ij¹¤³§ÅųöµÄ·ÏË®Àﺬ0.012mol¡¤L-1µÄÓÎÀë̬ÂȺÍ0.002mol¡¤L-1µÄÇâÀë×Ó£¬ÎªÁ˳ýÈ¥·ÏË®ÖеÄÓÎÀë̬ÂÈ£¬¶øÇÒʹ·ÏË®±äΪÖÐÐÔ£¬ÓÐÈËÌá³öÈçÏÂͼ·½°¸¡£ÔÚ·ÏË®Åųö¹ÜµÄA¡¢B´¦·Ö±ð×¢ÈëÒ»¶¨Á÷Á¿µÄ·ÏÉÕ¼îÈÜÒººÍÑÇÁòËáÄÆÈÜÒº¡£

    ÊÔд³ö£º

    (1)A¡¢B´¦Ó¦¼ÓÈëµÄÎïÖʵĻ¯Ñ§Ê½£º A                £¬B                ¡£

    (2)A¡¢B´¦·´Ó¦µÄÀë×Ó·½³Ìʽ£º

    A£º                       £»    B£º                     ¡£

    (3)ÿ´¦Àí1m3µÄ¸Ã·ÏË®£¬Ðè¼ÓÈë0.05mol¡¤L-1µÄNa2SO3ÈÜÒºµÄÌå»ýÊǶàÉÙ£¿

    (4)³ýÈ¥ÂȺóµÄ·ÏË®ÖÐÇâÀë×ÓŨ¶ÈԼΪ¶àÉÙ£¿

½âÎö£º¸Ã·ÏË®´¦ÀíÐèÂú×ãÁ½¸öÒªÇó£ºÒ»ÊdzýÈ¥Cl2£»¶þÊǵ÷ΪÖÐÐÔ¡£ÒòΪCl2¸úÓëË®·´Ó¦Ê±ÄÜÉú³ÉH+£¬ËùÒÔ³ýÈ¥H+Ó¦Ôڸ÷´Ó¦Ö®ºó½øÐС£

    ÿ1m3µÄ·ÏË®Öк¬Cl2£ºn(Cl2)=1000L¡Á0.012mol¡¤L-1=12mol£¬º¬H+£ºn(H+)=1000L¡Á0.002mol¡¤L-1=2mol£¬ÓÉ·½³ÌʽCl2+Na2SO3+H2O  Na2SO4+2HCl¿ÉÖª£¬ÏûºÄNa2SO3ºÍÉú³ÉHClµÄÎïÖʵÄÁ¿·Ö±ðΪ

    n(Na2SO3)=12mol

    n(HCl)=2¡Á12mol=24mol

   

´ð°¸£º(1)Na2SO3  NaOH

     (2)Cl2++H2O+2H++2Cl-    H++OH-H2O

     (3)240L    (4)0.021mol¡¤L-1


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ºÎïÀí½ÌÑÐÊÒ ÌâÐÍ£º022

ij¹¤³§ÅųöµÄ·ÏË®Àﺬ0.0122mol¡¤L-1µÄÓÎÀë̬ÂȺÍ0.002mol¡¤L-1µÄÇâÀë×Ó£¬ÎªÄþ³ýÈ¥·ÏË®ÖеÄÓÎÀë̬ÂȶøÇÒʹ·ÏË®±äΪÖÐÐÔ£¬ÓÐÈËÌá³öÈçÏÂͼ·½°¸¡£ÔÚ·ÏË®Åųö¹ÜµÄA¡¢B·Ö±ð×¢ÈëÒ»¶¨Á÷Á¿µÄ·ÏÉÕ¼îÈÜÒººÍÑÇÁòËáÄÆÈÜÒº¡£

ÊÔд³ö£º

£¨1£©A¡¢B´¦Ó¦¼ÓÈëµÄÎïÖʵĻ¯Ñ§Ê½£ºA________£¬B________¡£

£¨2£©A¡¢B´¦·´Ó¦µÄÀë×Ó·½³Ìʽ£º

A£º________________£¬

B£º________________¡£

£¨3£©Ã¿´¦Àí1m3µÄ¸Ã·ÏË®£¬Ðè¼ÓÈë0.05mol¡¤L-1µÄNa2SO3ÈÜÒºµÄÌå»ýÊǶàÉÙ£¿

£¨4£©³ýÈ¥ÂȺóµÄ·ÏË®Öа±Àë×ÓŨ¶ÈԼΪ¶àÉÙ£¿

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º038

ij¹¤³§ÅųöµÄ·ÏË®ÀﺬµÄÓÎÀë̬ÂȺ͵ÄÇâÀë×Ó£¬ÎªÁ˳ýÈ¥·ÏË®ÖеÄÓÎÀë̬ÂÈ£¬¶øÇÒʹ·ÏË®±äΪÖÐÐÔ£¬ÓÐÈËÌá³öÓÃÈçͼËùʾ·½°¸£®ÔÚ·ÏË®Åųö¹ÜµÄA¡¢B´¦·Ö±ð×¢ÈëÒ»¶¨Á÷Á¿µÄ·ÏÉÕ¼îÈÜÒººÍÑÇÁòËáÄÆÈÜÒº£®

ÊÔд³ö£»(1)A¡¢B´¦Ó¦¼ÓÈëµÄÎïÖʵĻ¯Ñ§Ê½£ºA_____________£¬B____________________________________________________________£®

(2)A¡¢B´¦·´Ó¦µÄÀë×Ó·½³Ìʽ£ºA£º_______________________________£¬

B£º___________________________________________________________£®

(3)ÿ´¦ÀíµÄ¸Ã·ÏË®£¬Ðè¼ÓÈëµÄÈÜÒºµÄÌå»ýÊǶàÉÙ?

(4)³ýÈ¥ÂȺóµÄ·ÏË®ÖÐÇâÀë×ÓŨ¶ÈԼΪ¶àÉÙ?

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ij¹¤³§ÅųöµÄ·ÏË®Àﺬ0.012 mol¡¤L-1µÄÓÎÀë̬ÂȺÍ0.002 mol¡¤L-1µÄÇâÀë×Ó¡£ÎªÁ˳ýÈ¥·ÏË®ÖеÄÓÎÀë̬ÂÈ£¬ÇÒʹ·ÏË®±äΪÖÐÐÔ£¬ÓÐÈËÌá³öÏÂͼËùʾ·½°¸¡£ÔÚ·ÏË®Åųö¹ÜµÄA¡¢B´¦·Ö±ð×¢ÈëÒ»¶¨Á÷Á¿µÄ·ÏÉÕ¼îÈÜÒººÍÑÇÁòËáÄÆÈÜÒº¡£

ÊÔд³ö£º

£¨1£©A¡¢B´¦Ó¦¼ÓÈëµÄÎïÖʵĻ¯Ñ§Ê½¡£

A_________£¬B_________¡£

£¨2£©A¡¢B´¦·´Ó¦µÄÀë×Ó·½³Ìʽ

A£º___________________________£¬

B£º___________________________¡£

£¨3£©Ã¿´¦Àí1 m3µÄ¸Ã·ÏË®£¬Ðè¼ÓÈë0.05 mol¡¤L-1µÄNa2SO3ÈÜÒºµÄÌå»ýÊǶàÉÙ£¿

£¨4£©³ýÈ¥ÂȺóµÄ·ÏË®ÖÐÇâÀë×ÓŨ¶ÈԼΪ¶àÉÙ£¿

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ij¹¤³§ÅųöµÄ·ÏË®Àﺬ0.012 mol¡¤L-1µÄÓÎÀë̬ÂȺÍ0.002 mol¡¤L-1µÄÇâÀë×Ó£¬ÎªÁ˳ýÈ¥·ÏË®ÖеÄÓÎÀë̬ÂÈ£¬¶øÇÒʹ·ÏË®±äΪÖÐÐÔ£¬ÓÐÈËÌá³öÈçÏÂͼ·½°¸¡£ÔÚ·ÏË®Åųö¹ÜµÄA¡¢B´¦·Ö±ð×¢ÈëÒ»¶¨Á÷Á¿µÄ·ÏÉÕ¼îÈÜÒººÍÑÇÁòËáÄÆÈÜÒº¡£

ÊÔд³ö£º

(1)A¡¢B´¦Ó¦¼ÓÈëµÄÎïÖʵĻ¯Ñ§Ê½£ºA______________£¬B______________¡£

(2)A¡¢B´¦·´Ó¦µÄÀë×Ó·½³Ìʽ£º

A£º___________________________________________________________£»

B£º___________________________________________________________¡£

(3)ÿ´¦Àí1 m3µÄ¸Ã·ÏË®£¬Ðè¼ÓÈë0.05 mol¡¤L-1µÄNa2SO3ÈÜÒºµÄÌå»ýÊǶàÉÙ£¿

(4)³ýÈ¥ÂȺóµÄ·ÏË®ÖÐÇâÀë×ÓŨ¶ÈԼΪ¶àÉÙ£¿

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸