Question

ijǿËáÐÔÈÜÒºXº¬ÓÐBa2+¡¢Al3+¡¢N¡¢Fe2+¡¢Fe3+¡¢C¡¢S¡¢S¡¢Cl-¡¢NÖеÄÒ»ÖÖ»ò¼¸ÖÖ,È¡¸ÃÈÜÒº½øÐÐʵÑé,ʵÑéÄÚÈÝÈçÏÂ:

¸ù¾ÝÒÔÉÏÐÅÏ¢,»Ø´ðÏÂÁÐÎÊÌâ:

(1)ÈÜÒºXÖгýH+Í⻹¿Ï¶¨º¬ÓеÄÀë×ÓÊÇ¡¡¡¡¡¡;²»ÄÜÈ·¶¨ÊÇ·ñº¬ÓеÄÀë×ÓÊÇ¡¡¡¡¡¡,ÈôҪȷ¶¨ÆäÖÐÑôÀë×ӵĴæÔÚ,×î¿É¿¿µÄ»¯Ñ§·½·¨ÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£ 

(2)³ÁµíGµÄ»¯Ñ§Ê½Îª¡¡¡¡¡¡¡£ 

(3)д³öÓйØÀë×Ó·½³Ìʽ:

²½Öè¢ÙÖÐÉú³ÉA¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£ 

²½Öè¢ÚÉú³É³ÁµíI¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£ 

(4)¼ÙÉè²â¶¨A¡¢F¡¢I¾ùΪ0.01 mol,10 mL XÈÜÒºÖÐn(H+)=0.04 mol,¶ø³ÁµíCÎïÖʵÄÁ¿0.07 mol,ÄÜ˵Ã÷(1)Öв»ÄÜÈ·¶¨µÄÒõÀë×Ó´æÔÚµÄÀíÓÉÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£ 

 

Answer 1

(1)Al3+¡¢N¡¢Fe2+¡¢S¡¡Cl-¡¢Fe3+¡¡È¡ÉÙÁ¿XÈÜÒº·ÅÈëÊÔ¹ÜÖÐ,¼ÓÈ뼸µÎKSCNÈÜÒº,ÈÜÒº²»±äºìɫ˵Ã÷ÎÞFe3+,Èô±äºìÔò˵Ã÷º¬Fe3+(ûÓÐÈ¡Ñù¡¢È¡Á¿¿Û·Ö)

(2)Fe(OH)3

(3)3Fe2++N+4H+3Fe3++NO¡ü+2H2O¡¡Al+CO2+2H2OAl(OH)3¡ý+HC

(4)Èô¼ìÑéFe3+¿Ï¶¨´æÔÚʱ,¾ÍÓÐCl-´æÔÚ,ÒòΪ¿Ï¶¨´æÔÚµÄÀë×ÓµçºÉ×ÜÊýÒÑÏàµÈ

¡¾½âÎö¡¿Ç¿ËáÐÔÈÜÒºXÒ»¶¨²»º¬C¡¢S;ÔÚËáÐÔÈÜÒºÖÐÓëBa(NO3)2ÈÜÒº»ìºÏÓгÁµíCÉú³É,¿ÉÖªXÖк¬ÓÐS,Ò»¶¨ÎÞBa2+;Éú³ÉÆøÌåAÖ»ÄÜΪNO,ËùÒÔXÖк¬Óл¹Ô­ÐÔÎïÖÊFe2+,ÎÞN;ÈÜÒºBÖк¬ÓÐ Fe3+,³ÁµíGΪFe(OH)3;ÓÉÆøÌåF¿ÉÖªXÖк¬ÓÐN,Óɲ½Öè¢Ú¿ÉÖªXÖк¬ÓÐAl3+;(4)n(NO)=0.01 mol¡¢n(NH3)=0.01 mol¡¢n[Al(OH)3]=0.01 mol¡¢n(H+)=0.04 mol¡¢n(BaSO4)=0.07 mol,ÒÀ¾ÝÔ­×Ó¼°»¯ºÏ¼ÛÊغã¿ÉÖªÈÜÒºÖк¬ÓÐ:n(Fe2+)=3n(NO)=0.03 mol¡¢n(N)=0.01 mol¡¢n(Al3+)=0.01 mol¡¢n(H+)=0.04 mol¡¢n(S)=0.07 mol,ÒÀ¾ÝµçºÉÊغã2n(Fe2+)+n(N)+3n(Al3+)+n(H+)=0.14 mol=2n(S)