ¿´¿¾»ÎÓÖÄÜÓÃÀ´¼ÆÁ¿»ìºÏÎï
C£®1 molÈκÎÆøÌåËùº¬µÄÆøÌå·Ö×ÓÊýÄ¿¶¼ÏàµÈ
D£®Óá°Ä¦¶û¡±¶ø²»Óá°¸ö¡±¼ÆÁ¿Î¢¹ÛÁ£×ÓÓëÓá°ÄÉÃס±¶ø²»Óá°Ãס±¼ÆÁ¿Ô×ÓÖ±¾¶£¬¼ÆÁ¿Ë¼Â·¶¼ÊÇÀ©´óµ¥Î»
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÉèNAΪ°¢·ü¼ÓµÂÂÞ³£ÊýµÄÖµ£»ÏÂÁÐÐðÊöÕýÈ·µÄÊÇ(¡¡¡¡)¡£
A£®±ê×¼×´¿öÏ£»33.6 L·ú»¯ÇâÖк¬ÓзúÔ×ÓµÄÊýĿΪ1.5NA
B£®³£Î³£Ñ¹Ï£»7.0 gÒÒÏ©Óë±ûÏ©µÄ»ìºÏÎïÖк¬ÓÐÇâÔ×ÓµÄÊýĿΪNA
C£®50 mL 18.4 mol·L-1ŨÁòËáÓë×ãÁ¿Í΢ÈÈ·´Ó¦£»Éú³ÉSO2·Ö×ÓµÄÊýĿΪ0.46NA
D£®Ä³ÃܱÕÈÝÆ÷Ê¢ÓÐ0.1 mol N2ºÍ0.3 mol H2£»ÔÚÒ»¶¨Ìõ¼þϳä·Ö·´Ó¦£»×ªÒƵç×ÓµÄÊýĿΪ0.6NA
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com