ij´ÎʵÑéÐèÒªÓÃ0.4mol/L NaOHÈÜÒº480mL£®ÅäÖÆ·½·¨ÈçÏ£º
£¨1£©ÅäÖƸÃÈÜҺӦѡÓÃ
500
500
mL ÈÝÁ¿Æ¿£®
£¨2£©ÓÃÍÐÅÌÌìƽ׼ȷ³ÆÁ¿
8.0
8.0
g ¹ÌÌåNaOH£®
£¨3£©½«³ÆÁ¿ºÃµÄNaOH¹ÌÌå·ÅÈë500mL ´óÉÕ±­£¬µ¹ÈëÔ¼200mL ÕôÁóË®£¬Óò£Á§°ô½Á°è£¬Ê¹¹ÌÌåÈ«²¿Èܽ⣬´ý
´ýÈÜÒºÀäÈ´ÖÁÊÒÎÂ
´ýÈÜÒºÀäÈ´ÖÁÊÒÎÂ
ºó£¬½«ÉÕ±­ÖеÄÈÜҺעÈëÈÝÁ¿Æ¿ÖУ®
£¨4£©ÓÃÉÙÁ¿
ÕôÁóË®
ÕôÁóË®
Ï´µÓÉÕ±­2¡«3´Î£¬Ï´µÓºóµÄÈÜÒº
Ò»ÆðתÈëÈÝÁ¿Æ¿ÖÐ
Ò»ÆðתÈëÈÝÁ¿Æ¿ÖÐ
£¬ÇáÇá»Î¶¯ÈÝÁ¿Æ¿£¬Ê¹ÈÜÒº»ìºÏ¾ùÔÈ£®
£¨5£©ÏòÈÝÁ¿Æ¿¼ÓÈëÕôÁóË®£¬µ½ÒºÃæ¾à¿Ì¶ÈÏß
1¡«2cm
1¡«2cm
ʱ£¬¸ÄÓÃ
½ºÍ·µÎ¹Ü
½ºÍ·µÎ¹Ü
¼ÓÕôÁóË®ÖÁÒºÃæÓë¿Ì¶ÈÏßÏàÇУ®¸ÇºÃÆ¿Èû£¬
ÉÏϵߵ¹»ìºÏ¾ùÔÈ
ÉÏϵߵ¹»ìºÏ¾ùÔÈ
£®
£¨6£©ÈôÔÚÅäÖƹý³ÌÖгöÏÖÏÂÁÐÇé¿ö£¬½«Ê¹ËùÅäÖƵÄNaOHÈÜҺŨ¶ÈÆ«¸ßµÄÊÇ
CE
CE
£¬Æ«µÍµÄÊÇ
AD
AD
£¬¶ÔʵÑé½á¹ûûÓÐÓ°ÏìµÄÊÇ
B
B
£¨ÌîÐòºÅ£©
A£®ËùÓõÄNaOHÖлìÓÐÉÙÁ¿µÄNa2CO3
B£®ÅäÖÆÈÜÒºËùÓõÄÈÝÁ¿Æ¿Ï´µÓºóûÓкæ¸É
C£®¹ÌÌåNaOHÔÚÉÕ±­ÖÐÈܽâºó£¬Á¢¼´½«ÈÜҺתÒƵ½ÈÝÁ¿Æ¿ºó£¬½øÐкóÃæµÄ²Ù×÷
D£®×ªÒÆÈÜÒººó£¬Î´Ï´µÓÉÕ±­ºÍ²£Á§°ô¾ÍÖ±½Ó¶¨ÈÝ
E£®×îºóÈ·¶¨NaOHÈÜÒºÌå»ý£¨¶¨ÈÝ£©Ê±£¬¸©ÊÓ¹Û²ìÒºÃ森
·ÖÎö£º£¨1£©Ò»¶¨ÈÝ»ýµÄÈÝÁ¿Æ¿Ö»ÄÜÅäÖÆÏàÓ¦Ìå»ýµÄÈÜÒº£¬¸ù¾ÝÈÜÒºµÄÌå»ý480mL£¬µ«ÈÝÁ¿Æ¿µÄ¹æ¸ñûÓÐ480mL£¬ÈÝÁ¿Æ¿Ìå»ýÒª´óÓÚ480mLÇÒÏà½ü£»
£¨2£©ÀûÓÃn=cv¼ÆËã³öÇâÑõ»¯ÄƵÄÎïÖʵÄÁ¿£¬ÔÙ¸ù¾Ým=nM¼ÆËãËùÐèÇâÑõ»¯ÄƵÄÖÊÁ¿£»
£¨3£©ÇâÑõ»¯ÄÆÈܽâ·Å³ö´óÁ¿µÄÈÈ£¬ÈÜÒº¾ßÓÐÈÈÕÍÀäËõµÄÐÔÖÊ£¬¹ÊÓ¦ÏÈÀäÈ´ÖÁÊÒÎÂÔÙÒÆÒº¶¨ÈÝ£»
£¨4£©Îª±£Ö¤ÈÜÖʾ¡¿ÉÄÜתÒƵ½ÈÝÁ¿Æ¿ÖУ¬ÐèÓÃÉÙÁ¿ÕôÁóˮϴµÓÉÕ±­2-3 ´Î£¬²¢½«Ï´µÓÒºÒ»ÆðתÈëÈÝÁ¿Æ¿ÖУ»
£¨5£©ÏòÈÝÁ¿Æ¿ÖмÓÈëÕôÁóË®£¬µ½ÒºÃæ 1-2cmʱ£¬¸ÄÓýºÍ·µÎ¹Ü¼ÓÕôÁóË®ÖÁÒºÃæ×îµÍµãÓë¿Ì¶ÈÏßÏàÇУ®¸ÇºÃÆ¿Èû£¬ÉÏϵߵ¹»ìºÏ¾ùÔÈ£»
£¨6£©·ÖÎö²Ù×÷¶ÔÈÜÖʵÄÎïÖʵÄÁ¿»ò¶ÔÈÜÒºµÄÌå»ýµÄÓ°Ï죬¸ù¾Ýc=
n
v
·ÖÎöÅжϣ®
½â´ð£º½â£º£¨1£©ÒòÈÜÒºµÄÌå»ý480mL£¬µ«ÈÝÁ¿Æ¿µÄ¹æ¸ñûÓÐ480mL£¬ËùÒÔÑ¡ÓÃ500mLÈÝÁ¿Æ¿£¬¹Ê´ð°¸Îª£º500mL£»
£¨2£©ÐèÇâÑõ»¯ÄƵÄÖÊÁ¿Îªm=0.5L¡Á0.4mol?L-1¡Á40g/mol=8.0g£¬¹Ê´ð°¸Îª£º8.0£»
£¨3£©ÇâÑõ»¯ÄÆÈܽâ·Å³ö´óÁ¿µÄÈÈ£¬ÈÜÒº¾ßÓÐÈÈÕÍÀäËõµÄÐÔÖÊ£¬Ó°ÏìÈÜÒºÌå»ý£¬¹ÊÓ¦ÏÈÀäÈ´ÖÁÊÒΣ¬¹Ê´ð°¸Îª£º´ýÈÜÒºÀäÈ´ÖÁÊÒΣ»
£¨4£©Îª±£Ö¤ÈÜÖʾ¡¿ÉÄÜתÒƵ½ÈÝÁ¿Æ¿ÖУ¬ÐèÓÃÉÙÁ¿ÕôÁóˮϴµÓÉÕ±­2-3 ´Î£¬²¢½«Ï´µÓÒºÒ»ÆðתÈëÈÝÁ¿Æ¿ÖУ¬¹Ê´ð°¸Îª£ºÕôÁóË®£»Ò»ÆðתÈëÈÝÁ¿Æ¿ÖУ»
£¨5£©ÏòÈÝÁ¿Æ¿ÖмÓÈëÕôÁóË®£¬µ½ÒºÃæÀë¿Ì¶ÈÏß1-2cmʱ£¬¸ÄÓýºÍ·µÎ¹Ü¼ÓÕôÁóË®ÖÁÒºÃæ×îµÍµãÓë¿Ì¶ÈÏßÏàÇУ®¸ÇºÃÆ¿Èû£¬ÉÏϵߵ¹»ìºÏ¾ùÔÈ£¬¹Ê´ð°¸Îª£º1¡«2cm£»½ºÍ·µÎ¹Ü£»ÉÏϵߵ¹»ìºÏ¾ùÔÈ£»
£¨6£©A£®ËùÓõÄNaOHÖлìÓÐÉÙÁ¿µÄNa2CO3£¬»áʹµÃNaOHµÄÖÊÁ¿¼õÉÙ£¬ËùÒÔÈÜҺŨ¶ÈÆ«µÍ£»
B£®×îºóÐèÒª¶¨ÈÝ£¬ÈÝÁ¿Æ¿Ï´¾»ºóûÓкæ¸É£¬¶ÔÈÜҺŨ¶ÈÎÞÓ°Ï죻
C£®ÇâÑõ»¯ÄÆÈܽâ·Å³ö´óÁ¿µÄÈÈ£¬ÈÜÒº¾ßÓÐÈÈÕÍÀäËõµÄÐÔÖÊ£¬¹ÊÓ¦ÏÈÀäÈ´ÖÁÊÒÎÂÔÙÒÆÒº¶¨ÈÝ£¬ËùÒÔ¹ÌÌåNaOHÔÚÉÕ±­ÖÐÈܽâºó£¬Á¢¼´½«ÈÜҺתÒƵ½ÈÝÁ¿Æ¿ºó£¬½øÐкóÃæµÄ²Ù×÷»áʹµÃÈÜÒºµÄÌå»ý±äС£¬ËùÒÔÈÜҺŨ¶ÈÆ«¸ß£»
D£®×ªÒÆÈÜÒººó£¬Î´Ï´µÓÉÕ±­ºÍ²£Á§°ô¾ÍÖ±½Ó¶¨ÈÝ£¬ÉÙÁ¿ÇâÑõ»¯ÄÆÕ´ÔÚÉÕ±­±ÚÓë²£Á§°ôÉÏ£¬ÇâÑõ»¯ÄƵÄʵ¼ÊÖÊÁ¿¼õС£¬ÈÜҺŨ¶ÈÆ«µÍ£»
E£®¶¨ÈÝʱ£¬¸©ÊÓÈÝÁ¿Æ¿¿Ì¶ÈÏߣ¬Ê¹ÈÜÒºµÄÌå»ýÆ«µÍ£¬ËùÒÔÈÜҺŨ¶ÈÆ«¸ß£®
ËùÒÔÆ«¸ßµÄÓÐCE£¬Æ«µÍÓÐAD£¬ÎÞÓ°ÏìµÄÊÇB£®
¹Ê´ð°¸Îª£ºCE£»AD£»B£®
µãÆÀ£º±¾Ì⿼²éÈÜÒºµÄÅäÖÆ£¬ÄѶȲ»´ó£¬¹Ø¼üÇå³þÈÜÒºÅäÖƵÄÔ­Àí£¬Í¨¹ýc=
n
v
¿ÉÒÔ¼ÓÉîÀí½â£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ʵÑéÊÒΪÍê³ÉijһʵÑ飬ÐèÓÃ240mL0.1mol/LµÄÏ¡ÑÎËᣬÏÖÓÃ11.8mol/LµÄŨÑÎËáÅäÖÆ£¬Ìî¿Õ²¢Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÅäÖÆÍê³ÉijһʵÑéËùÐè0.1mol/LµÄÑÎËáÈÜÒº£¬Ñ¡ÓÃ
250
250
mLÈÝÁ¿Æ¿£¬Ó¦Á¿È¡Å¨ÑÎËáÌå»ýΪ
2.1
2.1
mL£¬³ýÈÝÁ¿Æ¿Í⻹ÐèÒªµÄÆäËüÒÇÆ÷ÓÐ
10mlÁ¿Í²
10mlÁ¿Í²
¡¢
ÉÕ±­
ÉÕ±­
¡¢
²£Á§°ô
²£Á§°ô
¡¢
½ºÍ·µÎ¹Ü
½ºÍ·µÎ¹Ü
µÈ£®
£¨2£©ÅäÖÆʱ£¬ÆäÕýÈ·µÄ²Ù×÷˳ÐòÊÇ£¨ÓÃ×Öĸ±íʾ£¬Ã¿¸ö×ÖĸֻÄÜÓÃÒ»´Î£©
B¡¢C¡¢A¡¢F¡¢E¡¢D
B¡¢C¡¢A¡¢F¡¢E¡¢D
£®
A£®ÓÃ30mLˮϴµÓÉÕ±­2-3´Î£¬Ï´µÓÒº¾ù×¢ÈëÈÝÁ¿Æ¿£¬Õñµ´
B£®ÓÃÁ¿Í²×¼È·Á¿È¡ËùÐèµÄŨÑÎËáµÄÌå»ý£¬Ñز£Á§°ôµ¹ÈëÉÕ±­ÖУ¬ÔÙ¼ÓÈëÉÙÁ¿Ë®£¨Ô¼30mL£©£¬Óò£Á§°ôÂýÂý½Á¶¯£¬Ê¹Æä»ìºÏ¾ùÔÈ
C£®½«ÒÑÀäÈ´µÄÑÎËáÑز£Á§°ô×¢Èë250mLµÄÈÝÁ¿Æ¿ÖÐ
D£®½«ÈÝÁ¿Æ¿¸Ç½ô£¬Õñµ´£¬Ò¡ÔÈ
E£®¸ÄÓýºÍ·µÎ¹Ü¼ÓË®£¬Ê¹ÈÜÒº°¼ÒºÃæÇ¡ºÃÓë¿Ì¶ÈÏàÇÐ
F£®¼ÌÐøÍùÈÝÁ¿Æ¿ÄÚСÐļÓË®£¬Ö±µ½ÒºÃæ½Ó½ü¿Ì¶È1-2cm´¦
£¨3£©Èô³öÏÖÈçÏÂÇé¿ö£¬¶ÔËùÅäÈÜҺŨ¶È½«ÓкÎÓ°Ï죨ƫ¸ß¡¢Æ«µÍ»òÎÞÓ°Ï죩£ºÃ»ÓнøÐÐA²Ù×÷
Æ«µÍ
Æ«µÍ
£»¼ÓÕôÁóˮʱ²»É÷³¬¹ýÁ˿̶È
Æ«µÍ
Æ«µÍ
£»¶¨ÈÝʱ¸©ÊÓ
Æ«¸ß
Æ«¸ß
£®
£¨4£©1.06g¡¡Na2CO3Óë×ãÁ¿ËùÅäÖƵÄÑÎËá·´Ó¦£¬Éú³ÉCO2ÆøÌåÔÚ±ê×¼×´¿öϵÄÌå»ýÊÇ
0.224
0.224
Éý£®ÐèËùÅäÖƵÄÑÎËáµÄÌå»ýÖÁÉÙΪ
200
200
ºÁÉý²ÅΪ×ãÁ¿£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

£¨1£©¼×ͬѧÔÚij´ÎʵÑéÖдóÔ¼ÐèÒª0.10mol/LµÄÇâÑõ»¯ÄÆÈÜÒº900mL£¬ÅäÖÆʱÉæ¼°µ½ÈçϲÙ×÷£º
¢ÙÇáÇáÕñµ´ÈÝÁ¿Æ¿£¨Õñµ´Ê±²»Äܽ«ÈÜÒºÒç³ö¿Ì¶ÈÏßÍ⣩£¬Ê¹ÈÜÒº³ä·Ö»ìºÏ
¢ÚÓÃÌìƽ³ÆÁ¿´¿¾»µÄÇâÑõ»¯ÄƹÌÌå
4.0
4.0
g
¢Û´ýÉÕ±­ÖеÄÈÜÒºÀäÈ´ºóÑز£Á§°ôСÐĵØ×¢Èë
1000mLÈÝÁ¿Æ¿
1000mLÈÝÁ¿Æ¿
ÖÐ
¢Ü½«ÈÝÁ¿Æ¿ÓÃÆ¿Èû¸ÇºÃ£¬·´¸´ÉÏϵߵ¹¡¢Ò¡ÔÈ
¢Ý½«ÅäÖƺõÄÈÜÒºµ¹Èë¸ÉÔï¡¢½à¾»µÄÊÔ¼ÁÆ¿ÖУ¬ÌùºÃ±êÇ©±¸ÓÃ
¢ÞÏòÊ¢ÓÐNaOHµÄÈÝÆ÷ÖУ¬¼ÓÈëÊÊÁ¿µÄÕôÁóˮʹ¹ÌÌåÍêÈ«Èܽâ
¢ß¸ÄÓÃ
½ºÍ·µÎ¹Ü
½ºÍ·µÎ¹Ü
µÎ¼ÓÕôÁóË®ÖÁÈÜÒºµÄ°¼ÒºÃæÕýºÃÓë¿Ì¶ÈÏßÏàÇÐ
¢àÓÃÕôÁóˮϴµÓÉÕ±­ÄÚ±Ú2-3´Î£¬½«Ã¿´ÎÏ´µÓºóµÄÈÜÒºÒ²¶¼×¢ÈëÈÝÁ¿Æ¿ÖÐ
¢áÏòÈÝÁ¿Æ¿ÖÐ×¢ÈëÕôÁóË®£¬Ö±µ½ÈÝÁ¿Æ¿ÖеÄÒºÃæ½Ó½üÈÝÁ¿Æ¿¿Ì¶È´¦1cm-2cm´¦
ÇëЭÖú¼×ͬѧÏÈÍê³É²Ù×÷ÖеĿÕÓಿ·Ö£¬ÔÙÔÚÏÂÁÐÑ¡ÏîÖÐÑ¡ÔñÕýÈ·µÄ²Ù×÷˳Ðò£®ÕýÈ·µÄ²Ù×÷˳ÐòÊÇ
B
B
£®
A£®¢Ú¢Þ¢Û¢Ü¢Ù¢ß¢à¢á¢ÝB£®¢Ú¢Þ¢Û¢à¢Ù¢á¢ß¢Ü¢Ý
C£®¢Ú¢Û¢Ù¢Ü¢Þ¢ß¢à¢á¢ÝD£®¢Ú¢Û¢Ù¢Þ¢ß¢à¢á¢Ü¢Ý
£¨2£©ÈÝÁ¿Æ¿ÉϱêÓÐ
¢Ù¢Û¢Ý
¢Ù¢Û¢Ý
£¨ÌîÐòºÅ£© ¢ÙζȠ¢ÚŨ¶È ¢ÛÈÝ»ý ¢Üѹǿ ¢Ý¿Ì¶ÈÏß 
£¨3£©ÏÂÁвÙ×÷»áʹËùÅäÈÜÒºÎïÖʵÄÁ¿Å¨¶ÈÆ«µÍµÄÊÇ
ABCDG
ABCDG
£®
A£®¶¨ÈÝ¡¢¼Ó¸Çµ¹×ªÒ¡ÔȺ󣬷¢ÏÖÒºÃæµÍÓڿ̶ÈÏߣ¬ÓֵμÓÕôÁóË®ÖÁ¿Ì¶È
B£®¶¨ÈÝʱÏòÈÝÁ¿Æ¿ÖмÓÕôÁóË®£¬³¬¹ý¿Ì¶ÈÏߣ¬ÔÙÎü³öÉÙÐí
C£®Ð¡ÉÕ±­¡¢²£Á§°ôûÓÐÏ´µÓ
D£®¹Û²ìÈÝÁ¿Æ¿¿Ì¶ÈʱÑöÊÓ
E£®ËùÓÃÈÝÁ¿Æ¿ÖУ¬ÒÑÓÐÉÙÁ¿ÕôÁóË®
F£®ÔÚδ½µÖÁÊÒÎÂʱ£¬Á¢¼´½«ÈÜҺתÒÆÖÁÈÝÁ¿Æ¿¶¨ÈÝ
G£®³ÆÁ¿Ê±Òѹ۲쵽NaOHÎüË®
£¨4£©³ÆÁ¿NaOH¹ÌÌåʱÐè×¢ÒâÒÔÏÂÁ½¸öÎÊÌ⣺
¢ÙÒòΪNaOH¾ßÓи¯Ê´ÐÔ£¬ËùÒÔ³ÆÁ¿Ê±£¬Ðè×¢ÒâÑ¡Ôñ
ÉÕ±­
ÉÕ±­
_Ê¢×°NaOH¹ÌÌ壻
¢Ú³ÆÁ¿±ØÐëѸËÙ£¬Ä¿µÄÊÇ
·ÀÖ¹³ÆÁ¿Ê±¼ä¹ý³¤£¬NaOHÎüË®³±½â»òÎüÊÕ¿ÕÆøÖеĶþÑõ»¯Ì¼¶ø±äÖÊ
·ÀÖ¹³ÆÁ¿Ê±¼ä¹ý³¤£¬NaOHÎüË®³±½â»òÎüÊÕ¿ÕÆøÖеĶþÑõ»¯Ì¼¶ø±äÖÊ
£®
£¨5£©¶¨ÈݵÄÕýÈ·²Ù×÷ÊÇ
¼ÓË®ÖÁÀë¿Ì¶ÈÏß1¡«2cmʱ£¬¸ÄÓýºÍ·µÎ¹ÜµÎ¼ÓË®ÖÁÒºÃ棨»ò°¼ÒºÃæ×îµÍµã£©Óë¿Ì¶ÈÏßÏàÇÐ
¼ÓË®ÖÁÀë¿Ì¶ÈÏß1¡«2cmʱ£¬¸ÄÓýºÍ·µÎ¹ÜµÎ¼ÓË®ÖÁÒºÃ棨»ò°¼ÒºÃæ×îµÍµã£©Óë¿Ì¶ÈÏßÏàÇÐ
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ijʵÑéС×éÓÃ0.50mol/L NaOHÈÜÒººÍ0.50mol/LÁòËáÈÜÒº½øÐÐÖкÍÈȵIJⶨ£®
¢ñ£®ÅäÖÆ0.50mol/L NaOHÈÜÒº
£¨1£©ÈôʵÑéÖдóԼҪʹÓÃ245mL NaOHÈÜÒº£¬ÖÁÉÙÐèÒª³ÆÁ¿NaOH¹ÌÌå
5.0
5.0
g£®
£¨2£©´ÓͼÖÐÑ¡Ôñ³ÆÁ¿NaOH¹ÌÌåËùÐèÒªµÄÒÇÆ÷ÊÇ£¨Ìî×Öĸ£©£º
a b e
a b e
£®

¢ò£®²â¶¨Ï¡ÁòËáºÍÏ¡ÇâÑõ»¯ÄÆÖкÍÈȵÄʵÑé×°ÖÃÈçͼËùʾ£®
£¨1£©Ð´³ö¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£¨ÖкÍÈÈΪ57.3kJ/mol£©£º
H2SO4£¨aq£©+2NaOH£¨aq£©=Na2SO4£¨aq£©+2H2O£¨l£©¡÷H=-114.6kJ/mol
H2SO4£¨aq£©+2NaOH£¨aq£©=Na2SO4£¨aq£©+2H2O£¨l£©¡÷H=-114.6kJ/mol
£®
£¨2£©È¡50mL NaOHÈÜÒººÍ30mLÁòËáÈÜÒº½øÐÐʵÑ飬ʵÑéÊý¾ÝÈçÏÂ±í£®
¢ÙÇëÌîдϱíÖеĿհףº
ζÈ
ʵÑé´ÎÊý
ÆðʼζÈt1/¡æ ÖÕֹζÈ
t2/¡æ
ζȲîƽ¾ùÖµ
£¨t2-t1£©/¡æ
H2SO4 NaOH ƽ¾ùÖµ
1 26.2 26.0 26.1 30.1
4.0
4.0
 
2 27.0 27.4 27.2 33.3
3 25.9 25.9 25.9 29.8
4 26.4 26.2 26.3 30.4
¢Ú½üËÆÈÏΪ0.50mol/L NaOHÈÜÒººÍ0.50mol/LÁòËáÈÜÒºµÄÃܶȶ¼ÊÇ1g/cm3£¬ÖкͺóÉú³ÉÈÜÒºµÄ±ÈÈÈÈÝc=4.18J/£¨g?¡æ£©£®ÔòÖкÍÈÈ¡÷H=
-53.5 kJ/mol
-53.5 kJ/mol
£¨È¡Ð¡Êýµãºóһ룩£®
¢ÛÉÏÊöʵÑéÊýÖµ½á¹ûÓë57.3kJ/molÓÐÆ«²î£¬²úÉúÆ«²îµÄÔ­Òò¿ÉÄÜÊÇ£¨Ìî×Öĸ£©
acd
acd
£®
a£®ÊµÑé×°Öñ£Î¡¢¸ôÈÈЧ¹û²î
b£®Á¿È¡NaOHÈÜÒºµÄÌå»ýʱÑöÊÓ¶ÁÊý
c£®·Ö¶à´Î°ÑNaOHÈÜÒºµ¹ÈëÊ¢ÓÐÁòËáµÄСÉÕ±­ÖÐ
d£®ÓÃζȼƲⶨNaOHÈÜÒºÆðʼζȺóÖ±½Ó²â¶¨H2SO4ÈÜÒºµÄζȣ®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¾«Ó¢¼Ò½ÌÍøijʵÑéС×éÓÃ0.50mol/L NaOHÈÜÒººÍ0.50mol/LÁòËáÈÜÒº½øÐÐÖкÍÈȵIJⶨ£®
¢ñ£®ÅäÖÆ0.50mol/L NaOHÈÜÒº£¨1£©ÈôʵÑéÖдóԼҪʹÓÃ245mL NaOHÈÜÒº£¬ÖÁÉÙÐèÒª³ÆÁ¿NaOH¹ÌÌå
 
g£®
£¨2£©³ÆÁ¿NaOH¹ÌÌåËùÐèÒªµÄÒÇÆ÷ÊÇÏÂÁеÄ
 
£¨ÌîÐòºÅ£©£º
¢ÙÍÐÅÌÌìƽ¡¢¢ÚСÉÕ±­¡¢¢ÛÛá¹øǯ¡¢¢Ü²£°ô¡¢¢ÝÒ©³×¡¢¢ÞÁ¿Í²
¢ò£®²â¶¨Ï¡ÁòËáºÍÏ¡ÇâÑõ»¯ÄÆÖкÍÈȵÄʵÑé×°ÖÃÈçͼËùʾ£®
£¨1£©ËéÅÝÄ­ËÜÁϵÄ×÷ÓÃÊÇ
 
£®
£¨2£©Ð´³ö¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ£¨ÖкÍÈÈΪ57.3kJ/mol£©£º
 
£®
£¨3£©È¡50mL NaOHÈÜÒººÍ30mLÁòËáÈÜÒº½øÐÐʵÑ飬ʵÑéÊý¾ÝÈçÏÂ±í£®
¢ÙÇëÌîдϱíÖеĿհףº
ζÈʵÑé´ÎÊý ÆðʼζÈt1/¡æ ÖÕֹζÈt2/¡æ ζȲîƽ¾ùÖµ
£¨t2-t1£©/¡æ
H2SO4 NaOH ƽ¾ùÖµ
1 26.2 26.0 26.1 30.3
 
2 27.0 27.4 27.2 31.0
3 25.9 25.9 25.9 29.8
4 26.4 26.2 26.3 30.4
¢Ú½üËÆÈÏΪ0.50mol/L NaOHÈÜÒººÍ0.50mol/LÁòËáÈÜÒºµÄÃܶȶ¼ÊÇ1g/cm3£¬ÖкͺóÉú³ÉÈÜÒºµÄ±ÈÈÈÈÝc=4.18J/£¨g?¡æ£©£®Ôò²âµÃµÄÖкÍÈÈ¡÷H=
 
£¨È¡Ð¡Êýµãºóһ룩£®
¢ÛÉÏÊöʵÑéÊýÖµ½á¹ûÓë57.3kJ/molÓÐÆ«²î£¬²úÉúÆ«²îµÄÔ­Òò¿ÉÄÜÊÇ£¨Ìî×Öĸ£©
 
£®
a£®×°Öñ£Î¡¢¸ôÈÈЧ¹û²î£»
b£®Á¿È¡NaOHÈÜÒºµÄÌå»ýʱÑöÊÓ¶ÁÊý£»
c£®·Ö¶à´Î°ÑNaOHÈÜÒºµ¹ÈëÊ¢ÓÐÁòËáµÄСÉÕ±­ÖУ»
d£®Î¶ȼƲⶨNaOHÈÜÒºÆðʼζȺóÖ±½Ó²åÈëÏ¡H2SO4²âζȣ®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸