¢ñ.½ðÊôÂÁµÄÉú²úÊÇÒÔAl2O3ΪԭÁÏ£¬ÔÚÈÛÈÚ״̬ϽøÐеç½â£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©±ù¾§Ê¯£¨Na3AlF6£©µÄ×÷ÓÃÊÇ¡¡¡¡¡¡¡¡¡£

£¨2£©µç½âÉú³ÉµÄ½ðÊôÂÁÊÇÔÚÈÛÈÚÒºµÄ¡¡¡¡¡¡¡¡£¨Ìî¡°Éϲ㡱»ò¡°Ï²㡱£©¡£

£¨3£©µç½âʱËùÏûºÄµÄµç¼«ÊÇ¡¡¡¡¡¡¡¡£¨Ìî¡°Ñô¼«¡±»ò¡°Òõ¼«¡±£©¡£

£¨4£©ÂÁÊǸߺÄÄܲúÆ·£¬·Ï¾ÉÂÁ²ÄµÄ»ØÊÕÀûÓÃÊ®·ÖÖØÒª¡£ÔÚ¹¤ÒµÉÏ£¬×îÄÜÌåÏÖ½ÚÄܼõÅÅ˼ÏëµÄÊǽ«»ØÊÕÂÁ×ö³É¡¡¡¡¡¡¡¡£¨Ìî´úºÅ£©¡£

a.±ù¾§Ê¯¡¡¡¡¡¡¡¡b.Ñõ»¯ÂÁ¡¡¡¡¡¡¡¡c.ÂÁ¶§¡¡¡¡¡¡¡¡d.ÁòËáÂÁ

¢ò.¸ÖÌú¹¤Òµ¶Ô´Ù½ø¾­¼ÃºÍÉç»á·¢Õ¹ÆðÁËÖØÒª×÷Óá£

(1£©Á¶Ìú¸ß¯·ÖΪÎ岿·Ö£¬Ìú¿óʯÓë¸ßÎÂúÆøÖ÷ÒªÔÚ_________²¿·Ö·¢Éú·´Ó¦

(2£©Á¶¸Öʱ£¬³ýÁ׵Ļ¯Ñ§·½³ÌʽΪ_________£»¼ÓÈë¹è¡¢Ã̺ÍÂÁµÄÄ¿µÄÊÇ_______¡£

(3£©²»Ðâ¸Öº¬ÓеÄCrÔªËØÊÇÔÚÁ¶¸Ö¹ý³ÌµÄÑõ´µ_______(Ìî¡°Ç°¡±»ò¡°ºó¡±)¼ÓÈ룬

Ô­ÒòÊÇ_____________¡£

(4£©Á¶ÌúºÍÁ¶¸ÖÉú²úÖУ¬Î²Æø¾ùº¬ÓеÄÖ÷ÒªÎÛȾÎïÊÇ_________¡£´Ó»·±£ºÍ¾­¼Ã½Ç¶È¿¼ÂÇ£¬ÉÏÊöβÆø¾­´¦Àí¿ÉÓÃ×÷________¡£

 

¡¾´ð°¸¡¿

¢ñ.£¨1£©½µµÍAl2O3µÄÈÛ»¯ÎÂ¶È £¨1·Ö£©

£¨2£©Ï²㠣¨1·Ö£© £¨3£©   Ñô¼«£¨2·Ö£© £¨4£©c  £¨1·Ö£©

¢ò. (1)¯Éí£¨2·Ö£©

(2)2P+5FeO+3CaOCa3(PO4)2+5Fe£¨2·Ö£©£» ÍÑÑõºÍµ÷Õû¸ÖµÄ³É·Ö£¨2·Ö£©¡£

(3)ºó£¨1·Ö£©£»±ÜÃâCr±»Ñõ»¯£¨»ò¡°Ñõ´µÇ°¼ÓÈëCr»áÐγɯÔü±»³ýÈ¥¡±£©£¨1·Ö£©¡£

(4)CO£¨1·Ö£©£»È¼ÁÏ£¨»ò»¹Ô­¼Á£©£¨1·Ö£©¡£

¡¾½âÎö¡¿ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÂÁÊǵؿÇÖк¬Á¿×î¸ßµÄ½ðÊôÔªËØ£¬Ý½µ¥Öʼ°ÆäºÏ½ðÔÚÉú²úÉú»îÖеÄÓ¦ÓÃÊ®·Ö¹ã·º£®
£¨1£©½ðÊôÂÁµÄÉú²úÊÇÒÔA12O3ΪԭÁÏ£¬ÔÚÈÛÈÚ״̬ϽøÐеç½â£¬»¯Ñ§·½³ÌʽΪ£º2A12O3 
 Na3AlF6£¬¸ßΠ
.
ͨµç
4Al+3O2¡ü£®µç¼«¾ùÓÉʯī²ÄÁÏ×ö³É£¬µç½âʱ²»¶ÏÏûºÄµÄµç¼«ÊÇ
Ñô¼«
Ñô¼«
£¨Ìî¡°Òõ¼«¡¯»ò¡°Ñô¼«¡±£©£¬Ô­ÒòÊÇ
C+O2
 ¸ßΠ
.
 
CO2
C+O2
 ¸ßΠ
.
 
CO2
£¨Óû¯Ñ§·½³Ìʽ±íʾ£©£®
£¨2£©¶ÔÂÁÖÆÆ·½øÐп¹¸¯Ê´´¦Àí£¬¿ÉÑÓ³¤ÆäʹÓÃÊÙÃü£®ÒÔ´¦Àí¹ýµÄÂÁ²ÄΪÑô¼«£¬ÔÚH2SO4ÈÜÒºÖеç½â£¬ÂÁ²Ä±íÃæÐγÉÑõ»¯Ä¤£¬Ñô¼«·´Ó¦Ê½Îª
2Al+3H2O-6e-=Al2O3+6H+
2Al+3H2O-6e-=Al2O3+6H+
£®
£¨3£©ÔÚ½ðÊôÂÁ±íÃæÐγÉÒ»²ã¿¹¸¯Ê´¡¢¿¹Ä¥ËðÄÜÁ¦µÄÍ­¶ÆĤ£¬ÓÃ
Í­
Í­
×öÑô¼«£¬µ±ÓÐ64gÍ­Îö³öʱ£¬×ªÒƵĵç×ÓÊýΪ
1.204¡Á1024
1.204¡Á1024
£®
£¨4£©ÂÁµç³ØÐÔÄÜÓÅÔ½£¬Al-Ag2Oµç³Ø¿ÉÓÃ×÷ˮ϶¯Á¦µçÔ´£¬»¯Ñ§·´Ó¦Îª2A1+3Ag2O+2NaOH+3H2O¨T2Na[Al£¨OH£©4]+6Ag£¬Ôò¸º¼«µÄµç¼«·´Ó¦Ê½Îª
Al+4OH--3e-=[Al£¨OH£©4]-
Al+4OH--3e-=[Al£¨OH£©4]-
£¬Õý¼«¸½½üÈÜÒºµÄpH
±ä´ó
±ä´ó
£¨Ìî¡°±ä´ó¡±¡¢¡°²»±ä¡±»ò¡°±äС¡±£©£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2010?ÌìºÓÇøһģ£©ÏÂÁÐÐðÊöÕýÈ·µÄÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2009?ɽ¶«£©£¨»¯Ñ§-»¯Ñ§Óë¼¼Êõ£©
½ðÊôÂÁµÄÉú²úÊÇÒÔAl2O3ΪԭÁÏ£¬ÔÚÈÛÈÚ״̬ϽøÐеç½â£º2Al2O3
750-970oCͨµç£¬Na3AIF6
4Al+3O2
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©±ù¾§Ê¯£¨Na3AIF6£©µÄ×÷ÓÃÊÇ
½µµÍAl2O3µÄÈÛ»¯Î¶È
½µµÍAl2O3µÄÈÛ»¯Î¶È
£®
£¨2£©µç½âÉú³ÉµÄ½ðÊôÂÁÊÇÔÚÈÛÈÚÒºµÄ
ϲã
ϲã
£¨Ìî¡°Éϲ㡱»ò¡°Ï²㡱£©£®
£¨3£©Òõ¼«ºÍÑô¼«¾ùÓÉ
̼°ô£¨»òʯī£©
̼°ô£¨»òʯī£©
²ÄÁÏ×ö³É£»µç½âʱËùÏûºÄµÄµç¼«ÊÇ
Ñô¼«
Ñô¼«
£¨Ìî¡°Ñô¼«¡±»ò¡°Òõ¼«¡±£©£®
£¨4£©ÂÁÊǸߺÄÄܲúÆ·£¬·Ï¾ÉÂÁ²ÄµÄ»ØÊÕÀûÓÃÊ®·ÖÖØÒª£®ÔÚ¹¤ÒµÉÏ£¬×îÄÜÌåÏÖ½ÚÄܼõÅÅ˼ÏëµÄÊǽ«»ØÊÕÂÁ×ö³É
c
c
£¨Ìî´úºÅ£©£®
a£®±ù¾§Ê¯¡¡¡¡¡¡¡¡b£®Ñõ»¯ÂÁ¡¡¡¡¡¡¡¡c£®ÂÁ¶§¡¡¡¡¡¡¡¡d£®ÁòËáÂÁ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¹¤ÒµÉϽðÊôÂÁµÄÉú²úÊÇÒÔAl2O3ΪԭÁÏ£¬ÔÚÈÛÈÚ״̬ϽøÐеç½âÁ÷³ÌÈçÏ£º2Al2O 3
   750¡æ-970¡æ   
.
ͨµç£¬Na3AlF6
4Al+3O2
×¢£º±ù¾§Ê¯µÄ×÷ÓÃÊÇʹEÔڽϵÍζÈÏÂÈÛ»¯£®
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©±ùƷʯ£¨Na3AlF6£©µÄ×÷ÓÃÊÇ
½µµÍAl2O3µÄÈÛ»¯Î¶È
½µµÍAl2O3µÄÈÛ»¯Î¶È
£®
£¨2£©ÂÁµÄ×îÍâ²ãµç×ÓÊý
3
3
£¬ÔÚÖÜÆÚ±íÖеÄλÖÃÊÇ
µÚÈýÖÜÆÚ¡¢¢óA×å
µÚÈýÖÜÆÚ¡¢¢óA×å
£®
£¨3£©µç½âÉú³ÉµÄ½ðÊôÂÁÊÇÔÚÈÛÈÚÒºµÄ
ϲã
ϲã
£¨Ìî¡°Éϲ㡱»ò¡°Ï²㡱£©£®Òõ¼«ºÍÑô¼«¾ùÓÉ
̼ËØ£¨»òʯī£©
̼ËØ£¨»òʯī£©
²ÄÁÏ×ö³É£»µç½âʱËùÏûºÄµÄµç¼«ÊÇ
Ñô¼«
Ñô¼«
£¨Ìî¡°Ñô¼«¡±»ò¡°Òõ¼«¡±£©£®
£¨4£©ÔÚ±ê×¼×´¿öϲúÉú67.2LÑõÆø£¬¿ÉµÃµ½½ðÊôÂÁ
108
108
¿Ë£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨»¯Ñ§-»¯Ñ§Óë¼¼Êõ£©
¢ñ£®½ðÊôÂÁµÄÉú²úÊÇÒÔAl2O3ΪԭÁÏ£¬ÔÚÈÛÈÚ״̬ϽøÐеç½â£º2Al2O3
       750-970       
.
ͨµç£¬Na3AlF6
4Al+3O2¡ü
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©±ù¾§Ê¯£¨Na3AlF6£©µÄ×÷ÓÃÊÇ
 
£®
£¨2£©µç½âÉú³ÉµÄ½ðÊôÂÁÊÇÔÚÈÛÈÚÒºµÄ
 
£¨Ìî¡°Éϲ㡱»ò¡°Ï²㡱£©£®
£¨3£©µç½âʱËùÏûºÄµÄµç¼«ÊÇ
 
£¨Ìî¡°Ñô¼«¡±»ò¡°Òõ¼«¡±£©£®
£¨4£©ÂÁÊǸߺÄÄܲúÆ·£¬·Ï¾ÉÂÁ²ÄµÄ»ØÊÕÀûÓÃÊ®·ÖÖØÒª£®ÔÚ¹¤ÒµÉÏ£¬×îÄÜÌåÏÖ½ÚÄܼõÅÅ˼ÏëµÄÊǽ«»ØÊÕÂÁ×ö³É
 
£¨Ìî´úºÅ£©£®
a£®±ù¾§Ê¯¡¡¡¡¡¡¡¡b£®Ñõ»¯ÂÁ¡¡¡¡¡¡¡¡c£®ÂÁ¶§¡¡¡¡¡¡¡¡d£®ÁòËáÂÁ
¢ò£®¸ÖÌú¹¤Òµ¶Ô´Ù½ø¾­¼ÃºÍÉç»á·¢Õ¹ÆðÁËÖØÒª×÷Óã®
£¨1£©Á¶Ìú¸ß¯·ÖΪÎ岿·Ö£¬Ìú¿óʯÓë¸ßÎÂúÆøÖ÷ÒªÔÚ
 
²¿·Ö·¢Éú·´Ó¦
£¨2£©Á¶¸Öʱ£¬³ýÁ׵Ļ¯Ñ§·½³ÌʽΪ
 
£»¼ÓÈë¹è¡¢Ã̺ÍÂÁµÄÄ¿µÄÊÇ
 
£®
£¨3£©²»Ðâ¸Öº¬ÓеÄCrÔªËØÊÇÔÚÁ¶¸Ö¹ý³ÌµÄÑõ´µ
 
£¨Ìî¡°Ç°¡±»ò¡°ºó¡±£©¼ÓÈ룬ԭÒòÊÇ
 
£®
£¨4£©Á¶ÌúºÍÁ¶¸ÖÉú²úÖУ¬Î²Æø¾ùº¬ÓеÄÖ÷ÒªÎÛȾÎïÊÇ
 
£®´Ó»·±£ºÍ¾­¼Ã½Ç¶È¿¼ÂÇ£¬ÉÏÊöβÆø¾­´¦Àí¿ÉÓÃ×÷
 
£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸