¡¾ÌâÄ¿¡¿1molijÌþAºÍ1 mol±½ÍêȫȼÉÕ£¬ÔÚÏàͬÌõ¼þÏ£¬Éú³ÉCO2Ìå»ýÏàͬ£¬ÌþA±È±½¶àÏûºÄ1.5mol O2£¬ÊԻشð£º

£¨1£©ÌþAµÄ·Ö×ÓʽÊÇ__________ ¡£

£¨2£©ÈôÌþA²»ÄÜʹäåË®ÍÊÉ«£¬µ«ÔÚÒ»¶¨Ìõ¼þÏÂÄÜÓëCl2·¢ÉúÈ¡´ú·´Ó¦£¬ÆäÒ»ÂÈ´úÎïÖ»ÓÐÒ»ÖÖ£¬ÔòÌþAµÄ½á¹¹¼òʽΪ_______________ ¡£

£¨3£©ÈôÌþAÄÜʹäåË®ÍÊÉ«£¬ÇÒ·Ö×ÓÖÐËùÓÐ̼ԭ×Ó¹²Æ½Ã棬ÔòAµÄ½á¹¹¼òʽΪ____________________________ ¡£

£¨4£©±ÈAÉÙ2¸ö̼ԭ×ÓµÄAµÄÏ©ÌþµÄͬϵÎïµÄͬ·ÖÒì¹¹Ì壨°üÀ¨Á¢ÌåÒì¹¹£©¹²ÓÐ__________ÖÖ¡£

¡¾´ð°¸¡¿ C6H12 £¨CH3£©2C=C£¨CH3£©2 4

¡¾½âÎö¡¿±¾Ìâ·ÖÎö£º±¾ÌâÖ÷Òª¿¼²éÓлúÎïµÄ×é³É¡¢½á¹¹ÓëÐÔÖÊ¡£

1molijÌþAºÍ1 mol±½ÍêȫȼÉÕ£¬ÔÚÏàͬÌõ¼þÏ£¬Éú³ÉCO2Ìå»ýÏàͬ£¬ËµÃ÷AºÍ±½µÄ·Ö×Ó¶¼º¬ÓÐ6¸ö̼ԭ×Ó£¬ÌþA±È±½¶àÏûºÄ1.5mol O2£¬ËµÃ÷A·Ö×ӱȱ½·Ö×Ó¶à6¸öÇâÔ­×Ó£¬½á¹ûA·Ö×ÓʽΪC6H12¡£

£¨1£©ÌþAµÄ·Ö×ÓʽÊÇC6H12¡£

£¨2£©ÈôÌþA²»ÄÜʹäåË®ÍÊÉ«£¬ËµÃ÷AûÓв»±¥ºÍ½á¹¹£¬µ«ÔÚÒ»¶¨Ìõ¼þÏÂÄÜÓëCl2·¢ÉúÈ¡´ú·´Ó¦£¬ÆäÒ»ÂÈ´úÎïÖ»ÓÐÒ»ÖÖ£¬ËµÃ÷AµÄ·Ö×ӽṹ¸ß¶È¶Ô³Æ£¬ÔòÌþAµÄ½á¹¹¼òʽΪ¡£

£¨3£©ÈôÌþAÄÜʹäåË®ÍÊÉ«£¬ËµÃ÷Aº¬ÓÐ̼̼˫¼ü»òÈý¼ü£¬ÇÒ·Ö×ÓÖÐËùÓÐ̼ԭ×Ó¹²Æ½Ã棬˵Ã÷¶¼ÊÇË«¼ü̼ԭ×Ó»òÓëË«¼ü̼ԭ×ÓÏàÁ¬µÄ̼ԭ×Ó£¬ÔòAµÄ½á¹¹¼òʽΪ£¨CH3£©2C=C£¨CH3£©2¡£

£¨4£©±ÈAÉÙ2¸ö̼ԭ×ÓµÄAµÄÏ©ÌþµÄͬϵÎïµÄ·Ö×ÓʽΪC4H8£¬Í¬·ÖÒì¹¹Ì壨°üÀ¨Á¢ÌåÒì¹¹£©ÓÐ1-¶¡Ï©¡¢Ë³Ê½2-¶¡Ï©¡¢·´Ê½2-¶¡Ï©¡¢2-¼×»ù-1-±ûÏ©¹²4ÖÖ¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿±½µÄº¬ÑõÑÜÉúÎïBµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª180£¬ÆäÖÐ̼ԪËصÄÖÊÁ¿·ÖÊýΪ60%£¬ÑõÔªËصÄÖÊÁ¿·ÖÊýΪ35.6%¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)BµÄ·Ö×ÓʽΪ_________________¡£

(2)BÊÇÁÚλ¶þÈ¡´ú±½£¬ÆäÖÐÒ»¸öÈ¡´ú»ùÊÇôÈ»ù£¬BÄÜ·¢ÉúÈçͼËùʾת»¯¡£

¢ÙC¡ú EµÄ·´Ó¦ÌåϵÖк¬18OµÄÎïÖÊÓÐ_________ÖÖ¡£

¢ÚDÓë×ãÁ¿Å¨äåË®·´Ó¦µÄÖ÷Òª²úÎïµÄ½á¹¹¼òʽΪ__________________________________¡£

¢ÛF¾ßÓÐÏÂÁÐÄÄЩ»¯Ñ§ÐÔÖÊ£¿____________¡£

A£®ÓëŨäåË®·´Ó¦ B£®·¢Éú¼Ó³É·´Ó¦ C£®·¢ÉúÑõ»¯·´Ó¦ D. ·¢ÉúÏûÈ¥·´Ó¦

¢ÜBÓë×ãÁ¿NaOHÈÜÒº¹²ÈȵĻ¯Ñ§·½³ÌʽΪ£º

________________________________________________________________________¡£

CµÄÒ»ÖÖͬ·ÖÒì¹¹Ìå²»ÄÜ·¢ÉúË®½â·´Ó¦£¬µ«ÄÜ·¢ÉúÒø¾µ·´Ó¦£¬ÆäÒø¾µ·´Ó¦µÄ·½³ÌʽΪ£º_________________________________________________________________________

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿25 ¡æʱ£¬ÓÃŨ¶ÈΪ0.100 0 mol¡¤L£­1µÄNaOHÈÜÒº·Ö±ðµÎ¶¨20.00 mLŨ¶È¾ùΪ0.100 0 mol¡¤L£­1µÄHX£¬HYÈÜÒº£¬pHËæNaOHÈÜÒºÌå»ýµÄ±ä»¯ÈçͼËùʾ¡£ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ( )

A. µ±V(NaOH)£½0 mLʱ£¬c(X£­)>c(Y£­)

B. aµãʱ£ºc(Y£­)£«c(HY)£½0.100 0 mol¡¤L£­1

C. bµãʱ£ºc(HX)>c(Na£«)>c(X£­)>c(OH£­)>c(H£«)

D. µ±V(NaOH)£½20.00 mLʱ£¬NaX¡¢NaYÁ½ÈÜÒºÖеÄÒõÀë×Ó×ÜÊýÏà¶Ô´óС£ºNÇ°Õß>NºóÕß

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿³£ÎÂÏ£¬Ïò1 L 0.1 mol¡¤L£­1 NH4ClÈÜÒºÖУ¬²»¶Ï¼ÓÈë¹ÌÌåNaOHºó£¬NHÓëNH3 ¡¤ H2OµÄ±ä»¯Ç÷ÊÆÈçÏÂͼËùʾ(²»¿¼ÂÇÌå»ý±ä»¯ºÍ°±µÄ»Ó·¢)£¬ÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ(¡¡¡¡)

A. ÔÚMµãʱ£¬n(OH£­)£­n(H£«)£½(a£­0.05) mol

B. Ëæ×ÅNaOHµÄ¼ÓÈ룬²»¶ÏÔö´ó

C. MµãÈÜÒºÖÐË®µÄµçÀë³Ì¶È±ÈÔ­ÈÜҺС

D. µ±n(NaOH)£½0.1 molʱ£¬c(OH£­)£¾c(Cl£­)£­c(NH3¡¤H2O)

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿DAHBAÊÇijó{кϳɲÄÁϵÄÒ»ÖÖµ¥Ì壬ÏÂÃæÊÇÒÔASA£¨¶Ô°±»ùË®ÑîËᣩΪԭÁÏÖƱ¸DAHBAµÄÒ»ÖֺϳÉ·Ïߣº

»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ASAËáÐԵĹÙÄÜÍÅÓÐ_____________________£¨Ð´Ãû³Æ£©¡£

£¨2£©AHNBAµÄ½á¹¹¼òʽΪ_______________________________¡£

£¨3£©·´Ó¦¢ÚµÄ·´Ó¦ÀàÐÍΪ___________________¡£

£¨4£©·´Ó¦¢Ù¡¢¢ÛµÄÄ¿µÄÊÇ__________________________________¡£

£¨5£©·´Ó¦¢ÙµÄ»¯Ñ§·½³Ìʽ__________________________________¡£

£¨6£©Ë®ÑîËᣨ£©µÄͬ·ÖÒì¹¹ÌåÖУ¬ÄÜÓëFeCl3ÈÜÒº·¢ÉúÏÔÉ«·´Ó¦ÇÒÄÜ·¢ÉúÒø¾µ·´Ó¦µÄ¹²ÓÐ_____________ ÖÖ£¬ÆäÖÐÄÜ·¢ÉúË®½â·´Ó¦ÇҺ˴Ź²ÕñÇâÆ×ÏÔʾÓÐ4×é·åµÄ½á¹¹¼òʽΪ_______________________¡£

£¨7£©Ð´³öÒÔ¼×±½ÎªÔ­ÁÏ£¨ÎÞ»úÊÔ¼ÁÈÎÑ¡£©ÖƱ¸2£¬4£¬6-Èý°±»ù±½¼×ËáµÄºÏ³É·Ïߣº_____________________________________________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÉèNAΪ°¢·ü¼ÓµÂÂÞ³£ÊýµÄÖµ¡£ÏÂÁÐ˵·¨´íÎóµÄÊÇ

A. ±ê×¼×´¿öÏ£¬22.4L NOÓë11.2 LO2³ä·Ö·´Ó¦ºó·Ö×Ó×ÜÊýСÓÚNA

B. 1molNa2O2Óë×ãÁ¿Ë®·´Ó¦×ªÒƵç×ÓÊýΪNA

C. º¬2molH2SO4µÄŨÁòËáÓë×ãÁ¿Cu·´Ó¦£¬Éú³ÉNA¸öSO2·Ö×Ó

D. ³£Î³£Ñ¹Ï£¬28g N2¡¢COµÄ»ìºÏÆøÌåÖк¬ÓÐÔ­×ÓµÄÊýÄ¿µÈÓÚ2NA

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÌìÈ»´óÀíʯͨ³£º¬ÓÐFe2O3µÈÔÓÖÊ£¬¹¤ÒµÉÏÓôóÀíʯ×÷Ô­ÁÏʱÐèÒªÌá´¿£¬Ä³Ñо¿ÐÔѧϰС×éÔÚÀÏʦµÄÖ¸µ¼Ï£¬¶Ô´óÀíʯ½øÐÐÁËÌá´¿£¬Éè¼ÆÁËÈçϵÄʵÑéÁ÷³Ì£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)Èܽâ´óÀíʯʱ£¬ÓÃÏõËá¶ø²»ÓÃÁòËáµÄÔ­ÒòÊÇ____________________________________________¡£

(2)²Ù×÷¢ñµÄÃû³ÆÊÇ________£¬¸Ã²Ù×÷ÖÐÓõ½²£Á§°ô£¬²£Á§°ôÔÚ¸ÃʵÑéÖеÄ×÷ÓÃÊÇ___________________________¡£

(3)¼ìÑéÈÜÒºBÖÐÊÇ·ñº¬ÌúÀë×ӵIJÙ×÷·½·¨ÊÇ_________________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÏÂÁйØÓÚÕý¶¡Í飨b£©¡¢2-¼×»ù±ûÍ飨d£©¡¢¼×±½£¨p£©µÄ˵·¨ÖÐÕýÈ·µÄÊÇ

A. bÓëd»¥ÎªÍ¬ÏµÎï

B. b¡¢d¡¢pµÄÒ»ÂÈ´úÎïÖÖÊý·Ö±ðΪ2¡¢3¡¢4

C. b¡¢d¡¢p¾ù²»ÄÜʹËáÐÔ¸ßÃÌËá¼ØÈÜÒºÍÊÉ«

D. b¡¢d¡¢pÖÐÖ»ÓÐdµÄËùÓÐ̼ԭ×Ó²»ÄÜ´¦ÓÚͬһƽÃæ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿½«×ãÁ¿Ìú·ÛͶÈëÒ»¶¨Å¨¶ÈµÄÂÈ»¯ÌúºÍÂÈ»¯Í­µÄ»ìºÏÈÜÒºÖУ¬³ä·Ö·´Ó¦ºó£¬ÈÜÒºÖÐÊ£Óà¹ÌÌåµÄÖÊÁ¿Óë¼ÓÈËÌú·ÛµÄÖÊÁ¿Ïàͬ£¬ÔòÔ­ÈÜÒºÖÐÂÈ»¯ÌúºÍÂÈ»¯Í­µÄŨ¶ÈÖ®±ÈΪ

A£®2£º7 B£®3£»4 C£®4£º7 D£®2£º3

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸