ÏÂÁÐÈÜÒºÖÐÓйØÎïÖʵÄÁ¿Å¨¶È¹Øϵ²»ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®pH=2µÄHAÈÜÒºÓëpH=12µÄMOHÈÜÒºÈÎÒâ±È»ìºÏ£ºc£¨H+£©+c£¨M+£©=c£¨OH+£©+c£¨A+£©
B£®ÔÚ0.1 mol?L-NH4ClÈÜÒºÖУ¬c£¨H+£©=c£¨NH3?H2O£©+c£¨OH-£©
C£®ÎïÖʵÄÁ¿Å¨¶ÈÏàµÈCH3COOHºÍ CH3COONaÈÜÒºµÈÌå»ý»ìºÏ£ºc(CH2COO-)+c£¨OH-£©=c£¨H+£©+c£¨CH2COOH£©
D£®0£®lmol/L´×Ëá±µÈÜÒºÖУ¬c£¨B¦Á2+£©£¾c(CH2COO-)£¾c£¨OH-£©£¾c£¨H+£©
A¡¢ÔÚ»ìºÏºóµÄÈÜÒºÖУ¬´æÔÚµÄÀë×Ó×ñÑ­µçºÉÊغ㣬¼´c£¨H+£©+c£¨M+£©=c£¨OH+£©+c£¨A+£©£¬¹ÊAÕýÈ·£»
B¡¢ÔÚÂÈ»¯ï§ÈÜÒºÖУ¬´æÔÚÖÊ×ÓÊغãc£¨H+£©=c£¨NH3?H2O£©+c£¨OH-£©£¬¹ÊBÕýÈ·£»
C¡¢ÈÜÒºµÈÌå»ý»ìºÏºó£¬¸ù¾ÝµçºÉÊغ㣺c£¨CH3COO-£©+c£¨OH-£©=c£¨H+£©+c£¨Na+£©£¬»ìºÏÈÜÒºÖл¹´æÔÚc£¨CH3COO-£©+c£¨CH3COOH£©=2c£¨Na+£©£¬µ«ÊÇc£¨CH3COOH£©¡Ùc£¨Na+£©£¬¹ÊC´íÎó£»
D¡¢´×Ëá±µÈÜÒºÖУ¬¸ù¾ÝµçÀëÇé¿ö¿ÉÖª£ºc£¨CH3COO-£©£¾c£¨B¦Á2+£©£¬ÈÜÒºÖд×Ëá¸ùÀë×ÓË®½âÏÔ¼îÐÔ£¬
ËùÒÔc£¨OH-£©£¾c£¨H+£©£¬¼´c£¨CH3COO-£©£¾c£¨B¦Á2+£©£¾c£¨OH-£©£¾c£¨H+£©£¬¹ÊD´íÎó£®
¹ÊÑ¡CD£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÏÂÁÐÈÜÒºÖÐÓйØÎïÖʵÄÁ¿Å¨¶È¹ØϵÕýÈ·µÄÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2011?¸ÊËà¶þÄ££©ÏÂÁÐÈÜÒºÖÐÓйØÎïÖʵÄÁ¿Å¨¶È¹Øϵ´íÎóµÄÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÏÂÁÐÈÜÒºÖÐÓйØÎïÖʵÄÁ¿Å¨¶È¹ØϵºÍ¼ÆËã²»ÕýÈ·µÄÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÏÂÁÐÈÜÒºÖÐÓйØÎïÖʵÄŨ¶È¹ØϵÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A¡¢c£¨NH4+£©ÏàµÈµÄ£¨NH4£©2SO4¡¢NH4HSO4¡¢NH4ClÈÜÒºÖУºc£¨NH4HSO4£©£¾c[£¨NH4£©2SO4]£¾c£¨NH4Cl£©B¡¢Ïò´×ËáÄÆÈÜÒºÖмÓÈëÊÊÁ¿´×ËᣬµÃµ½µÄËáÐÔ»ìºÏÈÜÒº£ºc£¨Na+£©£¾c£¨CH3COO-£©£¾c£¨H+£©£¾c£¨OH-£©C¡¢1.0 mol/L Na2CO3ÈÜÒº£ºc£¨OH-£©=c£¨HCO3-£©+c£¨H+£©+2c£¨H2CO3£©D¡¢Ä³¶þÔªÈõËáµÄËáʽÑÎNaHAÈÜÒºÖУºc£¨H+£©+c£¨Na+£©=c£¨OH-£©+c£¨HA-£©+c£¨A2-£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÏÂÁÐÈÜÒºÖÐÓйØÎïÖʵÄÁ¿Å¨¶È¹Øϵһ¶¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸