µç½â·¨ÖÆÉÕ¼îµÄÔ­ÁÏÊDZ¥ºÍʳÑÎË®£¬ÓÉÓÚ´ÖÑÎÖк¬ÓÐÄàɳºÍCa2+¡¢Mg2+¡¢Fe3+¡¢SO42- ÔÓÖÊ£¬²»·ûºÏµç½âÒªÇó£¬Òò´Ë±ØÐë¾­¹ý¾«ÖÆ¡£Ä³Ð£ÊµÑéС×龫ÖÆ´ÖÑÎË®µÄʵÑé¹ý³ÌÈçÏ£º

Çë»Ø´ðÒÔÏÂÎÊÌ⣺

£¨1£©²Ù×÷aµÄÃû³ÆÊÇ____________¡£

£¨2£©ÔÚ¢ò²½ÖУ¬¼ÓÈë¹ýÁ¿ÊÔ¼Á¼×ºó£¬Éú³ÉÁËÁ½ÖÖ´óÁ¿µÄ³Áµí£¬ÔòÊÔ¼Á¼×Ϊ________ÈÜÒº¡£ÊÔ¼ÁÒÒΪ          £¬¹ÌÌåFΪ                        ¡£

£¨3£©ÔÚµÚ¢õ²½ÖУ¬¼ÓÈëÊÔ¼Á¶¡Ö±µ½ÈÜÒºÎÞÃ÷ÏԱ仯ʱ£¬Ð´³ö´Ë¹ý³ÌµÄ»¯Ñ§·½³Ìʽ                                      ¡¢                                  _   ¡£

£¨1£©¹ýÂË£¨1·Ö£©£¨2£©NaOH¡¢BaCl2¡¢CaCO3ºÍBaCO3£¨Ã¿¿Õ2·Ö£©£¨3£©NaOH + HCl = NaCl + H2O       Na2CO3 + 2HCl = 2NaCl + H2O + CO2¡ü£¨Ã¿¿Õ2·Ö£©

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

µç½â·¨ÖÆÉÕ¼îµÄÔ­ÁÏÊDZ¥ºÍʳÑÎË®£¬ÓÉÓÚ´ÖÑÎÖк¬ÓÐÄàɳºÍCa2+¡¢Mg2+¡¢Fe3+¡¢SO42- ÔÓÖÊ£¬²»·ûºÏµç½âÒªÇó£¬Òò´Ë±ØÐë¾­¹ý¾«ÖÆ£®Ä³Ð£ÊµÑéС×龫ÖÆ´ÖÑÎË®µÄʵÑé¹ý³ÌÈçÏ£º

Çë»Ø´ðÒÔÏÂÎÊÌ⣺
£¨1£©²Ù×÷aµÄÃû³ÆÊÇ
¹ýÂË
¹ýÂË
£®
£¨2£©ÔÚ¢ò²½ÖУ¬¼ÓÈë¹ýÁ¿ÊÔ¼Á¼×ºó£¬Éú³ÉÁËÁ½ÖÖ´óÁ¿µÄ³Áµí£¬ÔòÊÔ¼Á¼×Ϊ
NaOH
NaOH
ÈÜÒº£®ÊÔ¼ÁÒÒΪ
BaCl2
BaCl2
£¬¹ÌÌåFΪ
CaCO3ºÍBaCO3
CaCO3ºÍBaCO3
£®
£¨3£©ÔÚµÚ¢õ²½ÖУ¬¼ÓÈëÊÔ¼Á¶¡Ö±µ½ÈÜÒºÎÞÃ÷ÏԱ仯ʱ£¬Ð´³ö´Ë¹ý³ÌµÄ»¯Ñ§·½³Ìʽ
NaOH+HCl=NaCl+H2O
NaOH+HCl=NaCl+H2O
¡¢
Na2CO3+2HCl=2NaCl+H2O+CO2¡ü
Na2CO3+2HCl=2NaCl+H2O+CO2¡ü
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨11·Ö£©µç½â·¨ÖÆÉÕ¼îµÄÔ­ÁÏÊDZ¥ºÍʳÑÎË®£¬ÓÉÓÚ´ÖÑÎÖк¬ÓÐÄàɳºÍCa2+¡¢Mg2+¡¢Fe3+¡¢SO42-ÔÓÖÊ£¬²»·ûºÏµç½âÒªÇó£¬Òò´Ë±ØÐë¾­¹ý¾«ÖÆ¡£Ä³Ð£ÊµÑéС×龫ÖÆ´ÖÑÎË®µÄʵÑé¹ý³ÌÈçÏ£º

Çë»Ø´ðÒÔÏÂÎÊÌ⣺

£¨1£©²Ù×÷aµÄÃû³ÆÊÇ____________¡£

£¨2£©ÔÚ¢ò²½ÖУ¬¼ÓÈë¹ýÁ¿ÊÔ¼Á¼×ºó£¬Éú³ÉÁËÁ½ÖÖ´óÁ¿µÄ³Áµí£¬ÔòÊÔ¼Á¼×Ϊ________ÈÜÒº¡£ÊÔ¼ÁÒÒΪ         £¬¹ÌÌåFΪ                       ¡£

£¨3£©ÔÚµÚ¢õ²½ÖУ¬¼ÓÈëÊÔ¼Á¶¡Ö±µ½ÈÜÒºÎÞÃ÷ÏԱ仯ʱ£¬Ð´³ö´Ë¹ý³ÌµÄ»¯Ñ§·½³Ìʽ                                     ¡¢                                 _   ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010ÄêÁÉÄþÊ¡ÉòÑô¶þÖиßÒ»ÉÏѧÆÚ10ÔÂÔ¿¼£¨»¯Ñ§£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨11·Ö£©µç½â·¨ÖÆÉÕ¼îµÄÔ­ÁÏÊDZ¥ºÍʳÑÎË®£¬ÓÉÓÚ´ÖÑÎÖк¬ÓÐÄàɳºÍCa2+¡¢Mg2+¡¢Fe3+¡¢SO42-ÔÓÖÊ£¬²»·ûºÏµç½âÒªÇó£¬Òò´Ë±ØÐë¾­¹ý¾«ÖÆ¡£Ä³Ð£ÊµÑéС×龫ÖÆ´ÖÑÎË®µÄʵÑé¹ý³ÌÈçÏ£º

Çë»Ø´ðÒÔÏÂÎÊÌ⣺
£¨1£©²Ù×÷aµÄÃû³ÆÊÇ____________¡£
£¨2£©ÔÚ¢ò²½ÖУ¬¼ÓÈë¹ýÁ¿ÊÔ¼Á¼×ºó£¬Éú³ÉÁËÁ½ÖÖ´óÁ¿µÄ³Áµí£¬ÔòÊÔ¼Á¼×Ϊ________ÈÜÒº¡£ÊÔ¼ÁÒÒΪ         £¬¹ÌÌåFΪ                       ¡£
£¨3£©ÔÚµÚ¢õ²½ÖУ¬¼ÓÈëÊÔ¼Á¶¡Ö±µ½ÈÜÒºÎÞÃ÷ÏԱ仯ʱ£¬Ð´³ö´Ë¹ý³ÌµÄ»¯Ñ§·½³Ìʽ                                     ¡¢                                 _  ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010ÄêÁÉÄþÊ¡¸ßÒ»ÉÏѧÆÚ10ÔÂÔ¿¼£¨»¯Ñ§£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨11·Ö£©µç½â·¨ÖÆÉÕ¼îµÄÔ­ÁÏÊDZ¥ºÍʳÑÎË®£¬ÓÉÓÚ´ÖÑÎÖк¬ÓÐÄàɳºÍCa2+¡¢Mg2+¡¢Fe3+¡¢SO42- ÔÓÖÊ£¬²»·ûºÏµç½âÒªÇó£¬Òò´Ë±ØÐë¾­¹ý¾«ÖÆ¡£Ä³Ð£ÊµÑéС×龫ÖÆ´ÖÑÎË®µÄʵÑé¹ý³ÌÈçÏ£º

Çë»Ø´ðÒÔÏÂÎÊÌ⣺

£¨1£©²Ù×÷aµÄÃû³ÆÊÇ____________¡£

£¨2£©ÔÚ¢ò²½ÖУ¬¼ÓÈë¹ýÁ¿ÊÔ¼Á¼×ºó£¬Éú³ÉÁËÁ½ÖÖ´óÁ¿µÄ³Áµí£¬ÔòÊÔ¼Á¼×Ϊ________ÈÜÒº¡£ÊÔ¼ÁÒÒΪ          £¬¹ÌÌåFΪ                        ¡£

£¨3£©ÔÚµÚ¢õ²½ÖУ¬¼ÓÈëÊÔ¼Á¶¡Ö±µ½ÈÜÒºÎÞÃ÷ÏԱ仯ʱ£¬Ð´³ö´Ë¹ý³ÌµÄ»¯Ñ§·½³Ìʽ                                      ¡¢                                  _   ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

µç½â·¨ÖÆÉÕ¼îµÄÔ­ÁÏÊDZ¥ºÍʳÑÎË®£¬ÓÉÓÚ´ÖÑÎÖк¬ÓÐÄàɳºÍCa2+¡¢Mg2+¡¢Fe3+¡¢SO42- ÔÓÖÊ£¬²»·ûºÏµç½âÒªÇó£¬Òò´Ë±ØÐë¾­¹ý¾«ÖÆ£®Ä³Ð£ÊµÑéС×龫ÖÆ´ÖÑÎË®µÄʵÑé¹ý³ÌÈçÏ£º

Çë»Ø´ðÒÔÏÂÎÊÌ⣺
£¨1£©²Ù×÷aµÄÃû³ÆÊÇ______£®
£¨2£©ÔÚ¢ò²½ÖУ¬¼ÓÈë¹ýÁ¿ÊÔ¼Á¼×ºó£¬Éú³ÉÁËÁ½ÖÖ´óÁ¿µÄ³Áµí£¬ÔòÊÔ¼Á¼×Ϊ______ÈÜÒº£®ÊÔ¼ÁÒÒΪ______£¬¹ÌÌåFΪ______£®
£¨3£©ÔÚµÚ¢õ²½ÖУ¬¼ÓÈëÊÔ¼Á¶¡Ö±µ½ÈÜÒºÎÞÃ÷ÏԱ仯ʱ£¬Ð´³ö´Ë¹ý³ÌµÄ»¯Ñ§·½³Ìʽ______¡¢______£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸