¡¾ÌâÄ¿¡¿»·¾³¼à²âÏÔʾ£¬Ä³µØÊеÄÖ÷ÒªÆøÌåÎÛȾÎïΪSO2¡¢NOx¡¢COµÈ£¬ÆäÖ÷ÒªÀ´Ô´ÎªÈ¼Ãº¡¢»ú¶¯³µÎ²Æø¡£½øÐÐÈçÏÂÑо¿£º

£¨1£©Îª¼õÉÙȼú¶ÔSO2µÄÅÅ·Å£¬¿É½«Ãº×ª»¯ÎªÇå½àȼÁÏˮúÆø£¨COºÍH2£©¡£

ÒÑÖª£º ¦¤H£½241.8kJ¡¤mol£­1£¬

¦¤H£½£­110.5kJmol£­1

д³ö½¹Ì¿Óë1molË®ÕôÆø·´Ó¦Éú³ÉˮúÆøµÄÈÈ»¯Ñ§·½³Ìʽ£º________¡£

£¨2£©Æû³µÎ²ÆøÖÐNOÊÇÔÚ·¢¶¯»úÆû¸×ÖÐÉú³ÉµÄ£¬·´Ó¦ÎªN2£¨g£©£«O2£¨g£©2NO£¨g£© ¦¤H£¾0¡£

¢Ù½«º¬0.8molN2ºÍ0.2molO2£¨½üËÆ¿ÕÆø×é³É£©µÄ»ìºÏÆøÌå³äÈëijÃܱÕÈÝÆ÷ÖУ¬±£³Ö1300¡æ·´Ó¦´ïµ½Æ½ºâ£¬²âµÃÉú³É8¡Á10£­4molNO¡£¼ÆËã¸ÃζÈÏ´˷´Ó¦µÄ»¯Ñ§Æ½ºâ³£ÊýK£½________£¨Ìî½üËƼÆËã½á¹û£©¡£

¢ÚÆû³µÆô¶¯ºó£¬Æû¸×ÄÚζÈÔ½¸ß£¬µ¥Î»Ê±¼äÄÚNOÅÅ·ÅÁ¿Ô½´ó£¬Ô­ÒòÊÇ________£®

£¨3£©ÀûÓÃÈçͼËùʾװÖ㨵缫¾ùΪ¶èÐԵ缫£©¿ÉÎüÊÕSO2£¬²¢ÀûÓÃÒõ¼«ÅųöµÄÈÜÒºÎüÊÕNO2¡£

¢Ùµç¼«AµÄµç¼«·´Ó¦Ê½Îª________£»

µç¼«BµÄµç¼«·´Ó¦Ê½Îª________¡£

¢Ú¼îÐÔÌõ¼þÏ£¬ÓÃÒõ¼«ÅųöµÄÈÜÒºÎüÊÕNO2£¬Ê¹Æäת»¯ÎªÎÞº¦ÆøÌ壬ͬʱÉú³ÉSO32£­¡£¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ________¡£

¡¾´ð°¸¡¿C£¨s£©£«H2O£¨g£©£½CO£¨g£©£«H2£¨g£© ¦¤H£½£«131.3kJ¡¤mol£­14¡Á10£­6ζÈÉý¸ß£¬·´Ó¦ËÙÂʼӿìÇÒƽºâÕýÏòÒƶ¯SO2£«2H2O£­2e£­£½SO42£­£«4H£«2HSO3£­£«2H£«£«2e£­£½S2O42£­£«2H2O4S2O42£­£«2NO2£«8OH£­£½8SO32£­£«N2£«4H2O

¡¾½âÎö¡¿(1)¢ÙÒÑÖª£º¢Ù2H2(g)+O2(g)=2H2O(g)¡÷H=-483.6KJ/mol£»¢ÚC(s)+O2(g)¨TCO(g)£»¡÷H=-110.51kJmol-1£»ÀûÓøÇ˹¶¨ÂÉ£¬½«¢Ú-¢Ù¡Á¿ÉµÃ£ºC(s)+H2O(g)=CO(g)+H2(g)£¬¡÷H=(-110.5kJ/mol)-(-241.8kJ/mol)=+13l.3 kJ/mol£¬ËùÒÔ½¹Ì¿ÓëË®ÕôÆø·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ£ºC(s)+H2O(g)¨TCO(g)+H2(g)£»¡÷H=+13l.30kJmol-1£»

(2)¢ÙÉè·´Ó¦ÈÝÆ÷µÄÌå»ýÊÇaL£¬¸ù¾ÝÌâÒâµÃ£º
N2(g)+O2(g)2NO(g)
³õʼŨ¶È 0

ת»¯Å¨¶È

ƽºâŨ¶È - -

½«¸÷ÖÖÎïÖʵÄŨ¶È´øÈë±í´ïʽµÃK=¡Ö4¡Á10-6£»

¢ÚÆû¸×Öз¢ÉúµÄ»¯Ñ§·´Ó¦£ºN2(g)+O2(g)2NO(g)¡÷H£¾0£¬ÕâÊǸöÎüÈÈ·´Ó¦£¬Î¶ÈÉý¸ß£¬·´Ó¦ËÙÂʼӿ죬ƽºâÏòÕý·½ÏòÒƶ¯£¬µ¥Î»Ê±¼äÄÚ²úÉúµÄNO¶à£»

(3)¢ÙÒÀ¾Ýͼʾ¿ÉÖª£¬¶þÑõ»¯Áò±»Ñõ»¯ÎªÁòËá¸ù£¬ËùÒÔ¶þÑõ»¯ÁòËùÔÚµÄAÇøΪÑô¼«Çø£¬Ñô¼«Çø·¢Éú·´Ó¦SO2-2e-+2H2O¨TSO42-+4H+£»BÇøΪÒõ¼«Çø£¬HSO3£­±»»¹Ô­ÎªS2O42£­£¬·¢ÉúµÄµç¼«·´Ó¦Îª2HSO3£­£«2H£«£«2e£­£½S2O42£­£«2H2O£»

¢ÚÒõ¼«ÅųöµÄÈÜҺΪS2O42-£¬¶þÑõ»¯µªÓëÆä·¢Éú·´Ó¦£¬S2O42-ÖÐÁòÔªËØÓÉ+3¼Û£¬±äΪÁòËá¸ùÖÐÁòÔªËØΪ+4¼Û£¬S2O42-±»Ñõ»¯ÊÇ»¹Ô­¼Á£»¶þÑõ»¯µªÖеĵªÔªËØ»¯ºÏ¼ÛΪ+4¼Û±äΪµªÆø0¼Û£¬¶þÑõ»¯µª±»»¹Ô­ÎªÑõ»¯¼Á£¬ÒÀ¾ÝÔ­×ÓÊغãºÍµÃʧµç×ÓÊغã¿ÉµÃ£¬·¢ÉúµÄÀë×Ó·½³ÌʽΪ4S2O42-+2NO2+8OH-¨T8SO42-+N2+4H2O¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿Âȷ£¨CHCl3 £¬ ·Çµç½âÖÊ£©ÔÚ¿ÕÆøÖÐÄÜ·¢Éú»ºÂýÑõ»¯£¬Éú³É¾ç¶¾ÎïÖʹâÆø£¨COCl2 £¬ ·Çµç½âÖÊ£©£¬»¯Ñ§·½³ÌʽΪ2CHCl3+O2=2COCl2+2HCl£®¼ìÑéÂÈ·ÂÊÇ·ñ±»Ñõ»¯Ó¦Ñ¡ÓõÄÊÔ¼ÁÊÇ£¨¡¡¡¡£©
A.Ë®
B.NaOHÈÜÒº
C.·Ó̪ÈÜÒº
D.ÏõËáËữµÄÏõËáÒøÈÜÒº

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÔÚº¬ÓÐCu£¨NO3£©2¡¢Mg£¨NO3£©2ºÍAgNO3µÄÈÜÒºÖмÓÈëÊÊÁ¿Ð¿·Û£¬Ê×ÏÈÖû»³öµÄÊÇ£¨¡¡¡¡£©
A.Mg
B.Cu
C.Ag
D.H2

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÏÂÁи÷×éÎïÖÊ°´ÕÕµ¥ÖÊ¡¢Ñõ»¯Îï¡¢Ëá¡¢¼î¡¢ÑηÖÀà˳ÐòÅÅÁУ¬ÆäÖÐÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A.Ë®Òø¡¢¸É±ù¡¢ÁòËá¡¢Éռ´¿¼î
B.µâ¾Æ¡¢±ù¡¢ÏõËá¡¢¿ÁÐÔÄÆ¡¢µ¨·¯
C.ÇâÆø¡¢¶þÑõ»¯Áò¡¢ÑÎËá¡¢´¿¼î¡¢ÁòËáÍ­
D.Í­¡¢Ñõ»¯Í­¡¢´×Ëá¡¢Êìʯ»Ò¡¢Ê¯»Òʯ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿Ä³ÊµÑéС×éÓÃ0.50 mol/L NaOHÈÜÒººÍ0.50 mol/LÁòËáÈÜÒº½øÐÐÖкÍÈȵIJⶨ¡£

¢ñ£®ÅäÖÆ0.50 mol/L NaOHÈÜÒº

ÈôʵÑéÖдóԼҪʹÓÃ245 mL NaOHÈÜÒº£¬ÖÁÉÙÐèÒª³ÆÁ¿NaOH¹ÌÌå_____g¡£

¢ò£®²â¶¨Ï¡ÁòËáºÍÏ¡ÇâÑõ»¯ÄÆÖкÍÈȵÄʵÑé×°ÖÃÈçͼËùʾ¡£

£¨1£©Ð´³ö¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£¨ÖкÍÈÈΪ57.3 kJ/mol£©£º_____________¡£

£¨2£©È¡50 mL NaOHÈÜÒººÍ30 mLÁòËáÈÜÒº½øÐÐʵÑ飬ʵÑéÊý¾ÝÈçÏÂ±í¡£

¢ÙÇëÌîдϱíÖеĿհףº

ÆðʼζÈt1/¡æ

ÖÕֹζÈ

t2/¡æ

ζȲîƽ¾ùÖµ

£¨t2-t1£©/¡æ

H2SO4

NaOH

ƽ¾ùÖµ

1

26.2

26.0

26.1

30.1

______

2

27.0

27.4

27.2

33.3

3

25.9

25.9

25.9

29.8

4

26.4

26.2

26.3

¢Ú½üËÆÈÏΪ0.50 mol/L NaOHÈÜÒººÍ0.50 mol/LÁòËáÈÜÒºµÄÃܶȶ¼ÊÇ1 g/cm3£¬ÖкͺóÉú³ÉÈÜÒºµÄ±ÈÈÈÈÝc=4.18 J/(g¡¤¡æ£©¡£ÔòÖкÍÈÈ¡÷H=______________ȡСÊýµãºóһ룩¡£

¢ÛÉÏÊöʵÑéÊýÖµ½á¹ûÓë57.3 kJ/molÓÐÆ«²î£¬²úÉúÆ«²îµÄÔ­Òò¿ÉÄÜÊÇ£º______¡£

A£®ÊµÑé×°Öñ£Î¡¢¸ôÈÈЧ¹û²î

B£®Á¿È¡NaOHÈÜÒºµÄÌå»ýʱÑöÊÓ¶ÁÊý

C£®·Ö¶à´Î°ÑNaOHÈÜÒºµ¹ÈëÊ¢ÓÐÁòËáµÄСÉÕ±­ÖÐ

D£®ÓÃζȼƲⶨNaOHÈÜÒºÆðʼζȺóÖ±½Ó²â¶¨H2SO4ÈÜÒºµÄζÈ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿Æû³µÎ²ÆøÖк¬ÓÐCO¡¢NO2µÈÓж¾ÆøÌ壬¶ÔÆû³µ¼ÓװβÆø¾»»¯×°Ö㬿ÉʹÓж¾ÆøÌåÏ໥·´Ó¦×ª»¯³ÉÎÞ¶¾ÆøÌå¡£

(1)µ±¿Õȼ±È(¿ÕÆøÓëȼÓÍÆøµÄÌå»ý±È)²»Í¬Ê±£¬Æû³µÎ²ÆøµÄÖ÷Òª³É·Ö²»Í¬¡£¿Õȼ±È½ÏСʱµÄÓж¾ÆøÌåÖ÷ÒªÊÇ________(Ìѧʽ)¡£

(2)ij·Ö×ÓɸÀà´ß»¯¼Á(H£«½»»»·Ðʯ)´ß»¯NH3ÍѳýNO¡¢NO2µÄ·´Ó¦»úÀíÈçͼËùʾ¡£

²½Öè¢Ûת»¯·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ________________¡£°´ÉÏͼ·´Ó¦»úÀí£¬NH3ÍѳýNO¡¢NO2×Ü·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ_____________________________¡£

(3)NaClO2ÈÜÒº½«NOת»¯ÎªHNO3µÄ·´Ó¦Àú³ÌÈçÏ£º

NaClO2£«HCl===HClO2£«NaCl

8HClO2===6ClO2¡ü£«Cl2¡ü£«4H2O

2NaClO2£«Cl2===2NaCl£«2ClO2¡ü

5NO£«3ClO2£«4H2O===5HNO3£«3HCl

ÔòËáÐÔÌõ¼þÏÂNaClO2ÈÜÒº½«NOת»¯ÎªHNO3µÄ×Ü·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿Îíö²ÌìÆøÑÏÖØÓ°ÏìÈËÃǵÄÉú»îÖÊÁ¿£¬ÆäÖеªÑõ»¯ÎïºÍÁòÑõ»¯ÎïÊÇÔì³ÉÎíö²ÌìÆøµÄÖ÷ÒªÔ­ÒòÖ®Ò»¡£Ïû³ýµªÑõ»¯ÎïºÍÁòÑõ»¯ÎïÓжàÖÖ·½·¨¡£

(1)µª¡¢ÑõÔªËطǽðÊôÐÔ½ÏÇ¿µÄÊÇ________¡£

(2)NH3´ß»¯»¹Ô­µªÑõ»¯Îï(SCR)¼¼ÊõÊÇÄ¿Ç°Ó¦ÓÃ×î¹ã·ºµÄÑÌÆøµªÑõ»¯ÎïÍѳý¼¼Êõ¡£·´Ó¦Ô­ÀíÈçͼ1Ëùʾ£º

¢ÙÓÉͼ1¿ÉÖªSCR¼¼ÊõÖеÄÑõ»¯¼ÁΪ________¡£

¢ÚÓÃFe×÷´ß»¯¼Áʱ£¬ÔÚ°±Æø×ãÁ¿µÄÇé¿öÏ£¬²»Í¬c(NO2)/c(NO)¶ÔÓ¦µÄÍѵªÂÊÈçͼ2Ëùʾ£¬ÍѵªÐ§¹û×î¼ÑµÄc(NO2)/c(NO)£½________¡£

(3)º£Ë®¾ßÓÐÁ¼ºÃµÄÎüÊÕSO2µÄÄÜÁ¦£¬ÆäÎüÊÕ¹ý³ÌÈçÏ£º

¢ÙSO2ÈÜÓÚº£Ë®Éú³ÉH2SO3£¬H2SO3×îÖÕ»áµçÀë³öSO£¬SO¿ÉÒÔ±»º£Ë®ÖеÄÈܽâÑõÑõ»¯ÎªSO¡£º£Ë®µÄpH»á________(Ìî¡°Éý¸ß¡±¡°²»±ä¡±»ò¡°½µµÍ¡±)¡£

¢ÚSO2ºÍO2ÔÚH2SO4ÈÜÒºÖпÉÒÔ¹¹³ÉÔ­µç³Ø£¬Æ为¼«·´Ó¦Ê½ÊÇ_____________________¡£

(4)íÚ(Te)ΪµÚ¢öA×åÔªËØ£¬Êǵ±½ñ¸ßм¼ÊõвÄÁϵÄÖ÷Òª³É·ÖÖ®Ò»¡£¹¤ÒµÉϿɽ«SO2ͨÈëTeCl4µÄËáÐÔÈÜÒºÖнøÐС°»¹Ô­¡±µÃµ½íÚ£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ___________________

________________________________________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿²»Í¬ÔªËصÄÔ­×ÓÔÚ·Ö×ÓÄÚÎüÒýµç×ÓµÄÄÜÁ¦´óС¿ÉÓÃÒ»¶¨ÊýÖµ x À´±íʾ£¬Èô x Ô½´ó£¬ÆäÔ­×ÓÎüÒýµç×ÓÄÜÁ¦Ô½Ç¿£¬ÔÚËùÐγɵķÖ×ÓÖгÉΪ´ø¸ºµçºÉµÄÒ»·½¡£

ÏÂÃæÊÇijЩ¶ÌÖÜÆÚÔªËØµÄ x Öµ£º

ÔªËØ·ûºÅ

Li

Be

B

C

N

F

x Öµ

0.98

1.57

2.04

2.25

2.89

3.98

ÔªËØ·ûºÅ

Na

Mg

Si

P

S

Cl

x Öµ

0.93

1.35

1.90

2.19

2.58

3.16

£¨1£©Í¨¹ý·ÖÎö x Öµ±ä»¯¹æÂÉ£¬È·¶¨Al¡¢NµÄ x Öµ·¶Î§£º________£¼ x (Al)£¼________

£¨2£©ÍƲâ x ÖµÓëÔ­×Ӱ뾶¹ØϵÊÇ________£¬¸ù¾Ý¶ÌÖÜÆÚÔªËØµÄ x Öµ±ä»¯Ìص㣬ÌåÏÖÁËÔªËØÐÔÖʵÄ________±ä»¯¹æÂÉ¡£

£¨3£©Ä³Óлú»¯ºÏÎï½á¹¹Ê½Îª£º£¬ÆäÖÐSO¼üÖÐÄãÈÏΪ¹²Óõç×Ó¶ÔÆ«ÏòË­£¿________£¨Ð´Ô­×ÓÃû³Æ£©¡£

£¨4£©¾­Ñé¹æÂɸæËßÎÒÃÇ£ºµ±³É¼üµÄÁ½Ô­×ÓÏàÓ¦ÔªËØµÄ x ²îÖµ(¦¤ x )¼´ x £¾1.7ʱ£¬Ò»°ãΪÀë×Ó¼ü£»µ±¦¤ x £¼1.7ʱ£¬Ò»°ãΪ¹²¼Û¼ü¡£ÊÔÍƶÏAlF 3 Öл¯Ñ§¼üÀàÐÍÊÇ________¡£

£¨5£©Ô¤²âÔªËØÖÜÆÚ±íÖУ¬ x Öµ×îСµÄÔªËصÄλÖãº_______£¨·ÅÉäÐÔÔªËسýÍ⣩¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÏÂÁдëÊ©ÄÜʹˮµÄµçÀë³Ì¶ÈÔö´óµÄÊÇ£¨ £©

A. ¼ÓÈëÑÎËáÈÜÒº B. ¼Ó´×ËáÄÆ C. ¼ÓÈ백ˮ D. ½µÎÂ

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸