¡°»¯Ñ§¿ÉÒÔÔö´óµØÇòµÄÍÁµØ²úÁ¸Ãæ»ý¡±;ÒÔʯÓͲúÆ·ÒÒϩΪÆðʼԭÁϽøÐкϳɸ߷Ö×Ó»¯ºÏÎïFºÍG£¬ºÏ³É·ÏßÈçͼËùʾ£º

ÒÑÖª£ºEµÄ·Ö×ÓʽΪC4H6O2£¬FµÄ·Ö×ÓʽΪ(C4H6O2)n£¨Ë×Ãû¡°È齺¡±µÄÖ÷Òª³É·Ö£©£¬GµÄ·Ö×ÓʽΪ(C2H4O)n£¨¿ÉÓÃÓÚÖÆ»¯Ñ§½¬ºý£©£¬2CH2=CH2+2CH3COOH+O2 2C4H6O2£¨´×ËáÒÒÏ©õ¥£©+2H2O
ÓÖÖª£ºÓë½á¹¹ÏàËƵÄÓлúÎï²»Îȶ¨£¬·¢Éú·Ö×ÓÖØÅÅÉú³É
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Ð´³ö½á¹¹¼òʽ£ºD_______________£¬F___________________¡£
£¨2£©·´Ó¦¢Ù¡¢¢ÚµÄ·´Ó¦ÀàÐÍ______________¡¢___________________________¡£
£¨3£©Ð´³öÏÂÁÐÓйط´Ó¦µÄµÄ»¯Ñ§·½³Ìʽ¡£
A¡ª¡úB________________________________________________
B¡ª¡úC _______________________________________________

£¨1£©DΪCH3COOH£¬FΪ¡££¨2£©¼Ó³É·´Ó¦¡¢Ë®½â·´Ó¦¡£
£¨3£©ClCH2CH2Cl+H2O ClCH2CH2OH+HCl£»ClCH2CH2OH+ NaOHCH3CHO+NaCl+H2O¡£

½âÎöÊÔÌâ·ÖÎö£ºÓÉͼ¿ÉÒÔÍƶϳöAΪClCH2CH2Cl£¬BΪClCH2CH2OH£¬CΪCH3CHO£¬DΪCH3COOH£¬FΪËùÒÔ£¨1£©ÖУ¬DΪCH3COOH£¬FΪ£»£¨2£©ÖУ¬¢Ù¡¢¢ÚµÄ·´Ó¦·Ö±ðΪCH2=CH2+Cl2ClCH2CH2Cl£¬
 (C2H4O)n+nCH3COOH£¬¹ÊÆä·´Ó¦ÀàÐÍ·Ö±ðΪ¼Ó³É·´Ó¦¡¢Ë®½â·´Ó¦£»£¨3£©ÖУ¬A¡ª¡úBµÄ·´Ó¦·½³ÌʽΪClCH2CH2Cl+H2O ClCH2CH2OH+HCl£»B¡ª¡úCµÄ·´Ó¦·½³ÌʽΪClCH2CH2OH+ NaOHCH3CHO+NaCl+H2O¡£
¿¼µã£ºÓлúÍƶÏÌâ
µãÆÀ£º¸ÃÌâÊÇÒ»µÀÓлúÍƶÏÌ⣬ÊǸ߿¼¿¼²éµÄÖص㡣ÌâÖиø³öµÄÐÅÏ¢Á¿½Ï´ó£¬µ«ÊÇÏà¶ÔÀ´Ëµ»¹ÊDZȽÏÈÝÒ׵ġ£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¾«Ó¢¼Ò½ÌÍøµªÊǵØÇòÉϺ¬Á¿·á¸»µÄÒ»ÖÖÔªËØ£¬µª¼°Æ仯ºÏÎïÔÚ¹¤Å©ÒµÉú²ú¡¢Éú»îÖÐÓÐ×ÅÖØÒª×÷Óã¬
£¨1£©ÈçͼÊÇN2£¨g£©ºÍH2£¨g£©·´Ó¦Éú³É1mol NH3£¨g£©¹ý³ÌÖÐÄÜÁ¿±ä»¯Ê¾Òâͼ£¬Çëд³öN2ºÍH2·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£º
 
£»
£¨2£©ÈôÒÑÖªÏÂÁÐÊý¾Ý£º
»¯Ñ§¼ü H-H N¡ÔN
¼üÄÜ/kJ?mol-1 435 943
ÊÔ¸ù¾Ý±íÖм°Í¼ÖÐÊý¾Ý¼ÆËãN-HµÄ¼üÄÜ
 
kJ?mol-1
£¨3£©ºÏ³É°±·´Ó¦Í¨³£ÓÃÌú´¥Ã½×÷´ß»¯¼Á£®Ê¹ÓÃÌú´¥Ã½ºóE1ºÍE2µÄ±ä»¯ÊÇ£ºE1
 
£¬E2
 
£¨Ìî¡°Ôö´ó¡±¡¢¡°¼õС¡¢¡±¡°²»±ä¡±£©£®
£¨4£©ÓÃNH3´ß»¯»¹Ô­NOX»¹¿ÉÒÔÏû³ýµªÑõ»¯ÎïµÄÎÛȾ£®ÀýÈç
4NH3£¨g£©+3O2£¨g£©=2N2£¨g£©+6H2O£¨g£©£»¡÷H1=akJ/mol
N2£¨g£©+O2£¨g£©=2NO£¨g£©£»¡÷H2=bkJ/mol
Èô1mol NH3»¹Ô­NOÖÁN2£¬Ôò¸Ã·´Ó¦¹ý³ÌÖеķ´Ó¦ÈÈ¡÷H3=
 
kJ/mol£¨Óú¬a¡¢bµÄʽ×Ó±íʾ£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêÕã½­Ê¡º¼ÖݵØÇøÆßУ¸ß¶þÏÂѧÆÚÆÚÖÐÁª¿¼»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨8·Ö£©µªÊǵØÇòÉϺ¬Á¿·á¸»µÄÒ»ÖÖÔªËØ£¬µª¼°Æ仯ºÏÎïÔÚ¹¤Å©ÒµÉú²ú¡¢Éú»îÖÐÓÐ×ÅÖØÒª×÷Óã¬

£¨1£©ÉÏͼÊÇN2(g)ºÍH2(g)·´Ó¦Éú³É1mol NH3(g)¹ý³ÌÖÐÄÜÁ¿±ä»¯Ê¾Òâͼ£¬Çëд³öN2ºÍH2·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£º                                         £»
£¨2£©ÈôÒÑÖªÏÂÁÐÊý¾Ý£º

»¯Ñ§¼ü
H£­H
N¡ÔN
¼üÄÜ/kJ¡¤mol£­1
435
943
ÊÔ¸ù¾Ý±íÖм°Í¼ÖÐÊý¾Ý¼ÆËãN-HµÄ¼üÄÜ        kJ¡¤mol£­1
£¨3£©ºÏ³É°±·´Ó¦Í¨³£ÓÃÌú´¥Ã½×÷´ß»¯¼Á¡£Ê¹ÓÃÌú´¥Ã½ºóE1ºÍE2µÄ±ä»¯ÊÇ£ºE1______£¬E2______(Ìî¡°Ôö´ó¡±¡¢¡°¼õС¡¢¡±¡°²»±ä¡±)¡£
£¨4£©ÓÃNH3´ß»¯»¹Ô­NOX»¹¿ÉÒÔÏû³ýµªÑõ»¯ÎïµÄÎÛȾ¡£ÀýÈç
4NH3(g)+3O2(g) 2N2(g)+6H2O(g) £»¡÷H1= akJ¡¤mol-1
N2(g)+O2(g)  2NO(g)£»¡÷H2= bkJ/mol
Èô1mol NH3»¹Ô­NOÖÁN2£¬Ôò¸Ã·´Ó¦¹ý³ÌÖеķ´Ó¦ÈÈ¡÷H3=    kJ/mol£¨Óú¬a¡¢bµÄʽ×Ó±íʾ£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ìɽÎ÷Ê¡¸ß¶þ3ÔÂÔ¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÍƶÏÌâ

¡°»¯Ñ§¿ÉÒÔÔö´óµØÇòµÄÍÁµØ²úÁ¸Ãæ»ý¡±;ÒÔʯÓͲúÆ·ÒÒϩΪÆðʼԭÁϽøÐкϳɸ߷Ö×Ó»¯ºÏÎïFºÍG£¬ºÏ³É·ÏßÈçͼËùʾ£º

ÒÑÖª£ºEµÄ·Ö×ÓʽΪC4H6O2£¬FµÄ·Ö×ÓʽΪ(C4H6O2)n£¨Ë×Ãû¡°È齺¡±µÄÖ÷Òª³É·Ö£©£¬GµÄ·Ö×ÓʽΪ(C2H4O)n£¨¿ÉÓÃÓÚÖÆ»¯Ñ§½¬ºý£©£¬2CH2=CH2+2CH3COOH+O2 2C4H6O2£¨´×ËáÒÒÏ©õ¥£©+2H2O

ÓÖÖª£ºÓë½á¹¹ÏàËƵÄÓлúÎï²»Îȶ¨£¬·¢Éú·Ö×ÓÖØÅÅÉú³É

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Ð´³ö½á¹¹¼òʽ£ºD_______________£¬F___________________¡£

£¨2£©·´Ó¦¢Ù¡¢¢ÚµÄ·´Ó¦ÀàÐÍ______________¡¢___________________________¡£

£¨3£©Ð´³öÏÂÁÐÓйط´Ó¦µÄµÄ»¯Ñ§·½³Ìʽ¡£

A¡ª¡úB________________________________________________

B¡ª¡úC _______________________________________________

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄê½­Î÷Ê¡¸ÓÖÝÊÐʮһÏØ£¨ÊУ©¸ßÈýÉÏѧÆÚÆÚÖÐÁª¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

µªÊǵØÇòÉϺ¬Á¿·á¸»µÄÒ»ÖÖÔªËØ£¬µª¼°Æ仯ºÏÎïÔÚ¹¤Å©ÒµÉú²ú¡¢Éú»îÖÐÓÐ×ÅÖØÒª×÷Ó᣻شðÏÂÁйØÓÚµªÔªËصÄÓйØÎÊÌâ¡£

£¨1£©ÓÃCH4´ß»¯»¹Ô­µªÑõ»¯Îï¿ÉÒÔÏû³ýµªÑõ»¯ÎïµÄÎÛȾ¡£ÒÑÖª£º

¢ÙCH4£¨g£©+4NO2£¨g£© =4NO£¨g£© + CO2£¨g£© +2H2O£¨g£© £»¨SH=" -574" kJ¡¤mol£­1

¢ÚCH4£¨g£© +4NO£¨g£© =2N2£¨g£© + CO2£¨g£© + 2H2O£¨g£©£»¨SH=" -1160" kJ¡¤mol£­1

¢ÛH2O£¨g£© = H2O£¨l£© £» ¡÷H= -44£®0 kJ¡¤mol£­1

д³öCH4£¨g£©ÓëNO2£¨g£©·´Ó¦Éú³ÉN2£¨g£©¡¢CO2£¨g£©ºÍH2O£¨1£©µÄÈÈ»¯Ñ§·½³Ìʽ                          £¬¸Ã·´Ó¦µÄìرä¨SS     0£¨Ìî¡°£¾¡±¡¢¡°£¼¡±¡¢¡°="¡±" £©¡£

£¨2£©ÓûîÐÔÌ¿»¹Ô­·¨´¦ÀíµªÑõ»¯Îï¡£Óйط´Ó¦Îª£ºC£¨s£©+2NO£¨g£©N2£¨g£©+CO2£¨g£© ¡£Ä³Ñо¿Ð¡×éÏòijÃܱյÄÕæ¿ÕÈÝÆ÷£¨¼ÙÉèÈÝÆ÷Ìå»ý²»±ä£¬¹ÌÌåÊÔÑùÌå»ýºöÂÔ²»¼Æ£©ÖмÓÈëNOºÍ×ãÁ¿µÄ»îÐÔÌ¿£¬ºãΣ¨T1¡æ£©Ìõ¼þÏ·´Ó¦£¬·´Ó¦½øÐе½²»Í¬Ê±¼ä²âµÃ¸÷ÎïÖʵÄŨ¶ÈÈçÓÒ±í£º

¢Ù10min~20minÒÔV£¨CO2£© ±íʾµÄ·´Ó¦ËÙÂÊΪ              ¡£

¢Ú¸Ã·´Ó¦µÄƽºâ³£ÊýµÄ±í´ïʽΪ£ºK=         £¬¸ù¾Ý±íÖÐÊý¾Ý£¬¼ÆËãT1¡æʱ¸Ã·´Ó¦µÄƽºâ³£ÊýΪ   ¡¡¡¡   £¨±£ÁôÁ½Î»Ð¡Êý£©¡£

¢ÛÏÂÁи÷ÏîÄÜ×÷ΪÅжϸ÷´Ó¦´ïµ½Æ½ºâµÄÊÇ    £¨ÌîÐòºÅ×Öĸ£©¡£

a£®ÈÝÆ÷ÄÚѹǿ±£³Ö²»±ä¡¡¡¡      b£®2V£¨NO£©£¨Õý£©= V£¨N2£©£¨Ä棩

c£®ÈÝÆ÷ÄÚCO2µÄÌå»ý·ÖÊý²»±ä     d£®»ìºÏÆøÌåµÄÃܶȱ£³Ö²»±ä

¢Ü30minºó£¬¸Ä±äijһÌõ¼þ£¬·´Ó¦ÖØдﵽƽºâ£¬Ôò¸Ä±äµÄÌõ¼þ¿ÉÄÜÊÇ              ¡£

¢ÝÒ»¶¨Î¶ÈÏ£¬Ëæ×ÅNOµÄÆðʼŨ¶ÈÔö´ó£¬ÔòNOµÄƽºâת»¯ÂÊ        £¨Ìî¡°Ôö´ó¡±¡¢¡°²»±ä¡±»ò¡°¼õС¡±£© ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸