£¨1£©¹ý¶É½ðÊôÔªËØÌúÄÜÐγɶàÖÖÅäºÏÎÈ磺[Fe(H2NCONH2)6] (NO3)3 [ÈýÏõËáÁùÄòËغÏÌú(¢ó)]ºÍFe(CO)xµÈ¡£

¢Ù»ù̬Fe3+µÄM²ãµç×ÓÅŲ¼Ê½Îª                              ¡£

¢ÚÅäºÏÎïFe(CO)xµÄÖÐÐÄÔ­×Ó¼Ûµç×ÓÊýÓëÅäÌåÌṩµç×ÓÊýÖ®ºÍΪ18£¬Ôòx=      ¡£ Fe(CO)x³£ÎÂϳÊҺ̬£¬ÈÛµãΪ£­20.5¡æ£¬·ÐµãΪ103¡æ£¬Ò×ÈÜÓڷǼ«ÐÔÈܼÁ£¬¾Ý´Ë¿ÉÅжÏFe(CO)x¾§ÌåÊôÓÚ          £¨ÌÌåÀàÐÍ£©£»

£¨2£©OºÍNaÐγɵÄÒ»ÖÖÖ»º¬ÓÐÀë×Ó¼üµÄÀë×Ó»¯ºÏÎïµÄ¾§°û½á¹¹ÈçÓÒͼ£¬¾àÒ»¸öÒõÀë×ÓÖÜΧ×î½üµÄËùÓÐÑôÀë×ÓΪ¶¥µã¹¹³ÉµÄ¼¸ºÎÌåΪ            ¡£ÒÑÖª¸Ã¾§°ûµÄÃܶÈΪ¦Ñ g/cm3£¬°¢·ü¼ÓµÂÂÞ³£ÊýΪNA£¬Ç󾧰û±ß³¤ a =          cm¡£ (Óú¬¦Ñ¡¢NAµÄ¼ÆËãʽ±íʾ)

£¨3£©ÏÂÁÐÓйصÄ˵·¨ÕýÈ·µÄÊÇ            ¡£

A£®µÚÒ»µçÀëÄÜ´óС£ºS£¾P£¾Si

B£®µç¸ºÐÔ˳Ðò£ºC£¼N£¼O£¼F

C£®ÒòΪ¾§¸ñÄÜCaO±ÈKCl¸ß£¬ËùÒÔKCl±ÈCaOÈÛµãµÍ

D£®SO2ÓëCO2µÄ»¯Ñ§ÐÔÖÊÀàËÆ£¬·Ö×ӽṹҲ¶¼³ÊÖ±ÏßÐÍ£¬ÏàͬÌõ¼þÏÂSO2µÄÈܽâ¶È¸ü´ó

E£®·Ö×Ó¾§ÌåÖУ¬¹²¼Û¼ü¼üÄÜÔ½´ó£¬¸Ã·Ö×Ó¾§ÌåµÄÈ۷еãÔ½¸ß

£¨4£©Ô­×ÓÐòÊýСÓÚ36µÄX¡¢Y¡¢Z¡¢WËÄÖÖÔªËØ£¬ÆäÖÐXÊÇÐγɻ¯ºÏÎïÖÖÀà×î¶àµÄÔªËØ£¬YÔ­×Ó»ù̬ʱ×îÍâ²ãµç×ÓÊýÊÇÆäÄÚ²ãµç×ÓÊýµÄ2±¶£¬ZÔ­×Ó»ù̬ʱ2pÔ­×Ó¹ìµÀÉÏÓÐ3¸öδ³É¶ÔµÄµç×Ó£¬WµÄÔ­×ÓÐòÊýΪ29¡£»Ø´ðÏÂÁÐÎÊÌ⣺

¢Ù Y2X2·Ö×ÓÖÐYÔ­×Ó¹ìµÀµÄÔÓ»¯ÀàÐÍΪ        £¬1mol Y2X2º¬ÓЦҼüµÄÊýĿΪ    

        ¡£

¢Ú »¯ºÏÎïZX3µÄ·Ðµã±È»¯ºÏÎïYX4µÄ¸ß£¬ÆäÖ÷ÒªÔ­ÒòÊÇ             ¡£

¢Û ÔªËØYµÄÒ»ÖÖÑõ»¯ÎïÓëÔªËØZµÄÒ»ÖÖÑõ»¯ÎﻥΪµÈµç×ÓÌ壬ԪËØZµÄÕâÖÖÑõ»¯ÎïµÄ·Ö×ÓʽÊÇ                       ¡£


¡¾´ð°¸¡¿£¨1£©¢Ù 3s23p63d5                                                                                                                                                             £¨1·Ö£©          

¢Ú 5                                                                                                  £¨1·Ö£©  

·Ö×Ó¾§Ìå                                                                                 £¨1·Ö£©       

£¨2£©Á¢·½Ìå                                                                                        £¨1·Ö£©    

                                                                                           £¨1·Ö£©    

£¨3£©BC                                             £¨2·Ö£©£¨Â©Ñ¡µÃ1·Ö£¬¶àÑ¡¡¢´íÑ¡²»µÃ·Ö£©

£¨4£©¢ÙspÔÓ»¯                                                                                    £¨2·Ö£©

 3 NA»ò3¡Á6.02¡Á1023 ¸ö                                                                £¨2·Ö£©  

    ¢ÚNH3·Ö×Ó´æÔÚÇâ¼ü                                                                   £¨2·Ö£©  

¢ÛN2O                                                                                         £¨2·Ö£©¡£


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÈÝÁ¿Æ¿ÉϱêÓеÄÊÇ¢ÙÎÂ¶È ¢ÚŨ¶È¡¡¢ÛÈÝÁ¿ ¢ÜÖÊÁ¿ ¢Ý¿Ì¶ÈÏß ¢ÞËáʽ»ò¼îʽ

A£®¢Ù¢Û¢Ý         B£®¢Û¢Ý¢Þ        C£®¢Ù¢Ý¢Þ  ¡¡¡¡     D£®¢Ú¢Û¢Ý

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


8gÎÞË®ÁòËáÍ­Åä³É0.1mol/LµÄÁòËáÍ­Ë®ÈÜÒº£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ

A£®ÈÜÓÚ500mLË®ÖР              B£®ÈÜÓÚ1LË®ÖÐ

C£®ÈܽâºóÈÜÒºµÄ×ÜÌå»ýΪ500ml     D£®ÈܽâºóÈÜÒºµÄ×ÜÌå»ýΪ1L

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÑÇÂÈËáÄÆ£¨NaClO2£©ÊÇÒ»ÖÖÖØÒªµÄº¬ÂÈÏû¶¾¼Á£¬Ö÷ÒªÓÃÓÚË®µÄÏû¶¾ÒÔ¼°É°ÌÇ¡¢ÓÍÖ¬µÄƯ°×Óëɱ¾ú¡£ÒÔÏÂÊǹýÑõ»¯Çâ·¨Éú²úÑÇÂÈËáÄƵŤÒÕÁ÷³Ìͼ£º

ÒÑÖª£º¢ÙNaClO2µÄÈܽâ¶ÈËæζÈÉý¸ß¶øÔö´ó£¬Êʵ±Ìõ¼þÏ¿ɽᾧÎö³öNaClO2•3H2O¡£

¢Ú´¿ClO2Ò׷ֽⱬը£¬Ò»°ãÓÃÏ¡ÓÐÆøÌå»ò¿ÕÆøÏ¡Ê͵½10£¥ÒÔÏ°²È«¡£

¢Û160 g/L NaOHÈÜÒºÊÇÖ¸160 g NaOH¹ÌÌåÈÜÓÚË®ËùµÃÈÜÒºµÄÌå»ýΪ1L¡£

£¨1£©160 g/L NaOHÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ¡¡¡¡¡¡     ¡¡¡¡¡£ÈôÒª¼ÆËã¸ÃÈÜÒºµÄÖÊÁ¿·ÖÊý£¬»¹ÐèÒªµÄÒ»¸öÌõ¼þÊÇ¡¡¡¡¡¡¡¡¡¡¡¡                ¡¡¡¡¡¡¡¡¡¡¡¡£¨ÓÃÎÄ×Ö˵Ã÷£©¡£

£¨2£©·¢ÉúÆ÷ÖйÄÈë¿ÕÆøµÄ×÷ÓÿÉÄÜÊÇ¡¡¡¡¡¡£¨Ñ¡ÌîÐòºÅ£©¡£

a£®½«SO2Ñõ»¯³ÉSO3£¬ÔöÇ¿ËáÐÔ£»   b£®Ï¡ÊÍClO2ÒÔ·ÀÖ¹±¬Õ¨£»

c£®½«NaClO3Ñõ»¯³ÉClO2

£¨3£©ÎüÊÕËþÄÚ·´Ó¦µÄÀë×Ó·½³ÌʽΪ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£

ÎüÊÕËþµÄζȲ»Äܳ¬¹ý20¡æ£¬ÆäÄ¿µÄÊÇ¡¡¡¡                                ¡£

£¨4£©ÔÚ¼îÐÔÈÜÒºÖÐNaClO2±È½ÏÎȶ¨£¬ËùÒÔÎüÊÕËþÖÐӦά³ÖNaOHÉÔ¹ýÁ¿£¬ÅжÏNaOHÊÇ·ñ¹ýÁ¿µÄ¼òµ¥ÊµÑé·½·¨ÊÇ                                               ¡£

£¨5£©ÎüÊÕËþÖÐΪ·ÀÖ¹NaClO2±»»¹Ô­³ÉNaCl£¬ËùÓû¹Ô­¼ÁµÄ»¹Ô­ÐÔÓ¦ÊÊÖС£³ýH2O2Í⣬»¹¿ÉÒÔÑ¡ÔñµÄ»¹Ô­¼ÁÊÇ¡¡     ¡¡¡¡£¨Ñ¡ÌîÐòºÅ£©¡£

a£®Na2O2         b£®Na2S          c£®FeCl2      

£¨6£©´ÓÂËÒºÖеõ½NaClO2•3H2O´Ö¾§ÌåµÄʵÑé²Ù×÷ÒÀ´ÎÊÇ¡¡¡¡¡¡¡¡¡¡£¨Ñ¡ÌîÐòºÅ£©¡£

a£®ÕôÁó    b£®Õô·¢Å¨Ëõ   c£®×ÆÉÕ   d£®¹ýÂËÏ´µÓ    e£®ÀäÈ´½á¾§

ÒªµÃµ½¸ü´¿µÄNaClO2•3H2O¾§Ìå±ØÐë½øÐеIJÙ×÷ÊÇ¡¡¡¡¡¡   ¡¡¡¡    £¨Ìî²Ù×÷Ãû³Æ£©¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


A¡¢B¡¢C¡¢DÊÇÔ­×ÓÐòÊýÒÀ´ÎÔö´óµÄËÄÖÖ¶ÌÖÜÆÚÔªËØ£¬¼×¡¢ÒÒ¡¢±û¡¢¶¡¡¢ÎìÊÇÓÉÆäÖеÄÁ½ÖÖ»òÈýÖÖÔªËØ×é³ÉµÄ»¯ºÏÎ¶øÐÁÊÇÓÉCÔªËØÐγɵĵ¥ÖÊ¡£ÒÑÖª£º¼× + ÒÒ =¶¡ +ÐÁ£¬¼× + ±û = Îì + ÐÁ£»³£ÎÂÏÂ0.1 mol/L ¶¡ÈÜÒºµÄpHΪ13£¬ÔòÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ

A£®ÔªËØCÐγɵĵ¥ÖÊ¿ÉÒÔÔÚµãȼÌõ¼þ·Ö±ðÓëÔªËØA¡¢B¡¢DÐγɵĵ¥ÖÊ»¯ºÏ£¬ËùµÃ»¯ºÏÎï¾ù´æÔÚ¹²¼Û¼ü

B£®ÔªËØB¡¢C¡¢DµÄÔ­×Ӱ뾶ÓÉ´óµ½Ð¡µÄ˳ÐòΪ£ºr(D) > r(C) > r(B)

C£®1.0 L 0. 1 mol/LÎìÈÜÒºÖк¬ÒõÀë×Ó×ܵÄÎïÖʵÄÁ¿Ð¡ÓÚ0. 1 mol

D£®1 mol¼×Óë×ãÁ¿µÄÒÒÍêÈ«·´Ó¦¹²×ªÒÆÔ¼1.204 ¡Á 1024¸öµç×Ó

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


XÔªËØ×î¸ßÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïΪH3XO4£¬ÔòËü¶ÔÓ¦µÄÆø̬Ç⻯ÎïΪ£¨    £©        

A£®HX          B£®H2X              C£®XH4            D£® XH3

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ(¡¡¡¡)

A£®¢ñA×åÔªËصĽðÊôÐԱȢòA×åÔªËصĽðÊôÐÔÇ¿

B£®¢ôA×åÔªËصÄÇ⻯ÎïÖУ¬Îȶ¨ÐÔ×îºÃµÄÊÇCH4

C£®Í¬ÖÜÆڷǽðÊôÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïµÄËáÐÔ´Ó×óµ½ÓÒÒÀ´ÎÔöÇ¿

D£®µÚÈýÖÜÆÚÔªËصÄÀë×Ӱ뾶´Ó×óµ½ÓÒÖð½¥¼õС

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÂÁÐͼÏóÃèÊöÕýÈ·µÄÊÇ

A£®Í¼¢Ù±íʾÌå»ýºÍPHÖµ¾ùÏàͬµÄÏ¡ÁòËáºÍ´×ËᣬºÍ×ãÁ¿µÄþ·´Ó¦Éú³ÉH2Á¿µÄ¹Øϵ

B£®Í¼¢Ú±íʾÏò°±Ë®ÖеμӴ×ËᣬÈÜÒºµ¼µçÐԱ仯µÄ¹Øϵ

C£®Í¼¢Û±íʾ2SO2(g)+O2(g)2SO3(g)·´Ó¦ÖУ¬SO2ºÍO2·´Ó¦ËÙÂÊ´óС¹Øϵ

D£®Í¼¢Ü±íʾÏòH2SÖÐͨÈëCl2ʱ£¬ÈÜÒºµÄpH´óС±ä»¯¹Øϵ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÓÃŨÂÈ»¯ï§ÈÜÒº´¦Àí¹ýµÄÎę̀Ļ²¼²»Ò××Å»ð¡£ÆäÔ­ÒòÊÇ

   ¢ÙÄ»²¼µÄ×Å»ðµãÉý¸ß                 ¢ÚÄ»²¼µÄÖÊÁ¿Ôö¼Ó

   ¢ÛÂÈ»¯ï§·Ö½âÎüÊÕÈÈÁ¿£¬½µµÍÁËζȠ  ¢ÜÂÈ»¯ï§·Ö½â²úÉúµÄÆøÌå¸ô¾øÁË¿ÕÆø

A£®¢Ù¢Ú          B£®¢Ù¢Û           C£®¢Ú¢Ü           D£®¢Û¢Ü

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸