ͼ1-8
(1)AÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ__________________________________________________¡£
(2)ÔÚBÖй۲쵽µÄÏÖÏóÊÇ________________________________________________________¡£
(3)ÊÒÎÂÏ£¬Èô´Óµç½â¿ªÊ¼µ½Ê±¼äΪTʱ£¬A¡¢B×°ÖÃÖй²ÊÕ¼¯µ½ÆøÌå0.168 L(±ê×¼×´¿ö)£¬Èôµç½â¹ý³ÌÖÐÎÞÆäËû¸±·´Ó¦·¢Éú£¬ÇÒÈÜÒºÌå»ý±ä»¯ºöÂÔ²»¼Æ£¬ÔòÔÚTʱ£¬AÈÜÒºµÄpHΪ__________________¡£
½âÎö£ºÓÉʪÈóµÄKIµí·ÛÊÔÖ½C¶Ë±äÀ¶£¬¿ÉÖªÔÚC¶ËI-±»Ñõ»¯ÎªI2£¬¼´C¶ËΪÑô¼«£¬½ø¶øµÃµçÔ´ÓÒ¶ËΪÕý¼«£¬×ó¶ËΪ¸º¼«£¬Óɴ˵ÃA×°ÖÃÖÐFe°ôΪÒõ¼«£¬PtΪÑô¼«£¬¹ÊʵÖʵç½âAgNO3ºÍH2O£¬AÖеç½â×Ü·´Ó¦Îª4AgNO3+2H2O4Ag¡ý+O2¡ü+4HNO3¡£
B×°ÖÃÖÐ Cu°ôΪÑô¼«£¬Ê¯Ä«°ôΪÒõ¼«£¬ÊµÖʵç½âCuºÍH2O£¬Óɴ˵ÃBÖÐÏÖÏóΪʯīµç¼«±íÃæÓÐÆøÅݲúÉú£¬Íµç¼«ÖÜΧÈÜÒº±äÀ¶É«£»Ò»¶Îʱ¼äºóUÐιÜϲ¿ÓÐÀ¶É«³Áµí²úÉú£¬A¡¢B×°ÖÃÊÕ¼¯µ½µÄÆøÌå·Ö±ðÊÇO2ºÍH2£¬ÓÉתÒƵĵç×ÓÊýÏàµÈ£¬µÃn(O2)=n(H2)£¬ËùÒÔn(O2)=¡Á=0.002 5 mol£¬ÓÉA×Ü·´Ó¦µÃn(HNO3)=4n(O2)=0.010 0 mol
¹Ê£ÛH+£Ý==10-2 mol-1 pH=2
´ð°¸£º(1)4AgNO3+2H2O4Ag¡ý+O2¡ü+4HNO3
(2)ʯīµç¼«±íÃæÓÐÆøÅݲúÉú£¬Íµç¼«ÖÜΧÈÜÒº±äÀ¶É«£¬Ò»¶Îʱ¼äºó£¬UÐιÜϲ¿ÓÐÀ¶É«³Áµí²úÉú
(3)2
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â
| ||
| ||
| ||
| ||
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ºÑ¡ÐÞ¸ßÊÖ»¯Ñ§Ëս̡¤»¯Ñ§·´Ó¦ÔÀí Ëս̰æ ÌâÐÍ£º022
ÓÐÈçÏÂͼµç½â×°Öã¬Í¼ÖÐB×°ÖÃÊ¢1 L¡¡2 mol¡¤L£1¡¡Na2SO4ÈÜÒº£¬A×°ÖÃÖÐÊ¢1 L¡¡2 mol¡¤L£1¡¡AgNO3ÈÜÒº£®Í¨µçºó£¬ÊªÈóµÄKIµí·ÛÊÔÖ½µÄC¶Ë±äÀ¶É«£¬µç½âÒ»¶Îʱ¼äºó£¬ÊԻشð£º
(1)AÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_________£®
(2)ÔÚBÖй۲쵽µÄÏÖÏóÊÇ_________£®
(3)ÊÒÎÂÏ£¬Èô´Óµç½â¿ªÊ¼µ½Ê±¼äΪTʱ£¬A¡¢B×°ÖÃÖй²ÊÕ¼¯µ½ÆøÌå0.168 L(±ê×¼×´¿ö)£¬Èôµç½â¹ý³ÌÖÐÎÞÆäËû¸±·´Ó¦·¢Éú£¬ÇÒÈÜÒºÌå»ý±ä»¯ºöÂÔ²»¼Æ£¬ÔòÔÚTʱ£¬AÈÜÒºµÄpHΪ_________£®
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
(1)AÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ__________________________________________________¡£
(2)ÔÚBÖй۲쵽µÄÏÖÏóÊÇ________________________________________________________¡£
(3)ÊÒÎÂÏ£¬Èô´Óµç½â¿ªÊ¼µ½Ê±¼äΪTʱ£¬A¡¢B×°ÖÃÖй²ÊÕ¼¯µ½ÆøÌå
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com