PH4I(s)PH3(g)£«HI(g)
4PH3(g)P4(g)£«6H2(g)
2HI(g)H2(g)£«I2(g)
ÒÔÉÏÈý·´Ó¦½¨Á¢Æ½ºâºó£¬²âµÃHIΪbmol£¬I2£¨g£©Îªcmol£¬H2Ϊdmol¡£Çó£º
£¨1£©Æ½ºâºó£¬ÈÝÆ÷ÄÚP4£¨g£©ºÍPH3£¨g£©µÄÎïÖʵÄÁ¿£¨ÓôúÊýʽ±íʾ£© £»£¨2£©a,b,c,ÈýÕߵĹØϵΪa£¾________£¨Ìb£¬cµÄ´úÊýʽ£©£»£¨3£©b,c,dÈýÕߵĹØϵΪb£¾________£¨Ìc£¬dµÄ´úÊýʽ£©¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
PH4I(s)PH3(g)+HI(g)
4PH3(g)P4(g)+6H2(g)
2HI(g)H2(g)+I2(g)
ÒÔÉÏÈý·´Ó¦½¨Á¢Æ½ºâºó£¬²âµÃHIΪb mol¡¢I2Ϊc mol¡¢H2Ϊd mol¡£Çó£º
£¨1£©Æ½ºâºó£¬ÈÝÆ÷ÄÚP4ºÍPH3µÄÎïÖʵÄÁ¿£¨ÓôúÊýʽ±íʾ£©¡£
£¨2£©a¡¢b¡¢cÈýÕߵĹØϵ·þ´Óa£¾________________£¨Ìb¡¢cµÄ´úÊýʽ£©¡£
b¡¢c¡¢dÈýÕߵĹØϵ·þ´Ób£¾_____________________£¨Ìc¡¢dµÄ´úÊýʽ£©¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
£¨8·Ö£©ÔÚÕæ¿ÕÃܱÕÈÝÆ÷ÄÚ¼ÓÈëa mol PH4I¹ÌÌ壬ÔÚÒ»¶¨Î¶ÈÏ·¢ÉúÈçÏ·´Ó¦
PH4I£¨S£©PH3£¨g£© + HI£¨g£© ¢Ù £»
4PH3£¨g£© P4£¨g£©+ 6 H2£¨g£© ¢Ú £»
2HI£¨g£©H2£¨g£© + I2£¨g£© ¢Û
ÒÔÉÏÈý·´Ó¦½¨Á¢Æ½ºâºó£¬²âµÃHIΪb mol£¬I2(Æø)Ϊc mol£¬H2Ϊd mol¡£Çó£º
¢Å ƽºâºó£¬ÈÝÆ÷ÄÚP4(Æø)ºÍPH3µÄÎïÖʵÄÁ¿£¨ÓôúÊýʽ±íʾ£©£ºn(P4)= £¬n(PH3)= ¡£
¢Æ a£¬b£¬cÈýÕߵĹØϵ·þ´Óa > (Ìb£¬cµÄ´úÊýʽ)¡£
¢Ç ƽºâºó£¬Ôö´óѹǿ£¬ÈÝÆ÷ÄÚn(I2) , n(PH4I) (Ôö¼Ó¡¢¼õÉÙ¡¢²»±ä)
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêËÄ´¨Ê¡ÑÅ°²ÖÐѧ¸ß¶þÏÂѧÆÚ3ÔÂÔ¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ
£¨8·Ö£©ÔÚÕæ¿ÕÃܱÕÈÝÆ÷ÄÚ¼ÓÈëa mol PH4I¹ÌÌ壬ÔÚÒ»¶¨Î¶ÈÏ·¢ÉúÈçÏ·´Ó¦
PH4I£¨S£©PH3£¨g£© + HI£¨g£© ¢Ù £»
4PH3£¨g£© P4£¨g£©+ 6 H2£¨g£© ¢Ú £»
2HI£¨g£©H2£¨g£© + I2£¨g£© ¢Û
ÒÔÉÏÈý·´Ó¦½¨Á¢Æ½ºâºó£¬²âµÃHIΪb mol£¬I2(Æø)Ϊc mol£¬H2Ϊd mol¡£Çó£º
¢Åƽºâºó£¬ÈÝÆ÷ÄÚP4(Æø)ºÍPH3µÄÎïÖʵÄÁ¿£¨ÓôúÊýʽ±íʾ£©£ºn(P4)= £¬n(PH3)= ¡£
¢Æ a£¬b£¬cÈýÕߵĹØϵ·þ´Óa > (Ìb£¬cµÄ´úÊýʽ)¡£
¢Çƽºâºó£¬Ôö´óѹǿ£¬ÈÝÆ÷ÄÚn(I2) , n(PH4I) (Ôö¼Ó¡¢¼õÉÙ¡¢²»±ä)
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013½ìËÄ´¨Ê¡¸ß¶þÏÂѧÆÚ3ÔÂÔ¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ
£¨8·Ö£©ÔÚÕæ¿ÕÃܱÕÈÝÆ÷ÄÚ¼ÓÈëa mol PH4I¹ÌÌ壬ÔÚÒ»¶¨Î¶ÈÏ·¢ÉúÈçÏ·´Ó¦
PH4I£¨S£©PH3£¨g£© + HI£¨g£© ¢Ù £»
4PH3£¨g£© P4£¨g£©+ 6 H2£¨g£© ¢Ú £»
2HI£¨g£©H2£¨g£© + I2£¨g£© ¢Û
ÒÔÉÏÈý·´Ó¦½¨Á¢Æ½ºâºó£¬²âµÃHIΪb mol£¬I2(Æø)Ϊc mol£¬H2Ϊd mol¡£Çó£º
¢Å ƽºâºó£¬ÈÝÆ÷ÄÚP4(Æø)ºÍPH3µÄÎïÖʵÄÁ¿£¨ÓôúÊýʽ±íʾ£©£ºn(P4)= £¬n(PH3)= ¡£
¢Æ a£¬b£¬cÈýÕߵĹØϵ·þ´Óa > (Ìb£¬cµÄ´úÊýʽ)¡£
¢Ç ƽºâºó£¬Ôö´óѹǿ£¬ÈÝÆ÷ÄÚn(I2) , n(PH4I) (Ôö¼Ó¡¢¼õÉÙ¡¢²»±ä)
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com