Na¡¢Cu¡¢O¡¢Si¡¢S¡¢ClÊdz£¼ûµÄÁùÖÖÔªËØ¡£

(1)NaλÓÚÔªËØÖÜÆÚ±íµÚ________ÖÜÆÚµÚ________×壻SµÄ»ù̬ԭ×ÓºËÍâÓÐ________¸öδ³É¶Ôµç×Ó£»SiµÄ»ù̬ԭ×ÓºËÍâµç×ÓÅŲ¼Ê½Îª________________________¡£

(2)Óá°>¡±»ò¡°<¡±Ìî¿Õ£º

µÚÒ»µçÀëÄÜ

Àë×Ӱ뾶

ÈÛµã

ËáÐÔ

Si____S

O2£­____Na£«

NaCl____Si

H2SO4____HClO4

(3)CuCl(s)ÓëO2·´Ó¦Éú³ÉCuCl2(s)ºÍÒ»ÖÖºÚÉ«¹ÌÌå¡£ÔÚ25 ¡æ¡¢101 kPaÏ£¬ÒÑÖª¸Ã·´Ó¦Ã¿ÏûºÄ1 mol CuCl(s)£¬·ÅÈÈ44.4 kJ£¬¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÊÇ________________________________________________________________________

________________________________________________________________________¡£

(4)ClO2³£ÓÃÓÚË®µÄ¾»»¯£¬¹¤ÒµÉÏ¿ÉÓÃCl2Ñõ»¯NaClO2ÈÜÒºÖÆÈ¡ClO2¡£Ð´³ö¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ£¬²¢±ê³öµç×ÓתÒƵķ½ÏòºÍÊýÄ¿£º________________________________________________________________________¡£


(1)Èý¡¡¢ñ A¡¡2¡¡1s22s22p63s23p2

(2)

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


Ò»ÖÖ»ùÓÚËáÐÔȼÁϵç³ØÔ­ÀíÉè¼ÆµÄ¾Æ¾«¼ì²âÒÇ£¬¸º¼«Éϵķ´Ó¦Îª£º

    CH3CH2OH£­4e¡ª+H2O==CH3COOH£«4H+¡£ÏÂÁÐÓйØ˵·¨ÕýÈ·µÄÊÇ

  A£®¼ì²âʱ£¬µç½âÖÊÈÜÒºÖеÄH+Ïò¸º¼«Òƶ¯

  B£®ÈôÓÐ 0.4  molµç×ÓתÒÆ£¬ÔòÔÚ±ê×¼×´¿öÏÂÏûºÄ 4.48 LÑõÆø

  C£®µç³Ø·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCH3CH2OH£«O2===CH3COOH£«H2O

  D£®Õý¼«ÉÏ·¢ÉúµÄ·´Ó¦Îª£ºO2£«4e£­£«2H2O===4OH£­

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


·¢ÉäÎÀÐǵĻð¼ýÍƽøÆ÷Öдó¶àʹÓÃȼÁÏÆ«¶þ¼×룬Æ仯ѧʽC2H8N2¡£¼ÆË㣺

£¨1£©Æ«¶þ¼×ëµÄĦ¶ûÖÊÁ¿ÊÇ________£»480 gÆ«¶þ¼×ëµÄÎïÖʵÄÁ¿Îª________¡£

£¨2£©Æ«¶þ¼×ëÂÖÐ̼ԭ×ÓÓ뵪ԭ×ӵĸöÊýÖ®±ÈÊÇ________£¬ÆäÎïÖʵÄÁ¿Ö®±ÈÊÇ________£»1molÆ«¶þ¼×ëÂÖк¬ÓеÄÇâÔ­×ÓÊýÄ¿ÊÇ________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


Èôa g CO2º¬b¸ö·Ö×Ó£¬Ôò°¢·ü¼ÓµÂÂÞ³£ÊýµÄֵΪ  £¨    £©

A. ab/28         B. ab/14       C. 28/b           D. 44b/a

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


²Ýľ»ÒÖк¬ÓпÉÈÜÐÔ¼ØÑΣ¨Ö÷Òª³É·ÖÊÇK2SO4¡¢K2CO3¡¢KCl£©¡£Ä³Ñ§Éú°´ÏÂÁвÙ×÷ÌáÈ¡²Ýľ»ÒÖеļØÑΣº¢ÙÈ¡²Ýľ»Ò¼ÓË®Èܽ⣻¢Ú¹ýÂË.È¡ÂËÒº£»¢ÛÕô·¢ÂËÒº£»¢ÜÀäÈ´½á¾§¡£Îª¼ìÑé²Ýľ»ÒÖеÄÒõÀë×Ó£¬È¡ÉÙÁ¿¾§ÌåÈÜÓÚË®£¬²¢°ÑÈÜÒº·Ö³ÉÈýµÈ·Ö£º

¢ÙÈ¡Ò»·ÝÈÜÒº£¬¼ÓÈëÊÊÁ¿HCl£¬¹Û²ìµ½____________________________£¬Ö¤Ã÷º¬ÓÐ̼Ëá¸ù¡£

¢ÚÈ¡ÁíÒ»·ÝÈÜÒº£¬Îª¼ìÑéSO42-£¬Ó¦ÍùÈÜÒºÖÐÏȼÓÈë¹ýÁ¿µÄ_______£¬ÔÙ¼ÓÈëBaCl2ÈÜÒº¡£

¢ÛÈ¡Ê£ÓàµÄÒ»·ÝÈÜÒº£¬¼ÓÊÊÁ¿µÄÏõËáÒø£¬¹Û²ìµ½ÓгÁµí²úÉú£¬¸ÃÉúÓÉ´ËÖ¤Ã÷ÈÜÒºÖÐÒ»¶¨º¬Cl-¡£ÄãÈÏΪËùµÃµÄ½áÂÛÊÇ·ñÑÏÃÜ£¿______¡£ÀíÓÉÊÇ                              ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


Na¡¢Cu¡¢O¡¢Si¡¢S¡¢ClÊdz£¼ûµÄÁùÖÖÔªËØ¡£

(1)NaλÓÚÔªËØÖÜÆÚ±íµÚ________ÖÜÆÚµÚ________×壻SµÄ»ù̬ԭ×ÓºËÍâÓÐ________¸öδ³É¶Ôµç×Ó£»SiµÄ»ù̬ԭ×ÓºËÍâµç×ÓÅŲ¼Ê½Îª________________________¡£

(2)Óá°>¡±»ò¡°<¡±Ìî¿Õ£º

µÚÒ»µçÀëÄÜ

Àë×Ӱ뾶

ÈÛµã

ËáÐÔ

Si____S

O2£­____Na£«

NaCl____Si

H2SO4____HClO4

(3)CuCl(s)ÓëO2·´Ó¦Éú³ÉCuCl2(s)ºÍÒ»ÖÖºÚÉ«¹ÌÌå¡£ÔÚ25 ¡æ¡¢101 kPaÏ£¬ÒÑÖª¸Ã·´Ó¦Ã¿ÏûºÄ1 mol CuCl(s)£¬·ÅÈÈ44.4 kJ£¬¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÊÇ________________________________________________________________________

________________________________________________________________________¡£

(4)ClO2³£ÓÃÓÚË®µÄ¾»»¯£¬¹¤ÒµÉÏ¿ÉÓÃCl2Ñõ»¯NaClO2ÈÜÒºÖÆÈ¡ClO2¡£Ð´³ö¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ£¬²¢±ê³öµç×ÓתÒƵķ½ÏòºÍÊýÄ¿£º________________________________________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


 [»¯Ñ§¡ª¡ªÑ¡ÐÞ3£»ÎïÖʽṹÓëÐÔÖÊ](15·Ö)

ÖÜÆÚ±íÇ°ËÄÖÜÆÚµÄÔªËØa¡¢b¡¢c¡¢d¡¢e£¬Ô­×ÓÐòÊýÒÀ´ÎÔö´ó¡£aµÄºËÍâµç×Ó×ÜÊýÓëÆäÖÜÆÚÊýÏàͬ£¬bµÄ¼Ûµç×Ó²ãÖÐδ³É¶Ôµç×ÓÓÐ3¸ö£¬cµÄ×îÍâ²ãµç×ÓÊýΪÆäÄÚ²ãµç×ÓÊýµÄ3±¶£¬dÓëcͬ×壻eµÄ×îÍâ²ãÖ»ÓÐ1¸öµç×Ó£¬µ«´ÎÍâ²ãÓÐ18¸öµç×Ó¡£»Ø´ðÏÂÁÐÎÊÌ⣻

(1)b¡¢c¡¢dÖеÚÒ»µçÀëÄÜ×î´óµÄÊÇ________(ÌîÔªËØ·ûºÅ)£¬eµÄ¼Û²ãµç×Ó¹ìµÀʾÒâͼΪ________¡£

(2)aºÍÆäËûÔªËØÐγɵĶþÔª¹²¼Û»¯ºÏÎïÖУ¬·Ö×Ó³ÊÈý½Ç׶ÐΣ¬¸Ã·Ö×ÓµÄÖÐÐÄÔ­×ÓµÄÔÓ»¯·½Ê½Îª______£»·Ö×ÓÖмȺ¬Óм«ÐÔ¹²¼Û¼ü¡¢ÓÖº¬ÓзǼ«ÐÔ¹²¼Û¼üµÄ»¯ºÏÎïÊÇ________(Ìѧʽ£¬Ð´³öÁ½ÖÖ)¡£

(3)ÕâЩԪËØÐγɵĺ¬ÑõËáÖУ¬·Ö×ÓµÄÖÐÐÄÔ­×ӵļ۲ãµç×Ó¶ÔÊýΪ3µÄËáÊÇ________£»Ëá¸ù³ÊÈý½Ç׶½á¹¹µÄËáÊÇ________¡£(Ìѧʽ)

(4)eºÍcÐγɵÄÒ»ÖÖÀë×Ó»¯ºÏÎïµÄ¾§Ìå½á¹¹Èçͼ(a)£¬ÔòeÀë×ӵĵçºÉΪ________¡£

(5)Õâ5ÖÖÔªËØÐγɵÄÒ»ÖÖ1¡Ã1ÐÍÀë×Ó»¯ºÏÎïÖУ¬ÒõÀë×Ó³ÊËÄÃæÌå½á¹¹£»ÑôÀë×Ó³ÊÖáÏòÏÁ³¤µÄ°ËÃæÌå½á¹¹[Èçͼ(b)Ëùʾ]¡£

¡¡¡¡¡¡

(a)¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡(b)

¸Ã»¯ºÏÎïÖУ¬ÒõÀë×ÓΪ________£¬ÑôÀë×ÓÖдæÔڵĻ¯Ñ§¼üÀàÐÍÓÐ________£»¸Ã»¯ºÏÎï¼ÓÈÈʱÊ×ÏÈʧȥµÄ×é·ÖÊÇ________£¬ÅжÏÀíÓÉÊÇ______________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


£¨1£©ÒÀ¾ÝµÚ2ÖÜÆÚÔªËصÚÒ»µçÀëÄܵı仯¹æÂÉ£¬²ÎÕÕÓÒͼB¡¢FÔªËصÄλÖã¬ÓÃСºÚµã±ê³öC¡¢N¡¢OÈýÖÖÔªËصÄÏà¶ÔλÖá£

£¨2£©NF3¿ÉÓÉNH3ºÍF2ÔÚCu´ß»¯¼Á´æÔÚÏ·´Ó¦Ö±½ÓµÃµ½£º

¢ÙÉÏÊö»¯Ñ§·½³ÌʽÖеÄ5ÖÖÎïÖÊËùÊôµÄ¾§ÌåÀàÐÍÓÐ_________£¨ÌîÐòºÅ£©¡£

a.Àë×Ó¾§Ìå b.·Ö×Ó¾§Ìå c.Ô­×Ó¾§Ìå d.½ðÊô¾§Ìå

¢Ú»ù̬ͭԭ×ӵĺËÍâµç×ÓÅŲ¼Ê½Îª________¡£

£¨3£©BF3ÓëÒ»¶¨Á¿Ë®ÐγÉ(H2O)2¡¤BF3¾§ÌåQ£¬QÔÚÒ»¶¨Ìõ¼þÏ¿Éת»¯ÎªR£º

¢Ù¾§ÌåQÖи÷ÖÖ΢Á£¼äµÄ×÷ÓÃÁ¦²»Éæ¼°___________£¨ÌîÐòºÅ£©¡£

a.Àë×Ó¼ü b.¹²¼Û¼ü  c.Åäλ¼ü d.½ðÊô¼ü e.Çâ¼ü f.·¶µÂ»ªÁ¦

¢ÚRÖÐÑôÀë×ӵĿռ乹ÐÍΪ_______£¬ÒõÀë×ÓµÄÖÐÐÄÔ­×Ó¹ìµÀ²ÉÓÃ_______ÔÓ»¯¡£

£¨4£©ÒÑÖª±½·Ó()¾ßÓÐÈõËáÐÔ£¬ÆäKa=1.1 ¡Á10-10£»Ë®ÑîËáµÚÒ»¼¶µçÀëÐγɵÄÀë×ÓÄÜÐγɷÖ×ÓÄÚÇâ¼ü¡£¾Ý´ËÅжϣ¬ÏàͬζÈϵçÀëƽºâ³£ÊýKa2(Ë®ÑîËá)_______Ka(±½·Ó)£¨Ìî¡°>¡±»ò¡°<¡±£©£¬ÆäÔ­ÒòÊÇ__________¡£

¡¾ÖªÊ¶µã¡¿»¯Ñ§¼ü¡¢¾§Ìå½á¹¹¡¢µç×ÓÅŲ¼Ê½µÄÊéд¡¢ÔÓ»¯¹ìµÀ¡¢·Ö×ӵĿռ乹ÐÍÒÔ¼°µçÀë

³£ÊýµÈ֪ʶ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


Í­µ¥Öʼ°Æ仯ºÏÎïÔںܶàÁìÓòÓÐÖØÒªÓÃ;£¬Èç½ðÊôÍ­ÓÃÀ´ÖÆÔìµçÏßµçÀ£¬ÎåË®ÁòËáÍ­¿ÉÓÃ×÷ɱ¾ú¼Á¡£

£¨1£©CuλÓÚÔªËØÖÜÆÚ±íµÚ¢ñB×å¡£Cu2+µÄºËÍâµç×ÓÅŲ¼Ê½Îª_____________________¡£

£¨2£©ÏÂͼÊÇÍ­µÄijÖÖÑõ»¯ÎïµÄ¾§°û½á¹¹Ê¾Òâͼ£¬¿ÉÈ·¶¨¸Ã¾§°ûÖÐÒõÀë×ӵĸöÊýΪ________¡£

£¨3£©µ¨·¯CuSO4¡¤5H2O¿Éд³É£ÛCu£¨H2O£©4£ÝSO4¡¤H2O£¬Æä½á¹¹Ê¾ÒâͼÈçÏ£º

ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ_________________£¨Ìî×Öĸ£©¡£

A.ÔÚÉÏÊö½á¹¹Ê¾ÒâͼÖУ¬ËùÓÐÑõÔ­×Ó¶¼²ÉÓÃsp3ÔÓ»¯

B.ÔÚÉÏÊö½á¹¹Ê¾ÒâͼÖУ¬´æÔÚÅäλ¼ü¡¢¹²¼Û¼üºÍÀë×Ó¼ü

C.µ¨·¯ÊÇ·Ö×Ó¾§Ì壬·Ö×Ó¼ä´æÔÚÇâ¼ü

D.µ¨·¯ÖеÄË®ÔÚ²»Í¬Î¶ÈÏ»á·Ö²½Ê§È¥

£¨4£©ÍùÁòËáÍ­ÈÜÒºÖмÓÈë¹ýÁ¿°±Ë®£¬¿ÉÉú³É£ÛCu£¨NH3£©4£Ý2+ÅäÀë×Ó¡£ÒÑÖªNF3ÓëNH3µÄ¿Õ¼ä¹¹ÐͶ¼ÊÇÈý½Ç׶ÐΣ¬µ«NF3²»Ò×ÓëCu2+ÐγÉÅäÀë×Ó£¬ÆäÔ­ÒòÊÇ_____________________¡£

£¨5£©Cu2OµÄÈÛµã±ÈCu2SµÄ______________£¨Ìî¡°¸ß¡±»ò¡°µÍ¡±£©£¬Çë½âÊÍÔ­Òò____________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸