¡¾ÌâÄ¿¡¿Ã̼°Æ仯ºÏÎïÔÚ¹¤Å©ÒµÉú²úºÍ¿Æ¼¼ÁìÓò¾ßÓй㷺µÄÓ¦Óá£

¢ñ£®ÈÜÒºÖеÄMn2+¿É±»ËáÐÔ£¨NH4£©2S2O8ÈÜÒºÑõ»¯ÎªMnO4-£¬¸Ã·½·¨¿ÉÓÃÓÚ¼ìÑéMn2+¡£

£¨1£©ÓÃËáÐÔ£¨NH4£©2S2O8ÈÜÒº¼ìÑéMn2+ʱµÄʵÑéÏÖÏóΪ________________________¡£

£¨2£©¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ_____________________¡£

£¨3£©£¨NH4£©2S2O8¿ÉÊÓΪÓÉÁ½·Ö×ÓÁðËáËõºÏËùµÃ£¬ÈôÁòËáµÄ½á¹¹¼òʽΪ£¬ÔòH2S2O8µÄ½á¹¹¼òʽΪ ________________¡£

¢ò£®ÊµÑéÊÒÓú¬ÃÌ·ÏÁÏ£¨Ö÷Òª³É·ÖΪMnO2£¬»¹º¬ÓÐÉÙÁ¿Al2O3¡¢MgO¡¢SiO2£©ÎªÔ­ÁÏÖƱ¸MnµÄ¹¤ÒÕÁ÷³ÌÈçÏÂͼËùʾ¡£

ÒÑÖª£º¢Ù²¿·ÖÄÑÈÜÎïµÄÈܶȻý³£ÊýÈçϱíËùʾ¡£

ÄÑÈÜÎï

Fe£¨OH£©3

Al£¨OH£©3

Mg£¨OH£©2

Mn£¨OH£©2

ÈܶȻý³£Êý

4.0¡Á10-38

1.0¡Á10-33

1.8¡Á10-11

1.8¡Á10-13

¢Úµ±ÈÜÒºÖÐÀë×ÓŨ¶È¡Ü1.0¡Á10-5mol L-1ʱ£¬¿ÉÈÏΪ¸ÃÀë×Ó³ÁµíÍêÈ«¡£

£¨1£©¡°Ëá½þ¡±Ê±£¬MnO2½«FeÑõ»¯ÎªFe3+£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ________________________£»¸Ã¹ý³ÌÖнþ³öʱ¼äºÍÒº¹Ì±È¶ÔÃ̽þ³öÂʵÄÓ°Ïì·Ö±ðÈçÏÂͼËùʾ¡£

ÔòÊÊÒ˵Ľþ³öʱ¼äºÍÒº¹Ì±È·Ö±ðΪ____________¡¢____________¡£

£¨2£©Èô¡°Ëá½þ¡±ºóËùµÃÂËÒºÖÐc£¨Mn2+£©=0.18molL-1£¬ÔòÓ¦¡°µ÷pH¡±µÄ·¶Î§Îª________________________¡£

£¨3£©¡°ìÑÉÕ¡±·´Ó¦ÖÐÑõ»¯¼ÁÓ뻹ԭ¼ÁµÄÎïÖʵÄÁ¿Ö®±ÈΪ__________¡£¡°»¹Ô­¡±Ê±·¢ÉúµÄÖû»·´Ó¦ÔÚ»¯Ñ§ÉÏÓÖ½Ð×÷__________¡£

¡¾´ð°¸¡¿ÈÜÒºÓÉÎÞÉ«±äΪ×ϺìÉ« 5S2O82-+2Mn2++8H2O=2MnO4-+10SO42-+16H+ 3MnO2+2Fe+12H+=3Mn2++2Fe3++6H2O 60min 3:1 ¡ÜpH£¼8 1:2 ÂÁÈÈ·´Ó¦

¡¾½âÎö¡¿

¢ò.ÓÃÁòËá½þÈ¡ÖУ¬Ö»ÓÐSiO2²»ÓëÁòËá·´Ó¦£¬ÂËÔüÖÐÓÐSiO2¡£¸ù¾ÝºóÃæµÄÁ÷³ÌÖÐÖмä²úÎïΪMnCO3£¬ÔòFeµÄ×÷ÓþÍÊÇΪÁ˽«Ã̵Ļ¯ºÏ¼Û´Ó+4»¹Ô­µ½+2£¬ÂËÔü1Öл¹°üÀ¨Á˹ýÁ¿µÄÌú·Û¡£µ÷½ÚpH³ÁµíÌúÀë×ÓºÍÂÁÀë×Ó£¬¼ÓÈëNaF³ÁµíþÀë×Ó£¬¼ÓÈë̼ËáÇâ麟ÁµíÃÌ£¬Éú³É̼ËáÃÌ£¬ÔÚ¿ÕÆøÖÐìÑÉÕ±»ÑõÆøÑõ»¯ÎªMnO2£¬¾­¹ýÂÁÈÈ·´Ó¦µÃµ½Ã̵¥ÖÊ¡£

¢ñ.£¨1£©ÈÜÒºÖеÄMn2+ת»¯ÎªMnO4-ʱµÄʵÑéÏÖÏóΪÈÜÒºÓÉÎÞÉ«±äΪ×ϺìÉ«¡£´ð°¸ÎªÈÜÒºÓÉÎÞÉ«±äΪ×ϺìÉ«£»

£¨2£©Mn2+±»ËáÐÔ£¨NH4£©2S2O8ÈÜÒºÑõ»¯ÎªMnO4-£¬»¹Ô­²úÎïӦΪSO42-£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ5S2O82-+2Mn2+ +8H2O==2MnO4-+10SO42-+16H+¡£´ð°¸Îª5S2O82-+2Mn2++8H2O=2MnO4-+10SO42-+16H+£»

£¨3£©H2S2O8¿ÉÊÓΪÓÉÁ½·Ö×ÓÁòËáËõºÏËùµÃ£¬ÁòËáµÄ½á¹¹¼òʽΪ£¬ÔòH2S2O8µÄ½á¹¹¼òʽΪ¡£´ð°¸Îª£»

¢ò.£¨1£©ÓÉÌâÖÐÐÅÏ¢¿ÉÖª£¬¡°Ëá½þ¡±Ê±£¬MnO2ÔÚËáÐÔ½éÖÊÖн«FeÑõ»¯ÎªFe3+£¬±¾Éí±»»¹Ô­ÎªMn2+£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ 3MnO2+2Fe+12H+=3Mn2++2Fe3++6H2O£»ÓÉͼ¼×¿ÉÖª£¬ÊÊÒ˵Ľþ³öʱ¼äΪ60min£¬ÓÉͼÒÒ¿ÉÖª£¬ÊÊÒ˵ÄҺͬ±ÈΪ3:1¡£´ð°¸Îª3MnO2+2Fe+12H+=3Mn2++2Fe3++6H2O 60min 3:1£»

£¨2£©ÓÉÁ÷³ÌͼÖÐÐÅÏ¢Öª£¬¡°µ÷pH¡±µÄÄ¿µÄÊÇʹFe3+ºÍA13+³ÁµíÍêÈ«£¬¶øMn2+²»³Áµí£¬¸ù¾ÝKsp[A1£¨OH£©3]= 1.0¡Á10-33£¬,Ksp[Fe£¨OH£©3] = 4.0¡Á10-38¿ÉÖª£¬Al3+³ÁµíÍêȫʱFe3+ÒѳÁµíÍêÈ«£¬Al£¨OH£©3Ç¡ºÃÍêÈ«³ÁµíʱµÄpHΪ-lg£¬Mn2+¿ªÊ¼³ÁµíʱµÄpHΪ-lg=8£¬Ôò¡°µ÷pH¡±µÄ·¶Î§Îª¡ÜpH£¼8¡£´ð°¸Îª¡ÜpH£¼8£»

£¨3£©¸ù¾ÝÐÅÏ¢Öª£¬¡°ìÑÉÕ¡±Ê±£¬¿ÕÆøÖеÄO2½«MnCO3Ñõ »¯ÎªMnO2£¬¸ù¾ÝµÃʧµç×ÓÊغã¿ÉµÃ¹ØϵʽO2 2MnCO3£¬¼´Ñõ»¯¼ÁÓ뻹ԭ¼ÁµÄÎïÖʵÄÁ¿Ö®±ÈΪ1:2¡£¡°»¹Ô­¡±Ê±·¢ÉúÂÁ·ÛÓë¸ßÈÛµã½ðÊôÑõ»¯ÎïµÄ·´Ó¦£¬ÓÖ³ÆÂÁÈÈ·´Ó¦¡£´ð°¸Îª1:2 ÂÁÈÈ·´Ó¦¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿»¯ºÏÎïIÊÇÒ»ÖÖ¿¹ÄÔȱѪҩÎºÏ³É·ÏßÈçÏ£º

ÒÑÖª£º

»Ø´ðÏÂÁÐÎÊÌ⣺

(1)»¯ºÏÎïEµÄ½á¹¹¼òʽ____________________£»IÖйÙÄÜÍŵÄÃû³Æ_____________¡£

(2)AµÄϵͳÃû³Æ__________________________£»

(3)H¡úIµÄ·´Ó¦·½³Ìʽ______________________________¡£

(4)A¡úB¡¢E¡úFµÄ·´Ó¦ÀàÐÍ·Ö±ðÊÇ______________·´Ó¦£»_____________·´Ó¦¡£

(5)д³öA·¢Éú¼Ó¾Û·´Ó¦µÄ·´Ó¦·½³Ìʽ___________________________________¡£

(6)GµÄͬ·ÖÒì¹¹ÌåÓжàÖÖ£¬Ð´³ö·ûºÏÏÂÁÐÌõ¼þµÄGµÄËùÓÐͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ_________________¡£

¢ÙÓöFeCl3ÈÜÒº·¢ÉúÏÔÉ«·´Ó¦£»¢ÚºË´Å¹²ÕñÇâÆ×ÓÐ4×é·å

(7)a,a-¶þ¼×»ùÜд¼ÊǺϳÉÒ½Ò©¡¢Å©Ò©µÄÖмäÌ壬ÒÔ±½ºÍ2-ÂȱûÍéΪÆðʼԭÁÏÖƱ¸a£¬a-¶þ¼×»ùÜд¼µÄºÏ³É·ÏßÈçÏ£º

¸Ã·ÏßÖÐÊÔ¼ÁÓëÌõ¼þ1Ϊ____________£»XµÄ½á¹¹¼òʽΪ___________£¬YµÄ½á¹¹¼òʽΪ____________£»ÊÔ¼ÁÓëÌõ¼þ2Ϊ____________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÒÔÈíÃÌ¿ó(Ö÷Òª³É·ÖΪMnO2)ºÍÁòÃÌ¿ó(Ö÷Òª³É·ÖΪMnS)ΪԭÁÏÖƱ¸ÁòËáÃ̾§ÌåµÄ¹¤ÒÕÁ÷³ÌÈçÏ£º

(1)ÂËÔüÖдæÔÚÒ»ÖַǽðÊôµ¥ÖÊ£¬ÔòËá½þ¹ý³ÌÖеĻ¯Ñ§·½³ÌʽΪ_________________________________¡£

(2)ʵÑéÊÒ³£ÓÃÑõ»¯»¹Ô­·¨²â¶¨MnSO4¡¤H2O¾§ÌåµÄ´¿¶È£¬Ô­ÀíÈçÏ£º2Mn2£«£«NO3-£«4PO43-£«2H£«===2[Mn(PO4)2]3£­£«NO2-£«H2O NH4+£«NO2-===N2¡ü£«2H2O [Mn(PO4)2]3£­£«Fe2£«===Mn2£«£«[Fe(PO4)2]3£­£»³ÆÈ¡MnSO4¡¤H2OÑùÆ·1.000 0 g£¬ÈÜÓÚÊÊÁ¿Ë®£¬ÒÔÁ×Ëá×÷Åäλ¼Á£¬¼ÓÈë¹ýÁ¿ÏõËá泥¬ÔÚ220¡«240 ¡æϳä·Ö·´Ó¦¡£È»ºóÒÔN¡ª±½´úÁÚ°±»ù±½¼×Ëá×÷ָʾ¼Á£¬ÓÃ0.100 0 mol¡¤L£­1ÁòËáÑÇÌú隣ê×¼ÈÜÒºµÎ¶¨Éú³ÉµÄ[Mn(PO4)2]3£­ÖÁÖյ㡣Öظ´²Ù×÷3´Î£¬¼Ç¼Êý¾ÝÈçÏÂ±í£º

µÎ¶¨´ÎÊý

±ê×¼Òº¶ÁÊýmL

µÎ¶¨Ç°

µÎ¶¨ºó

1

0.10

20.20

2

1.32

21.32

3

1.05

20.95

¢ÙÒÑÖª£ºFe2£«£«NO2-£«2H£«===Fe3£«£«NO¡ü£«H2O¡£

²â¶¨¹ý³ÌÖУ¬ÏõËá淋Ä×÷ÓÃÊÇ____________________ºÍ____________________¡£

¢ÚÈôµÎ¶¨¹ý³ÌÖбê×¼ÈÜÒºÁòËáÑÇÌú鱗»ÊÇÐÂÅäÖõģ¬Ëù²â¶¨µÄMnSO4¡¤H2O¾§ÌåµÄ´¿¶È½«»á________(Ìî¡°Æ«¸ß¡±¡°Æ«µÍ¡±»ò¡°²»±ä¡±)¡£

¢Û¼ÆËãÑùÆ·ÖÐMnSO4¡¤H2OµÄÖÊÁ¿·ÖÊý(д³ö¼ÆËã¹ý³Ì)__________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿¹¤ÒµÉÏÒÔîÑÌú¿ó[Ö÷Òª³É·ÖΪîÑËáÑÇÌú(FeTiO3)£¬º¬ÓÐMgO¡¢SiO2 µÈÔÓÖÊ]ΪԭÁÏ£¬ÖƱ¸½ðÊôîѺÍÌúºìµÄ¹¤ÒÕÁ÷³ÌÈçÏ£ºÒÑÖª£º¢ÙËáÈÜʱ£¬FeTiO3ת»¯ÎªFe2+ºÍTiO2+£»¢Ú±¾ÊµÑéζÈÏ£¬Ksp[Mg(OH)2]= 1.0¡Á10-11£»Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)FeTiO3ÖÐTiÔªËصĻ¯ºÏ¼ÛΪ_______¼Û¡£ÌúºìµÄÓÃ;Ϊ________________(ÈÎдһÖÖ)¡£

(2)¡°Ë®½â¡±ÖУ¬·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ____________________________________________¡£

(3)¡°³ÁÌú¡±ÖУ¬Æø̬²úÎïµÄµç×ÓʽΪ_________£»¸Ã¹ý³ÌÐè¿ØÖÆ·´Ó¦Î¶ȵÍÓÚ35¡æ£¬Ô­ÒòΪ_____________¡£

(4)FeCO3ת»¯ÎªÌúºìʱ£¬·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ________________________________________¡£

(5)ÂËÒº3¿ÉÓÃÓÚÖƱ¸Mg(OH)2¡£ÈôÂËÒº3 ÖÐc(Mg2+)=1.2¡Á10-4 mol¡¤L-1£¬ÏòÆäÖмÓÈëµÈŨ¶ÈµÈÌå»ýµÄNaOHÈÜҺʱ£¬Í¨¹ý¼ÆËã˵Ã÷ÓÐÎÞ³ÁµíÉú³É______________________________(ÈÜÒºÌå»ý½üËƵþ¼Ó)¡£

(6)µç½âÉú²úîÑʱÓÃTiO2ºÍʯī×öµç¼«£¬µç½âÖÊΪÈÛÈÚµÄCaO£¬ÔòÒõ¼«·´Ó¦Ê½Îª__________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÈçͼÁ½Æ¿Ìå»ýÏàµÈµÄÆøÌ壬ÔÚͬΡ¢Í¬Ñ¹ÏÂÆ¿ÄÚÆøÌåµÄ¹Øϵһ¶¨ÕýÈ·µÄÊÇ

A.Ô­×ÓÊýÏàµÈ

B.ÃܶÈÏàµÈ

C.ÖÊÁ¿ÏàµÈ

D.ÖÊ×ÓÊýÏàµÈ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÏÂÁжÔÎÄÖÐÃèÊöÄÚÈݵÄÏà¹Ø½âÊÍÕýÈ·µÄÊÇ£¨ £©

Ñ¡Ïî

ÃèÊö

½âîì

A

µ¤É°ÉÕÖ®³ÉË®Òø£¬»ý±äÓÖ»¹³Éµ¤É°

Á½¸ö·´Ó¦»¥Îª¿ÉÄæ·´Ó¦

B

·²ÛïÄàÔìÍߣ¬¾òµØ¶þ³ßÓ࣬ÔñÈ¡ÎÞɳճÍÁ¶øΪ֮

ÆäÖС°Íß¡±µÄÖ÷Òª³É·ÖΪ¹èËáÑÎ

C

Ïõʯ£¨KNO3£©ÈçÎÕÑÎÑ©²»±ù£¬Ç¿ÉÕÖ®£¬×ÏÇàÑÌÆð

²úÉú¡°×ÏÇàÑÌ¡±µÄÔ­ÒòΪKNO3·Ö½â

D

Æä·¨ÓÃŨ¾Æ¾«ºÍ²ÛÈëÆ¿£¬ÕôÁîÆøÉÏ£¬ÓÃÆ÷³ÐµÎ¶

ÆäÖÐÉæ¼°µÄ²Ù×÷·½·¨ÎªÕô·¢Å¨Ëõ

A. AB. BC. CD. D

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÊµÑéÊÒÖƱ¸Ïõ»ù±½µÄʵÑé×°ÖÃÈçͼËùʾ£¨¼Ð³Ö×°ÖÃÒÑÂÔÈ¥£©¡£

ÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ£¨ £©

A. ˮԡ¼ÓÈȵÄÓŵãΪʹ·´Ó¦ÎïÊÜÈȾùÔÈ¡¢ÈÝÒ׿ØÖÆζÈ

B. ½«Å¨ÁòËᡢŨÏõËáºÍ±½»ìºÏʱ£¬Ó¦ÏòŨÏõËáÖмÓÈËŨÁòËᣬ´ýÀäÈ´ÖÁÊÒκ󣬽«ËùµÃ»ìºÏÎï¼ÓÈë±½ÖÐ

C. ʵÑé¹ý³ÌÖз¢ÏÖÒÇÆ÷bÖÐδ¼ÓÈëËé´ÉƬ£¬¿ÉÀäÈ´ºó²¹¼Ó

D. ·´Ó¦ÍêÈ«ºó£¬¿ÉÓÃÒÇÆ÷a¡¢bÕôÁóµÃµ½²úÆ·

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿Ä³Î¶ÈÏ£¬ÖÊÁ¿Îª95 gµÄÂÈ»¯Ã¾ÈܽâÔÚ0.2 LË®ÖУ¨Ë®µÄÃܶȽüËÆΪ1 g/mL£©Ç¡ºÃµÃµ½ÂÈ»¯Ã¾µÄ±¥ºÍÈÜÒº£¬ËùµÃÈÜÒºµÄÃܶÈΪ¦Ñ g/mL£¬ÎïÖʵÄÁ¿Å¨¶ÈΪc mol/L£¬Èܽâ¶ÈΪs£¬NA±íʾ°¢·ü¼ÓµÂÂÞ³£ÊýµÄÖµ£¬ÔòÏÂÁÐÐðÊöÖÐÕýÈ·µÄÊÇ£¨¡¡¡¡£©

A. ËùµÃÈÜÒºÖк¬ÓÐNA¸öÂÈ»¯Ã¾·Ö×Ó

B. ËùµÃÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ5 mol/L

C. ËùµÃÈÜÒºµÄÈܽâ¶È¿É±íʾΪ9500 c/£¨1000¦Ñ-95c£©

D. ËùµÃÈÜÒºµÄÖÊÁ¿·ÖÊý¿É±íʾΪ95 ¦Ñ/£¨1000c£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿Ä³ÐÂÐÍÒ©ÎïH£¨£©ÊÇÒ»ÖÖ¿ÉÓÃÓÚÖÎÁÆÖ×ÁöµÄÒ©ÎÆäºÏ³É·ÏßÈçͼËùʾ£º

ÒÑÖª£º

£¨1£©EµÄ·Ö×ÓʽΪC9H8O2£¬ÄÜʹäåµÄËÄÂÈ»¯Ì¼ÈÜÒºÍÊÉ«£»

£¨2£©RCOOH £»

£¨3£©+R1NH2 +HBr¡££¨ÒÔÉÏR£¬R1¾ùΪÌþ»ù£©

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©AµÄ½á¹¹¼òʽΪ___________£»EµÄ¹ÙÄÜÍŵÄÃû³ÆΪ___________¡£

£¨2£©¢ÙµÄ·´Ó¦ÀàÐÍÊÇ________£»¢ÜµÄ·´Ó¦Ìõ¼þÊÇ__________¡£

£¨3£©Ð´³öC¡úDµÄ»¯Ñ§·½³Ìʽ£º______________________¡£

£¨4£©Ð´³öF+G¡úHµÄ»¯Ñ§·½³Ìʽ£º_________________________________________¡£

£¨5£©EÓжàÖÖͬ·ÖÒì¹¹Ì壬ͬʱÂú×ãÏÂÁÐÌõ¼þµÄEµÄͬ·ÖÒì¹¹ÌåÓÐ____£¨¿¼ÂÇ˳·´Òì¹¹£©ÖÖ¡£

i.ÄÜ·¢ÉúÒø¾µ·´Ó¦£»

ii.ÄÜ·¢ÉúË®½â·´Ó¦£»

iii.·Ö×ÓÖк¬µÄ»·Ö»Óб½»·¡£

£¨6£©²ÎÕÕHµÄÉÏÊöºÏ³É·Ïߣ¬Éè¼ÆÒ»ÌõÓÉÒÒÈ©ºÍNH2CH(CH3)2ΪÆðʼԭÁÏÖƱ¸Ò½Ò©ÖмäÌåCH3CONHCH(CH3)2µÄºÏ³É·Ïß__________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸