£¨12·Ö£©
£¨1£©ÊÒÎÂÏ£¬ÔÚpH=12µÄNaCNÈÜÒºÖУ¬ÓÉË®µçÀëµÄc(OH¡ª)Ϊ_______ mol¡¤L£­1¡£
£¨2£©µÈÌå»ýµÄÏÂÁÐÈÜÒºÖУ¬ÑôÀë×ÓµÄ×ÜÎïÖʵÄÁ¿×î´óµÄÊÇ_________£¨ÌîÐòºÅ£©¡£
¢Ù 0.2 mol¡¤L£­1µÄCuSO4ÈÜÒº        ¢Ú 0.1 mol¡¤L£­1µÄNa2CO3
¢Û 0.2 mol¡¤L£­1µÄKCl               ¢Ü 0.1 mol¡¤L£­1µÄNa2SO4
£¨3£©Å¨¶ÈΪ0.100 mol¡¤L-1µÄÏÂÁи÷ÎïÖʵÄÈÜÒºÖУ¬c(NH4+)ÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ_______£¨ÌîÐòºÅ£©¡£
¢ÙNH4Cl    ¢ÚNH4HSO4    ¢ÛNH3¡¤H2O   ¢ÜCH3COONH4 
£¨4£©Ä³¶þÔªËᣨ»¯Ñ§Ê½ÓÃH2A±íʾ£©ÔÚË®ÖеĵçÀë·½³ÌʽÊÇ£º
H2A ="===" H+ HA£­ £¬ HA£­ H+ A2£­¡£
¢ÙÔòNa2AÈÜÒºÏÔ________£¨Ìî¡°ËáÐÔ¡±¡°ÖÐÐÔ¡±»ò¡°¼îÐÔ¡±£©£»NaHAÈÜÒºÏÔ________£¨Ìî¡°ËáÐÔ¡±¡°ÖÐÐÔ¡±»ò¡°¼îÐÔ¡±£©¡£
¢ÚÈôÓÐ0.1 mol¡¤L£­1 Na2AµÄÈÜÒº£¬ÆäÖи÷ÖÖÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ£º      £¨ÌîÐòºÅ£©¡£

A£®c(Na+)£¾c(A2£­)£¾c(OH£­)£¾c(HA£­)£¾c(H+)
B£®c(Na+)£¾c(OH£­)£¾c(HA£­)£¾c(A2£­)£¾c(H+)
C£®c(Na+)£¾c(H+)£¾c(A2£­)£¾c(OH£­)£¾c(HA£­)
D£®c(A2£­)£¾c(Na+)£¾c(OH£­)£¾c(H+)£¾c(HA£­)

£¨1£©10-2         £¨2£©¢Ù   
£¨3£©¢Ú £¾¢Ù £¾ ¢Ü £¾ ¢Û
£¨4£© ¢Ù ¼îÐÔ   ËáÐÔ  ¢Ú  A 

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨1£©ÊÒÎÂÏ£¬ÔÚpH=12µÄijÖÖÈÜÒºÖУ¬ÓÉË®µçÀëµÄ²úÉúµÄc£¨OH-£©Îª
10-12 mol/L»ò10-2 mol/L
10-12 mol/L»ò10-2 mol/L
£®
£¨2£©µÈÌå»ýµÄÏÂÁÐÈÜÒºÖУ¬ÑôÀë×ÓµÄ×ÜÎïÖʵÄÁ¿×î´óµÄÊÇ
¢Ù
¢Ù
£®
¢Ù0.2mol?L-1µÄCuSO4ÈÜÒº       ¢Ú0.1mol?L-1µÄNa2CO3
¢Û0.2mol?L-1µÄKCl              ¢Ü0.1mol?L-1µÄNa2SO4
£¨3£©Å¨¶ÈΪ0.100mol?L-1µÄÏÂÁи÷ÎïÖʵÄÈÜÒºÖУ¬c£¨NH4+£©ÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ
¢Ú¢Ù¢Ü¢Û
¢Ú¢Ù¢Ü¢Û
£¨ÌîÐòºÅ£©£®
¢ÙNH4Cl         ¢ÚNH4HSO4           ¢ÛNH3?H2O       ¢ÜCH3COONH4
£¨4£©Ä³¶þÔªËᣨ»¯Ñ§Ê½ÓÃH2A±íʾ£©ÔÚË®ÖеĵçÀë·½³ÌʽÊÇ£ºH2A=H++HA-£¬HA-?H++A2-£®
¢ÙÔòNa2AÈÜÒºÏÔ
¼îÐÔ
¼îÐÔ
£¨Ìî¡°ËáÐÔ¡±¡¢¡°ÖÐÐÔ¡±»ò¡°¼îÐÔ¡±£©£¬ÀíÓÉÊÇ
A2-+H2O?HA-+OH-
A2-+H2O?HA-+OH-
£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©£®
¢ÚÈôÓÐ0.1mol?L-1 Na2AµÄÈÜÒº£¬ÆäÖи÷ÖÖÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ£º
c£¨Na+£©£¾c£¨A2-£©£¾c£¨OH-£©£¾c£¨HA-£©£¾c£¨H+£©
c£¨Na+£©£¾c£¨A2-£©£¾c£¨OH-£©£¾c£¨HA-£©£¾c£¨H+£©
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨1£©ÊÒÎÂÏ£¬ÔÚpH=12µÄijÖÖÈÜÒºÖУ¬ÓÉË®µçÀëµÄc£¨OH-£©Îª
 
£®
£¨2£©µÈÌå»ýµÄÏÂÁÐÈÜÒºÖУ¬ÑôÀë×ÓµÄ×ÜÎïÖʵÄÁ¿×î´óµÄÊÇ
 
£®
¢Ù0.2mol?L-1µÄCuSO4ÈÜÒº
¢Ú0.1mol?L-1µÄNa2CO3
¢Û0.2mol?L-1µÄKCl
¢Ü0.1mol?L-1µÄNa2SO4
£¨3£©Å¨¶ÈΪ0.100mol?L-1µÄÏÂÁи÷ÎïÖʵÄÈÜÒºÖУ¬c£¨NH4+£©ÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ
 
£¨ÌîÐòºÅ£©£®
¢ÙNH4Cl         ¢ÚNH4HSO4           ¢ÛNH3?H2O       ¢ÜCH3COONH4
£¨4£©Ä³¶þÔªËᣨ»¯Ñ§Ê½ÓÃH2A±íʾ£©ÔÚË®ÖеĵçÀë·½³ÌʽÊÇ£ºH2A¨TH++HA-£¬HA-?H++A2-£®
¢ÙÔòNa2AÈÜÒºÏÔ
 
£¨Ìî¡°ËáÐÔ¡±¡°ÖÐÐÔ¡±»ò¡°¼îÐÔ¡±£©£¬ÀíÓÉÊÇ
 
£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©£®
¢ÚÈôÓÐ0.1mol?L-1 Na2AµÄÈÜÒº£¬ÆäÖи÷ÖÖÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ£º
 
£¨ÌîÐòºÅ£©£®
A£®c£¨Na+£©£¾c£¨A2-£©£¾c£¨OH-£©£¾c£¨HA-£©£¾c£¨H+£©
B£®c£¨Na+£©£¾c£¨OH-£©£¾c£¨HA-£©£¾c£¨A2-£©£¾c£¨H+£©
C£®c£¨Na+£©£¾c£¨H+£©£¾c£¨A2-£©£¾c£¨OH-£©£¾c£¨HA-£©
D£®c£¨A2-£©£¾c£¨Na+£©£¾c£¨OH-£©£¾c£¨H+£©£¾c£¨HA-£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨12·Ö£©

£¨1£©ÊÒÎÂÏ£¬ÔÚpH=12µÄNaCNÈÜÒºÖУ¬ÓÉË®µçÀëµÄc(OH¡ª)Ϊ     mol¡¤L£­1 ¡££¨2£©µÈÌå»ýµÄÏÂÁÐÈÜÒºÖУ¬ÑôÀë×ÓµÄ×ÜÎïÖʵÄÁ¿×î´óµÄÊÇ    ¡££¨ÌîÐòºÅ£©¡£

¢Ù0.2 mol¡¤L£­1µÄCuSO4ÈÜÒº        ¢Ú 0.1 mol¡¤L£­1µÄNa2CO3

¢Û0.2 mol¡¤L£­1µÄKCl               ¢Ü 0.1mol¡¤L£­1µÄNa2SO4

£¨3£©Å¨¶ÈΪ0.100 mol¡¤L-1µÄÏÂÁи÷ÎïÖʵÄÈÜÒºÖУ¬c(NH4+)ÓÉ´óµ½Ð¡µÄ˳    ¡££¨ÌîÐòºÅ£©¡£

¢ÙNH4Cl    ¢ÚNH4HSO4    ¢ÛNH3¡¤H2O   ¢ÜCH3COONH4 

£¨4£©Ë®µÄµçÀëƽºâÈçͼËùʾ£º

¢ÙÈôAµã±íʾ25¡æʱˮµÄµçÀëƽºâ״̬£¬µ±Î¶ÈÉÏÉýµ½100¡æʱ£¬Ë®µÄµçÀëƽºâ״̬µ½´ïBµã¡£Ôò´ËʱˮµÄÀë×Ó»ý´Ó   Ôö¼Óµ½    ¡£

¢Ú100¡æʱ£¬Èô10Ìå»ýµÄijǿËáÈÜÒºÓë1Ìå»ýµÄijǿ¼îÈÜÒº»ìºÏºóÈÜÒº³ÊÖÐÐÔ£¬Ôò»ìºÏ֮ǰ£¬¸ÃÇ¿ËáµÄpHÖµpH1ÓëÇ¿¼îµÄpHÖµpH2Ö®¼äÓ¦Âú×ãµÄ¹ØϵÊÇ     ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨6·Ö£©£¨1£©ÊÒÎÂÏ£¬ÔÚpH=12µÄijÖÖÈÜÒºÖУ¬ÓÉË®µçÀëµÄc£¨OH-£©Îª             ¡£

£¨2£©µÈÌå»ýµÄÏÂÁÐÈÜÒºÖУ¬ÑôÀë×ÓµÄ×ÜÎïÖʵÄÁ¿×î´óµÄÊÇ             ¡£

¢Ù0.2mol¡¤L-1µÄCuSO4ÈÜÒº                 ¢Ú0.1mol¡¤L-1µÄNa2CO3

¢Û0.2mol¡¤L-1µÄKCl                       ¢Ü0.1 mol¡¤L-1µÄNa2SO4

£¨3£©Å¨¶ÈΪ0.100 mol¡¤L-1µÄÏÂÁи÷ÎïÖʵÄÈÜÒºÖУ¬c£¨NH4+£©ÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ             ¡£

¢ÙNH4Cl           ¢ÚNH4HSO4              ¢ÛNH3¡¤H2O            ¢ÜCH3COONH4

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012½ì½­ËÕÊ¡¸ß¶þµÚ¶þѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

£¨6·Ö£©£¨1£©ÊÒÎÂÏ£¬ÔÚpH=12µÄijÖÖÈÜÒºÖУ¬ÓÉË®µçÀëµÄc£¨OH-£©Îª              ¡£

£¨2£©µÈÌå»ýµÄÏÂÁÐÈÜÒºÖУ¬ÑôÀë×ÓµÄ×ÜÎïÖʵÄÁ¿×î´óµÄÊÇ              ¡£

¢Ù0.2 mol¡¤L-1µÄCuSO4ÈÜÒº                  ¢Ú0.1 mol¡¤L-1µÄNa2CO3

¢Û0.2 mol¡¤L-1µÄKCl                        ¢Ü0.1 mol¡¤L-1µÄNa2SO4

£¨3£©Å¨¶ÈΪ0.100 mol¡¤L-1µÄÏÂÁи÷ÎïÖʵÄÈÜÒºÖУ¬c£¨NH4+£©ÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ              ¡£

¢ÙNH4Cl            ¢ÚNH4HSO4               ¢ÛNH3¡¤H2O             ¢ÜCH3COONH4

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸